I have a simple RCP application. I have a perspective and three views added to it. Initially one of the view will be disabled for the users. There is a toolbar item which launches a dialog. User authenticates himself in the dialog. After successful authentication, I want to make the view editable. I could get the reference of that specific view in my dialog.But I dont know how to enable it. I could not use selection listener as I am not selecting anything. Also I saw an example about using activities extension. But that opens/closes the view and not just enable/disable it. Can someone help me? Thanks.
As I understand you, you want to show the view in one of two states: either disabled if the user is not authenticated, or enabled when the user has been authenticated.
This is actually pretty easy :-) and I have made a small example application for you that illustrates the technique: so-edi.zip
UPDATED with new link
In RCP 3.x you have to expose the View's Control's enabled state in your implementation of ViewPart:
import org.eclipse.swt.widgets.Composite;
import org.eclipse.swt.widgets.Control;
import org.eclipse.ui.part.ViewPart;
public class View extends ViewPart {
private Control control;
#Override
public void createPartControl(Composite parent) {
control = new Composite(parent, SWT.NONE);
}
#Override
public void setFocus() {
}
public void setEnabled(boolean enabled) {
control.setEnabled(enabled);
}
public boolean isEnabled() {
return control.getEnabled()
}
}
Related
I have a web application project with MVC 4 and I use Telerik panel bar and bind it by site map for my menu.but now i want to each user according to user access roles in my program see particular items of menu and hide remind menu items . how can i do this work in MVC any tips or trick would be welcome
this is link of Telerik website that i use it for creating my menu just i use it in partial view and just render its action in my layout razor code
Assume you have this global class :
public class AccessControlList{
public static bool IsAdmin {
get{
//put your code here
return false;
}
}
public static bool HasOpenFileAccess{
get{
//put your code here
return true;
}
}
}
then in your view.cshtml you may have something like this :
#(Html.Telerik().Menu()
.Name("mnuMain")
.Items(itemAdder =>
{
itemAdder.Add()
.Text("Admin Menu")
.Visible(false)
.Url("~/Home")
.Visible(AccessControlList.IsAdmin);
itemAdder.Add()
.Text("Files")
.Items(subItemAdder =>
{
subItemAdder.Add()
.Text("Open File...")
.Url("~/Files/Open")
.Visible(AccessControlList.HasOpenFileAccess)
....
complete your AccessControlList class (AccessControlList.cs file) to check if the authenticated person has your required access or not.
I'm writing an Eclipse plugin, I want to create a wizard for my new project type. I created pages by classes extends org.eclipse.jface.wizard.WizardPage. My requirement is, based on some condition in one page, I need to go back to previous page without pressing back button on page(programmatically).
Is it possible?
Thanks a million in advance!
I don't think this is a good idea. The user will be confused by doing this. I would disable the finish and the next button and give an error, telling the user that he has to go back to the first page.
If you want to reuse some UI from the first page, define the UI as a new class and reuse it.
I implemented something similar using the WizardDialog:showPage() method:
MyWizard.java
public void createPageControls(Composite pageContainer) {
// TODO Auto-generated method stub
super.createPageControls(pageContainer);
wizardDialog = (WizardDialog) getContainer();
}
public void skipProcessPage() {
wizardDialog.showPage(workPage == arisDbPage ? focusPage : arisDbPage);
}
public void setWorkPage(IWizardPage workPage) {
this.workPage = workPage;
}
here the processPage does the lengthy db lookup!
HTH thomas
I am trying to control when a new view is created and when an existing view is shown.
This is a very similar scenario as outlined in the "Navigating to Existing Views" section in the Prism documentation, but I can't get it to work fully:
http://msdn.microsoft.com/en-us/library/gg430861(v=pandp.40).aspx
I am finding I can create the view/view model to begin with ok, but I am then unable to create a new instance of it. I.e. I want more than one instance to exist at once.
Here's an example of the view model:
[Export]
[PartCreationPolicy(CreationPolicy.NonShared)]
public class DataEntryPageViewModel : INavigationAware, IRegionMemberLifetime
{
private Guid id;
[ImportingConstructor]
public DataEntryPageViewModel()
{
id = Guid.NewGuid();
}
public bool IsNavigationTarget(NavigationContext navigationContext)
{
// In actual fact there would be more logic here to determine
// whether this should be shown to the user
return false;
}
public void OnNavigatedFrom(NavigationContext navigationContext)
{
}
public void OnNavigatedTo(NavigationContext navigationContext)
{
}
public bool KeepAlive
{
// For the purposes of this example we don't want the view or the viewModel
// to be disposed of.
get { return true; }
}
}
I am navigating to this as follows:
m_RegionManager.RequestNavigate(
"MainRegion",
new Uri("/DataEntryPageView", UriKind.Relative));
So the first time I call the above the view is shown.
The next time I call RequestNavigate the IsNavigationTarget is hit and it returns false. What I then want it to do is to create a new instance but that doesn't happen. I know it's not happening because the constructor does not get hit and the UI does not update to show the new instance of the view.
Any ideas how I can make it create a new instance?
Many thanks,
Paul
Edit
I have noticed that the second time I call RequestNavigate (to request another instance of the same view) the callback reports an error "View already exists in region." It therefore seems that I can have multiple instances of different views in a region, but not multiple instances of the same view. My understand of this isn't great though so I could be wrong.
Why are you not creating the view when you want a new one to be created? It looks to me like you are using MEF.
Use the container to resolve a new instance of your view
Add the new instance of the view to the MainRegion
Then call Navigate and handle the appropriate logic in IsNavigationTarget
You should use the [Export] attribute in your view with a contract name: [Export("DataEntryPageView")].
I have now been able to get this to work, it was because I didn't have
[PartCreationPolicy(CreationPolicy.NonShared)]
on the class declaration of the view. I had it on the ViewModel.
So this is now resulting in the behaviour I expected.
Thanks though to Zabavsky and Alan for your suggestions.
So let me put it this way.
I have a LogInViewModel and a LogInView. There is a Login() method in the ViewModel that gets called if the user clicks on a button in the View. Now I want the dashboard to show if the login was successful. How do I do this? I can't find a clear answer to this in the documentation.
I assume that your dashboard is essentially your shell. In which case, you can bootstrap your LoginViewModel and in the Login method, after a successful login, you can show the DashboardViewModel and close the LoginViewModel using the Caliburn.Micro WindowManager.
Something like (using MEF):
Bootstrapper.cs
public class Bootstrapper : Caliburn.Micro.Bootstrapper<ILoginViewModel>
{
...
}
LoginViewModel.cs
public class LoginViewModel : Screen, ILoginViewModel
{
private readonly IWindowManager windowManager;
private readonly IDashboardViewModel dashboardViewModel;
[ImportingConstructor]
public LoginViewModel(IWindowManager windowManager, IDashboardViewModel dashboardViewModel)
{
this.windowManager = windowManager;
this.dashboardViewModel = dashboardViewModel;
}
public void Login()
{
// if login success...
this.windowManager.ShowDialog(this.dashboardViewModel);
this.TryClose();
}
}
I've just added a very simple login example SL4 project in my "lab repository" for Caliburn.Micro.
https://github.com/jenspettersson/Caliburn.Micro.Labs/tree/master/src/Login
It uses the Show class that Rob Eisenberg uses in his "Game Library" example to switch between views.
In the Login() method, it tells my Shell (your dashboard?) to show my LoginResultViewModel and sets the login result message.
yield return Show.Child<LoginResultViewModel>().In<IShell>().Configured(c => c.ResultMessage = "Successfully logged in!");
Check the code in my github repo.
I havent used Caliburn.Micro very much lately, so I am by no means an expert, but this way works for me.
//J
Edit: This answers how to navigate between views, if you want to show a "popup" to display if the login was successful, go with the other recomendations.
I have an Eclipse plug-in with a checkbox in the plug-in's preference page.
This checkbox is used for enabling and disabling an editor, which is being launched from this plug-in.
However, the problem is, I would also like to be able to enable and disable this 'editor-launch' from another plug-in, by having actions which change the value of the checkbox in the above mentioned preference page.
Here's the problem, how do I access that local preference store from another plug-in?
I've tried things like..
View myView = (View) PlatformUI.getWorkbench().getActiveWorkbenchWindow().getActivePage().findView("ViewID");
But this 'myView' always seems to be null.. And also, what would I do with the view since it's the Plug-in I want.
Platform.getBundle('bundleName')...
Same here, want the Plugin, not the bundle corresponding to is.
No matter what I try nothing seems to work.
Does anyone have any ideas?
There are two ways of doing this:
Please refer to http://www.vogella.com/tutorials/EclipsePreferences/article.html#preferences_pluginaccess
Using .getPluginPreferences(). For example, there is a plugin class "com.xxx.TestPlugin" which extends org.eclipse.ui.plugin.AbstractUIPlugin.Plugin, in order to get access to the preferences of TestPlugin. The plugin code could be below:
public class TestPlugin extends AbstractUIPlugin {
private static TestPlugin plugin;
public static final String PREF_TEST = "test_preference";
/**
* The constructor.
*/
public TestPlugin() {
plugin = this;
}
/**
* This method is called upon plug-in activation
*/
public void start(BundleContext context) throws Exception {
super.start(context);
}
/**
* This method is called when the plug-in is stopped
*/
public void stop(BundleContext context) throws Exception {
super.stop(context);
plugin = null;
}
/**
* Returns the shared instance.
*/
public static TestPlugin getDefault() {
return plugin;
}
}
To access the preference of TestPlugin, the code could be:
TestPlugin.getDefault().getPluginPreferences().getDefaultBoolean(TestPlugin.PREF_TEST);
Or have a look at this answer: Writing Eclipse plugin to modify Editor Preferences
This thread recommend the use of a Service tracker:
ServiceTracker tracker = new ServiceTracker(ToolkitPlugin.getDefault().getBundle().getBundleContext(),
IProxyService.class.getName(), null);
tracker.open();
proxyService = (IProxyService) tracker.getService();
proxyService.addProxyChangeListener(this);
This may work.
Prefs stores are found per plugin. This is one way to get a prefs store for the plugin whose activator class is ActivatorA.
IPreferenceStore store = ActivatorA.getDefault().getPreferenceStore();
If you want another plugin to refer to the same store, perhaps you could expose some api on ActivatorA for it to get there, e.g.
public IPreferenceStore getSharedPrefs() {
return ActivatorA.getDefault().getPreferenceStore();
}
The second plugin would find the shared store by doing this
IPreferenceStore sharedPrefs = ActivatorA.getSharedPrefs();
Good luck.