Getting the last record in SQL in WHERE condition - sql

i have loanTable that contain two field loan_id and status
loan_id status
==============
1 0
2 9
1 6
5 3
4 5
1 4 <-- How do I select this??
4 6
In this Situation i need to show the last Status of loan_id 1 i.e is status 4. Can please help me in this query.

Since the 'last' row for ID 1 is neither the minimum nor the maximum, you are living in a state of mild confusion. Rows in a table have no order. So, you should be providing another column, possibly the date/time when each row is inserted, to provide the sequencing of the data. Another option could be a separate, automatically incremented column which records the sequence in which the rows are inserted. Then the query can be written.
If the extra column is called status_id, then you could write:
SELECT L1.*
FROM LoanTable AS L1
WHERE L1.Status_ID = (SELECT MAX(Status_ID)
FROM LoanTable AS L2
WHERE L2.Loan_ID = 1);
(The table aliases L1 and L2 could be omitted without confusing the DBMS or experienced SQL programmers.)
As it stands, there is no reliable way of knowing which is the last row, so your query is unanswerable.

Does your table happen to have a primary id or a timestamp? If not then what you want is not really possible.
If yes then:
SELECT TOP 1 status
FROM loanTable
WHERE loan_id = 1
ORDER BY primaryId DESC
-- or
-- ORDER BY yourTimestamp DESC

I assume that with "last status" you mean the record that was inserted most recently? AFAIK there is no way to make such a query unless you add timestamp into your table where you store the date and time when the record was added. RDBMS don't keep any internal order of the records.

But if last = last inserted, that's not possible for current schema, until a PK addition:
select top 1 status, loan_id
from loanTable
where loan_id = 1
order by id desc -- PK

Use a data reader. When it exits the while loop it will be on the last row. As the other posters stated unless you put a sort on the query, the row order could change. Even if there is a clustered index on the table it might not return the rows in that order (without a sort on the clustered index).
SqlDataReader rdr = SQLcmd.ExecuteReader();
while (rdr.Read())
{
}
string lastVal = rdr[0].ToString()
rdr.Close();
You could also use a ROW_NUMBER() but that requires a sort and you cannot use ROW_NUMBER() directly in the Where. But you can fool it by creating a derived table. The rdr solution above is faster.

In oracle database this is very simple.
select * from (select * from loanTable order by rownum desc) where rownum=1

Hi if this has not been solved yet.
To get the last record for any field from a table the easiest way would be to add an ID to each record say pID. Also say that in your table you would like to hhet the last record for each 'Name', run the simple query
SELECT Name, MAX(pID) as LastID
INTO [TableName]
FROM [YourTableName]
GROUP BY [Name]/[Any other field you would like your last records to appear by]
You should now have a table containing the Names in one column and the last available ID for that Name.
Now you can use a join to get the other details from your primary table, say this is some price or date then run the following:
SELECT a.*,b.Price/b.date/b.[Whatever other field you want]
FROM [TableName] a LEFT JOIN [YourTableName]
ON a.Name = b.Name and a.LastID = b.pID
This should then give you the last records for each Name, for the first record run the same queries as above just replace the Max by Min above.
This should be easy to follow and should run quicker as well

If you don't have any identifying columns you could use to get the insert order. You can always do it like this. But it's hacky, and not very pretty.
select
t.row1,
t.row2,
ROW_NUMBER() OVER (ORDER BY t.[count]) AS rownum from (
select
tab.row1,
tab.row2,
1 as [count]
from table tab) t
So basically you get the 'natural order' if you can call it that, and add some column with all the same data. This can be used to sort by the 'natural order', giving you an opportunity to place a row number column on the next query.
Personally, if the system you are using hasn't got a time stamp/identity column, and the current users are using the 'natural order', I would quickly add a column and use this query to create some sort of time stamp/incremental key. Rather than risking having some automation mechanism change the 'natural order', breaking the data needed.

I think this code may help you:
WITH cte_Loans
AS
(
SELECT LoanID
,[Status]
,ROW_NUMBER() OVER(ORDER BY (SELECT 1)) AS RN
FROM LoanTable
)
SELECT LoanID
,[Status]
FROM LoanTable L1
WHERE RN = ( SELECT max(RN)
FROM LoanTable L2
WHERE L2.LoanID = L1.LoanID)

Related

Write Oracle SQL query to fetch from Tasks table top Approval Statuses that appear after some first null value

Write Oracle SQL query to fetch from Tasks table top Approval Statuses that appear after some first null value in the Approval_Status Column and then Approval Status sequence and then some null values
Facts
I only need the top Approval Statuses sequence
Serial Number for each task ID Sequence starts from 1 and then comes in Sequence like 1.2.3... and so on
There are thousands of tasks in the table like from T1 .... Tn
See the Query Result below i need to write a query that returns data in that format
I have heard analytic function i.e. "Partition By clause" for this can be used but i don't know how to use that
Tasks
Query Result
I really appreciate experts help in this regard
Thanks
You can do this with analytic functions, but there is a trick. The idea is to look only at rows where approval_status is not null. You want the first group of sequential serial numbers in this group.
The group is identified by the difference between a sequence that enumerates all the rows and the existing serial number. To get the first, use dense_rank(). Finally, choose the first by looking for the ones with a rank equal to 1:
select t.*
from (select t.*, dense_rank(diff) over (partition by taskid) as grpnum
from (select t.*,
(row_number() over (partition by taskid order by serial_number) -
serial_number
) as diff
from tasks
where approval_status is not null
) t
) t
where grpnum = 1;

SQL Select WHERE duplicate in one column x AND column y != z

So we had a duplicate SQL scripts running on our server and didn't realize it till just recently. Essentially I have many rows where there are 2 entries with the same column x (crn).
The initially got entered with the same column y (status) as well. Our application has users update the column y (status). However now we have 2 rows one with a status of 'S' and one with a status of something other than 'S'. My goal:
DELETE everything from the table WHERE there is a duplicate CRN and the STATUS is S. I don't want to delete rows unless there is a duplicate, but if there is, I only want to delete the row with a status of 'S'. Also, I'd rather not delete both records if both have a status of S, but if I do, that isn't such a big deal because I will get the courses again in the next download.
I have started making a select statement to query the rows I want, but don't know how to do the ONLY SELECT IF DUPLICATE EXISTS part. I feel like I need to UNION or LEFT JOIN or something to only get records if a duplicate exists.
SELECT * FROM
cas_usuECourses
WHERE
crn IN (SELECT crn FROM cas_usuECourses GROUP BY crn having count(1) > 1)
AND status = 'S'
AND termCode = 201320
EDIT: Is there a way to say... the above, but if both dups have 'S' only delete one of them?
EDIT: I "think" this looks good to me. Any thoughts?
SELECT id FROM (
SELECT id, Row_Number() Over (Partition By crn ORDER BY id DESC) as ranking
FROM cas_usuECourses
WHERE status = 'S'
AND termCode = 201320
) as ranking
WHERE ranking = 1
I think this will give me all the ids where the status is 'S', and if there are two with 'S' this will give me the one that was created second. I found out that every entry in our termCode has duplicates, so... don't need to worry about checking for the duplicates.
If you could add one column to your table and fill it with distinct values, it would be trivial - you could target each row.
Otherwise, after your initial step, I would generally open a cursor on your subselect with status S to select only crn's where both statuses are 'S', and in each loop iteration delete top 1 record with appropriate crn. That way you can get rid of duplicate crn/status pairs.

Delete multiple occurrences of the same ID # and code in a junction table

enter code here
My problem is this: in this database the junction table contains some rows where the kha_id and the icd_fk are the same. While it's OK that kha_id appears in icd_junction more than once , it has to be with a separate icd_fk. I can run a query and get all of the ID#s and the codes which are listed more than once, but is there an industry-standard way of going about deleting all but one occurrence of each?
example: what i have is above
KHA_ID: 123456 V23
123456 V23
123456 V24
I need one of the rows kha_id=123456 and ICD_FK=V23 taken out.
This:
DELETE j1
FROM ICD_Junction AS j1
WHERE EXISTS
( SELECT 1
FROM ICD_Junction AS j2
WHERE j2.KHA_ID = j1.KHA_ID
AND j2.ICD_FK = j1.ICD_FK
AND j2.ID < j1.ID
)
;
will delete, for each KHA_ID and ICD_FK, all but one relevant row of ICD_Junction. (Specifically, it will keep the one with the least ID, and delete the rest.)
Once you've run the above, you should fix whatever code caused the duplication, and add a unique constraint to prevent this from happening again.
(Disclaimer: Not tested, and it's been a while since I last used SQL Server.)
Edited to add: If I'm understanding your comment correctly, you also need help with the query to find duplicates? For that, you can write:
SELECT KHA_ID,
ICD_FK,
COUNT(1) -- the number of duplicates
FROM ICD_Junction
GROUP
BY KHA_ID,
ICD_FK
HAVING COUNT(1) > 1
;
The original question was delete but the comment was find
Select jDup.*
FROM ICD_Junction AS j
JOIN ICD_Junction AS jDup
On j.KHA_ID = jDup.KHA_ID
AND j.ICD_FK = jDup.ICD_FK
AND j.ID < jDup.ID
Select max(jDup.ID), min(jDup.ID), count(*), jDup.KHA_ID, jDup.ICD_FK
FROM ICD_Junction AS jDup
Group By jDup.KHA_ID, jDup.ICD_FK
Having Count(*) > 1
You want something that uses ROW_NUMBER() and partition by. The reason is that it will let you pick one row to keep from a table that doesn't have a unique id. Like if this was a pure intersection table with no identity, you could use a variation on this to delete all rows where RowID > 1, leaving you just the unique rows. And it works just as well when you do have a unique id, where you can choose to preserve the earliest id.
select * from (select KHA_ID, ICD_FK, ROW_NUMBER()
OVER(PARTITION BY KHA_ID, ICD_FK
ORDER BY ID ASC) AS RowID
from ICD_Junction ) ordered where RowID > 1

How to get the position of a record in a table (SQL Server)

Following problem:
I need to get the position of a record in the table. Let's say I have five record in the table:
Name: john doe, ID: 1
Name: jane doe, ID: 2
Name: Frankie Boy, ID: 4
Name: Johnny, ID: 9
Now, "Frankie Boy" is in the third position in the table. But How to get this information from the SQL server? I could count IDs, but they are not reliable, Frankie has the ID 4, but is in the third position because the record with the ID '3' was deleted.
Is there a way? I am aware of ROW_RANK but it would be costly, because I need to select basically the whole set first before I can rank row_rank them.
I am using MS SQL Server 2008 R2.
Tables don't have 'position'. Rows in a table (=set) are identified by their primary key value. Only result rows have 'position' which can be deterministic when a ORDER BY clause is present. Assuming that tables (=sets) have a position will lead only to problems and is the wrong mind set.
You can use row_number() to "label" rows. You've got to specify a way to order the rows:
select row_number() over (order by id) as PositionInTable
, *
from YourTable
If performance is an issue, you could store the position in a new column:
update yt1
set PositionInTable = rn
from YourTable yt1
join (
select row_number() over (order by id) as rn
, id
from YourTable
) yt2
on yt1.id = yt2.id
With an index on PositionInTable, this would be lightning fast. But you would have to update this after each insert on the table.
Tables are [conceptually] without order. Unless you specify ORDER BY in a select statement to order a results set, results may be returned in any order. Repeated executions of the exact same SQL may return the results set in different orders fro each execution.
To get the row number in a particular result set, use the row_number() function:
select row = row_number() over( order by id ) , *
from sysobjects
This will assign a row number to each row in sysobjects as if the table were ordered by id.
A simple way to do this without having to use ROW_NUMBER would be to simply count how many rows in the table have an index less or equal to the selected index, this would give the row number.
SELECT COUNT(*) FROM YourTable WHERE ID <= 4 -- Frankie Boy, Result = 3
This may not be the most efficient way to do it for your particular scenario, but it's a simple way of achieving it.

SQL Max Function per group

I have a complex query and which may return more than one record per group. There is a field that has a numeric sequential number. If in a group there is more than one record returned I just want the record with the highest sequential number.
I’ve tried using the SQL MAX function, but if I try to add more than one field it returns all records, instead of the one with the highest sequential field in that group.
I am trying to accomplish this in MS Access.
Edit: 4/5/11
Trying to create a table as an example of what I am trying to do
I have the following table:
tblItemTrans
ItemID(PK)
Eventseq(PK)
ItemTypeID
UserID
Eventseq is a number field that increments for each ItemID. (Don’t ask me why, that’s how the table was created.) Each ItemID can have one or many Evenseq’s. I only need the last record (max(Eventseq)) PER each ItemTypeID.
Hope this helps any.
SELECT A.*
FROM YourTable A
INNER JOIN (SELECT GroupColumn, MAX(SequentialColumn) MaxSeq
FROM YourTable
GROUP BY GroupColumn) B
ON A.GroupColumn = B.GroupColumn AND A.SequentialColumn = B.MaxSeq
If your SequentialNumber is an ID (unique across the table), then you could use
select *
from tbl
where seqnum in (
select max(seqnum) from tbl
group by groupcolumn)
If it is not, an alternative to Lamak's query is the Access domain function DMAX
select *
from tbl
where seqnum = DMAX("seqnum", "tbl", "groupcolumn='" & groupcolumn & "'")
Note: if the groupcolumn is a date, use # instead of single quotes ' in the above, if it is a numeric, remove the single quotes.