SQL Server 2008 R2
I have 3 tables contained data for 3 different types of events
Type1, Type2, Type3 with two columns:
DatePoint ValuePoint
I want to produce result table which would look like that:
DatePoint TotalType1 TotalType2 TotalType3
I've started from that
SELECT [DatePoint]
,SUM(ValuePoint) as TotalType1
FROM [dbo].[Type1]
GROUP BY [DatePoint]
ORDER BY [DatePoint]
SELECT [DatePoint]
,SUM(ValuePoint) as TotalType2
FROM [dbo].[Type2]
GROUP BY [DatePoint]
ORDER BY [DatePoint]
SELECT [DatePoint]
,SUM(ValuePoint) as TotalType3
FROM [dbo].[Type3]
GROUP BY [DatePoint]
ORDER BY [DatePoint]
So I have three result but I need to produce one (Date TotalType1 TotalType2 TotalType3), what I need to do next achieve my goal?
UPDATE
Forgot to mention that DatePoint which is exists in one type may or may not exist in another
Here's my take. I assume that you don't have the same datetime values in every table (certainly, the stuff I get to work with is never so consistant). There should be an easier way to do this, but once you're past two outer joins things can get pretty tricky.
SELECT
dp.DatePoint
,isnull(t1.TotalType1, 0) TotalType1
,isnull(t2.TotalType2, 0) TotalType2
,isnull(t3.TotalType3, 0) TotalType3
from (-- Without "ALL", UNION will filter out duplicates
select DatePoint
from Type1
union select DatePoint
from Type2
union select DatePoint
from Type3) dp
left outer join (select DatePoint, sum(ValuePoint) TotalType1
from Type1
group by DatePoint) t1
on t1.DatePoint = db.DatePoint
left outer join (select DatePoint, sum(ValuePoint) TotalType2
from Type2
group by DatePoint) t2
on t2.DatePoint = db.DatePoint
left outer join (select DatePoint, sum(ValuePoint) TotalType3
from Type3
group by DatePoint) t3
on t3.DatePoint = db.DatePoint
order by dp.DatePoint
Suppose some distinct could help, but the general idea should be the following:
SELECT
t.[DatePoint],
SUM(t1.ValuePoint) as TotalType1,
SUM(t2.ValuePoint) as TotalType2,
SUM(t3.ValuePoint) as TotalType3
FROM
(
SELECT [DatePoint] FROM [dbo].[Type1]
UNION
SELECT [DatePoint] FROM [dbo].[Type2]
UNION
SELECT [DatePoint] FROM [dbo].[Type3]
) as t
LEFT JOIN
[dbo].[Type1] t1
ON
t1.[DatePoint] = t.[DatePoint]
LEFT JOIN
[dbo].[Type2] t2
ON
t2.[DatePoint] = t.[DatePoint]
LEFT JOIN
[dbo].[Type3] t3
ON
t3.[DatePoint] = t.[DatePoint]
GROUP BY
t.[DatePoint]
ORDER BY
t.[DatePoint]
To avoid all of the JOINs:
SELECT
SQ.DatePoint,
SUM(CASE WHEN SQ.type = 1 THEN SQ.ValuePoint ELSE 0 END) AS TotalType1,
SUM(CASE WHEN SQ.type = 2 THEN SQ.ValuePoint ELSE 0 END) AS TotalType2,
SUM(CASE WHEN SQ.type = 3 THEN SQ.ValuePoint ELSE 0 END) AS TotalType3
FROM (
SELECT
1 AS type,
DatePoint,
ValuePoint
FROM
dbo.Type1
UNION ALL
SELECT
2 AS type,
DatePoint,
ValuePoint
FROM
dbo.Type2
UNION ALL
SELECT
3 AS type,
DatePoint,
ValuePoint
FROM
dbo.Type3
) AS SQ
GROUP BY
DatePoint
ORDER BY
DatePoint
From the little information provided though, it seems like there are some flaws in the database design, which is probably part of the reason that querying the data is so difficult.
Related
select home2012.region_name, avg(home2012.per_price), avg(home2019.per_price)
from home2012 left join
(select region_name, avg(per_price) from home2019 group by region_name)
on home2012.region_name = home2019.region_name
group by region_name;
I want to group by region_name each table(home2012, home2019) and left join them by same region_name(after group by).
But it occurs error.
Make two subselects and join them
SELECT
t2012.region_name, t2012.avgprice2012, t2019.avgprice2019
FROM
(SELECT
home2012.region_name, AVG(home2012.per_price) avgprice2012
FROM
home2012
GROUP BY region_name) AS t2012
LEFT JOIN
(SELECT
region_name, AVG(per_price) avgprice2019
FROM
home2019
GROUP BY region_name) AS t2019 ON t2012.region_name = t2019.region_name
;
select
home2012.region_name,
avg(home2012.per_price),
avg(home2019.per_price)
from
home2012
left join (select region_name, avg(per_price) from home2019 group by
region_name) on home2012.region_name = home2019.region_name
group by region_name;
what is the use of joining as mentioned above? does it make any difference rather than increasing one step workload on server.
select
home2012.region_name,
avg(home2012.per_price),
avg(home2019.per_price)
from
home2012
left join home2019 on home2012.region_name = home2019.region_name
group by region_name;
SELECT
name,
AVG("2012") as "2012",
AVG("2018") as "2018"
FROM
(
SELECT
'region' AS name,
1 AS "2012",
NULL AS "2018" // put column as null
FROM
dual
UNION
SELECT
'region' AS name,
NULL AS "2012", // put column as null
avg(3) AS "2018"
FROM
dual
group by 1
)
GROUP BY
name
am not sure about your requirement, try something like this.
The query I'm executing seems to be ignoring the where clause in the subquery
(select count(amazon) from orders where b.amazon = 2 and manifest = a.dbid)
column amazon is type INT
SQL SERVER 2014
If I run the query on its own and enter the value for manifest I get the correct result which I am expecting and is 1
select count(amazon) from orders where amazon = 2 and manifest = '211104'
Result Returns 1
When I run the query below I get a result of 5 which is the count of all orders where manifest = 211104 but the value of amazon is 1 in 4 results and 2 in 1 result.
Select distinct
top 30 DBID, today ,sum([amazon-orders])
From
(
SELECT [dbid], [today],
(select count(amazon) from orders
where b.amazon = 2 and manifest = a.dbid) as [amazon-orders]
FROM [manifest] a
join orders b on a.[dbid] = b.[manifest]
) t1
Group By
DBID, today
order by dbid desc
Can someone please help me.
Thanks
You have an extra join so you are counting multiple times... do this:
Select distinct
top 30 DBID, today ,sum([amazon-orders])
From
(
SELECT [dbid], [today],
(select count(amazon) from orders b
where b.amazon = 2 and manifest = a.dbid) as [amazon-orders]
FROM [manifest] a
) t1
Group By
DBID, today
order by dbid desc
or like this
SELECT [dbid], [today], count(o.amazon)
FROM [manifest] a
join orders o on a.dbid = o.manifest and o.amazon = 2
group by dbid, today
or this if you have columns you don't want to join (there is more going on than just this one join in your query and you need to use a left join):
SELECT [dbid], [today], sum(case when o.amazon is not null then 1 else 0 end)
FROM [manifest] a
left join orders o on a.dbid = o.manifest and o.amazon = 2
group by dbid, today
How's this?
SELECT top 30 [dbid], [today], sum(case when b.amazon = 2 then 1 else 0 end) as [amazon-orders]
FROM [manifest] a
join orders b on a.[dbid] = b.[manifest]
group by DBID, today
order by dbid desc
Pretty sure that because your query is in effect joining orders twice it's increasing the count.
Use this :
select a.DBID, a.today, count(b.amazon) from [manifest] a
join orders b on a.[dbid] = b.[manifest] and b.amazon = 2
Group By a.DBID, a.today
I am joining two tables on HANA and, to get some statistics, I am LEFT joining the items table 3 times to get a total count, number of entries processed and number of errors, as shown below.
This is a dev system and the items table has only 1500 items. But the query below runs for 17 seconds.
When I remove any of the three aggregation terms (but leave the corresponding JOIN in place), the query executes almost immediately.
I have also tried adding indexes on the fields used in the specific JOINs, but that makes no difference.
select rk.guid, rk.run_id, rk.status, rk.created_at, rk.created_by,
count( distinct rp.guid ),
count( distinct rp2.guid ),
count( distinct rp3.guid )
from zbsbpi_rk as rk
left join zbsbpi_rp as rp
on rp.header = rk.guid
left join zbsbpi_rp as rp2
on rp2.header = rk.guid
and rp2.processed = 'X'
left join zbsbpi_rp as rp3
on rp3.header = rk.guid
and rp3.result_status = 'E'
where rk.run_id = '0000000010'
group by rk.guid, run_id, status, created_at, created_by
I think you can re-write you query to improve the performance:
select rk.guid, rk.run_id, rk.status, rk.created_at, rk.created_by,
count( distinct rp.guid ),
count( distinct (CASE WHEN rp.processed = 'X' then rp.guid else null end) ),
count( distinct (CASE WHEN rp.result_status = 'E' then rp.guid else null end))
from zbsbpi_rk as rk
left join zbsbpi_rp as rp
on rp.header = rk.guid
where rk.run_id = '0000000010'
group by rk.guid, run_id, status, created_at, created_by
I'm not entirely sure if the count distinct case construct will work on hana but you may try.
My apologies, but I forgot that I had posted this question here. I had posted the same question at answers.sap.com after not getting any joy here: https://answers.sap.com/questions/172096/multiple-left-joins-with-aggregation-on-same-table.html
I eventually came up with the solution, which was a bit of a "doh!" moment:
select rk.guid, rk.run_id, rk.status, rk.created_at, rk.created_by,
count( distinct rp.guid ),
count( distinct rp2.guid ),
count( distinct rp3.guid )
from zbsbpi_rk as rk
join zbsbpi_rp as rp
on rp.header = rk.guid
left join zbsbpi_rp as rp2
on rp2.guid = rp.guid
and rp2.processed = 'X'
left join zbsbpi_rp as rp3
on rp3.guid = rp.guid
and rp3.result_status = 'E'
where rk.run_id = '0000000010'
group by rk.guid, run_id, status, created_at, created_by
The subsequent left joins needed only to be joined to the first join on the same table, as the first join contained a superset of all the records anyway.
I have this two query
1.
select CL_Clients.cl_id,CL_Clients].cl_name,COUNT(*) AS number_of_orders
from CL_Clients,CLOI_ClientOrderItems
where CL_Clients.cl_id=CLOI_ClientOrderItems.cl_id
group by CL_Clients.cl_name,CL_Clients.cl_id
2.
select CL_Clients.cl_id,count(cloi_current_status) as dis
from CLOI_ClientOrderItems,CL_Clients
where cloi_current_status]='12'
and CL_Clients.cl_id=CLOI_ClientOrderItems.cl_id
group by CL_Clients.cl_name,CL_Clients.cl_id,CLOI_ClientOrderItems.cloi_current_status
i have this column i need to put count function and where condition
[cloi_current_status]
166
30
30
30
150
150
150
150
150
150
150
Quite simple, you just encapsulate the queries and give their result sets an alias and then do a JOIN between their aliases on the column that is common. (In the query below I assume you'll be joining by client id)
SELECT *
FROM (
SELECT CL_Clients.cl_id,
CL_Clients].cl_name,
COUNT(*) AS number_of_orders
FROM CL_Clients,
CLOI_ClientOrderItems
WHERE CL_Clients.cl_id = CLOI_ClientOrderItems.cl_id
GROUP BY CL_Clients.cl_name,
CL_Clients.cl_id
) A
INNER JOIN (
SELECT CL_Clients.cl_id,
count(cloi_current_status) AS dis
FROM CLOI_ClientOrderItems,
CL_Clients
WHERE cloi_current_status] = '12'
AND CL_Clients.cl_id = CLOI_ClientOrderItems.cl_id
GROUP BY CL_Clients.cl_name,
CL_Clients.cl_id,
CLOI_ClientOrderItems.cloi_current_status
) B
ON A.cl_id = B.cl_id
WHERE ...
GROUP BY ...
This will be treated as a separate result set, so you can also filter results with a WHERE or just a GROUP BY, just like in a normal SELECT.
UPDATE:
To answer the question in your comments, when you join two tables that have a column with the same value and use
SELECT * FROM A INNER JOIN B the * will show all columns returned by the join, meaning all columns from A and all columns from B, this is why you have duplicate columns.
If you want to filter the columns returned you can specifiy which columns you want returned. So, in your case, the top SELECT * can be replaced with
SELECT A.cl_id, A.cl_name, A.number_of_orders, B.dis so, your query becomes:
SELECT A.cl_id, A.cl_name, A.number_of_orders, B.dis
FROM (
SELECT CL_Clients.cl_id,
CL_Clients].cl_name,
COUNT(*) AS number_of_orders
FROM CL_Clients,
CLOI_ClientOrderItems
WHERE CL_Clients.cl_id = CLOI_ClientOrderItems.cl_id
GROUP BY CL_Clients.cl_name,
CL_Clients.cl_id
) A
INNER JOIN (
SELECT CL_Clients.cl_id,
count(cloi_current_status) AS dis
FROM CLOI_ClientOrderItems,
CL_Clients
WHERE cloi_current_status] = '12'
AND CL_Clients.cl_id = CLOI_ClientOrderItems.cl_id
GROUP BY CL_Clients.cl_name,
CL_Clients.cl_id,
CLOI_ClientOrderItems.cloi_current_status
) B
ON A.cl_id = B.cl_id
UPDATE #2:
For your last question, you need to GROUP BY at the end of the big query and use a HAVING condtion, like this:
GROUP BY A.cl_id, A.cl_name, A.number_of_orders, B.dis
HAVING COUNT(cloi_current_status) > 100
All depends on what data you are trying to get, but you can go about it like this.
SELECT Column_x, Column_y, etc..
FROM ClL_Clients a
JOIN (select CL_Clients.cl_id,CL_Clients].cl_name,COUNT(*) AS number_of_orders
from CL_Clients,CLOI_ClientOrderItems
where CL_Clients.cl_id=CLOI_ClientOrderItems.cl_id
group by CL_Clients.cl_name,CL_Clients.cl_id) b
on a.cl_id = b.cl_id
JOIN (select CL_Clients.cl_id,count(cloi_current_status) as dis
from CLOI_ClientOrderItems,CL_Clients
where cloi_current_status]='12'
and CL_Clients.cl_id=CLOI_ClientOrderItems.cl_id
group by CL_Clients.cl_name,CL_Clients.cl_id,CLOI_ClientOrderItems.cloi_current_status) c
on a.cl_id = c.cl_id
Group by BLAH BLAH
Hope this gets you in the right direction.
I'm using the following SQL (with a union to two similar queries):
SELECT
distinct a.source,
a.p_id,
a.name,
b.prod_count,
b.prod_amt,
'Def' as prod_type
FROM
dwh.attribution_product_count a
LEFT OUTER JOIN
(
SELECT
distinct source,
p_id,
name,
sum(acct_count) as prod_count,
sum(acct_amt) as prod_amt
FROM
dwh.prod_count
WHERE
month = 3 AND
default_banner_flag = 0 AND
loan_flag = 3
GROUP BY
source,
name,
p_id ) as b
ON
a.p_id = b.p_id
UNION
SELECT
distinct a.source,
a.p_id,
a.name,
b.prod_count,
b.prod_amt,
'Other' as prod_type
FROM
dwh.attribution_product_count a
LEFT OUTER JOIN
(
SELECT
distinct source,
p_id,
name,
sum(acct_count) as prod_count,
sum(acct_amt) as prod_amt
FROM
dwh.prod_count
WHERE
month = 3 AND
default_banner_flag = 1 AND
loan_flag = 3
GROUP BY
source,
name,
p_id
ORDER BY
name ) as b
ON
a.p_id = b.p_id
The output I'm getting looks like this:
Essentially since FakeName #2 has one row showing actual numbers (not null), I ONLY want FakeName #2 to show up. This means I also want the null row for FakeName #2. But, since FakeName #1 and #3 have 2 null rows, I don't need them to show. What type of SQL command (or edit to my query) can accomplish this?
Firstly, if I read your query correctly, you can eliminate the need for a UNION by using CASE and IN. You also have a couple of bogus DISTINCTs in there (since you're using GROUP BY anyway). That gives:
SELECT DISTINCT
a.source,
a.p_id,
a.name,
b.prod_count,
b.prod_amt,
Case When default_banner_flag = 0 Then 'Def' Else 'Other' End as prod_type
FROM
dwh.attribution_product_count a
LEFT OUTER JOIN
(
SELECT
source,
p_id,
name,
default_banner_flag,
sum(acct_count) as prod_count,
sum(acct_amt) as prod_amt
FROM
dwh.prod_count
WHERE
month = 3 AND
default_banner_flag in (0, 1) AND
loan_flag = 3
GROUP BY
source,
name,
p_id,
default_banner_flag
) as b
ON
a.p_id = b.p_id
However, what you actually want is information about those p_ids which have at least one row in dwh.prod_count, so I think you can change your whole query around to use that as the sub-select:
SELECT
a.source,
a.p_id,
a.name,
sum(acct_count) as prod_count,
sum(acct_amt) as prod_amt,
Case When default_banner_flag = 0 Then 'Def' Else 'Other' End as prod_type
FROM
dwh.attribution_product_count a
LEFT OUTER JOIN
dwh.prod_count b
On a.p_id = b.p_id
INNER JOIN
(
SELECT DISTINCT
p_id
FROM
dwh.prod_count
WHERE
month = 3 AND
default_banner_flag in (0, 1) AND
loan_flag = 3
) as c
ON a.p_id = c.p_id
WHERE
month = 3 AND
default_banner_flag in (0, 1) AND
loan_flag = 3
(You could also rewrite this as a WHERE p_id IN ( sub-select ) or with a little fiddling WHERE EXISTS ( ... ), but this seemed the easiest version to demonstrate.)
Note that I haven't actually tested any of these queries, but I think they're logically sound.