Grouping columns in pivot query - sql

Question

Let's consider such query:
SELECT *
FROM (
SELECT
YEAR(OrderDate) [Year],
MONTH(OrderDate) [Month],
SubTotal
FROM Sales.SalesOrderHeader
) TableDate
PIVOT (
SUM(SubTotal)
FOR [Month] IN (
[1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12]
)
) PivotTable
It returns a table looking like this:
year 1 2 3 4 5 6 ... 12 //MONTH
2001 100 100 100 100 100 100 100
How can we group the columns and return a result in the form,for example:
year 1-3 4-5 5-10 11-12 //Group the columns!
2001 300 200 500 200
I need a T-SQL query to do this. I 've checked dynamic query execution but it also doesn't help much..

Answer 1

In the subquery, first put your months in the right buckets, then perform a pivot on that table.
SELECT *
FROM (
SELECT
YEAR(OrderDate) [Year],
CASE WHEN MONTH(OrderDate)<=3 THEN '1-3'
WHEN MONTH(OrderDate)<=5 THEN '4-5',
WHEN MONTH(OrderDate)<=10 THEN '6-10',
ELSE '11-12' END [MonthRange]
SubTotal
FROM Sales.SalesOrderHeader
) TableDate
PIVOT (
SUM(SubTotal)
FOR [MonthRange] IN (
['1-3'],['4-5'],['6-10'],['11-12']
)
) PivotTable

Answer 2

I don't use PIVOT that much (and don't have enough info here to re-create your sample), but can't you just say instead of SELECT *:
SELECT [year], [1-3] = [1] + [2] + [3], [4-5] = [4] + [5], ...
FROM ( SELECT YEAR ...) TableDate
PIVOT ( SUM(SubTotal) FOR ...) PivotTable;
EDIT
Adding a simple working example for #t-clausen.dk:
CREATE TABLE #x([year] INT, [month] INT, total INT);
INSERT #x SELECT 2011, 1, 15
UNION ALL SELECT 2011, 2, 20
UNION ALL SELECT 2011, 2, 30
UNION ALL SELECT 2011, 3, 15
UNION ALL SELECT 2011, 4, 22
UNION ALL SELECT 2011, 5, 13
UNION ALL SELECT 2011, 6, 22
UNION ALL SELECT 2011, 7, 12
UNION ALL SELECT 2011, 8, 14
UNION ALL SELECT 2011, 9, 30
UNION ALL SELECT 2011, 10, 30
UNION ALL SELECT 2011, 11, 20
UNION ALL SELECT 2011, 12, 45;
SELECT
[year],
[1-3] = [1] + [2] + [3],
[4-5] = [4] + [5],
[6-10] = [6] + [7] + [8] + [9] + [10],
[11-12] = [11] + [12]
FROM ( SELECT [year], [month], total FROM #x ) AS TableDate
PIVOT (
SUM(total)
FOR [month] IN
(
[1], [2], [3], [4],
[5], [6], [7], [8],
[9],[10],[11],[12]
)
) AS PivotTable
ORDER BY [year];
DROP TABLE #x;