How to find missing id in the table - sql

Question

I have column looks like below
SID101
SID102
SID103
SID105
SID107
In the above criteria i need to find missed SID numbers. SID104 and SID 106 are missed while ordering.
How can i find the missed id numbers.Could any one help me finding it.
Thanks in advance.

Answer 1

If your table contains gaps with length more than 1 item, you can use this query:
declare #t table(s varchar(20))
insert #t values ('SID101'),('SID102'),('SID103'),('SID105'),('SID108');
with cte as
(
select substring(t.s, 4, len(t.s)) [i]
from #t t
)
select 'SID' + cast(m.number as varchar(20))
from master..spt_values m
left join cte c on c.i = m.number
where [Type] = 'P'
and m.number >= (select min(i) from cte)
and m.number <= (select max(i) from cte)
and c.i is null
Output:
-----------------------
SID104
SID106
SID107

Answer 2

Something like this should work:
DECLARE #i INT;
SET #i = 100;
CREATE TABLE #idsToCheck (checkId varchar(100));
WHILE (#i < 200)
BEGIN
INSERT INTO #idsToCheck VALUES ('SID' + CONVERT(varchar(100), #i));
SET #i = #i + 1;
END
SELECT * FROM #idsToCheck itc
LEFT OUTER JOIN MainTable mt ON itc.checkId = mt.realId
WHERE mt.realId = NULL
DROP TABLE #idsToCheck
... where MainTable is your table containing the SID101, SID102, etc. column values, and MainTable.realId is the column containing those IDs. Modify the #i initial value and number in the while loop condition based on which SIDs you want to check from/to.

Answer 3

It's difficult. With
SELECT COUNT(*),MAX(CAST(REPLACE(y.name,'SID','') AS INT)) AS col_max FROM
sys.objects x INNER JOIN sys.columns y ON x.object_id=y.object_id
WHERE x.name='<TABLE_NAME>'
you should know, how much columns are missing (i.e. COUNT(*) is 5 and col_max is 107)
When you have a table, which contains only one column with all possible IDs from 1 to max (i.e. 100,101,102,103,104,...,132) then you could do
SELECT * FROM (
SELECT CAST(REPLACE(y.name,'SID','') AS INT) AS col_id FROM
sys.objects x INNER JOIN sys.columns y ON x.object_id=y.object_id
WHERE x.name='<TABLE_NAME>'
) a
RIGHT JOIN <TABLE_IDS> b ON a.col_id=b.id
WHERE a.col_id IS NULL AND b.id<=(
SELECT MAX(CAST(REPLACE(y.name,'SID','') AS INT)) AS col_max FROM
sys.objects x INNER JOIN sys.columns y ON x.object_id=y.object_id
WHERE x.name='<TABLE_NAME>'
)
EDIT: sorry, I've seen just now, that these values aren't column names, but values. My solution will find missing column names

Answer 4

 Declare #St int
declare #end int
set #st = CAST( (select RIGHT( max(data),4) from orderno)as int)
set #end = CAST( (select RIGHT( min(data),4) from orderno)as int)
create table #temp(data int)
while(#St <= #end )
begin
insert into #temp values(#St)
set #St = #St +1
end
select * from orderno
select * from #temp
select data from #temp where data not in (select cast(RIGHT(data,4))

Answer 5

declare #t table(s varchar(20))
insert #t values ('SID101'),('SID102'),('SID103'),('SID105'),('SID107');
with cte as
(
select substring(t.s, 4, len(t.s)) [i]
from #t t
)
select 'SID' + cast(t1.i + 1 as varchar(20))
from cte t1
join cte t2 on t2.i > t1.i
and not exists(
select 1
from cte c3
where c3.i > t1.i and c3.i < t2.i
)
where t2.i <> t1.i + 1
Output:
-----------------------
SID104
SID106