Daily builds with MsBuild - msbuild

What i want to do is to copy all files and subfolders from the OutputPath to the daily folder. For example i have project called Clock, i have msbuild script for it:
<?xml version="1.0" encoding="utf-8" ?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<ProjectPath>C:\Clock</ProjectSolutionName>
<ProjectSolutionName>Clock</ProjectSolutionName>
</PropertyGroup>
<Target Name="ReleaseBuild">
<Message Text="Building $(ProjectSolutionName) Release Build" />
<MSBuild Projects="$(ProjectPath)\$(ProjectSolutionName).sln" Targets="Clean" Properties="Configuration=Release" />
<MSBuild Projects="$(ProjectPath)\$(ProjectSolutionName).sln" Targets="Build" Properties="Configuration=Release" />
<Message Text="$(ProjectSolutionName) Release Build Complete!" />
</Target>
</Project>
Now when i run the script it compiles the solution and the files will be stored to a Release folder. How could i copy all the files and subfolders from the Release folder to folder named as the date, as for today for example: C:\Clock_Builds\20110803

This should do most of what you ask (its msbuild 4):
<Project DefaultTargets="DateCopy" xmlns="http://schemas.microsoft.com/developer/msbuild/2003" ToolsVersion="4.0">
<Target Name="DateCopy">
<ItemGroup>
<Release Include="d:\Build\**\**"/>
</ItemGroup>
<PropertyGroup>
<StringDate>$([System.DateTime]::Now.ToString('yyyyMMdd'))</StringDate>
</PropertyGroup>
<MakeDir Directories="D:\Release\$(StringDate)"/>
<Message Text="$(StringDate)" Importance="High"/>
<Copy SourceFiles="#(Release)"
DestinationFolder="D:\Release\$(StringDate)\%(RecursiveDir)"/>
</Target>
</Project>
Hope that helps

Related

Execute a XCopy operation after all the projects build in MSBuild

I have a .proj file which is configured to execute a solution file which in turn build all the projects in the solution.
I want to add an XCopy operation which should copy the .dll files of all projects to another location only after all the projects build is completed.
I have tried with below, but it is not copying the dlls.
I am newbie in writing MSBuild tags, so it could be that I may be wrong in choosing this approach to write the task in this way.
Please provide a solution, if anyone knows.
<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="Current" DefaultTargets="Build" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<Configuration Condition="'$(Configuration)' == 'Release|Debug'"/>
<Platform Condition="'$(Platform)' == ''">x64</Platform>
</PropertyGroup>
<ItemDefinitionGroup>
<SolutionToBuild>
<Properties>Configuration=$(Configuration);Platform=$(Platform)</Properties>
<Targets>Clean;Build</Targets>
</SolutionToBuild>
</ItemDefinitionGroup>
<ItemGroup>
<SolutionToBuild Include="..\Seg\Algorithms.sln" />
</ItemGroup>
<Target Name="Build" >
<MSBuild Projects="#(SolutionToBuild)" Targets="%(SolutionToBuild.Targets)" Properties="%(SolutionToBuild.Properties)" BuildInParallel="false" ContinueOnError="false" />
</Target>
<Target Name="Clean">
<MSBuild Projects="#(SolutionToBuild)" Targets="Clean" Properties="%(SolutionToBuild.Properties)" BuildInParallel="false" ContinueOnError="false" />
</Target>
<PropertyGroup>
<CopyDestination>..\Extern\Algo\bin\$(Configuration)\</CopyDestination>
<CopySource>..\Seg\Algorithms\$(Configuration)\DoBin\</CopySource>
</PropertyGroup>
<ItemGroup>
<FilesToCopy Include="$(CopySource)*.dll"/>
</ItemGroup>
<ItemGroup>
<CustomBuildStep Include ="#(FilesToCopy)">
<Message>Copying..</Message>
<Command> XCOPY %(Identity) $(CopyDestination) /f /y </Command>
</CustomBuildStep>
</ItemGroup>
<PropertyGroup>
<CustomBuildAfterTargets>Build</CustomBuildAfterTargets>
</PropertyGroup>
</Project>
Think of Targets as methods that are called. They run in sequence, so you just need to put your copy after the solution build:
<Target Name="Build">
<MSBuild Projects="#(SolutionToBuild)" Targets="%(SolutionToBuild.Targets)" Properties="%(SolutionToBuild.Properties)" BuildInParallel="false" ContinueOnError="false" />
<ItemGroup>
<FilesToCopy Include="..\Seg\Algorithms\$(Configuration)\DoBin\*.dll" />
</ItemGroup>
<Copy SourceFiles="#(FilesToCopy)" DestinationFolder="..\Extern\Algo\bin\$(Configuration)\" SkipUnchangedFiles="true" />
</Target>

How to extract directory from property?

I have a property GroupProj storing a full path name. How can I extract the directory of the property?
I have the following code, but it doesn't work as expected:
<PropertyGroup>
<GroupProj>C:\development\project\default.groupproj</GroupProj>
</PropertyGroup>
<Target Name="Default">
<Message Text="Echo: $(GroupProj->'%(RootDir)')" />
</Target>
I will describe my actual intention of doing so. Perhaps there is a way to do the job that I am not aware of.
I have a Delphi groupproj (MSBuild project) file, C:\development\project\default.groupproj:
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<ItemGroup>
<Projects Include="project1.dproj">
<Dependencies/>
</Projects>
<Projects Include="project2.dproj">
<Dependencies/>
</Projects>
<Projects Include="project3.dproj">
<Dependencies/>
</Projects>
</ItemGroup>
...
</Project>
There are other 3 MSBuild files (project1.dproj, project2.dproj and project3.dproj) stored in same folder as default.groupproj.
I create a MSBuild project file (c:\test.targets):
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="Build" ToolsVersion="3.5">
<Import Project="$(GroupProj)" />
<Target Name="Build">
<MSBuild BuildInParallel="True" Projects="project1.dproj;project2.dproj;project3.dproj"/>
</Target>
</Project>
And execute as:
c:\> msbuild /p:GroupProj="C:\development\project\default.groupproj" test.targets
The execution shall fail as MSBuild can't find projectN.dproj file. The issue shall be the working directory isn't set to default.groupproj.
One straight solution come into my mind is to extract directory of $(GroupProj) and concat to there projectN.dproj file.
That's the whole story of my question.
Try something like this:
<?xml version="1.0" encoding="utf-8"?>
<Project DefaultTargets="Build" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<GroupProj>C:\development\project\default.groupproj</GroupProj>
</PropertyGroup>
<Target Name="Build">
<CreateItem Include="$(GroupProj)">
<Output TaskParameter="Include" ItemName="ItemFromProp"/>
</CreateItem>
<Message Text="1. #(ItemFromProp -> '%(RootDir)%(Directory)')"/>
<Message Text="2. %(ItemFromProp.RootDir)%(ItemFromProp.Directory)"/>
<Message Text="3. %(ItemFromProp.Identity)"/>
<Message Text="4. %(ItemFromProp.FullPath)"/>
<Message Text="5. %(ItemFromProp.FileName)"/>
<Message Text="6. %(ItemFromProp.Extension)"/>
</Target>
</Project>
EDIT:
To build the projects in parallel try this:
<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="4.0" DefaultTargets="Build" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<Target Name="GetGroupProjPath">
<ItemGroup>
<GroupProj Include="$(GroupProj)" />
<GroupProjPath Include="#(GroupProj->'%(Directory)')" />
</ItemGroup>
<PropertyGroup>
<GroupProjPath>#(GroupProjPath->'%(RootDir)%(Identity)')</GroupProjPath>
</PropertyGroup>
</Target>
<Import Project="$(GroupProj)" />
<Target Name="GetDProjs" DependsOnTargets="GetGroupProjPath">
<ItemGroup>
<DProjs Include="#(Projects->'$(GroupProjPath)%(FileName)%(Extension)')" />
</ItemGroup>
</Target>
<Target Name="Build" DependsOnTargets="GetDProjs">
<Message Text="#(DProjs)" />
</Target>
</Project>

How wait copy process on msbuild

I create example to copy file from one folder to another (use msbuild). I try check after copy, if file was moved? But message still show, that files didn't moved. But when I see on folder, files was moved successful. So how it's fix?
<?xml version="1.0" encoding="utf-8"?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<PathPackage>C:\Users\test\Desktop\test\1\*.txt</PathPackage>
<Files>C:\Users\test\Desktop\test\2\*.*</Files>
</PropertyGroup>
<ItemGroup>
<Packages Include="$(PathPackage)"/>
<FilesOnFolder Include="$(Files)"/>
</ItemGroup>
<Target Name="B">
<Message Importance="normal" Text="Package before copy:#(Packages)"/>
<CreateItem Include="#(Packages)">
<Output TaskParameter="Include" ItemName="FilesToMove" />
</CreateItem>
<Copy
SourceFiles="#(Packages)"
DestinationFolder="C:\Users\test\Desktop\test\2"
/>
<Delete Files="#(Packages)" />
<Message Importance="normal" Text="Package after package:#(Packages)"/><!--It's full! -->
<Message Importance="normal" Text="Destination Folder:#(FilesOnFolder)"/> <!--It's empty! -->
</Target>
</Project>
Problem was in ItemGroup. It need write inside target.

MSBuild and creating ZIP files

Here is my build script:
<?xml version="1.0" encoding="utf-8" ?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<Import Project="$(MSBuildExtensionsPath)\MSBuildCommunityTasks\MSBuild.Community.Tasks.Targets"/>
<PropertyGroup>
<!-- Path where the solution file is located (.sln) -->
<ProjectPath>W:\Demo</ProjectPath>
<!-- Location of compiled files -->
<DebugPath>W:\Demo\bin\Debug</DebugPath>
<ReleasePath>W:\Demo\bin\Release</ReleasePath>
<!-- Name of the solution to be compiled without the .sln extension --> <ProjectSolutionName>DemoTool</ProjectSolutionName>
<!-- Path where the nightly zip file will be copyd -->
<NightlyBuildPath>W:\Nightly_Builds\Demo</NightlyBuildPath>
<!-- Name of the nighly zip file (YYYYMMDD_NightlyZipName.zip, date added automatically) -->
<NightlyZipName>Demo</NightlyZipName>
</PropertyGroup>
<ItemGroup>
<!-- All files and folders from ./bin/Debug or ./bin/Release what will be added to the nightly zip -->
<DebugApplicationFiles Include="$(DebugPath)\**\*.*" Exclude="$(DebugPath)\*vshost.exe*" />
<ReleaseApplicationFiles Include="$(ReleasePath)\**\*.*" Exclude="$(ReleasePath)\*vshost.exe*" />
</ItemGroup>
<Target Name="DebugBuild">
<Message Text="Building $(ProjectSolutionName) Debug Build" />
<MSBuild Projects="$(ProjectPath)\$(ProjectSolutionName).sln" Targets="Clean" Properties="Configuration=Debug"/>
<MSBuild Projects="$(ProjectPath)\$(ProjectSolutionName).sln" Targets="Build" Properties="Configuration=Debug"/>
<Message Text="$(ProjectSolutionName) Debug Build Complete!" />
<CallTarget Targets="CreateNightlyZip" />
</Target>
<Target Name="CreateNightlyZip">
<PropertyGroup>
<StringDate>$([System.DateTime]::Now.ToString('yyyyMMdd'))</StringDate>
</PropertyGroup>
<MakeDir Directories="$(NightlyBuildPath)"/>
<Zip Files="#(DebugApplicationFiles)"
WorkingDirectory="$(DebugPath)"
ZipFileName="$(NightlyBuildPath)\$(StringDate)_$(NightlyZipName).zip"
ZipLevel="9" />
</Target>
</Project>
My script works perfectly, only there is one strange problem. When i build a project first time and there is no \bin\Debug folder and its created during the build, but the ZIP file still comes empty. Running the build script second time when the \bin\Debug folder is now in place with builded files then the file are added to the ZIP.
What could be the problem that running script first time the ZIP file is empty?
The problem is in the DebugApplicationFiles item collection. It is created before the build is invoked. Move the DebugApplicationFiles into CreateNightlyZip target. Update your script this way:
<Target Name="CreateNightlyZip">
<PropertyGroup>
<StringDate>$([System.DateTime]::Now.ToString('yyyyMMdd'))</StringDate>
</PropertyGroup>
<ItemGroup>
<DebugApplicationFiles Include="$(DebugPath)\**\*.*" Exclude="$(DebugPath)\*vshost.exe*" />
</ItemGroup>
<MakeDir Directories="$(NightlyBuildPath)"/>
<Zip Files="#(DebugApplicationFiles)"
WorkingDirectory="$(DebugPath)"
ZipFileName="$(NightlyBuildPath)\$(StringDate)_$(NightlyZipName).zip"
ZipLevel="9" />
</Target>
If powershell 5.0 or greater is available, you could use powershell command directly.
<Target Name="Zip" BeforeTargets="AfterBuild">
<ItemGroup>
<ZipFiles Include="$(OutDir)release\file1.exe" />
<ZipFiles Include="$(OutDir)release\file2.exe" />
</ItemGroup>
<Exec Command="PowerShell -command Compress-Archive #(ZipFiles, ',') $(OutDir)release\zippedfiles.zip" />
</Target>
Should you wish to zip a whole folder for 'xcopy deploy', since MSBuild 15.8 there is a simple way - the ZipDirectory build task.
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<Target Name="ZipOutputPath" AfterTargets="Build">
<ZipDirectory
SourceDirectory="$(OutputPath)"
DestinationFile="$(OutputPath)\..\$(AssemblyName).zip"
Overwrite=="true" />
</Target>
</Project>
[1] https://learn.microsoft.com/en-us/visualstudio/msbuild/zipdirectory-task?view=vs-2019

Using MSBuild to buld a solution (.sln) with many projects in how can I make each project build into its own folder?

I am trying to create a simple build process for a quite complex (many projects) vs2010 solution.
I wish for a folder structure such as this
-Build
-Proj1
-proj1.exe
-proj1.dll
-Proj2
-proj2.exe
-proj2.dll
......
-Projn
-projn.exe
-projn.dll
What I am getting from my attempts below is
-Build
-proj1.exe
-proj1.dll
-proj2.exe
-proj2.dll
-projn.exe
-projn.dll
I currently have this as a .proj file. (see below)
This builds things fine, however it puts everything in the "build" folder that I specify. I want each project to be in its own seperate folder within that 'build' folder. How can I achive this?
<?xml version="1.0" encoding="utf-8"?>
<Project DefaultTargets="Build" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<BuildOutputDir>C:\Projects\BuildScripts\Build</BuildOutputDir>
<SolutionToCompile>PathToSolution.sln</SolutionToCompile>
</PropertyGroup>
<Target Name="Clean">
<RemoveDir Directories="$(BuildOutputDir)" />
</Target>
<Target Name="Compile">
<MakeDir Directories="$(BuildOutputDir)" />
<MSBuild Projects="$(SolutionToCompile)"
properties = "OutputPath=$(BuildOutputDir)" Targets="Rebuild" />
</Target>
<Target Name="Build" DependsOnTargets="Clean;Compile">
<Message Text="Clean, Compile"/>
</Target>
</Project>
I call the .proj with a simple bat
"%windir%\Microsoft.NET\Framework\v4.0.30319\MSBuild.exe" /nologo externalBuild.proj /m:2 %*
pause
I have also tried a more complex version (copy and paste!) that looks more like it should work, but still puts things in a single folder.
<?xml version="1.0" encoding="utf-8"?>
<Project DefaultTargets="BuildAll" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<ItemGroup>
<ProjectsToBuild Include="path to solution folder\**\*proj" Exclude="$(MSBuildProjectFile)"/>
</ItemGroup>
<PropertyGroup>
<Configuration>CI</Configuration>
</PropertyGroup>
<Target Name="CoreBuild">
<MSBuild Projects ="#(ProjectsToBuild)"
ContinueOnError ="false"
Properties="Configuration=$(Configuration)">
<Output ItemName="OutputFiles" TaskParameter="TargetOutputs"/>
</MSBuild>
</Target>
<PropertyGroup>
<DestFolder>Build\</DestFolder>
</PropertyGroup>
<Target Name="CopyFiles">
<Copy SourceFiles="#(OutputFiles)"
DestinationFiles="#(OutputFiles->'$(DestFolder)%(RecursiveDir)%(Filename)%(Extension)')" />
</Target>
<Target Name="CleanAll">
<!-- Delete any files this process may have created from a previous execution -->
<CreateItem Include="$(DestFolder)\**\*exe;$(DestFolder)\**\*dll">
<Output ItemName="GeneratedFiles" TaskParameter="Include"/>
</CreateItem>
<Delete Files="#(GeneratedFiles)"/>
<MSBuild Projects="#(ProjectsToBuild)" Targets="Clean" Properties="Configuration=$(Configuration);"/>
</Target>
<PropertyGroup>
<BuildAllDependsOn>CleanAll;CoreBuild;CopyFiles</BuildAllDependsOn>
</PropertyGroup>
<Target Name="BuildAll" DependsOnTargets="$(BuildAllDependsOn)"/>
</Project>
Using devenv.com to build from the command line will do what you want. It will use the output directories specified in the project files. This is what we're using, because at the moment we don't need more control over the build mechanism.