How would I show something in SQL where the date is greater than the current date?
I want to pull out data that shows everything greater from today (now) for the next coming 90 days.
I was thinking =< {fn NOW()} but that doesnt seem to work in my sql view here.
How can this be done?
SELECT *
FROM MyTable
WHERE CreatedDate >= getdate()
AND CreatedDate <= dateadd(day, 90, getdate())
http://msdn.microsoft.com/en-us/library/ms186819.aspx
Assuming you have a field for DateTime, you could have your query look like this:
SELECT *
FROM TABLE
WHERE DateTime > (GetDate() + 90)
In sql server, you can do
SELECT *
FROM table t
WHERE t.date > DATEADD(dd,90,now())
For those that want a nice conditional:
DECLARE #MyDate DATETIME = 'some date in future' --example DateAdd(day,5,GetDate())
IF #MyDate < DATEADD(DAY,1,GETDATE())
BEGIN
PRINT 'Date NOT greater than today...'
END
ELSE
BEGIN
PRINT 'Date greater than today...'
END
For SQL Server
select *
from YourTable
where DateCol between getdate() and dateadd(d, 90, getdate())
Select * from table where date > 'Today's date(mm/dd/yyyy)'
You can also add time in the single quotes(00:00:00AM)
For example:
Select * from Receipts where Sales_date > '08/28/2014 11:59:59PM'
If you're using SQL Server it would be something like this:
DATEDIFF(d,GETDATE(),FUTUREDATE) BETWEEN 0 AND 90
Related
I have a question which I'm not sure if possible or not but let's say I have a table with Employeeid, Date and AttendanceStatus i.e "Present"/"Absent".
I can get the status of all employees for all dates or for dates I specify in the query.
My question is that is it possible to get today's date by default so whenever I run the query it give me the data rows for today's instead of all the records from the database. I want to use default so that I don't have to change the date everyday.
Thanks in advance
Try this:
select * from TABLE_NAME where
where cast([Date] as date) = cast(getdate() as date)
Also, as already mentioned, you could create a view:
create view V_TABLE_NAME as
select * from TABLE_NAME where
where cast([Date] as date) = cast(getdate() as date)
You can apply where clause for current day;
select * from table where
Date > cast(getdate() as date) and
Date < DATEADD(day,1,cast(getdate() as date))
Or you can create a view;
create view v_table
as
select * from table where
Date > cast(getdate() as date) and
Date < dateadd(day,1,cast(getdate() as date))
Then query;
select * from v_table
Try This Logic
DECLARE #MyDate DATE
SELECT
*
FROM YourTable
WHERE DateField = ISNULL(#MyDate,GETDATE())
Here, If You are not passing any values in the Parameter #MyDate, it will take Current Date as Default. The following can also be used
DECLARE #MyDate DATE
SELECT
*
FROM YourTable
WHERE
DateField = CASE WHEN ISDATE(#MyDate) = 1 THEN #MyDate ELSE GETDATE() END
I need to find anniversary date and anniversary year of employees and send email in every 14 days.But I have a problem with last week of December when using the following query if start date and end date are in different years.
Select * from Resource
where (DATEPART(dayofyear,JoinDate)
BETWEEN DATEPART(dayofyear,GETDATE())
AND DATEPART(dayofyear,DateAdd(DAY,14,GETDATE())))
Instead of comparing to a dayofyear (which resets to zero at jan 1st and is the reason your query breaks within 14 days of the end of the year) you could update the employee's joindate to be the current year for the purpose of the query and just compare to actual dates
Select * from Resource
-- Add the number of years difference between joinDate and the current year
where DATEADD(year,DATEDIFF(Year,joinDate,GetDate()),JoinDate)
-- compare to range "today"
BETWEEN GetDate()
-- to 14 days from today
AND DATEADD(Day,14,GetDate())
-- duplicate for following year
OR DATEADD(year,DATEDIFF(Year,joinDate,GetDate())+1,JoinDate) -- 2016-1-1
BETWEEN GetDate()
AND DATEADD(Day,14,GetDate())
Test query:
declare #joindate DATETIME='2012-1-1'
declare #today DATETIME = '2015-12-26'
SELECT #joinDate
where DATEADD(year,DATEDIFF(Year,#joinDate,#today),#JoinDate) -- 2015-1-1
BETWEEN #today -- 2015-12-26
AND DATEADD(Day,14,#today) -- 2016-01-09
OR DATEADD(year,DATEDIFF(Year,#joinDate,#today)+1,#JoinDate) -- 2016-1-1
BETWEEN #today -- 2015-12-26
AND DATEADD(Day,14,#today) -- 2016-01-09
(H/T #Damien_The_Unbeliever for a simple fix)
The above correctly selects the joinDate which is in the first week of Jan (note I've had to fudge #today as Ive not managed to invent time travel).
The above solution should also solve the issue with leap years that was hiding in your original solution.
Update
You expressed in comments the requirement to select AnniversaryDate and Years of service, you need to apply some CASE logic to determine whether to add 1 (year or date) to your select
select *,
CASE
WHEN DATEADD(YEAR,DATEDIFF(Year,JoinDate,GETDATE()),JoinDate) < GetDate()
THEN DATEDIFF(Year,JoinDate,GETDATE())+1
ELSE DATEDIFF(Year,JoinDate,GETDATE())
END as [Years],
CASE WHEN DATEADD(YEAR,DATEDIFF(Year,JoinDate,GETDATE()),JoinDate) < GetDate()
THEN DATEADD(YEAR,DATEDIFF(Year,JoinDate,GETDATE())+1,JoinDate)
ELSE DATEADD(YEAR,DATEDIFF(Year,JoinDate,GETDATE()),JoinDate)
end as [AnniversaryDate]
.... // etc
You could do this:
Select * from Resource
where DATEPART(dayofyear,JoinDate)
BETWEEN DATEPART(dayofyear,GETDATE())
AND DATEPART(dayofyear,DateAdd(DAY,14,GETDATE()))
OR
DATEPART(dayofyear,JoinDate)
BETWEEN (DATEPART(dayofyear,GETDATE()) + 365)
AND (DATEPART(dayofyear,DateAdd(DAY,14,GETDATE())) + 365)
Try this:
DECLARE #Today DATE = GETDATE() --'12/25/2013'
DECLARE #Duration INT = 14
;WITH Recur AS
(
SELECT #Today AS RecurDate
UNION ALL
SELECT DATEADD(DAY, 1, RecurDate)
FROM Recur
WHERE DATEDIFF(DAY, #Today, RecurDate)+1 < #Duration
)
SELECT
r.*
FROM
Resource r
JOIN Recur
ON CONVERT(VARCHAR(5), JoinDate, 101) = CONVERT(VARCHAR(5), RecurDate, 101)
WHERE JoinDate < #Today
You can use the SQL DATEADD() function with week number parameter
Here is how you can use it:
DECLARE #date date = getdate()
Select * from Resource
where
JoinDate BETWEEN #date AND DATEADD(ww,2,#date)
I'm looking to do something similar to Simple DateTime sql query but with a difference: I want to specify the time (7.00 am) on today's date.
I want to count the number of records that match the criteria at that time:
SELECT COUNT(SEQNO)
FROM TABLE
WHERE [CRITERIA]
and [datetimecolumn] between (datetime=[today's date]at 7.00am)
and (datetime=[today's date]at 10.00am)
I can do it with date alone, but the time bit has me confused.
try this
Declare #i date=getdate()
Declare #j varchar(10)='07:00'
Declare #k varchar(10)= '10:00:00'
select COALESCE(COUNT(DISTINCT SOH.SEQNO),0) from dbo.SALESORD_HDR SOH
inner join SALESORDHIST SOHIS on SOH.SEQNO = SOHIS.HEADER_SOURCE_SEQ
where SOHIS.HISTDATETIME between ( DATEADD(day, DATEDIFF(day, 0, #i), #j)
and DATEADD(day, DATEDIFF(day, 0, #i), #k))
and SOHIS.EVENT_TYPE = 'I'
Not sure if this will help you as I assume 7am and 10am would remain the same as it is.
============================================
BETWEEN syntax should be something like this
mysql> SELECT * FROM employee_tbl
-> WHERE daily_typing_pages BETWEEN 170 AND 300;
Credited to this site
So your code should be: (Please include the brackets for the datetimecolumn)
and ([datetimecolumn] between CONCAT( CURDATE(), " 07:00:00" )
and CONCAT( CURDATE() , " 10:00:00" )
Well this is my case: I have an input date X (dd-mm-yyyy), and I want to count the number of days between it with the year part is changed into current year and today's date in SQL. I t comes with the following condition, after the year is changed temporarily: (Here's my current idea of the logic)
- If date X is earlier than today, then difference = datediff(X,now), with the X year is current year
- If date X is later than today, then difference = datediff(X,now), with the X year is one year before
Sample case:
1st case: The input date is 6-6-1990. Today (automatically generated) is 22-8-2011. Then the difference will be = datediff(6-6-2011,22-08-2011)
2nd case: The input date is 10-10-1990. Today (automatically generated) is 22-8-2011. Then the difference will be = datediff(10-10-2010,22-08-2011)
Any idea how to do this in SQL (in SQL Server)? Or is there any other more simple alternatives for this problem? I'd also like this to be done in the query and not using a stored procedure or function
Sorry if there's already a similar question, I just don't know the exact keyword for this problem :( if there's a question like this previously, feel free to direct me there.
Thanks in advance
Here is the implementation (if I understood the logic you need correctly):
USE YourDbName
GO
CREATE FUNCTION YearPartDiff (#date datetime)
RETURNS int
AS
BEGIN
DECLARE #dateCurrentYear datetime
SET #dateCurrentYear = DATEADD(year, YEAR(GETDATE()) - YEAR(#date), #date)
DECLARE #result int
IF #dateCurrentYear < GETDATE()
SET #result = ABS(DATEDIFF(day, #dateCurrentYear, GETDATE()))
ELSE
SET #result = ABS(DATEDIFF(day, DATEADD(year, -1, #dateCurrentYear), GETDATE()))
RETURN(#result)
END
GO
And the example of usage:
USE YourDbName
GO
DECLARE #someDate datetime
SET #someDate = '2011-06-06'
SELECT dbo.YearPartDiff(#someDate) /*returns 77*/
SET #someDate = '2010-10-10'
SELECT dbo.YearPartDiff(#someDate) /*returns 316*/
Basically, #Andrei's solution, but in a single statement:
SELECT
DayDiff = DATEDIFF(
DAY,
DATEADD(YEAR, CASE WHEN LastOcc > GETDATE() THEN -1 ELSE 0 END, LastOcc),
GETDATE()
)
FROM (
SELECT LastOcc = DATEADD(YEAR, YEAR(GETDATE()) - YEAR(#InputDate), #InputDate)
) s
This seems to do the job
SELECT DATEDIFF(DAY, CONVERT(DATETIME, N'2011-06-06'), CONVERT(DATETIME, N'2011-08-22'))
So the basic syntax is
SELECT DATEDIFF(DAY, CONVERT(DATETIME, N'yyyy-mm-dd'), CONVERT(DATETIME, N'yyyy-mm-dd '))
Alternatively, you can use GETDATE() instead of the string for today's date
I have used "SELECT DATEDIFF( D, "+myDate+", GETDATE())" in my code, on SQL Server 2005. It works for me. The value myDate of course would be the DateTime input value.
you should try this query:
create table #T (inp_date datetime)
insert #T values ('06-06-1990')
insert #T values ('08-22-1990')
insert #T values ('10-10-1990')
--select * from #T
select inp_date, GETDATE(),
CASE
WHEN DATEADD(yy,DATEDIFF(yy,inp_date,GETDATE()),inp_date) <= GETDATE()
THEN DATEDIFF(dd,DATEADD(yy,DATEDIFF(yy,inp_date,GETDATE()),inp_date),GETDATE())
ELSE DATEDIFF(dd,DATEADD(yy,DATEDIFF(yy,inp_date,GETDATE())-1,inp_date),GETDATE())
END
from #T
How do you get the 30 days before today in SQL.
T-SQL
declare #thirtydaysago datetime
declare #now datetime
set #now = getdate()
set #thirtydaysago = dateadd(day,-30,#now)
select #now, #thirtydaysago
or more simply
select dateadd(day, -30, getdate())
(DATEADD on BOL/MSDN)
MYSQL
SELECT DATE_ADD(NOW(), INTERVAL -30 DAY)
( more DATE_ADD examples on ElectricToolbox.com)
In MS SQL Server, it is:
SELECT getdate() - 30;
SELECT (column name) FROM (table name) WHERE (column name) < DATEADD(Day,-30,GETDATE());
Example.
SELECT `name`, `phone`, `product` FROM `tbmMember` WHERE `dateofServicw` < (Day,-30,GETDATE());
Try adding this to your where clause:
dateadd(day, -30, getdate())