Using SQL Server 2008...
I'm having some troubles in trying to order my rows in a specific order that I would like them to be ordered by. I've found a few examples that use the ORDER BY CASE clause, but am unsure whether using this method will produce the result that I want it to, thus I come to the community!
Here's what I have:
First, I select, if it exists, a distinct year that is equal to the current year:
IF EXISTS(SELECT DISTINCT [Year]
FROM Assessment WHERE ProjectCode = #ProjectCode AND [Year] = DATENAME(YEAR, GETDATE()))
SELECT DISTINCT [Year]
FROM Assessment WHERE ProjectCode = #ProjectCode
But, then I find some confusion in ordering the results. I'd like to set the current year to the first row returned using the ORDER BY clause, then order the rest of the returned years in a descending order, here's what I have so far:
ORDER BY (CASE WHEN [Year] = (DATENAME(YEAR, GETDATE())) THEN 1
ELSE 100 END) ASC, [Year] desc
Next, if the current year is not contained in the query, select each year and order by year descending.
ELSE
SELECT DISTINCT [Year]
FROM Assessment WHERE ProjectCode = #ProjectCode
ORDER BY [Year] desc
Thanks, in advance!
You don't need conditional statements here at all:
SELECT *
FROM (
SELECT DISTINCT [Year]
FROM Assessment
WHERE projectCode = #projectCode
) q
ORDER BY
CASE [Year] WHEN YEAR(GETDATE()) THEN 1 ELSE 2 END,
[Year]
will output the current year (if exists) first, the other later.
You're question isn't very clear because you don't specify what is broken or where you're having issues. From what I gather, however, you don't need an IF/ELSE. Instead you could do something like ...
SELECT DISTINCT [Year],
CASE [Year]
WHEN DATENAME(Year, GETDATE()) THEN 9999
ELSE [Year] END AS GarbageSoDistinctWorks
FROM Assessment
WHERE ProjectCode = #ProjectCode
ORDER BY
CASE [Year]
WHEN DATENAME(Year, GETDATE()) THEN 9999
ELSE [Year] END DESC
FYI ... i added the case to the select list as a throw away column to avoid the error I assume you're getting.. There are other ways, like a derived table, but for now this should work..
Msg 145, Level 15, State 1, Line 2
ORDER BY items must appear in the select list if SELECT DISTINCT is specified.
HTH,
-eric
Your example code appears to do what you describe. What problems are you having?
As a side note: You don't need the IF statement. By using the ORDER BY from your first example (with the CASE statement), you will get the correct results for both scenarios.
- If "this year" is in your data, it comes first. Everything else comes next in DESC order
- If "this year" isn't in your data, you just get everything else in DESC order
Related
I am writing a SQL query using with as expression. I always get a result in the square of what I required.
This is my query:
DECLARE #MAX_DATE AS INT
SET #MAX_DATE = (SELECT DATEPART(MONTH,FECHA) FROM ALBVENTACAB WHERE NUMALBARAN IN (SELECT DISTINCT MAX(NUMALBARAN) FROM ALBVENTACAB));
;WITH TABLE_LAST AS (
SELECT CONCAT(DATEPART(MONTH,FECHA),'-',DATEPART(YEAR,FECHA)) as LAST_YEAR_MONTH
,SUM(TOTALNETO) AS LAST_YEAR_VALUE
FROM ALBVENTACAB
WHERE DATEPART(YEAR,CURRENT_TIMESTAMP) -1 = DATEPART(YEAR,FECHA) AND NUMSERIE LIKE 'A%'
AND DATEPART(MONTH,FECHA) <= #MAX_DATE
GROUP BY CONCAT(DATEPART(MONTH,FECHA),'-',DATEPART(YEAR,FECHA))
)
,TABLE_CURRENT AS(
SELECT CONCAT(DATEPART(MONTH,FECHA),'-',DATEPART(YEAR,FECHA)) as CURR_YEAR_MONTH
,SUM(TOTALNETO) AS CURR_YEAR_VALUE
FROM ALBVENTACAB
WHERE DATEPART(YEAR,CURRENT_TIMESTAMP) <= DATEPART(YEAR,FECHA) AND NUMSERIE LIKE 'A%'
GROUP BY CONCAT(DATEPART(MONTH,FECHA),'-',DATEPART(YEAR,FECHA))
)
SELECT *
FROM TABLE_CURRENT, TABLE_LAST
When I run the query I get exactly the square of the result.
I want to compare sale monthly with last year.
2-2020 814053.3 2-2019 840295.1
1-2020 1094993.65 2-2019 840295.1
3-2020 293927.3 2-2019 840295.1
2-2020 814053.3 1-2019 1050701.68
1-2020 1094993.65 1-2019 1050701.68
3-2020 293927.3 1-2019 1050701.68
2-2020 814053.3 3-2019 887776.1
1-2020 1094993.65 3-2019 887776.1
3-2020 293927.3 3-2019 887776.1
I should get only 3 rows instead of 9 rows.
You need to properly join your two CTE - the way you're doing it now, you're getting a Cartesian product of each row in either CTE together.
Do something like:
*;WITH TABLE_LAST AS
( ....
),
TABLE_CURRENT AS
( ....
)
SELECT *
FROM TABLE_CURRENT curr
INNER JOIN TABLE_LAST last ON (some join condition here)
What that join condition is going to be - I have no idea, and cannot tell from your question - but you have to define how these two sets of data "connect" ....
It could be something like:
SELECT *
FROM TABLE_CURRENT curr
INNER JOIN TABLE_LAST last ON curr.CURR_YEAR_MONTH = last.LAST_YEAR_MONT
or whatever else makes sense in your situation - but basically, you need to somehow "tie together" these two sets of data and get only those rows that make sense - not just every row from "last" combined with every row from "curr" ....
While you already got the answer on how to join the two results, I thought I'd tell you how to typically approach such problems.
From the same table, you want two sums on different conditions (different years that is). You solve this with conditional aggregation, which does just that: aggregate (sum) based on a condition (year).
select
datepart(month, fecha) as month,
sum(case when datepart(year, fecha) = datepart(year, getdate()) then totalneto end) as this_year,
sum(case when datepart(year, fecha) = datepart(year, getdate()) -1 then totalneto end) as last_year
from albventacab
where numserie like 'A%'
and fecha > dateadd(year, -2, getdate())
group by datepart(month, fecha)
order by datepart(month, fecha);
I want to put a condition if [2015] and [2016] are NULL then hide row,
but I cant pull it off.
I don't have interest in the billname if it doesn't have data.
SELECT
IssuedByUserGroup,
BILLNAME,
SUM([2016]) AS [2016],
SUM([2015])AS [2015]
FROM Sum_Orders
PIVOT
(
SUM(Sum_SellPrice)
FOR OrderperiodYear IN ([2016],[2015])
) AS pvt
WHERE ( (MONTH(OrderDate) = MONTH(GETDATE())
AND day(OrderDate) <= DAY(GETDATE())) OR MONTH(OrderDate) < MONTH(GETDATE()))
--This part above is just for getting the data since january 1 to sep 23(to the date)
AND OrderStatus in ('Complete','invoiced')
AND OrderPrefix IN ('LAX6')
GROUP BY BILLNAME,IssuedByUserGroup
ORDER BY IssuedByUserGroup desc
This is returning the following as expected:
Thank you !
Add COALESCE under GROUP BY part:
HAVING COALESCE(SUM([2016]), SUM([2015])) IS NOT NULL
You should be able to use a WHERE clause below the PIVOT, something like this:
WHERE [2015] IS NOT NULL
I have the below query that was created to show the summation of the "Last" values for a year, usually this is a december value, but the year could potentially end in any month so i want to add together the last values for each goalmontecarloheaderid. I have it working 99%, but there are some random duplicates in the [year] value.
WITH endBalances AS (
SELECT ROW_NUMBER() OVER (PARTITION By GoalMonteCarloHeaderID, Year(Convert(date,MonthDate)) Order By Max(Month(Convert(date,MonthDate))) desc) n, Max(Month(Convert(date,MonthDate))) maxMonth, GrowthBucket, WithdrawalBucket, NoTaxesBucket,
Year(MonthDate) [year]
From GoalMonteCarloMedianResults mcmr
full join GoalMonteCarloHeader mch on mch.ID = mcmr.GoalMonteCarloHeaderID
full join GoalChartData gcd on gcd.ID = mch.GoalChartDataID and gcd.TypeID = 2
inner join Goal g on g.iGoalID = gcd.GoalID
where g.iTypeID in (1) and g.iHHID = 850802
group by GoalMonteCarloHeaderID, MonthDate, GrowthBucket, WithdrawalBucket, NoTaxesBucket
)
SELECT [year], Sum(GrowthBucket) GrowthBucket, Sum(WithdrawalBucket) WithdrawalBucket,Sum(NoTaxesBucket) NoTaxesBucket, maxMonth
From endBalances
where [year] is not null and n=1
Group By [year], maxMonth
order by [year] asc
Showing two random duplicates in the database result;
you can see in the image there are two examples where the year is duplicated and displayed for more than just the 'last' month in the year. Am I doing something wrong with the group by or the PARTITION BY() in my query? I am not the most familiar with this functionality of T-SQL.
T-SQL has a lovely function for this which has no direct equivalent in MySQL.
ROW_NUMBER() OVER (PARTITION BY [year] ORDER BY MonthDate DESC) AS rn
Then anything with rn=1 will be the last entry in a year.
The answers to this question have a few ideas:
ROW_NUMBER() in MySQL
I'm attempting to write a query that will return any customer that has multiple work orders with these work orders falling on different days of the week. Every work order for each customer should be falling on the same day of the week so I want to know where this is not the case so I can fix it.
The name of the table is Core.WorkOrder, and it contains a column called CustomerId that specifies which customer each work order belongs to. There is a column called TimeWindowStart that can be used to see which day each work order falls on (I'm using DATENAME(weekday, TimeWindowStart) to do so).
Any ideas how to write this query? I'm stuck here.
Thanks!
Select ...
From WorkOrder As W
Where Exists (
Select 1
From WorkOrder As W1
And W1.CustomerId = W.CustomerId
And DatePart( dw, W1.TimeWindowStart ) <> DatePart( dw, W.TimeWindowStart )
)
SELECT *
FROM (
SELECT *,
COUNT(dp) OVER (PARTITION BY CustomerID) AS cnt
FROM (
SELECT DISTINCT CustomerID, DATEPART(dw, TimeWindowStart) AS dp
FROM workOrder
) q
) q
WHERE cnt >= 2
SELECT CustomerId,
MIN(DATENAME(weekday, TimeWindowStart)),
MAX(DATENAME(weekday, TimeWindowStart))
FROM Core.WorkOrder
GROUP BY CustomerId
HAVING MIN(DATENAME(weekday, TimeWindowStart)) != MAX(DATENAME(weekday, TimeWindowStart))
I have the following table schema in acess (2007).
Date eventDate bit(boolean) lunch,
bit(boolean) snacks, bit(boolean) Tea,
I would like to have a single query that gives count of luch, snacks and tea (each as a column) for a given month (using the eventdate).
Thanks for help.
In Access, True is -1 and False is 0. So you can use the absolute value of the sum of those values to indicate how many were True.
SELECT Abs(Sum(lunch)) AS SumofLunch, Abs(Sum(snacks)) AS SumofSnacks, Abs(Sum(Tea)) AS SumofTea
FROM YourTable
WHERE eventDate >= #2009/08/01# And eventDate < #2009/09/01#;
Try:
SELECT SUM(ABS(lunch)) AS lunchCount, SUM(ABS(snacks)) AS snackCount, SUM(ABS(tea)) AS teaCount
FROM <TableName>
WHERE eventDate >= #1/1/2009# AND eventDate < #2/1/2009#
I'd attack this in access using IIF statements (think like CASE statements in other databases). IIF in Access returns a value when the specified condition is true (after the first comma) or another value if it evaluates to false (after the second comma). Because you are using booleans, checking for a true condition and rolling up via an aggregate sum will do the trick for you.
SELECT Month(EventDate) AS TheMonth, Year(EventDate) AS TheYear,
SUM(IIF(Lunch, 1, 0)) AS LunchCount,
SUM(IIF(Snacks, 1, 0)) AS SnackCount,
SUM(IIF(Tea, 1, 0)) AS TeaCount
FROM YourTable
GROUP BY Month(EventDate), Year(EventDate)
ORDER BY Month(EventDate), Year(EventDate)
The above query of course returns counts for all months and years however you could easily key in on a date range like below if need be.
SELECT Month(EventDate) AS TheMonth, Year(EventDate) AS TheYear,
SUM(IIF(Lunch, 1, 0)) AS LunchCount,
SUM(IIF(Snacks, 1, 0)) AS SnackCount,
SUM(IIF(Tea, 1, 0)) AS TeaCount
FROM YourTable
WHERE EventDate BETWEEN #1/1/2009# AND #1/31/2009#
GROUP BY Month(EventDate), Year(EventDate)
ORDER BY Month(EventDate), Year(EventDate)