How to assign the values for the parameters - objective-c

How to assign the values for the parameters.
Rs232MsgRawEncoded(const int nMsgId,const INT8U* pSrc=NULL,unsigned int nSize=0);
I have declared the above cpp method declaration in Objective C as the following
-(id)initWithRS232MsgRawEncoded:(const int)nMsgId withpSrc:(const uint8_t*)pSrc withSize:(unsigned int)nSize;
Inside the function i'm checking whether its null or with some value.
I could not able to declare the variables as pSrc=NULL and nSize=0 in the Objective C
Is there any way to do this?

Objective-c (as well as c) does not support default parameters for functions.
So you can either use the function you have and pass all parameters to it every time. If you don't - create new functions with some parameters omitted and call your 'main' function with default parameters inside, e.g.:
-(id)initWithRS232MsgRawEncoded:(const int)nMsgId{
return [self initWithRS232MsgRawEncoded:nMsgId withpSrc:NULL withSize:0];
}

Related

How to declare a global variable inside a function

I am not able to find the required solution. I want to call a function and want to use some variable which is being declared in that function(I don't want to return that variable). I just want to make it global.
func foo(){
temp:=30
}
func main(){
foo()
// How to use temp without returning or without declaring it outside foo and main
}
You can't. You can only declare a package variable (aka global variable) in package scope. You can modify it from inside a function, but you can't declare it inside a function. This is because anything else referring to that variable has to have that reference resolvable at compile time. Otherwise, what happens when Bar() tries to reference the variable before Foo() could declare it? That would break compile-time safety that Go guarantees.
That said, the solution is simple; just declare it in package scope. It's unclear in the question why you wouldn't want to do that - if you want a global, that's what you do.

Can there be two return types in a C function?

I am looking at a project which aims expose Cocoa API's to OCaml. The code comprises of a function which has two values where return type is mentioned.
CAMLprim value ml_NSWindow_center(value win_v)
{
CAMLparam1(win_v);
NSWindow *win = NSWindow_val(win_v);
[win center];
CAMLreturn(Val_unit);
}
Is that possible ? or that is not a return type.
CAMLprim seems not to be a type at all, but a linkage/storage class for the function - it seems to be #defined to empty strings in some headers that I found. The real return type is value, which is a typedef for an integer type.
As per the documentation, for any function with the return as CAMLprim value
This function must have return type CAMLprim value and its parameter type has to be value. All parameters given to C functions from OCaml are of type value. The include header provides conversion macros to convert the type value to C native types. In this case to convert to a C integer, that macro is Int_val(). Then as the return value of the OCaml function is unit, the C function have to return a unit, which is done with the macro Val_unit.

lua modules - what's the difference between using ":" and "." when defining functions? [duplicate]

This question already has answers here:
Difference between . and : in Lua
(3 answers)
Closed 8 years ago.
I'm still playing around with lua modules and I've found the following "interesting" issue that occurs depending on how you create your methods / functions inside a module.
Note the following code in a file called test_suite.lua:
local mtests = {} -- public interface
function mtests:create_widget(arg1)
print(arg1)
-- does something
assert(condition)
print("TEST PASSED")
end
return mtests
Using the above code, arg1 is always nil, no matter what I pass in when calling create_widget(). However, if I change the definition of the function to look like this:
function mtests.create_widget(arg1) -- notice the period instead of colon
print(arg1)
-- does something
assert(condition)
print("TEST PASSED")
end
then, the system displays arg1 properly.
This is how I call the method:
execute_test.lua
local x = require "test_suite"
x.create_widget(widgetname)
Can you tell me what the difference is? I've been reading: http://lua-users.org/wiki/ModuleDefinition
But I haven't come across anything that explains this to me.
Thanks.
All a colon does in a function declaration is add an implicit self argument. It's just a bit of syntactic sugar.
So if you're calling this with (assuming you assign the mtests table to foo), foo.create_widget(bar), then bar is actually assigned to self, and arg1 is left unassigned, and hence nil.
foo = {}
function foo:bar(arg)
print(self)
print(arg)
end
Calling it as foo.bar("Hello") prints this:
Hello
nil
However, calling it as foo:bar("Hello") or foo.bar(foo, "Hello") gives you this:
table: 0xDEADBEEF (some hex identifier)
Hello
It's basically the difference between static and member methods in a language like Java, C#, C++, etc.
Using : is more or less like using a this or self reference, and your object (table) does not have a arg1 defined on it (as something like a member). On the other way, using . is just like defining a function or method that is part of the table (maybe a static view if you wish) and then it uses the arg1 that was defined on it.
. defines a static method / member, a static lib, Which means you can't create a new object of it. static methods / libs are just for having some customized functions like printing or download files from the web, clearing memory and...
: Is used for object members, members that are not static. These members change something in an object, for example clearing a specified textbox, deleting an object and...
Metamethod functions(Functions that have :) can be made in lua tables or C/C++ Bindings. a metamethod function is equal to something like this on a non-static object:
function meta:Print()
self:Remove()
end
function meta.Print(self)
self:Remove()
end
Also, with . you can get a number/value that doesn't require any call from a non-static or static object. For example:
-- C:
int a = 0;
-- Lua:
print(ent.a)
-- C:
int a()
{
return 0;
}
-- Lua:
print(ent:a())
same function on a static member would be:
print(entlib.a())
Basically, each non-static object that has a function that can be called will be converted to : for better use.

Function/variable scope (pass by value or reference?)

I'm completely confused by Lua's variable scoping and function argument passing (value or reference).
See the code below:
local a = 9 -- since it's define local, should not have func scope
local t = {4,6} -- since it's define local, should not have func scope
function moda(a)
a = 10 -- creates a global var?
end
function modt(t)
t[1] = 7 -- create a global var?
t[2] = 8
end
moda(a)
modt(t)
print(a) -- print 9 (function does not modify the parent variable)
print(t[1]..t[2]) -- print 78 (some how modt is modifying the parent t var)
As such, this behavior completely confuses me.
Does this mean that table variables
are passed to the function by
reference and not value?
How is the global variable creation
conflicting with the already define
local variable?
Why is modt able to
modify the table yet moda is not able
to modify the a variable?
You guessed right, table variables are passed by reference. Citing Lua 5.1 Reference Manual:
There are eight basic types in Lua: nil, boolean, number, string, function, userdata, thread, and table.
....
Tables, functions, threads, and (full) userdata values are objects: variables do not actually contain these values, only references to them. Assignment, parameter passing, and function returns always manipulate references to such values; these operations do not imply any kind of copy.
So nil, booleans, numbers and strings are passed by value. This exactly explains the behavior you observe.
Lua's function, table, userdata and thread (coroutine) types are passed by reference. The other types are passed by value. Or as some people like to put it; all types are passed by value, but function, table, userdata and thread are reference types.
string is also a kind of reference type, but is immutable, interned and copy-on-write - it behaves like a value type, but with better performance.
Here's what's happening:
local a = 9
local t = {4,6}
function moda(a)
a = 10 -- sets 'a', which is a local introduced in the parameter list
end
function modt(t)
t[1] = 7 -- modifies the table referred to by the local 't' introduced in the parameter list
t[2] = 8
end
Perhaps this will put things into perspective as to why things are the way they are:
local a = 9
local t = {4,6}
function moda()
a = 10 -- modifies the upvalue 'a'
end
function modt()
t[1] = 7 -- modifies the table referred to by the upvalue 't'
t[2] = 8
end
-- 'moda' and 'modt' are closures already containing 'a' and 't',
-- so we don't have to pass any parameters to modify those variables
moda()
modt()
print(a) -- now print 10
print(t[1]..t[2]) -- still print 78
jA_cOp is correct when he says "all types are passed by value, but function, table, userdata and thread are reference types."
The difference between this and "tables are passed by reference" is important.
In this case it makes no difference,
function modt_1(x)
x.foo = "bar"
end
Result: both "pass table by reference" and "pass table by value, but table is a reference type" will do the same: x now has its foo field set to "bar".
But for this function it makes a world of difference
function modt_2(x)
x = {}
end
In this case pass by reference will result in the argument getting changed to the empty table. However in the "pass by value, but its a reference type", a new table will locally be bound to x, and the argument will remain unchanged. If you try this in lua you will find that it is the second (values are references) that occurs.
I won't repeat what has already been said on Bas Bossink and jA_cOp's answers about reference types, but:
-- since it's define local, should not have func scope
This is incorrect. Variables in Lua are lexically scoped, meaning they are defined in a block of code and all its nested blocks.
What local does is create a new variable that is limited to the block where the statement is, a block being either the body of a function, a "level of indentation" or a file.
This means whenever you make a reference to a variable, Lua will "scan upwards" until it finds a block of code in which that variable is declared local, defaulting to global scope if there is no such declaration.
In this case, a and t are being declared local but the declaration is in global scope, so a and t are global; or at most, they are local to the current file.
They are then not being redeclared local inside the functions, but they are declared as parameters, which has the same effect. Had they not been function parameters, any reference inside the function bodies would still refer to the variables outside.
There's a Scope Tutorial on lua-users.org with some examples that may help you more than my attempt at an explanation. Programming in Lua's section on the subject is also a good read.
Does this mean that table variables are passed to the function by reference and not value?
Yes.
How is the global variable creation conflicting with the already define local variable?
It isn't. It might appear that way because you have a global variable called t and pass it to a function with an argument called t, but the two ts are different. If you rename the argument to something else, e,g, q the output will be exactly the same. modt(t) is able to modify the global variable t only because you are passing it by reference. If you call modt({}), for example, the global t will be unaffected.
Why is modt able to modify the table yet moda is not able to modify the a variable?
Because arguments are local. Naming your argument a is similar to declaring a local variable with local a except obviously the argument receives the passed-in value and a regular local variable does not. If your argument was called z (or was not present at all) then moda would indeed modify the global a.

Calling a function by name input by user

Is it possible to call a function by name in Objective C? For instance, if I know the name of a function ("foo"), is there any way I can get the pointer to the function using that name and call it? I stumbled across a similar question for python here and it seems it is possible there. I want to take the name of a function as input from the user and call the function. This function does not have to take any arguments.
For Objective-C methods, you can use performSelector… or NSInvocation, e.g.
NSString *methodName = #"doSomething";
[someObj performSelector:NSSelectorFromString(methodName)];
For C functions in dynamic libraries, you can use dlsym(), e.g.
void *dlhandle = dlopen("libsomething.dylib", RTLD_LOCAL);
void (*function)(void) = dlsym(dlhandle, "doSomething");
if (function) {
function();
}
For C functions that were statically linked, not in general. If the corresponding symbol hasn’t been stripped from the binary, you can use dlsym(), e.g.
void (*function)(void) = dlsym(RTLD_SELF, "doSomething");
if (function) {
function();
}
Update: ThomasW wrote a comment pointing to a related question, with an answer by dreamlax which, in turn, contains a link to the POSIX page about dlsym. In that answer, dreamlax notes the following with regard to converting a value returned by dlsym() to a function pointer variable:
The C standard does not actually define behaviour for converting to and from function pointers. Explanations vary as to why; the most common being that not all architectures implement function pointers as simple pointers to data. On some architectures, functions may reside in an entirely different segment of memory that is unaddressable using a pointer to void.
With this in mind, the calls above to dlsym() and the desired function can be made more portable as follows:
void (*function)(void);
*(void **)(&function) = dlsym(dlhandle, "doSomething");
if (function) {
(*function)();
}