what's the procedure I should follow to run a simple test on a domain www.example.com? I'm on Windows environment and have installed WAMP server 2.1.
I actually know which command I should use (Ex. ab -n 1 http://www.example.com/) but don't know where I should type it.
I don't know the path WampServer is installed to, so I'll just show you how I do it under WampDeveloper (which is what I use).
Run cmd.exe.
Inside...
C:
cd \WampDeveloper\Components\Apache\bin
ab -n 1 http://www.example.com/
To answer your question, you type it in the command line changed to the bin folder of your Apache folder since this is where ab.exe exists. If this folder location is in the system path, you can also just type it in anywhere (without changing paths in cmd.exe).
This 1st line changes the drive letter. Then second the path (aka working directory). The third runs ab.exe.
I do agree, PATH ENVIRONMENT setup manually
C:/YOUR_INSTALLATION_APACHE2/bin
Path to environment on control panel system settings.
Related
In my home folder in Linux I have several config files that have "rc" as a file name extension:
$ ls -a ~/|pcregrep 'rc$'
.bashrc
.octaverc
.perltidyrc
.screenrc
.vimrc
What does the "rc" in these names mean?
It looks like one of the following:
run commands
resource control
run control
runtime configuration
Also I've found a citation:
The ‘rc’ suffix goes back to Unix's grandparent, CTSS. It had a command-script feature called "runcom". Early Unixes used ‘rc’ for the name of the operating system's boot script, as a tribute to CTSS runcom.
Runtime Configuration normally if it's in the config directory. I think of them as resource files. If you see rc in file name this could be version i.e. Release Candidate.
Edit: No, I take it back officially... "run commands"
[Unix: from runcom files on the CTSS system 1962-63, via the startup script /etc/rc]
Script file containing startup instructions for an application program (or an entire operating system), usually a text file containing commands of the sort that might have been invoked manually once the system was running but are to be executed automatically each time the system starts up.
Thus, it would seem that the "rc" part stands for "runcom", which I believe can be expanded to "run commands". In fact, this is exactly what the file contains, commands that bash should run.
Quoted from What does “rc” in .bashrc stand for?
I learnt something new! :)
In the context of Unix-like systems, the term rc stands for the phrase "run commands". It is used for any file that contains startup information for a command. It is believed to have originated somewhere in 1965 from a runcom facility from the MIT Compatible Time-Sharing System (CTSS).
Reference: https://en.wikipedia.org/wiki/Run_commands
In Unix world, RC stands for "Run Control".
http://www.catb.org/~esr/writings/taoup/html/ch10s03.html
To understand rc files, it helps to know that Ubuntu boots into several different runlevels. They are 0-6, 0 being "halt", 1 being "single-user", 2 being "multi-user"(the default runlevel), etc. This system has now been outdated by the Upstart and initd programs in most Linux Distros. It is still maintained for backwards compatibility.
Within the /etc directory are several folders labeled "rc0.d, rc1.d" etc, through rc6.d. These are the directories the kernel refers to to know which init scripts it should run for that runlevel. They are symbolic links to the system service scripts residing in the /etc/init.d directory.
In the context you are using it, it would appear that you are listing any files with rc in the name. The code in these files will set the way the services/tasks startup and run when initialized.
Trying to get the sidekick image built and having some issues. Is there any documentation other than the README.md file?
My current problem is with getting the JRE requirement working but there are others. The page says "download Oracle JRE and place it inside the working directory. Optionally if you have a company wide distribution url, use that one at a later step." and the help says "Java (JRE) download url or path inside working directory". Have not been able to get this to work.
I went to the JRE link provided and was presented with options to download a rpm file or a tar.gz file. Which is expected (was unable to get either one working)?
It says to place the file in the "working directory" but not sure where exactly. Tried in sidekick folder and in sidekick/jre both without success no matter what I used after the -j command. Is this just the path or should the filename be included as well? Can I get an example?
I'm running this script using my login but noticed the output folder is being created with root user and group. I see no indication that this should be run with sudo. What is the correct way to run this script?
Using debug, I see the function "download if not cached". Can I save these files (JRE, Bamboo jar file, etc.) somewhere so I don't have to worry about downloading them? If so, where should they go? Looks like I might have a problem with the wget to d/l the jar file so would like to just be able to place all these in a folder and be done with it.
It looks like the major problem is the script didn't clean up after itself if it fails. The issue was the first time it failed then that caused subsequent issues as the output folder was already there. Removing this directory between each attempt help.
As for the correct syntax for the -j JRE option I manually downloaded the JRE and placed in a folder called per-build-container/sidekick/stuff/. For the command line it is not just the path but the file name as well (the tar.gz and not the RPM). For my case it was
-j stuff/jre-8u251-linux-x64.tar.gz
Note I also ran the script as sudo. Wasn't stated but seemed to work OK.
Another issue I ran into was the download of the agent jar file. There is a redirect in the wget file that was not working for us. I ended up editing the script and replacing the Altassian based url with the redirected one.
This addresses all the issues I ran into with the initial question.
I am trying to change WAMP directory but in my path there is one word (comupter name) with special character š, so when I change dir and restart wamp it stays yellow... I am sure it is because of that because when I use some other path (without special char) it works just fine.
How can I change WAMP root dir to be that path?
Full path : C:\Users\Dušan\Dropbox
This may be difficult. As you need to make Apache, MySQL, and PHP all work with this special path... On windows.
And I'm honestly unsure if this won't cause major problems.
My advice is to crate a SHORTCUT folder (like ln -sf on linux), and link it to your destination. You can then install there and work directly on your sites.
Apache conf and mysql, etc. would see a normal path name.
God only knows how the UTF-8 path conversion works between linux and windows ports of these products.
Again, I'd try a standard folder C:\wamp, linked to your www or whichever directory via a shortcut.
I have been trying on this for hours
i Get the below error
'php' is not recognized as an internal or external command,
operable program or batch file.
Steps i have done
1- I have added to Windows Environement variables C:\wamp\bin\php\php5.3.13;
2-re-installed wamp 2 times
3-Apache and php error log is clean
I have the below configuration
Windows 8 64 bit
Apache 2.2
PHP 5.3.13
Actually the php exe you run in wamp for the CLI is just php.exe
It is found in the c\wamp\bin\php\phpX.Y.Z\ folder and called php.exe
Suggest you create a little batch file to setup the path so you can use it from anywhere by just keying php, like this:
phppath.cmd
set path=%PATH%;c:\wamp\bin\php\phpX.Y.Z
php -v
Store this batch file in a folder on your path and you are golden.
You need to add php to your system path as follows:
go to system properties
chooose advance tab
check the system variables
choose Path then edit it and add at the end ;C:\xampp\php\
Note that system variables in Path are separated with ;
same thing applies to WAMP all you need is to specify your php binaries folder
seems that php-cli.exe dosent come along with WAMP, I installed XAMPP instead and CLI worked perfectly
I'm running a java application that we distribute as a server-side system. I'm trying to write a launcher ("write" is somewhat of an overstatement here, I'm basically just copying the Java.exe file so that we can get the desired name in the process explorer of windows). This exe is in our bin/ directory of our application file tree.
Now, we also have a jre/ directory in our file tree, which is where Java.exe actually resides (we ship our product with the Java environment). When I use Java.exe as the launcher, which is located in \jre\jre1.6.0_21\bin, or if I place the copy (call this exectuable 'Orange.exe') I made in this directory, it works just fine. But, if I put my 'Orange.exe' in the bin\ directory, then I get the following error:
Error: no 'server' JVM at 'C:\Program Files\Java\jre6\bin\server\jvm.dll'
I think I understand what is happening here - I want to use the server version of the jvm.dll file, which is in our jre directory. The problem is, I don't understand WHY it doesn't look in the jre\jre1.6.0_21 directory in my application path. I've set my JAVA_HOME environment variable to this location. It seems like it's defaulting to another, system-wide expected location.
Does anyone know how I can change this, so that it looks in my application-provided java environment directory? Ideally, this will be an environment variable, as I need to call this application with parameters using a batch file.
There is a little trick to get the server JVM up and running:
Copy "server" folder from the JDK's JRE's bin folder example: C:\Program Files\Java\jdk1.6.0\jre\bin\server
Paste the "server" folder to JRE's bin folder example: C:\Program Files\Java\jre1.6.0\bin
Done
See official readme for details.
I've just been struggling with this same problem in Eclipse and I noted that as suggested by the answer above the JBoss site has a thread on this issue saying the same as the answer above to copy files from the jdk to the jre folder.
I noticed that you can avoid having to do this if you define the runtime to be the jdk when you create the server. I didn't find how to edit an existing server though.
AFAIK, the JRE usually doesn't ship with a server VM (only the client VM). If you really need the server VM, you have to use the JDK installation.
See Oracle Java for Developers Download page for JRE's with Server VM.
I had the same problem here but, in my case, I just had not properly update the JAVA_HOME and my PATH for my recently installed JDK.
I just updated it to my new JDK location and the server started just fine.
Windows looks for DLLs in LIBPATH environment variable.
And make sure your 1.6.0_21 is somewhere first in PATH.
I solved the same problem by setting the JAVA_HOME path to C:\Program Files (x86)\Java\jre1.8.0_131\bin
The easiest fix is simply to copy the contents of client folder inside bin and put in a newly created folder 'server' inside bin.
Copy from C:\Program Files (x86)\Java\jre1.8.0_261\bin\client
Paste in C:\Program Files (x86)\Java\jre1.8.0_261\bin\server
*server is the new folder
Make sure that server/jvm.dll file must be there when we are trying to run servers like servicemix.
Copy "server" folder from the JDK's JRE's bin folder example: C:\Program Files\Java\jdk1.6.0\jre\bin\server
Paste the "server" folder to JRE's bin folder example: C:\Program Files\Java\jre1.6.0\bin
I paced problem, I went through above..That's working fine.
Thanks!