How do I go about doing the following?
I am using the following query to get a specific users tab ids:
select id
from intranet.dbo.tabs
where cms_initials = #user
order by id asc
which might return the following ids
4
5
6
7
I now want to insert the rows from the following query:
select tabs_id, widgets_id, sort_column, sort_row
from intranet.dbo.columns c
inner join intranet.dbo.tabs t on c.tabs_id = t.id
where t.is_default = 1
But use the ids from the first query to replace the tab ids
so if the second query originally returns tabs_id's as
0
0
0
0
1
1
1
2
2
2
3
3
I should end up with
0
0
0
0
1
1
1
2
2
2
3
3
4
4
4
4
5
5
5
6
6
6
7
7
Is this possible with sql server 2005 without using stored procedures?
So far I have
insert into intranet.dbo.columns ( tabs_id, widgets_id, sort_column, sort_row )
select tabs_id, widgets_id, sort_column, sort_row
from intranet.dbo.columns c
inner join intranet.dbo.tabs t on c.tabs_id = t.id
where t.is_default = 1
But this just copies everything as is, I need to do that, but replace the ids in the copied rows.
This solution uses common table expressions and ranking functions. A and B are your original queries ranked by tab order. A and B are then joined by tab ranking and inserted.
USE intranet
;WITH A AS
(
SELECT ROW_NUMBER() OVER (ORDER BY id) AS tab_ranking
, id
FROM dbo.tabs
WHERE cms_initials = #user
),
B AS
(
SELECT DENSE_RANK() OVER (ORDER BY tabs_id) AS tab_sequence
, tabs_id, widgets_id, sort_column, sort_row
FROM dbo.columns
WHERE tabs_id IN (SELECT t.id FROM dbo.tabs t WHERE t.is_default = 1)
)
INSERT INTO dbo.columns (tabs_id, widgets_id, sort_column, sort_row)
SELECT a.id, b.widgets_id, b.sort_column, b.sort_row
FROM A
INNER JOIN B ON B.tab_ranking = A.tab_ranking
Related
The table to find which rows contains same value on two different columns for 2 rows. Here is a small sample rows among 2k+ rows.
id left right
1 3 4
2 4 1
3 1 9
4 2 6
5 2 5
6 9 8
7 0 7
In the above case, I need to get row 1,2,3,6 as it contains 4 on two rows of two different columns i.e (id=1&2),1 on two rows of two different columns(id=1&3) and 9 on two rows of two different columns(id=3&6)
My thoughts:
I did thought many things for example cross join on left and right column, group by and count etc.
with Final as (With OuterTable as (WITH Alias AS (SELECT id as left_id , left FROM Test)
SELECT DISTINCT id, left_id FROM Alias
INNER JOIN Test ON Alias.left = Test.right)
SELECT id from OuterTable
UNION ALL
SELECT left_id from OuterTable)
SELECT DISTINCT * from Final;
It's messy, but it works.
You can do it with EXISTS:
SELECT t1.*
FROM tablename t1
WHERE EXISTS (
SELECT 1 FROM tablename t2
WHERE t1.id <> t2.id AND (t2.left = t1.right OR t1.left = t2.right)
)
See the demo.
Results:
id
left
right
1
3
4
2
4
1
3
1
9
6
9
8
I have a table that looks similar to this:
ID OLD NEW TIME
1 a b 5
1 b c 7
1 c d 45
1 d e 4
2 a b 1
2 b d 8
2 d e 45
3 b c 15
3 c d 14
And I would like to build a report that looks like this (basically for each OLD data point grab the TIME value):
ID TimeForA TimeForB TimeForC TimeForD
1 5 7 45 4
2 1 8 NULL 45
3 NULL 15 14 NULL
I have been able to get all the data into the correct columns, but have not been able to combine each row into a single row for each ID. My current query looks like this (no I don't have every column in place yet, still just testing):
WITH CTE (id, ATime, BTime)
AS
(
select T1.oid, T1.loggedFor, null, T1.time as Atime
from Table1 T1
where T1.OLD = 'a'
union
select T1.oid, T1.loggedFor, T1.time as BTime, null
from Table1 T1
where T1.old = 'b'
)
select ID, ATime, BTime
from CTE
order by ID
Any help appreciated!
Try this:
select id,
sum(if(old = 'a',time,null)) as time_for_a,
sum(if(old = 'b',time,null)) as time_for_b,
sum(if(old = 'c',time,null)) as time_for_c,
sum(if(old = 'd',time,null)) as time_for_d
from test_tbl
group by id
order by id;
I have a table 'TempC3'
Itemset itemset2
1 3
2 3
2 5
3 5
I want combination of elements in these columns without repetition. So the output table shall be
Itemset itemset2 Itemset3
1 3 5
2 3 5
1 2 3
I designed a query but it wont return the last row of the desired output table -
Select distinct a.Itemset,
a. Itemset2,
c.itemset2
from TempC3 a
Join TempC3 c
ON c.Itemset2 > a.Itemset2
This query only results this:
Itemset itemset2 Itemset3
1 3 5
2 3 5
Since you want all combinations of itemsets, you have to concatenate the two columns in your input table into a single column first. You could do this, for example, using a CTE:
Fiddle Here
WITH CTE AS (
SELECT Itemset FROM TempC3
UNION
SELECT Itemset2 FROM TempC3
)
SELECT I1.Itemset, I2.Itemset, I3.Itemset FROM CTE AS I1
INNER JOIN CTE AS I2 ON I2.Itemset > I1.Itemset
INNER JOIN CTE AS I3 ON I3.Itemset > I2.Itemset
I have tables:
Category: Id, Name...
News: Id, Title
News_Category_Mapping: Id, NewsId, CategoryId
Where newsid, categoryid are foreign keys to these 2 tables.
News_category_mapping:
Id NewsID CategoryId
1 1 1
2 2 1
3 3 1
4 4 3
5 5 5
6 6 3
so i may want to get maximum 2 news items from every categoryid, say like
Id NewsID CategoryId
1 1 1
2 2 1
4 5 3
6 6 3
5 5 5
Sorry for my english.
Let say you need 2 items each
Select *
From Category C
CROSS APPLY (Select top 2 Id,CatId,NewsName
From News Nw where Nw.CatId=C.Id) As N
Here is the fiddle sample
Try this:
WITH CTE AS
(SELECT C.Id,N.Id,N.Title,RN=ROW_NUMBER() OVER (PARTITION BY NC.CategoryID ORDER BY NC.NewsId)
FROM News_Category_Mapping NC JOIN
News N ON NC.NewsId=N.Id JOIN
Category C ON NC.CategoryId=C.Id)
SELECT * FROM CTE WHERE RN<3
Explanation:
Here, the inner query selects the records along a row number RN. To know how the query works, please execute the inner query first.
You can use CROSS APPLY, like so:
Select c.*, Sub.*
from
Categories c cross apply
(
select top 2
*
from
News n
where
exists
(
select 1
from NewsCategories nc
where nc.CatId = c.id and n.id = nc.NewsId
)
) Sub
Here is an SQLFiddle for this
id Name claim priority
1 yatin 70 5
6 yatin 1 10
2 hiren 30 3
3 pankaj 40 2
4 kavin 50 1
5 jigo 10 4
7 jigo 1 10
this is my table and i want to arrange this table as shown below
id Name claim priority AlternateFlag
1 yatin 70 5 0
6 yatin 1 10 0
2 hiren 30 3 1
3 pankaj 40 2 0
4 kavin 50 1 1
5 jigo 10 4 0
7 jigo 1 10 0
It is sorted as alternate group of same row.
I am Using sql server 2005. Alternate flag starts with '0'. In my example First record with name "yatin" so set AlternateFlag as '0'.
Now second record has a same name as "yatin" so alternate flag would be '0'
Now Third record with name "hiren" is single record, so assign '1' to it
In short i want identify alternate group with same name...
Hope you understand my problem
Thanks in advance
Try
SELECT t.*, f.AlternateFlag
FROM tbl t
JOIN (
SELECT [name],
AlternateFlag = ~CAST(ROW_NUMBER() OVER(ORDER BY MIN(ID)) % 2 AS BIT)
FROM tbl
GROUP BY name
) f ON f.name = t.name
demo
You could use probably an aggregate function COUNT() and then HAVING() and then UNION both Table, like:
SELECT id, A.Name, Claim, Priority, 0 as AlternateFlag
FROM YourTable
INNER JOIN (
SELECT Name, COUNT(*) as NameCount
FROM YourTable
GROUP BY Name
HAVING COUNT(*) > 1 ) A
ON YourTable.Name = A.Name
UNION ALL
SELECT id, B.Name, Claim, Priority, 1 as AlternateFlag
FROM YourTable
INNER JOIN (
SELECT Name, COUNT(*) as NameCount
FROM YourTable
GROUP BY Name
HAVING COUNT(*) = 1 ) B
ON YourTable.Name = B.Name
Now, this assumes that the Names are unique meaning the names like Yatin for example although has two counts is only associated to one person.
See my SqlFiddle Demo
You can use Row_Number() function with OVER that will give you enumeration, than use the reminder of integer division it by 2 - so you'll get 1s and 0s in your SELECT or in the view.