Note: I would like to do this in a single SQL statement. not pl/sql, cursor loop, etc.
I have data that looks like this:
ID String
-- ------
01 2~3~1~4
02 0~3~4~6
03 1~4~5~1
I want to provide a report that somehow pivots the values of the String column into distinct rows such as:
Value "Total number in table"
----- -----------------------
1 3
2 1
3 2
4 3
5 1
6 1
How do I go about doing this? It's like a pivot table but I am trying to pivot the data in a column, rather than pivoting the columns in the table.
Note that in real application, I do not actually know what the values of the String column are; I only know that the separation between values is '~'
Given this test data:
CREATE TABLE tt (ID INTEGER, VALUE VARCHAR2(100));
INSERT INTO tt VALUES (1,'2~3~1~4');
INSERT INTO tt VALUES (2,'0~3~4~6');
INSERT INTO tt VALUES (3,'1~4~5~1');
This query:
SELECT VALUE, COUNT(*) "Total number in table"
FROM (SELECT tt.ID, SUBSTR(qq.value, sp, ep-sp) VALUE
FROM (SELECT id, value
, INSTR('~'||value, '~', 1, L) sp -- 1st posn of substr at this level
, INSTR(value||'~', '~', 1, L) ep -- posn of delimiter at this level
FROM tt JOIN (SELECT LEVEL L FROM dual CONNECT BY LEVEL < 20) q -- 20 is max #substrings
ON LENGTH(value)-LENGTH(REPLACE(value,'~'))+1 >= L
) qq JOIN tt on qq.id = tt.id)
GROUP BY VALUE
ORDER BY VALUE;
Results in:
VALUE Total number in table
---------- ---------------------
0 1
1 3
2 1
3 2
4 3
5 1
6 1
7 rows selected
SQL>
You can adjust the maximum number of items in your search string by adjusting the "LEVEL < 20" to "LEVEL < your_max_items".
Related
I have in my Oracle Responsys Database a table that contains records with amongst other two variables:
status
location_id
I want to count the number of records grouped by status and location_id, and display it as a pivot table.
This seems to be the exact example that appears here
But when I use the following request :
select * from
(select status,location_id from $a$ )
pivot (count(status)
for location_id in (0,1,2,3,4)
) order by status
The values that appear in the pivot table are just the column names :
output :
status 0 1 2 3 4
-1 0 1 2 3 4
1 0 1 2 3 4
2 0 1 2 3 4
3 0 1 2 3 4
4 0 1 2 3 4
5 0 1 2 3 4
I also gave a try to the following :
select * from
(select status,location_id , count(*) as nbreports
from $a$ group by status,location_id )
pivot (sum(nbreports)
for location in (0,1,2,3,4)
) order by status
but it gives me the same result.
select status,location_id , count(*) as nbreports
from $a$
group by status,location_id
will of course give me the values I want, but displaying them as a column and not as a pivot table
How can I get the pivot table to have in each cell the number of records with the status and location in row and column?
Example data:
CUSTOMER,STATUS,LOCATION_ID
1,-1,1
2,1,1
3,2,1
4,3,0
5,4,2
6,5,3
7,3,4
The table data types :
CUSTOMER Text Field (to 25 chars)
STATUS Text Field (to 25 chars)
LOCATION_ID Number Field
Please check if my understanding for your requirement is correct, you can do vice versa for the location column
create table test(
status varchar2(2),
location number
);
insert into test values('A',1);
insert into test values('A',2);
insert into test values('A',1);
insert into test values('B',1);
insert into test values('B',2);
select * from test;
select status,location,count(*)
from test
group by status,location;
select * from (
select status,location
from test
) pivot(count(*) for (status) in ('A' as STATUS_A,'B' as STATUS_B))
I have a table with an numeric column. There are data records, lets take for Example { 1,7, 10, 11, 12, 19, 20}. I want to use SQL to get the next "free" number from a specific x:
>8 for x=7
>8 for x=8
>13 for x=10
>21 for x=20
Does anybody have an idea?
OK: I want to insert something with an 'x'. The column is unique, so I cannot put something with x=7 in the table when there already is a '7' in there. So I want a routine that returns me '8' if there is already a record with '7'. Or '9' if there already is an '8'.
IN Pseudo SQL:
x = 7 // for example
select COL from myTable where COL= (x or if x does not exist, the y : y > x, y - x smallest possible)
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE NUMBERS
("NUM" int)
;
INSERT ALL
INTO NUMBERS ("NUM")
VALUES (1)
INTO NUMBERS ("NUM")
VALUES (7)
INTO NUMBERS ("NUM")
VALUES (10)
INTO NUMBERS ("NUM")
VALUES (11)
INTO NUMBERS ("NUM")
VALUES (12)
INTO NUMBERS ("NUM")
VALUES (19)
INTO NUMBERS ("NUM")
VALUES (20)
SELECT * FROM dual
;
Query 1:
select min(n.VAL) as NextFree
from (
SELECT LEVEL as VAL
FROM DUAL
CONNECT BY LEVEL <= 100000
ORDER BY LEVEL
) n
left outer join NUMBERS d on n.VAL = d.NUM
where d.NUM is null
and n.VAL >= 10
Results:
| NEXTFREE |
|----------|
| 13 |
Similar to the answer above but there's no need for a left join:
select nvl(nextfree, 10) as nextfree from (
select max(d.NUM) + 1 as nextfree
from NUMBERS d
CONNECT BY PRIOR NUM + 1 = NUM
START WITH NUM = 10
)
| NEXTFREE |
|----------|
| 13 |
I want to insert multiple rows from one column by splitting column value. But I have to do that without cursors because of performance issues.
Every value is splitted to 6 chars length values. Then these values also splitted to 3, 1 and 2 chars length values to insert different columns in table B.
I think giving a sample will clarify my question:
Table A
ID Value
1 ABCDEFGHJKLM
2 NOPRST
3 NULL VALUE
I want to insert these values into table B like this format
Table B
ID Value1 Value2 Value3
1 ABC D EF
1 GHJ K LM
2 NOP R ST
Supposing 600(100 rows) as maximum length of value:
insert into tableB
select id, substr(value,n*6+1,3), substr(value,n*6+4,1), substr(value,n*6+5,2)
from tableA
join (select level-1 as n from dual connect by level <= 100)
on length(value) > n*6;
see Sqlfiddle.
select ID,
SUBSTR(value,number*6+1,3),
SUBSTR(value,number*6+4,1),
SUBSTR(value,number*6+5,2)
from yourtable,
(select 0 as number union select 1 union select 2 union select 3 union select 4
union select 5 union select 6) as numbers
/* etc up to the max length of your string /6 */
where LEN(value)>number*6
try this:
Please convert it to ORACLE SQL..
Even though, its using a while loop, its doing bulk inserts..and the loop is executed as per the length of maximun length of value in the table
declare #max_len int=0;
declare #counter int=0;
declare #col_index int=1;
select #max_len=MAX(len(Value)) from TableA
while (#max_len/6 > #counter)
begin
set #counter=#counter+1
Insert into TableB
select ID,substring(Value,#col_index,3),
substring(Value,#col_index+3,1),
substring(Value,#col_index+4,2)
from TableA where substring(Value,#col_index,3) is not null
set #col_index=#col_index+6
end
I have following data set
a b c
`1` 2 3
3 6 9
9 2 11
As you can see column a's first value is fixed (i.e. 1), but from second row it picks up the value of column c of previous record.
Column b's values are random and column c's value is calculated as c = a + b
I need to write a sql query which will select this data in above format. I tried writing using lag function but couldn't achieve.
Please help.
Edit :
Column b exists in table only, a and c needs to calculated based on the values of b.
Hanumant
SQL> select a
2 , b
3 , c
4 from dual
5 model
6 dimension by (0 i)
7 measures (0 a, 0 b, 0 c)
8 rules iterate (5)
9 ( a[iteration_number] = nvl(c[iteration_number-1],1)
10 , b[iteration_number] = ceil(dbms_random.value(0,10))
11 , c[iteration_number] = a[iteration_number] + b[iteration_number]
12 )
13 order by i
14 /
A B C
---------- ---------- ----------
1 4 5
5 8 13
13 8 21
21 2 23
23 10 33
5 rows selected.
Regards,
Rob.
Without knowing the relation between the rows ,how can we calculate the sum of the previous row a and b column to current row a column .I have created two more column id and parent in the table to find the relation between the two rows.
parent is the column which tell us about the previous row ,and id is the primary key of the row .
create table test1 (a number ,b number ,c number ,id number ,parent number);
Insert into TEST1 (A, B, C, ID) Values (1, 2, 3, 1);
Insert into TEST1 (B, PARENT, ID) Values (6, 1, 2);
Insert into TEST1 (B, PARENT, ID) Values (4, 2, 3);
WITH recursive (a, b, c,rn) AS
(SELECT a,b,c,id rn
FROM test1
WHERE parent IS NULL
UNION ALL
SELECT (rec.a+ rec.b) a
,t1.b b
,(rec.a+ rec.b+t1.b) c
,t1.id rn
FROM recursive rec,test1 t1
WHERE t1.parent = rec.rn
)
SELECT a,b,c
FROM recursive;
The WITH keyword defines the name recursive for the subquery that is to follow
WITH recursive (a, b, c,rn) AS
Next comes the first part of the named subquery
SELECT a,b,c,id rn
FROM test1
WHERE parent IS NULL
The named subquery is a UNION ALL of two queries. This, the first query, defines the starting point for the recursion. As in my CONNECT BY query, I want to know what is the start with record.
Next up is the part that was most confusing :
SELECT (rec.a+ rec.b) a
,t1.b b
,(rec.a+ rec.b+t1.b) c
,t1.id rn
FROM recursive rec,test1 t1
WHERE t1.parent = rec.rn
This is how it works :
WITH query: 1. The parent query executes:
SELECT a,b,c
FROM recursive;
This triggers execution of the named subquery. 2 The first query in the subquery's union executes, giving us a seed row with which to begin the recursion:
SELECT a,b,c,id rn
FROM test1
WHERE parent IS NULL
The seed row in this case will be for id =1 having parent is null. Let's refer to the seed row from here on out as the "new results", new in the sense that we haven't finished processing them yet.
The second query in the subquery's union executes:
SELECT (rec.a+ rec.b) a
,t1.b b
,(rec.a+ rec.b+t1.b) c
,t1.id rn
FROM recursive rec,test1 t1
WHERE t1.parent = rec.rn
I've received data from an external source, which is in a summarised format. I need a way to disaggregate this to fit into a system I am using.
To illustrate, suppose the data I received looks like this:
receivedTable:
Age Gender Count
40 M 3
41 M 2
I want this is a disaggregated format like this:
systemTable:
ID Age Gender
1 40 M
2 40 M
3 40 M
4 41 M
5 41 M
Thanks
Karl
Depending of the range of your count you could use a lookup table that holds exactly x records for each integer x. Like this:
create table counter(num int)
insert into counter select 1
insert into counter select 2
insert into counter select 2
insert into counter select 3
insert into counter select 3
insert into counter select 3
insert into counter select 4
insert into counter select 4
insert into counter select 4
insert into counter select 4
then join with this table:
create table source(age int, gender char(1), num int)
insert into source select 40, 'm', 3
insert into source select 30, 'f', 2
insert into source select 20, 'm', 1
--insert into destination(age, gender)
select age, gender
from source
inner join counter on counter.num = source.num
From the "Works on my machine (TM)" stable a recursive query, with all the usual caveats about maximum recursion depth.
with Expanded(exAge, exGender, exRowIndex) as
(
select
Age as exAge,
Gender as exGender,
1 as exRowIndex
from
tblTest1
union all
select
exAge,
exGender,
exRowIndex+1
from
tblTest1 t1
inner join
Expanded e on (e.exAge = t1.Age and e.exGender = t1.Gender and e.exRowIndex < t1.Count)
)
select
exAge,
exGender,
exRowIndex
from
Expanded
order by
exAge,
exGender,
exRowIndex
option (MAXRECURSION 0) -- BE CAREFUL!!
You don't get the row identifier - but inserting the result of the query into a table with an identity column would deal with that.