I need to return the rows that contain both _1 and _2 from the SQL Server table. Below is my query and it returns the rows even both the above conditions are not matched.
As per my knowledge, I can use [ and ] to match multiple values when using the LIKE clause with wild cards.
DECLARE #TempTable AS TABLE (Col VARCHAR(MAX))
INSERT INTO #TempTable VALUES
('001098E2-5995-446F-87DC-BE71D2B30D37_2|69FA4BCD-C90B-4375-B08C-B3615C55500D_2'),
('0025F9BF-995D-4C88-BBD6-4C707A88BC32_1|F53668A8-F819-4309-BC0C-8DE4C2637419_2'),
('007BB00A-3B69-45FC-A265-1EC8B00E011A_2|0701649E-8BFE-4B03-8456-51E2D9169BD5_2|08950E50-80B2-4BDF-9FC7-3AB0AA4587AE_1')
SELECT * FROM #TempTable
WHERE (Col LIKE '%[_1]%' AND Col LIKE '%[_2]%')
I expect not to return 001098E2-5995-446F-87DC-BE71D2B30D37_2|69FA4BCD-C90B-4375-B08C-B3615C55500D_2, but SQL Server returns all 3 records.
Thanks in advance.
SELECT * FROM #TempTable
WHERE (Col LIKE '%[_]1%' AND Col LIKE '%[_]2%')
Using Wildcard Characters As Literals
You can use the wildcard pattern matching characters as literal characters. To use a wildcard character as a literal character, enclose the wildcard character in brackets. The following table shows several examples of using the LIKE keyword and the [ ] wildcard characters.
_ is also a wildcard matching one arbitrary character. You can define an ESCAPE character and escape it to match a regular underscore. You don't need [], i.e. character classes here.
SELECT *
FROM #temptable
WHERE col LIKE '%\_1%' ESCAPE '\'
AND col LIKE '%\_2%' ESCAPE '\';
db<>fiddle
You can use the wildcard pattern matching characters as literal characters.
To use a wildcard character as a literal character, enclose the wildcard character in brackets.
WHERE (Col LIKE '%[_]1%' AND Col LIKE '%[_]2%')
you can also escape the underscore like this
WHERE (Col LIKE '%$_1%' ESCAPE '$')
AND (Col LIKE '%$_2%' ESCAPE '$')
I try to execute such query:
select * from my_table where table_name ilike 'PDK\1100090'
this query returns 0 rows, but in fact that table contains a row with such string. I verified that by selecting everything from that table. I also used '=' instead of ilike, and tried esaping the string with E'PDK\1100090' with no luck. I assume there is a problem with a backslash in the string but I could be wrong about that.
Thanks in advance
You claim to have tried double back slashes. Try this:
where table_name ilike 'PDK_1100090'
Does that return anything? (The underscore should match any character in that position.)
Then try for any sequence:
where table_name ilike 'PDK%1100090'
Then look for unusual characters at the beginning/ending of the string:
where table_name ilike '%PDK%1100090%'
If the double backslash isn't working, then you have some other funkiness in the string.
Replacing the query by adding 3 more backslashes solve the problem. Now it looks like this:
select * from my_table where table_name ilike 'PDK\\\\1100090'
I wrote the below SQL query with a LIKE condition:
SELECT * FROM Manager
WHERE managerid LIKE '_%'
AND managername LIKE '%_%'
In the LIKE I want to search for any underscores %_%, but I know that my columns' data has no underscore characters.
Why does the query give me all the records from the table?
Sample data:
create table Manager(
id int
,managerid varchar(3)
,managername varchar(50)
);
insert into Manager(id,managerid,managername)values(1,'A1','Mangesh');
insert into Manager(id,managerid,managername)values(2,'A2','Sagar');
insert into Manager(id,managerid,managername)values(3,'C3','Ahmad');
insert into Manager(id,managerid,managername)values(4,'A4','Mango');
insert into Manager(id,managerid,managername)values(5,'B5','Sandesh');
Sql-Fiddle
Modify your WHERE condition like this:
WHERE mycolumn LIKE '%\_%' ESCAPE '\'
This is one of the ways in which Oracle supports escape characters. Here you define the escape character with the escape keyword. For details see this link on Oracle Docs.
The '_' and '%' are wildcards in a LIKE operated statement in SQL.
The _ character looks for a presence of (any) one single character. If you search by columnName LIKE '_abc', it will give you result with rows having 'aabc', 'xabc', '1abc', '#abc' but NOT 'abc', 'abcc', 'xabcd' and so on.
The '%' character is used for matching 0 or more number of characters. That means, if you search by columnName LIKE '%abc', it will give you result with having 'abc', 'aabc', 'xyzabc' and so on, but no 'xyzabcd', 'xabcdd' and any other string that does not end with 'abc'.
In your case you have searched by '%_%'. This will give all the rows with that column having one or more characters, that means any characters, as its value. This is why you are getting all the rows even though there is no _ in your column values.
The underscore is the wildcard in a LIKE query for one arbitrary character.
Hence LIKE %_% means "give me all records with at least one arbitrary character in this column".
You have to escape the wildcard character, in sql-server with [] around:
SELECT m.*
FROM Manager m
WHERE m.managerid LIKE '[_]%'
AND m.managername LIKE '%[_]%'
See: LIKE (Transact-SQL)
Demo
As you want to specifically search for a wildcard character you need to escape that
This is done by adding the ESCAPE clause to your LIKE expression. The character that is specified with the ESCAPE clause will "invalidate" the following wildcard character.
You can use any character you like (just not a wildcard character). Most people use a \ because that is what many programming languages also use
So your query would result in:
select *
from Manager
where managerid LIKE '\_%' escape '\'
and managername like '%\_%' escape '\';
But you can just as well use any other character:
select *
from Manager
where managerid LIKE '#_%' escape '#'
and managername like '%#_%' escape '#';
Here is an SQLFiddle example: http://sqlfiddle.com/#!6/63e88/4
Underscore is a wildcard for something.
for example
'A_%' will look for all match that Start whit 'A' and have minimum 1 extra character after that
In case people are searching how to do it in BigQuery:
An underscore "_" matches a single character or byte.
You can escape "\", "_", or "%" using two backslashes. For example, "\%". If you are using raw strings, only a single backslash is required. For example, r"\%".
WHERE mycolumn LIKE '%\\_%'
Source: https://cloud.google.com/bigquery/docs/reference/standard-sql/operators
You can write the query as below:
SELECT * FROM Manager
WHERE managerid LIKE '\_%' escape '\'
AND managername LIKE '%\_%' escape '\';
it will solve your problem.
I know you can use LIKE for a select statement to search for a string and then use wildcards to match that string.. ex:
Select * from table where first_name LIKE '%r%';
Would return names such as robert, roland, craig, etc.
I'm curious how you would search for an actual wildcard in the string such as the %:
Select * from table where values LIKE '% % %';
(the middle % being what you would be looking for) (obviously this is not the correct way to do it which is why I'm asking).
How about
LIKE '%\%%' ESCAPE '\'
http://docs.oracle.com/cd/B12037_01/server.101/b10759/conditions016.htm
Just LIKE '%%' will be even easier.
I want to use the like command in a query to find specific results in Access. In the field that I want to utilize the like command has the wildcard (*) command in that field, which I want to search by. Is there a way around this? Example below:
SELECT *
FROM TABLE_NAME
WHERE FIELD_NAME LIKE '*'
Assuming you want to find columns that actually contain an asterisk (*) via the LIKE operator, here is an idea to try (see http://office.microsoft.com/en-us/access-help/using-wildcard-characters-in-string-comparisons-HP001032284.aspx )
SELECT *
FROM TABLE_NAME
WHERE FIELD_NAME LIKE '[*]'
The square brackets indicate that it's a literal asterisk to match, and not a wildcard.
* is not a wildcard in sql server like. So you can use:
SELECT *
FROM TABLE_NAME
WHERE FIELD_NAME LIKE '%*%' ;
If you want to search for actual wildcard %, you can change the wilcard to something else say &
SELECT *
FROM TABLE_NAME
WHERE FIELD_NAME LIKE '&%&' ESCAPE '&';