How to "do something" for each input text files - awk

Question

Say that I read in the following information stored in three diffrent text files (Can be many more)
File 1
1 2 rt 45
2 3 er 44
File 2
rf r 4 5
3 er 4 t
er t yu 4
File 3
er tyu 3er 3r
der 4r 5e
edr rty tyu 4r
edr 5t yt5 45
When I read in this information I want it to print this information from these two files into separate arrays as for now they are printed out in the same time
Now I Have this script printing out all information at the same time
{
TESTd[NR-1] = $2; g++
}
END {
for (i = 0 ; i <= g-1; i ++ ) {
print " [\"" TESTd[i] "\"]"
}
print " _____"
}
But is there a way to read in multiple files and do this for every text file?
Like instead of getting this output when doing awk -f test.awk 1.txt 2.txt 3.txt
["2"]
["3"]
["r"]
["er"]
["t"]
["tyu"]
["4r"]
["rty"]
["5t"]
_____
I get this output
["2"]
["3"]
_____
["r"]
["er"]
["t"]
_____
["tyu"]
["4r"]
["rty"]
["5t"]
_____
And reading in each file at the time is preferably not an option here since I will have like 30 text files.
EDIT________________________________________________________________
I want to do this in awk if possible because I'm going to do something like this
{
PRINTONCE[NR-1] = $2; g++
PRINTONEATTIME[NR-1] = $3
}
END {
#Do this for all arguments once
for (i = 0 ; i <= g-1; i ++ ) {
print " [\"" PRINTONCE[i] "\"] \n"
}
print " _____"
#Do this for loop for every .txt file that is read in as an argument
#for(j=0;j<args.length;j++){
for (i = 0 ; i <= g-1; i ++ ) {
print " [\"" PRINTONEATTIME[i] "\"] \n"
}
print " _____"
}

Answer 1

From what i understand, you have an awk script that works and you want to run that awk script on many files and want their output to have a new line(or _) in between so you can distinguish which output is from which file.
Try this bash script :-
dir=~/*.txt #all txt files in ~(home) directory
for f in $dir
do
echo "File is $f"
awk 'BEGIN{print "Hello"}' $f #your awk code will take $f file as input.
echo "------------------"; echo;
done
Also, if you do not want to do this to all files you can write the for loop as for f in 1.txt 2.txt 3.txt.

Answer 2

If you don't want to do it in awk directly. You can call it like this in bash or zsh for example:
for fic in test*.txt; awk -f test.awk $fic

Answer 3

It's quite simple to do it directly in awk:
# define a function to print out the array
function dump(array, n) {
for (i = 0 ; i <= n-1; i ++ ) {
print " [\"" array[i] "\"]"
}
print " _____"
}
# dump and reset when starting a new file
FNR==1 && NR!=1 {
dump(TESTd, g)
delete TESTd
g = 0
}
# add data to the array
{
TESTd[FNR-1] = $2; g++
}
# dump at the end
END {
dump(TESTd, g)
}
N.B. using delete TESTd is a non-standard gawk feature, but the question is tagged as gawk so I assumed it's OK to use it.
Alternatively you could use one or more of ARGIND, ARGV, ARGC or FILENAME to distinguish the different files.
Or as suggested by see https://stackoverflow.com/a/10691259/981959, with gawk 4 you can use an ENDFILE group instead of END in your original:
{
TESTd[FNR-1] = $2; g++
}
ENDFILE {
for (i = 0 ; i <= g-1; i ++ ) {
print " [\"" TESTd[i] "\"]"
}
print " _____"
delete TESTd
g = 0
}

Answer 4

Write a bash shell script or a basic shell script. Try to put below into test.sh. Then call /bin/sh test.sh or /bin/bash test.sh, see which one will work
for f in *.txt
do
echo "File is $f"
awk -F '\t' 'blah blah' $f >> output.txt
done
Or write a bash shell script to call your awk script
for f in *.txt
do
echo "File is $f"
/bin/sh yourscript.sh
done