SQL joining 6 tables - sql

Question

Please take a look at the image.There are 5tables related to appointTable with appointID.
Now i need all the data with same appointment id..what should be the joining query?Can any one help me about it?
Here is the generated query(I am using Left outer Join)
SELECT dbo.Appointment.appointment_id, dbo.Appointment.patient_id, dbo.PatientInvestigaiton.investigation_name, dbo.PatientInvestigaiton.investigation_id,
dbo.PatientTreatmentMedicine.medecine_id, dbo.PatientTreatmentMedicine.medicinename, dbo.PatientTreatmentMedicine.medicinetype,
dbo.PatientFindings.finding_id, dbo.PatientFindings.finding_value, dbo.PatientAdvice.advice_description, dbo.PatientCC.cc_value, dbo.PatientCC.cc_id,
dbo.PatientDiagonosis.diagonosis_name, dbo.PatientDiagonosis.diagonosis_id
FROM dbo.Appointment LEFT OUTER JOIN
dbo.PatientInvestigaiton ON dbo.Appointment.appointment_id = dbo.PatientInvestigaiton.appointment_id LEFT OUTER JOIN
dbo.PatientTreatmentMedicine ON dbo.Appointment.appointment_id = dbo.PatientTreatmentMedicine.appointment_id LEFT OUTER JOIN
dbo.PatientFindings ON dbo.Appointment.appointment_id = dbo.PatientFindings.appointment_id LEFT OUTER JOIN
dbo.PatientDiagonosis ON dbo.Appointment.appointment_id = dbo.PatientDiagonosis.appointment_id LEFT OUTER JOIN
dbo.PatientCC ON dbo.Appointment.appointment_id = dbo.PatientCC.appointment_id LEFT OUTER JOIN
dbo.PatientAdvice ON dbo.Appointment.appointment_id = dbo.PatientAdvice.appointment_id
where dbo.Appointment.appointment_id='46';

Answer 1

Since appointmnent_id is the primary key of Appointment, this table has a 1:N relationship with all 6 tables.
This is the case where joining to these 6 tables will produce multiple rows with duplicate data, it's like a Cartesian Product. For example if (for only one id=46), there are:
3 rows for PatientInvestigation
6 rows for PatientTreatmentMedicine
4 rows for PatientFindings
2 rows for PatientDiagnosis
2 rows for PatientCC
5 rows for PatientAdvice
you'll get 3x6x4x2x2x5 = 1440 rows in the result set, while you only need 3+6+4+2+2+5 (+1) = 23 rows. That is 60 times more rows (and with many more columns) than needed.
It's better if you do 6 separate queries with one JOIN to one (of the 6) tables in each query (and one more query to get the data from the base table Appointment). And combine the results of the 6 queries in the application code. Example for the base query and the query to join to the first table:
Base table:
SELECT
a.appointment_id,
a.patient_id
FROM
Appointment AS a
WHERE
a.appointment_id = 46
Join-1 to PatientInvestigation:
SELECT
pi.investigation_name,
pi.investigation_id
FROM
Appointment AS a
JOIN
PatientInvestigation AS pi
ON pi.appointment_id = a.appointment_id
WHERE
a.appointment_id = 46

Answer 2

SELECT
Appointment.appointment_id,
Appointment.patient_id,
PatientInvestigaiton.investigation_name,
PatientInvestigaiton.investigation_id,
PatientTreatmentMedicine.medecine_id,
PatientTreatmentMedicine.medicinename,
PatientTreatmentMedicine.medicinetype,
PatientFindings.finding_id,
PatientFindings.finding_value,
PatientAdvice.advice_description,
PatientCC.cc_value,
PatientCC.cc_id,
PatientDiagonosis.diagonosis_name,
PatientDiagonosis.diagonosis_id
FROM
Appointment
LEFT OUTER JOIN PatientInvestigaiton ON Appointment.appointment_id = PatientInvestigaiton.appointment_id AND Appointment.appointment_id='46'
LEFT OUTER JOIN PatientTreatmentMedicine ON Appointment.appointment_id = PatientTreatmentMedicine.appointment_id
LEFT OUTER JOIN PatientFindings ON Appointment.appointment_id = PatientFindings.appointment_id
LEFT OUTER JOIN PatientDiagonosis ON Appointment.appointment_id = PatientDiagonosis.appointment_id
LEFT OUTER JOIN PatientCC ON Appointment.appointment_id = PatientCC.appointment_id
LEFT OUTER JOIN PatientAdvice ON Appointment.appointment_id = PatientAdvice.appointment_id

Answer 3

SELECT {TABLE1}.appointment_id,{OTHER FIELDS} FROM {TABLE1}
JOIN {TABLE2} ON {TABLE1}.appointment_id = {TABLE2}.appointment_id
JOIN {TABLE3} ON {TABLE1}.appointment_id = {TABLE3}.appointment_id
JOIN {TABLE4} ON {TABLE1}.appointment_id = {TABLE4}.appointment_id
JOIN {TABLE5} ON {TABLE1}.appointment_id = {TABLE5}.appointment_id
JOIN {TABLE6} ON {TABLE1}.appointment_id = {TABLE6}.appointment_id
JOIN {TABLE7} ON {TABLE1}.appointment_id = {TABLE7}.appointment_id
JOIN {TABLE8} ON {TABLE1}.appointment_id = {TABLE8}.appointment_id;
Try this:
SELECT
dbo.Appointment.appointment_id, dbo.Appointment.patient_id,
dbo.PatientInvestigaiton.investigation_name, dbo.PatientInvestigaiton.investigation_id,
dbo.PatientTreatmentMedicine.medecine_id, dbo.PatientTreatmentMedicine.medicinename, dbo.PatientTreatmentMedicine.medicinetype,
dbo.PatientFindings.finding_id, dbo.PatientFindings.finding_value,
dbo.PatientAdvice.advice_description,
dbo.PatientCC.cc_value, dbo.PatientCC.cc_id,
dbo.PatientDiagonosis.diagonosis_name, dbo.PatientDiagonosis.diagonosis_id
FROM
dbo.Appointment
LEFT JOIN dbo.PatientInvestigaiton
ON dbo.Appointment.appointment_id = dbo.PatientInvestigaiton.appointment_id
LEFT JOIN dbo.PatientTreatmentMedicine
ON dbo.Appointment.appointment_id = dbo.PatientTreatmentMedicine.appointment_id
LEFT JOIN dbo.PatientFindings
ON dbo.Appointment.appointment_id = dbo.PatientFindings.appointment_id
LEFT JOIN dbo.PatientDiagonosis
ON dbo.Appointment.appointment_id = dbo.PatientDiagonosis.appointment_id
LEFT JOIN dbo.PatientCC
ON dbo.Appointment.appointment_id = dbo.PatientCC.appointment_id
LEFT JOIN dbo.PatientAdvice
ON dbo.Appointment.appointment_id = dbo.PatientAdvice.appointment_id
WHERE
dbo.Appointment.appointment_id='46';