ntfs cluster allocation - ntfs

I'm interested in finding out how cluster allocation by NTFS works agaings write/IRP. NTFS does store this information in MFT but what actually happens at that time. Is there an I/O object in the kernel that stores this information before the data is flush to the disk or does USN journal plays any role here. If so how.

NTFS has to look up where the data actually is on the volume, that's its job. The O/S provides something called a, "Map Control Block" (MCB) package that the file systems use to cache this information, but if it's not in the MCB it has to be looked up from the MFT. The USN is different, that's just logging various events.
If you're interested in Windows file systems I suggest reading the file systems internals book:
http://www.amazon.com/Windows-System-Internals-Classic-Reprints/dp/0976717514/ref=sr_1_1?ie=UTF8&qid=1309880147&sr=8-1
As well as taking a look at the FAT source in the WDK, which is a great starting point compared to NTFS (NTFS is much more complicated).
-scott

Related

Can I securely delete a file this way?

Let's say I have a 10 MB file and go through these steps:
Open it in my favorite programming language for Read/Write
Erase everything in the stream
Write exactly 10 MB of random back to the same stream
Save the changes to disk
Delete the file through normal means
Can I be certain that the new 10 MB successfully overwrote the old 10 MB on a sector level in the hard drive? Or is it possible that the "erase everything in the stream" step deletes the old file and potentially writes the new 10 MB in a new location?
The data may still be accessible by a professional who knows what they're doing and can access the raw data on the disk (i.e. without going through the filesystem).
Your program is basically equivalent to the Linux shred command, which contains the following warning:
CAUTION: Note that shred relies on a very important assumption:
that the file system overwrites data in place. This is the traditional
way to do things, but many modern file system designs do not satisfy this
assumption. The following are examples of file systems on which shred is
not effective, or is not guaranteed to be effective in all file system modes:
log-structured or journaled file systems, such as those supplied with
AIX and Solaris (and JFS, ReiserFS, XFS, Ext3, etc.)
file systems that write redundant data and carry on even if some writes
fail, such as RAID-based file systems
file systems that make snapshots, such as Network Appliance's NFS server
file systems that cache in temporary locations, such as NFS
version 3 clients
compressed file systems
There's other situations as well, such as SSDs with wear leveling.
no, since on any modern file system commits are atomic, you can be almost 100% certain the 10Mb did not overwrite the old 10Mb, and that's before we consider journaled file systems that actually guarantee this.
Short answer: No.
This might depend on your language and OS. I have a feeling that the stream calls are passed to the OS and the OS then decides what to do, so I'd lean towards your second question being correct just to err on the safe side. Furthermore, magnetic artifacts will be present after a deletion which can still be used to recover said data. Even overwriting the same sectors with all zeros could leave behind the data in a faded state. Generally it is recommended to make several deletion passes. See here for an explanation or here for an open source C# file shredder.
For Windows you could use the SDelete command line utility which implements the Department of Defense clearing and sanitizing standard:
Secure delete applications overwrite a deleted file's on-disk data
using techiques that are shown to make disk data unrecoverable, even
using recovery technology that can read patterns in magnetic media
that reveal weakly deleted files.
Of particular note:
Compressed, encrypted and sparse are managed by NTFS in 16-cluster
blocks. If a program writes to an existing portion of such a file NTFS
allocates new space on the disk to store the new data and after the
new data has been written, deallocates the clusters previously
occupied by the file.

Write time to hard drive

I realize this number will change based on many factors, but in general, when I write data to a hard-drive (e.g. copy a file), how long does it take for that data to actually be written to the platter after Windows says the copy is done?
Could anyone point me in the right direction to discover more on this topic?
If you are looking for a hard number, that is pretty much unknowable. Generally it is the order of a tens to a few hundred milliseconds for the data to start reaching the disk platters, but can be as high as several seconds in a large server disk array with RAID and de-duplication.
The flow of events goes something like this.
The application calls a function like fwrite().
This call is handled by the filesystem layer in your Operating System, which has to figure out what specific disk sectors are to be manipulated.
The SATA/IDE driver in your OS will talk to the hard drive controller hardware. On a modern PC, it typically uses DMA to feed the data to the disk.
The data sits in a write cache inside the hard disk (RAM).
When the physical platters and heads have made it into position, it will begin to transfer the contents of cache onto the platters.
Steps 3-6 may repeat several times depending on how much data is to be written, where on the disk it is to be written. Additionally, there is usually filesystem metadata that must be updated (e.g. free space counters), which will trigger more writes to the disk.
The time it takes from steps 1-3 can be unpredictable in a general purpose OS like Windows due to task scheduling, background threads, and your disk write is probably queued up with a few dozen other processes. I'd say it is usually on the order of 10-100msec on a typical PC. If you go to the Windows Resource Monitor and click the Disk tab, you can get an idea of the average disk queue length. You can use the Performance Monitor to produce more finely-controlled graphs.
Steps 3-4 are largely controlled by the disk controller and disk interface (SATA, SAS, etc). In the server world, you can be talking about a SAN with FC or iSCSI network switches, which impose their own latencies.
Step 5 will be controlled by they physical performance of the disk. Many consumer-grade HDD manufacturers do not post average seek times anymore, but 10-20msec is common.
Interesting detail about Step 5: Some HDDs lie about flushing their write cache to get better benchmark scores.
Step 6 will depend on your filesystem and how much data you are writing.
You are right that there can be a delay between Windows indicating that data writing is finished and the last data actually written. Things to consider are:
Device Manager, Disk Drive, Properties, Policies - Options for disabling Write Caching.
You might be better off using Direct I/O so that Windows does not save it temporarily in File Cache.
If your program writes the data, you can log what has been copied.
If you are sending the data over a network, you are likely to have no control of when the remote system has finished.
To see what is happening, you can set up Perfmon logging. One of my examples of monitoring:
http://www.roylongbottom.org.uk/monitor1.htm#anchor2

IPC through writing into files?

I have a question about Inter-process-communication in operating systems.
Can 2 processes communicate with each other by both processes opening the same file (which say was created before both processes, so both processes have the file handler) and then communicating by writing into this file?
If yes, what does this method come under? I have heard that 2 major ways of IPC is by shared-memory and message-passing. Which one of these, this method comes under?
The reason, I am not sure if it comes under shared-memory is that, because this file is not mapped to address space of any of these processes. And, from my understanding, in shared-memory, the shared-memory-region is part of address space of both the processes.
Assume that processes write into the file in some pre-agreed protocol/format so both have no problem in knowing where the other process writes and when etc. This assumption is to merely understand. In real world though, this may be too stringent to hold true etc.
If no, what is wrong with this scenario? Is it that if 2 different processes open the same file, then the changes made by 1st process are not flushed into persistent storage for others to view until the process terminates? or something else?
Any real world example from Windows and Linux should also be useful.
Thanks,
Using a file is a kind of shared memory. Instead of allocating a common memory buffer in RAM, a common file is used.
To successfully manage the communication some kind of locking mechanism for different ranges in the file is needed. This could either be locking of ranges provided by the file system (available at least on Windows) or global operating system mutexes.
One real-world scenario where disk storage is used for inter-process-communication is the quorom disk used in clusters. It is a common disk resource, accessible over a SAN by all cluster nodes, that stores the cluster's configuration.
The posix system call mmap does mappings of files to virtual memory. If the mapping is shared between two processes, writes to that area in one process will affect other processes. Now coming to you question, yes a process reading from or writing to the underlying file will not always see the same data that the process that has mapped it, since the segment of the file is copied into RAM and periodically flushed to disk. Although I believe you can force synchronization with the msync system call. Do read up on mmap(). It has a host of other memory sharing options.

Are disk sector writes atomic?

Clarified Question:
When the OS sends the command to write a sector to disk is it atomic? i.e. Write of new data succeeds fully or old data is left intact should the power fail immediately following the write command. I don't care about what happens in multiple sector writes - torn pages are acceptable.
Old Question:
Say you have old data X on disk, you write new data Y over it, and a tree falls on the power line during that write. With no fancy UPS or battery backed disk controller, you can end up with a torn page, where the data on disk is part X and part Y. Can you ever end up with a situation where the data on disk is part X, part Y, and part garbage?
I've been trying to understand the design of ACID systems like databases, and to my naive thinking, it seems firebird, which does not use a write-ahead log, is relying that a given write will not destroy old data (X) - only fail to fully write new data (Y). That means that if part of X is being overwritten, only the part of X that is being overwritten can be changed, not the part of X we intend to keep.
To clarify, this means if you have a page sized buffer, say 4096 bytes, filled with half Y, half X that we want to keep - and we tell the OS to write that buffer over X, there is no situation short of serious disk failure where the half X that we want to keep is corrupted during the write.
The traditional (SCSI, ATA) disk protocol specifications don't guarantee that any/every sector write is atomic in the event of sudden power loss (but see below for discussion of the NVMe spec). However, it seems tacitly agreed that non-ancient "real" disks quietly try their best to offer this behaviour (e.g. Linux kernel developer Christoph Hellwig mentions this off-hand in the 2017 presentation "Failure-Atomic file updates for Linux").
When it comes to synthetic disks (e.g. network attached block devices, certain types of RAID etc.) things are less clear and they may or may not offer sector atomicity guarantees while legally behaving per their given spec. Imagine a RAID 1 array (without a journal) comprised of a disk that offers 512 byte sized sectors but where the other disk offered a 4KiB sized sector thus forcing the RAID to expose a sector size of 4KiB. As a thought experiment, you can construct a scenario where each individual disk offers sector atomicity (relative to its own sector size) but where the RAID device does not in the face of power loss. This is because it would depend on whether the 512 byte sector disk was the one being read by the RAID and how many of the 8 512-byte sectors compromising the 4KiB RAID sector it had written before the power failed.
Sometimes specifications offer atomicity guarantees but only on certain write commands. The SCSI disk spec is an example of this and the optional WRITE ATOMIC(16) command can even give a guarantee beyond a sector but being optional it's rarely implemented (and thus rarely used). The more commonly implemented COMPARE AND WRITE is also atomic (potentially across multiple sectors too) but again it's optional for a SCSI device and comes with different semantics to a plain write...
Curiously, the NVMe spec was written in such a way to guarantee sector atomicity thanks to Linux kernel developer Matthew Wilcox. Devices that are compliant with that spec have to offer a guarantee of sector write atomicity and may choose to offer contiguous multi-sector atomicity up to a specified limit (see the AWUPF field). However, it's unclear how you can discover and use any multi-sector guarantee if you aren't currently in a position to send raw NVMe commands...
Andy Rudoff is an engineer who talks about investigations he has done on the topic of write atomicity. His presentation "Protecting SW From Itself: Powerfail Atomicity for Block Writes" (slides) has a section of video where he talks about how power failure impacts in-flight writes on traditional storage. He describes how he contacted hard drive manufacturers about the statement "a disk's rotational energy is used to ensure that writes are completed in the face of power loss" but the replies were non-committal as to whether that manufacturer actually performed such an action. Further, no manufacturer would say that torn writes never happen and while he was at Sun, ZFS added checksums to blocks which led to them uncovering cases of torn writes during testing. It's not all bleak though - Andy talks about how sector tearing is rare and if a write is interrupted then you usually get only the old sector, or only the new sector, or an error (so at least corruption is not silent). Andy also has an older slide deck Write Atomicity and NVM Drive Design which collects popular claims and cautions that a lot of software (including various popular filesystems on multiple OSes) are actually unknowingly dependent on sector writes being atomic...
(The following takes a Linux centric view but many of the concepts apply to general-purpose OSes that are not being deployed in a tightly controlled hardware environments)
Going back to 2013, BtrFS lead developer Chris Mason talked about how (the now defunct) Fusion-io had created a storage product that implemented atomic operation (Chris was working for Fusion-io at the time). Fusion-io also created a proprietary filesystem "DirectFS" (written by Chris) to expose this feature. The MariaDB developers implemented a mode that could take advantage of this behaviour by no longer doing double buffering resulting in "43% more transactions per second and half the wear on the storage device". Chris proposed a patch so generic filesystems (such as BtrFS) could advertise that they provided atomicity guarantees via a new flag O_ATOMIC but block layer changes would also be needed. Said block layer changes were also proposed by Chris in a later patch series that added a function blk_queue_set_atomic_write(). However, neither of the patch series ever entered the mainline Linux kernel and there is no O_ATOMIC flag in the (current 2020) mainline 5.7 Linux kernel.
Before we go further, it's worth noting that even if a lower level doesn't offer an atomicity guarantee, a higher level can still provide atomicity (albeit with performance overhead) to its users so long as it knows when a write has reached stable storage. If fsync() can tell you when writes are on stable storage (technically not guaranteed by POSIX but the case on modern Linux) then because POSIX rename is atomic you can use the create new file/fsync/rename dance to do atomic file updates thus allowing applications to do double buffering/Write Ahead Logging themselves. Another example lower down in the stack are Copy On Write filesystems like BtrFS and ZFS. These filesystems give userspace programs a guarantee of "all the old data" or "all the new data" after a crash at sizes greater than a sector because of their semantics even though a disk many not offer atomic writes. You can push this idea all the way down into the disk itself where NAND based SSDs don't overwrite the area currently used by an existing LBA and instead write the data to a new region and keep a mapping of where the LBA's data is now.
Resuming our abridged timeline, in 2015 HP researchers wrote a paper Failure-Atomic Updates of Application Data
in a Linux File System (PDF) (media) about introducing a new feature into the Linux port of AdvFS (AdvFS was originally part of DEC's Tru64):
If a file is opened with a new O_ATOMIC flag, the state of its application data will always reflect the most recent successful msync, fsync, or fdatasync. AdvFS furthermore includes a new syncv operation that combines updates to multiple files into a failure-atomic bundle [...]
In 2017, Christoph Hellwig wrote experimental patches to XFS to provide O_ATOMIC. In the "Failure-Atomic file updates for Linux" talk (slides) he explains how he drew inspiration from the 2015 paper (but without the multi-file support) and the patchset extends the XFS reflink work that already existed. However, despite an initial mailing list post, at the time of writing (mid 2020) this patchset is not in the mainline kernel.
During the database track of the 2019 Linux Plumbers Conference, MySQL developer Dimitri Kravtchuk asked if there were plans to support O_ATOMIC (link goes to start of filmed discussion). Those assembled mention the XFS work above, that Intel claim they can do atomicity on Optane but Linux doesn't provide an interface to expose it, that Google claims to provide 16KiB atomicity on GCE storage1. Another key point is that many database developers need something larger than 4KiB atomicity to avoid having to do double writes - PostgreSQL needs 8KiB, MySQL needs 16KiB and apparently the Oracle database needs 64KiB. Further, Dr Richard Hipp (author of the SQLite database) asked if there's a standard interface to request atomicity because today SQLite makes use of the F2FS filesystem's ability to do atomic updates via custom ioctl()s but the ioctl was tied to one filesystem. Chris replied that for the time being there's nothing standard and nothing provides the O_ATOMIC interface.
At the 2021 Linux Plumbers Conference Darrick Wong re-raised the topic of atomic writes (link goes to start of filmed discussion). He pointed out there are two different things that people mean when they say they want atomic writes:
Hardware provides some atomicity API and this capability is somehow exposed through the software stack
Make the filesystem do all the work to expose some sort of atomic write API irrespective of hardware
Darrick mentioned that Christoph had ideas for 1. in the past but Christoph has not come back to the topic and further there are unanswered questions (how you make userspace aware of limits, if the feature was exposed it would be restricted to direct I/O which may problematic for many programs). Instead Darrick suggested tackling 2. was to propose his FIEXCHANGE_RANGE ioctl which swaps the contents of two files (the swap is restartable if it fails part way through). This approach doesn't have the limits (e.g. smallish contiguous size, maximum number of scatter gather vectors, direct I/O only) that a hardware based solution would have and could theoretically be implementable in the VFS thus being filesystem agnostic...
TLDR; if you are in tight control of your whole stack from application all the way down the the physical disks (so you can control and qualify the whole lot) you can arrange to have what you need to make use of disk atomicity. If you're not in that situation or you're talking about the general case, you should not depend on sector writes being atomic.
When the OS sends the command to write a sector to disk is it atomic?
At the time of writing (mid-2020):
When using a mainline 4.14+ Linux kernel
If you are dealing with a real disk
a sector write sent by the kernel is likely atomic (assuming a sector is no bigger than 4KiB). In controlled cases (battery backed controller, NVMe disk which claims to support atomic writes, SCSI disk where the vendor has given you assurances etc.) a userspace program may be able to use O_DIRECT so long as O_DIRECT wasn't reverting to being buffered, the I/O didn't get split apart/merged at the block layer / you are sending device specific commands and are bypassing the block layer. However, in the general case neither the kernel nor a userspace program can safely assume sector write atomicity.
Can you ever end up with a situation where the data on disk is part X, part Y, and part garbage?
From a specification perspective if you are talking about a SCSI disk doing a regular SCSI WRITE(16) and a power failure happening in the middle of that write then the answer is yes: a sector could contain part X, part Y AND part garbage. A crash during an inflight write means the data read from the area that was being written to is indeterminate and the disk is free to choose what it returns as data from that region. This means all old data, all new data, some old and new, all zeros, all ones, random data etc. are all "legal" values to return for said sector. From an old draft of the SBC-3 spec:
4.9 Write failures
If one or more commands performing write operations are in the task set and are being processed when power is lost (e.g., resulting in a vendor-specific command timeout by the application client) or a medium error or hardware error occurs (e.g., because a removable medium was incorrectly unmounted), the data in the logical blocks being written by those commands is indeterminate. When accessed by a command performing a read or verify operation (e.g., after power on or after the removable medium is mounted), the device server may return old data, new data, or vendor-specific data in those logical blocks.
Before reading logical blocks which encountered such a failure, an application client should reissue any commands performing write operations that were outstanding.
1 In 2018 Google announced it had tweaked its cloud SQL stack and that this allowed them to use 16k atomic writes MySQL's with innodb_doublewrite=0 via O_DIRECT... The underlying customisations Google performed were described as being in the virtualized storage, kernel, virtio and the ext4 filesystem layers. Further, a no longer available beta document titled Best practices for 16 KB persistent disk and MySQL (archived copy) described what end users had to do to safely make use of the feature. Changes included: using an appropriate Google provided VM, using specialized storage, changing block device parameters and carefully creating an ext4 filesystem with a specific layout. However, at some point in 2020 this document vanished from GCE's online guides suggesting such end user tuning is not supported.
I think torn pages are not the problem. As far as I know, all drives have enough power stored to finish writing the current sector when the power fails.
The problem is that everybody lies.
At least when it comes to the database knowing when a transaction has been committed to disk, everybody lies. The database issues an fsync, and the operating system only returns when all outstanding writes have been committed to disk, right? Maybe not. It's common, especially with RAID cards and/or SATA drives, for your program to be told everything has committed (that is, fsync returns) and yet there is data not yet on the drive.
You can try using Brad's diskchecker to find out if the platform you are going to use for your database can survive pulling the plug without losing data. The bottom line: If diskchecker fails, the platform is not safe for running a database. Databases with ACID rely upon knowing when a transaction has been committed to backing store and when it has not. This is true whether or not the databases uses write-ahead loggin (and if the database returns to the user without having done an fsync, then transactions can be lost in the event of a failure, so it should not claim that it provides ACID semantics).
There's a long thread on the Postgresql mailing list discussing durability. It starts out talking about SSDs, but then it gets into SATA drives, SCSI drives, and file systems. You may be surprised to learn how exposed your data can be to loss. It's a good thread for anyone with a database that needs durability, not just those running Postgresql.
Nobody seems to agree on this question. So I spent a lot of time trying different Google queries until I finally found an answer.
from Dr. Stephen Tweedie, RedHat employee and linux kernel filesystem and virtual memory developer in a talk on ext3 (which he developed) transcript here. If anyone knows, it'd be him.
"It's not sufficient just to write the thing to the journal, because there's got to be some mark in the journal which says: well, (has this journal record actually) does this journal record actually represent a complete consistency to the disk? And the way you do that is by having some atomic operation which marks that transaction as being complete on disk" [23m, 14s]
"Now, disks these days actually make these guarantees. If you start a write operation to a disk, then even if the power fails in the middle of that sector write, the disk has enough power available, and it can actually steal power from the rotational energy of the spindle; it has enough power to complete the write of the sector that's being written right now. In all cases, the disks make that guarantee." [23m, 41s]
No, they are not. Worse yet, disks may lie and say the data is written when it is in fact in the disk cache, under default settings. For performance reasons, this may be desirable (actual durability is up to an order of magnitude slower) but it means if you lose power and the disk cache is not physically written, your data is gone.
Real durability is both hard and slow unfortunately, since you need to make at least one full rotation per write, or 2+ with journalling/undo. This limits you to a couple hundred DB transactions per second, and requires disabling write caching at a fairly low level.
For practical purposes though, the difference is not that big of a deal in most cases.
See:
How (not) to achieve durability.
FSync() may not flush to disk
People don't seem to agree on what happens during a sector write if the power fails. Maybe because it depends on the hardware being used, and even the filesystem.
From wikipedia (http://en.wikipedia.org/wiki/Journaling_file_system):
Some disk drives guarantee write
atomicity during a power failure.
Others, however, may stop writing
midway through a sector after power is
lost, leaving it mismatched against
its error-correcting code. The sector
is thus corrupt and its contents lost.
A physical journal guards against such
corruption because it holds a complete
copy of the sector, which it can
replay over the corruption upon next
mount.
Seems to suggest that some hard drives will not finish writing the sector, but that a journaling filesystem can protect you from data loss the same way the xlog protects a database.
From the linux kernel mailing list in a discussion on ext3 journaling filesystem:
In any case bad sector checksum is
hardware bug. Sector write is supposed
to be atomic, it either happens or
not.
I'd tend to believe that over the wiki comment. Actually, the very existence of a database (firebird) with no xlog implies that sector write is atomic, that it cannot clobber data you did not mean to change.
There's quite a bit of discussion Here about atomicity of sector writes, and again no agreement. But the people who are disagreeing seem to be talking about multiple-sector writes (which are not atomic on many modern hard-drives.) Those who are saying sector writes are atomic do seem to know more about what they're talking about.
The answer to your first question depends on the hardware involved. At least with some older hardware, the answer was yes -- a power failure could result it garbage being written to the disk. Most current disks, however, have a bit of a "UPS" built into the disk itself -- a capacitor that's large enough to power the disk long enough to write the data in the on-disk cache out to the disk platter. They also have circuitry to detect whether the power supply is still good, so when the power gets flaky, they write the data in the cache to the platter, and ignore garbage they might receive.
As far as a "torn page" goes, a typical disk only accepts commands to write an entire sector at a time, so what you'll get will normally be an integral number of sectors written correctly, and others remaining unchanged. If, however, you're using a logical page size that's larger than a single sector, you can certainly end up with a page that's partially written.
That, however, mostly applies to a direct connection to a normal moving-platter type hard drive. With almost anything else, the rules can and often will be different. Just for an obvious example, if you're writing over the network, you're mostly at the mercy of the network protocol in use. If you transmit data over TCP, data that doesn't match up with the CRC will be rejected, but the same data transmitted over UDP, with the same corruption, might be accepted.
I suspect this assumption is wrong.
Modern HDDs encode the data in sectors - and additionally protect it with ECC. Therefore you can end-up with garbaging all the sector content - it will just not make sense with the encoding used.
As for increasingly poplular SSDs, the situation is even more gruesome - the block is cleared prior to being overwritten, so, depending on the firmware being used and the amount of free space, entirely unrelated sectors can be damaged.
By the way, an OS crash will not lead to data being damaged within single sector.
I would expect one torn page to consist of part X, part Y, and part unreadable sector. If a head is in the middle of writing a sector when the power fails, the drive should park the heads immediately, so that the rest of the drive (aside from that one sector) will remain undamaged.
In some cases I would expect several torn pages consisting of part X and part Y, but only one torn page would include an unreadable sector. The reason for several torn pages is that the drive can buffer lots of writes internally, and the order of writing might interleave various sectors from various pages.
I've read conflicting stories about whether a new write to the unreadable sector will make it readable again. Even if the answer is yes, that will be new data Z, neither X nor Y.
when updating the
disk, the only guarantee drive manufactures make is that a single 512-
byte write is atomic (i.e., it will either complete in its entirety or it won’t
complete at all); thus, if an untimely power loss occurs, only a portion of
a larger write may complete (sometimes called a torn write).

Best Dual HD Set up for Development

I've got a machine I'm going to be using for development, and it has two 7200 RPM 160 GB SATA HDs in it.
The information I've found on the net so far seems to be a bit conflicted about which things (OS, Swap files, Programs, Solution/Source code/Other data) I should be installing on how many partitions on which drives to get the most benefit from this situation.
Some people suggest having a separate partition for the OS and/or Swap, some don't bother. Some people say the programs should be on the same physical drive as the OS with the data on the other, some the other way around. Same with the Swap and the OS.
I'm going to be installing Vista 64 bit as my OS and regularly using Visual Studio 2008, VMWare Workstation, SQL Server management studio, etc (pretty standard dev tools).
So I'm asking you--how would you do it?
If the drives support RAID configurations in your BIOS, you should do one of the following:
RAID 1 (Mirror) - Since this is a dev machine this will give you the fault tolerance and peace of mind that your code is safe (and the environment since they are such a pain to put together). You get better performance on reads because it can read from both/either drive. You don't get any performance boost on writes though.
RAID 0 - No fault tolerance here, but this is the fastest configuration because you read and write off both drives. Great if you just want as fast as possible performance and you know your code is safe elsewhere (source control) anyway.
Don't worry about mutiple partitions or OS/Data configs because on a dev machine you sort of need it all anyway and you shouldn't be running heavy multi-user databases or anything anyway (like a server).
If your BIOS doesn't support RAID configurations, however, then you might consider doing the OS/Data split over the two drives just to balance out their use (but as you mentioned, keep the programs on the system drive because it will help with caching). Up to you where to put the swap file (OS will give you dump files, but the data drive is probably less utilized).
If they're both going through the same disk controller, there's not going to be much difference performance-wise no matter which way you do it; if you're going to be doing lots of VM's, I would split one drive for OS and swap / Programs and Data, then keep all the VM's on the other drive.
Having all the VM's on an independant drive would let you move that drive to another machine seamlessly if the host fails, or if you upgrade.
Mark one drive as being your warehouse, put all of your source code, data, assets, etc. on there and back it up regularly. You'll want this to be stable and easy to recover. You can even switch My Documents to live here if wanted.
The other drive should contain the OS, drivers, and all applications. This makes it easy and secure to wipe the drive and reinstall the OS every 18-24 months as you tend to have to do with Windows.
If you want to improve performance, some say put the swap on the warehouse drive. This will increase OS performance, but will decrease the life of the drive.
In reality it all depends on your goals. If you need more performance then you even out the activity level. If you need more security then you use RAID and mirror it. My mix provides for easy maintenance with a reasonable level of data security and minimal bit rot problems.
Your most active files will be the registry, page file, and running applications. If you're doing lots of data crunching then those files will be very active as well.
I would suggest if 160gb total capacity will cover your needs (plenty of space for OS, Applications and source code, just depends on what else you plan to put on it), then you should mirror the drives in a RAID 1 unless you will have a server that data is backed up to, an external hard drive, an online backup solution, or some other means of keeping a copy of data on more then one physical drive.
If you need to use all of the drive capacity, I would suggest using the first drive for OS and Applications and second drive for data. Purely for the fact of, if you change computers at some point, the OS on the first drive doesn't do you much good and most Applications would have to be reinstalled, but you could take the entire data drive with you.
As for dividing off the OS, a big downfall of this is not giving the partition enough space and eventually you may need to use partitioning software to steal some space from the other partition on the drive. It never seems to fail that you allocate a certain amount of space for the OS partition, right after install you have several gigs free space so you think you are fine, but as time goes by, things build up on that partition and you run out of space.
With that in mind, I still typically do use an OS partition as it is useful when reloading a system, you can format that partition blowing away the OS but keep the rest of your data. Ways to keep the space build up from happening too fast is change the location of your my documents folder, change environment variables for items such as temp and tmp. However, there are some things that just refuse to put their data anywhere besides on the system partition. I used to use 10gb, these days I go for 20gb.
Dividing your swap space can be useful for keeping drive fragmentation down when letting your swap file grow and shrink as needed. Again this is an issue though of guessing how much swap you need. This will depend a lot on the amount of memory you have and how much stuff you will be running at one time.
For the posters suggesting RAID - it's probably OK at 160GB, but I'd hesitate for anything larger. Soft errors in the drives reduce the overall reliability of the RAID. See these articles for the details:
http://alumnit.ca/~apenwarr/log/?m=200809#08
http://permabit.wordpress.com/2008/08/20/are-fibre-channel-and-scsi-drives-more-reliable/
You can't believe everything you read on the internet, but the reasoning makes sense to me.
Sorry I wasn't actually able to answer your question.
I usually run a box with two drives. One for the OS, swap, typical programs and applications, and one for VMs, "big" apps (e.g., Adobe CS suite, anything that hits the disk a lot on startup, basically).
But I also run a cheap fileserver (just an old machine with a coupla hundred gigs of disk space in RAID1), that I use to store anything related to my various projects. I find this is a much nicer solution than storing everything on my main dev box, doesn't cost much, gives me somewhere to run a webserver, my personal version control, etc.
Although I admit, it really isn't doing much I couldn't do on my machine. I find it's a nice solution as it helps prevent me from spreading stuff around my workstation's filesystem at random by forcing me to keep all my work in one place where it can be easily backed up, copied elsewhere, etc. I can leave it on all night without huge power bills (it uses <50W under load) so it can back itself up to a remote site with a little script, I can connect to it from outside via SSH (so I can always SCP anything I need).
But really the most important benefit is that I store nothing of any value on my workstation box (at least nothing that isn't also on the server). That means if it breaks, or if I want to use my laptop, etc. everything is always accessible.
I would put the OS and all the applications on the first disk (1 partition). Then, put the data from the SQL server (and any other overflow data) on the second disk (1 partition). This is how I'd set up a machine without any other details about what you're building. Also make sure you have a backup so you don't lose work. It might even be worth it to mirror the two drives (if you have RAID capability) so you don't lose any progress if/when one of them fails. Also, backup to an external disk daily. The RAID won't save you when you accidentally delete the wrong thing.
In general I'd try to split up things that are going to be doing a lot of I/O (such as if you have autosave on VS going off fairly frequently) Think of it as sort of I/O multithreading
I've observed significant speedups by putting my virtual machines on a separate disk. Whenever Windows is doing something stupid in the VM (e.g., indexing yet again), it doesn't thrash my Mac's disk quite so badly.
Another issue is that many tools (Visual Studio comes to mind) break in frustrating ways when bits of them are on the non-primary disk.
Use your second disk for big random things.