sql timesheet count by day for the week - sql

Question

my table looks like this:
select clocktime, for_UID, in1_out0 from timeclockentries
clocktime for_UID in1_out0
2011-08-07 15:13:58.390 user193 1
2011-08-07 21:09:45.093 user193 0
2011-08-09 14:10:00.000 user193 1
2011-08-09 20:10:00.000 user193 0
I want the results to look like (assuming start of week is Saturday), separated by COLUMNS named 'day1', 'day2', etc.... (but for readability, i've typed them out with linefeeds) :
day1 day2 day3
1900-01-01 00:00:00.000 1900-01-01 05:55:46.700 1900-01-01 00:00:00.000
day4 day5 day6
1900-01-01 06:00:00.000 1900-01-01 00:00:00.000 1900-01-01 00:00:00.000
day7
1900-01-01 00:00:00.000
(i'm using sql2005)
below is what i'm using for a single day:
CREATE PROCEDURE [dbo].[sp_gethoursbyday]
#whichforUID varchar(20),
#whichdate datetime
AS
BEGIN
;WITH CTE as(
SELECT
DENSE_RANK() over (Partition by for_UID , in1_out0 Order by clocktime) id,
clocktime,
for_UID,
in1_out0
FROM
kdhcastle.dbo.timeclockentries tc
WHERE
tc.for_UID = #whichforUID
and month(tc.[clocktime]) = month(#whichdate)
and day(tc.[clocktime]) = day(#whichdate)
and year(tc.[clocktime]) = year(#whichdate)
)
SELECT
Cast(cast(sum(
cast(outTime.clocktime as float) - cast(inTime.clocktime as float)
)as datetime) as datetime) as 'hoursbydy'
FROM
CTE inTime
INNER JOIN CTE outTime
ON inTime.for_UID = outTime.for_UID
AND inTime.id = outTime.id
AND inTime.in1_out0 = 1
and outTime.in1_out0 = 0
END

Answer 1

SELECT
SUM(CASE WHEN DayOfWeek = 1 THEN Duration ELSE 0 END) AS Day1,
SUM(CASE WHEN DayOfWeek = 2 THEN Duration ELSE 0 END) AS Day2,
SUM(CASE WHEN DayOfWeek = 3 THEN Duration ELSE 0 END) AS Day3,
SUM(CASE WHEN DayOfWeek = 4 THEN Duration ELSE 0 END) AS Day4,
SUM(CASE WHEN DayOfWeek = 5 THEN Duration ELSE 0 END) AS Day5,
SUM(CASE WHEN DayOfWeek = 6 THEN Duration ELSE 0 END) AS Day6,
SUM(CASE WHEN DayOfWeek = 7 THEN Duration ELSE 0 END) AS Day7
FROM
(
SELECT
DATEDIFF(DAY, '2011 Jan 01', clocktime) % 7 + 1 AS DayOfWeek,
CAST(MAX(clocktime) - MIN(clocktime) AS FLOAT) AS Duration
FROM
yourTable
GROUP BY
for_UID,
DATEDIFF(DAY, '2011 Jan 01', clocktime)
)
AS [data]

Answer 2

This is more verbose but my focus was (a) to avoid repeating expressions and (b) to simulate all of the input parameters intended to be fed to the stored procedure so that the results are filtered on the desired user / date. Note that the #whichdate parameter is reeled back to the preceding Saturday at midnight, regardless of which day of the week it is or what time is associated with it.
Input parameters:
DECLARE #whichdate DATETIME;
SET #whichdate = '2011-08-08T12:34:00';
DECLARE #whichforUID VARCHAR(32);
SET #whichforUID = 'user193';
Body (just comment out the DECLARE #t / INSERT #t lines, and change #t in the first CTE to the real table name:
SET #whichdate = DATEADD(DAY, -DATEPART(WEEKDAY, #whichdate), #whichdate);
SET #whichdate = DATEADD(DAY, 0, DATEDIFF(DAY, 0, #whichdate));
DECLARE #t TABLE(clocktime DATETIME, for_UID VARCHAR(32), in1_out0 BIT);
INSERT #t SELECT '2011-08-07 15:13:58.390','user193',1
UNION ALL SELECT '2011-08-07 21:09:45.093','user193',0
UNION ALL SELECT '2011-08-09 14:10:00.000','user193',1
UNION ALL SELECT '2011-08-09 20:10:00.000','user193',0;
WITH s(dw, ct, in1_out0) AS
(
SELECT 1 + (DATEDIFF(DAY, '2011-01-01', clocktime) % 7),
clocktime, in1_out0 FROM #t
where for_UID = #whichforUID
AND clocktime >= #whichdate
AND clocktime < DATEADD(DAY, 7, #whichdate)
),
d(dw, min_ct, max_ct) AS
(
SELECT dw,
MIN(CASE WHEN in1_out0 = 1 THEN ct ELSE NULL END),
MAX(CASE WHEN in1_out0 = 0 THEN ct ELSE NULL END)
FROM s GROUP BY dw
),
x AS
(
SELECT d = DATEADD(MILLISECOND, DATEDIFF(MILLISECOND, min_ct, max_ct), 0),
dw FROM d
),
pvt AS (
SELECT * FROM x PIVOT
(MAX(d) FOR dw IN ([1],[2],[3],[4],[5],[6],[7])) AS p
)
SELECT
day1 = COALESCE([1], '19000101'),
day2 = COALESCE([2], '19000101'),
day3 = COALESCE([3], '19000101'),
day4 = COALESCE([4], '19000101'),
day5 = COALESCE([5], '19000101'),
day6 = COALESCE([6], '19000101'),
day7 = COALESCE([7], '19000101')
FROM pvt;