I have a physical map (real world), for example, a little town map.
A "path" line is painted over the map, think about it like "you are here. here's how to reach the train station" :)
Now, let's suppose I can get an image of that scenario (likewise, coming from a photo).
An image that looks like:
My goal is not easy way out!
I want to GET the path OUT of the image, i.e., separate the two layers.
Is there a way to extract those red marks from the image?
Maybe using CoreGraphics? Maybe an external library?
It's not an objective C specific question, but I am working on Apple iOS.
I already worked with something similar, the face-recognition.
Now the answer I expect is: "What do you mean by PATH?"
Well, I really don't know, maybe a line (see above image) of a completely different color from the 'major' colors in the background.
Let's talk about it.
If you can use OpenCV then it becomes simpler. Here's a general method:
Separate the image into Hue, Saturation and Variation (HSV colorspace)
Here's the OpenCV code:
// Compute HSV image and separate into colors
IplImage* hsv = cvCreateImage( cvGetSize(img), IPL_DEPTH_8U, 3 );
cvCvtColor( img, hsv, CV_BGR2HSV );
IplImage* h_plane = cvCreateImage( cvGetSize( img ), 8, 1 );
IplImage* s_plane = cvCreateImage( cvGetSize( img ), 8, 1 );
IplImage* v_plane = cvCreateImage( cvGetSize( img ), 8, 1 );
cvCvtPixToPlane( hsv, h_plane, s_plane, v_plane, 0 );
Deal with the Hue (h_plane) image only as it gives just the hue without any change in value for a lighter or darker shade of the same color
Check which pixels have Red hue (i think red is 0 degree for HSV, but please check the OpenCV values)
Copy these pixels into a separate image
I's strongly suggest using the OpenCV library if possible, which is basically made for such tasks.
You could filter the color, define a threshold for what the color red is, then filter everything else to alpha, and you have left over what your "path" is?
Related
Very basic question. I have a single vector (e.g., [53, 21, 110]) and I want to print the RGB color it represents in a colab notebook. Like a color swatch. What's the simplest way to do this?
The simplest way would be using the Image module from PIL. According to the documentation, you can construct an image with:
PIL.Image.new(mode, size, color=0)
mode [required]: determines the mode used for the image, it can be RGB, RGBA, HSV, etc. You can find more modes in the docs
size [required]: this is a tuple (weight, height) that represents the dimensions of your image in pixels.
color [optional]: this is the color of the image, it can receive a tuple to represent the RGB color in your case. The default color is black.
Then, to show the image within colab, you would use
display(img)
Given your question, the mode would need to be 'RGB' and if your vector is a list, you need to convert into a tuple to use it.
To show an 300px by 300px image, the code would look like.
from PIL import Image
img = Image.new('RGB', (300,300), color = (53, 21, 110))
display(img)
I have been trying to use opencv's template matching function to match templates within images. However, when the images are dark brown and dark green, the template matching does not work so well. I am pretty sure it is the grey scale conversion that is responsible for this because in greyscale it looks very similar.
However from what I see, cv2.matchtemplate() only takes in grey scale images. How can I do coloured template matching? Should I seperate the RGB image into 3 images: one red, one green, one blue and treat each one as gray scale images and apply matchtemplate then sum the similarity rating for each pixel position? Is that the way to do it? Or is there a different function or a parameter value I can use to make matchtemplate work for coloured images?
You may try this code:
import numpy as np
import cv2
threshold = 0.8
##Read Main and Needle Image
imageMainRGB = cv2.imread(main/Image/Path/main.png)
imageNeedleRGB = cv2.imread(needle/Image/Path/needle.png)
##Split Both into each R, G, B Channel
imageMainR, imageMainG, imageMainB = cv2.split(imageMainRGB)
imageNeedleR, imageNeedleG, imageNeedleB = cv2.split(imageNeedleRGB)
##Matching each channel
resultB = cv2.matchTemplate(imageMainR, imageNeedleR, cv2.TM_SQDIFF)
resultG = cv2.matchTemplate(imageMainG, imageNeedleG, cv2.TM_SQDIFF)
resultR = cv2.matchTemplate(imageMainB, imageNeedleB, cv2.TM_SQDIFF)
##Add together to get the total score
result = resultB + resultG + resultR
loc = np.where(result >= 3 * threshold)
print("loc: ", loc)
The Image I tested with are:
main.png
needle.png
result.png
Remark: This code may not function in some photos, where a user may need to modify it further to enhance it.
Note: This image was getting from pexels.com which is free copyright. If you have any issues with the image copyright and want to take down this image, welcome to contact me. Thanks.
I have a webcam directly over a chicken nest. This camera takes images and uploads them to a folder on a server. I'd like to detect if an egg has been laid from this image.
I'm thinking the best method would be to compare the contrast as the egg will be much more reflective than the straw nest. (The camera has Infrared so the image is partly grey scale)
I'd like to do this in .NET if possible.
Try to resize your image to a smaller size, maybe 10 x 10 pixel. This averages out any small disturbing details.
Const N As Integer = 10
Dim newImage As New Bitmap(N, N)
Dim fromCamera As Image = Nothing ' Get image from camera here
Using gr As Graphics = Graphics.FromImage(newImage)
gr.SmoothingMode = SmoothingMode.HighSpeed
gr.InterpolationMode = InterpolationMode.Bilinear
gr.PixelOffsetMode = PixelOffsetMode.HighSpeed
gr.DrawImage(fromCamera, New Rectangle(0, 0, N, N))
End Using
Note: you do not need a high quality, but you need a good averaging. Maybe you will have to test different quality settings.
Since now, a pixel covers a large area of your original image, a bright pixel is very likely part of an egg. It might also be a good idea to compare the brightness of the brightest pixel to the average image brightness, since that would reduce problems due to global illumination changes.
EDIT (in response to comment):
Your code is well structured and makes sense. Here some thoughts:
Calculate the gray value from the color value with:
Dim grayValue = c.R * 0.3 + c.G * 0.59 + c.B * 0.11
... instead of comparing the three color components separately. The different weights are due to the fact, that we perceive green stronger than red and red stronger than blue. Again, we do not want a beautiful thumbnail we want a good contrast. Therefore, you might want to do some experiments here as well. May be it is sufficient to use only the red component. Dependent on lighting conditions one color component might yield a better contrast than others. I would recommend, to make the gray conversion part of the thumbnail creation and to write the thumbnails to a file or to the screen. This would allow you to play with the different settings (size of the thumbnail, resizing parameters, color to gray conversion, etc.) and to compare the (intermediate) results visually. Creating a bitmap (bmp) with the (end-)result is a very good idea.
The Using statement does the Dispose() for you. It does it even if an exception should occur before End Using (There is a hidden Try Finally involved).
Hi I am working on an OBJ loader for use in iOS programming, I have managed to load the vertices and the faces but I have an issue with the transparency of the faces.
For the colours of the vertices I have just made them for now, vary from 0 - 1. So each vertex will gradually change from black to white. The problem is that the white vertices and faces seem to appear over the black ones. The darker the vertices the more they appeared covered.
For an illustration of this see the video I posted here < http://youtu.be/86Sq_NP5jrI >
The model here consists of two cubes, one large cube with a smaller one attached to a corner.
How do you assign a color to vertex? I assume, that you have RGBA render target. So you need to setup color like this:
struct color
{
u8 r, g, b, a;
};
color newColor;
newColor.a = 255;//opaque vertex, 0 - transparent
//other colors setup
I'm trying to draw a "conical"/"arcing" gradient (I don't know what would be the correct term for this) (Photoshop calls it an "angle" gradient —your friendly neighborhood stackoverflow editor) using Objective-C (IOS), pretty much exactly like the image shown in the following thread.
After days of googling and searching the internet to no avail, I've decided to ask for help here.
A little background on what I'm trying to do. My objective is to create a custom UIView, which is circular progress bar, a ring basicly, somewhat similar to the activity indicator as seen in the TweetBot iPhone app (displays when you drag to refresh, which can be seen in action here, around 17-18 seconds into the video, on top of the iphone screen). I want the progress indicator (the fill of the ring) to be a simple two color gradient, which can be set programmatically, and the view to be resizable.
Filling the ring shape with a gradient that "follows" the arc of the ring is where I'm stuck. The answers that I get from googling, reading Apple's Core Graphics documentation on gradients and searching on SO are either about radial gradients or linear/axial gradients, which is not what I'm trying to achieve.
The thread linked above suggests using pre-made images, but this isn't an option because the colors of the gradient should be settable, the view should be resizable and the fill of the progress bar isn't always 100% full obviously (which would be the state of the gradient as shown in the picture in the thread above).
The only solution that I've come up with is to draw the gradient "manually", so without using a CGGradientRef, clipping small slices of the gradient with single solid color fills within a circular path. I don't know exactly how well this will perform when the bar is being animated though, it shouldn't be that bad, but it might be a problem.
So my first question:
Is there an easier/different solution to draw a conical/arcing gradient in Objective-C (IOS) than the solution I've come up with?
Second question:
If I have to draw the gradient manually in my view using the solution I came up with, how can I determine or calculate (if this is even possible) the value (HEX or RGBA) of each color "slice" of the gradient that I'm trying to draw, as illustrated in the image below.
(Can't link image) gradient slice illustration
Looks to me like a job for a pixel shader. I remember seeing a Quartz Composer example that simulated a radar sweep, and that used a pixel shader to produce an effect like you're describing.
Edit:
Found it. This shader was written by Peter Graffignino:
kernel vec4 radarSweep(sampler image, __color color1,__color color2, float angle, vec4 rect)
{
vec4 val = sample(image, samplerCoord(image));
vec2 locCart = destCoord();
float theta, r, frac, angleDist;
locCart.x = (locCart.x - rect.z/2.0) / (rect.z/2.0);
locCart.y = (locCart.y - rect.w/2.0) / (rect.w/2.0);
// locCart is now normalized
theta = degrees(atan(locCart.y, locCart.x));
theta = (theta < 0.0) ? theta + 360.0 : theta;
r = length(locCart);
angleDist = theta - angle;
angleDist = (angleDist < 0.0) ? angleDist + 360.0 : angleDist;
frac = 1.0 - angleDist/360.0;
// sum up 3 decaying phosphors with different time constants
val = val*exp2(-frac/.005) + (val+.1)*exp2(-frac/.25)*color1 + val*exp2(-frac/.021)*color2;
val = r > 1.0 ? vec4(0.0, 0.0,0.0,0.0) : val; // constrain to circle
return val;
}
The thread linked above suggests using pre-made images, but this isn't an option because the colors of the gradient should be settable, the view should be resizable and the fill of the progress bar isn't always 100% full obviously (which would be the state of the gradient as shown in the picture in the thread above).
Not a problem!
Use the very black-to-white image from the other question (or a bigger version if you need one), in the following fashion:
Clip to whatever shape you want to draw the gradient in.
Fill with the color at the end of the gradient.
Use the black-to-white gradient image as a mask.
Fill with the color at the start of the gradient.
You can rotate the gradient by rotating the mask image.
This only supports the simplest case of a gradient with a color at each extreme end; it doesn't scale to three or more colors and doesn't support unusual gradient stop positioning.
FYI: here's also a good tutorial for creating a circular progress bar using Quartz drawing.
http://www.turnedondigital.com/blog/quartz-tutorial-how-to-draw-in-quartz/