SQL - using a value in a nested select - sql

Hope the title makes some kind of sense - I'd basically like to do a nested select, based on a value in the original select, like so:
SELECT MAX(iteration) AS maxiteration,
(SELECT column
FROM table
WHERE id = 223652
AND iteration = maxiteration)
FROM table
WHERE id = 223652;
I get an ORA-00904 invalid identifier error.
Would really appreciate any advice on how to return this value, thanks!

It looks like this should be rewritten with a where clause:
select iteration,
col
from tbl
where id = 223652
and iteration = (select max(iteration) from tbl where id = 223652);

You can circumvent the problem alltogether by placing the subselect in an INNER JOIN of its own.
SELECT t.iteration
, t.column
FROM table t
INNER JOIN (
SELECT id, MAX(iteration) AS iteration
FROM table
WHERE id = 223652
) tm ON tm.id = t.id AND tm.iteration = t.iteration

Since you're using Oracle, I'd suggest using analytic functions for this:
SELECT * FROM (
SELECT col,
iteration,
row_number() over (partition by id order by iteration desc) rn
FROM tab
WHERE id = 223652
) WHERE rn = 1

do it like this:
with maxiteration as
(
SELECT MAX(iteration) AS maxiteration
FROM table
WHERE id = 223652
)
select
column,
iteration
from
table
where
id = 223652
AND iteration = maxiteration
;

Not 100% sure on Oracle syntax, but isn't it something like:
select iteration, column from table where id = 223652 order by iteration desc limit 1

I would approach this problem in a slightly different way. You're basically looking for the row that has no other iterations greater than it. There are at least 3 ways I can think of to do this:
SELECT
T1.iteration AS maxiteration,
T1.column
FROM
Table T1
WHERE
T1.id = 223652 AND
NOT EXISTS
(
SELECT *
FROM Table T2
WHERE
T2.id = 223652 AND
T2.iteration > T1.iteration
)
Or...
SELECT
T1.iteration AS maxiteration,
T1.column
FROM
Table T1
LEFT OUTER JOIN Table T2 ON
T2.id = T1.id AND
T2.iteration > T1.iteration
WHERE
T1.id = 223652 AND
T2.id IS NULL
Or...
SELECT
T1.iteration AS maxiteration,
T1.column
FROM
Table T1
INNER JOIN (SELECT id, MAX(iteration) AS maxiteration FROM Table T2 GROUP BY id) SQ ON
SQ.id = T1.id AND
SQ.maxiteration = T1.iteration
WHERE
T1.id = 223652
EDIT: I didn't see the ORA error the first time reading the question and it wasn't tagged as Oracle specific. I think that there may be some differences in the syntax and use of aliases in Oracle, so you may need to tweak some of the above queries.
The Oracle error is telling you that it doesn't know what maxiteration is, because the column alias isn't available yet inside the subquery. You need to refer to it by the table alias and column name instead of the column alias I believe.

You do something like
select maxiteration,column from table a join (select max(iteration) as maxiteration from table where id=1) b using (id) where b.maxiteration=a.iteration;
This could of course return multiple rows for one maxiteration unless your table has a constraint against it.

Related

SQL Tables need to be appended, but not like JOINS

I've a scenario as below.
I've two tables, and a Common column/Key between the two.
I need Table2 data to be just appended to Table1 without repetition like JOINs.
If there are more rows in one table, other table rows can be NULL.
As shown in figure, Result Table has NULLs when there is no corresponding row count from Table2.
I tried using Joins, but I'm getting a result of 45 rows. But I should get 9 rows.
Thanks in advance.
Edit: Added my queries
SELECT DISTINCT
APPT.PRSN_ID
,APPT.SCHEDULEDAPPOINTMENTS
,APPT.OVERDUEAPPOINTMENTS
,Visit.ENCOUNTER_CATEGORY
,Visit.ENCOUNTER_TYPE
,Visit.ENCOUNTER_DATE
,Visit.ENCOUNTER_FOLLOWUP_DATE
FROM
APPOINTMENTS APPT
OUTER APPLY dbo.fn_GetVisitsOfAPerson(PROV.PRSN_ID) AS Visit
/***********************************************************/
--IN THE ABOVE QUERY, THE FUNCTION IS DEFINED AS BELOW
CREATE FUNCTION dbo.fn_GetVisitsOfAPerson(#PrsnID AS bigint)
RETURNS TABLE
AS
RETURN
(
SELECT
VISITS.PVISITS_PRSN_KEY
,DATA.HE_Category_Description AS 'ENCOUNTER_CATEGORY'
,DATA.HE_Type_Description AS 'ENCOUNTER_TYPE'
,VISITS.PVISITS_DATE AS 'ENCOUNTER_DATE'
,VISITS.PVISITS_FOLLOWUP_DATE AS 'ENCOUNTER_FOLLOWUP_DATE'
FROM
[HS_PRSN_HEALTH_VISITS] VISITS INNER JOIN
[HS_HealthEncounter_Table] DATA ON
ENCOUNTER.PVISITS_CATEGORY = DATA.HE_Category_Code AND
ENCOUNTER.PVISITS_TYPE = DATA.HE_Type_Code
WHERE
PVISITS_PRSN_KEY = #PrsnID
AND PVISITS_VOID = 0
)
GO
I cannot read your data tables, but I think you just need to introduce a row number.
It would be something like this:
select . . .
from (select t1.*, row_number() over (partition by key order by ??) as seqnum
from table1 t1
) full join
(select t2.*, row_number() over (partition by key order by ??) as seqnum
from table1 t2
) t2
on t1.key = t2.key and t1.seqnum = t2.seqnum;
Based on you wanting the 9 rows present in the Visit table it looks like you need an OUTER JOIN, something like:
SELECT DISTINCT
APPT.PRSN_ID
,APPT.SCHEDULEDAPPOINTMENTS
,APPT.OVERDUEAPPOINTMENTS
,Visit.ENCOUNTER_CATEGORY
,Visit.ENCOUNTER_TYPE
,Visit.ENCOUNTER_DATE
,Visit.ENCOUNTER_FOLLOWUP_DATE
FROM Visit
LEFT OUTER JOIN
APPOINTMENTS APPT
ON Visit.key = APP.key

Left Join with duplicate keys in the right table

I'm trying merging 2 tables as follow
SELECT * FROM T1
LEFT JOIN T2 ON T1.EMPnum = T2.EMPnum
The above works well but I need the joining to use only the first appearance of the common key EMPnum record in table T2 so that the query returns exactly the same number of rows as T1
Thanks Avi
SQL tables are inherently unordered, so there is no such thing as a "first" key. In most databases, you can do something like this:
with t2 as (
select t2.*, row_number() over (partition by EMPnum order by id) as seqnum
from t2
)
select *
from t1 left join
t2
on t1.EMPnum = t2.EMPnum and t2.seqnum = 1;
Here id is just any column that specifies the ordering. If none exist, you can use EMPnum to get an arbitrary row.

How to simplify this query with sql joins?

my_table has 4 columns: id integer, value integer, value2 integer, name character varying
I want all the records that:
have the same value2 as a record which name is 'a_name'
have a field value inferior to the one of a record which name is 'a_name'
And I have satisfying results with the following query:
select t.id
from my_table as t
where t.value < ( select value from my_table where name = 'a_name')
and s.value2 = (select value2 from my_table where name = 'a_name');
But is it possible to simplify this query with sql joins ?
Joining on the same table is still too much intricate in my mind. And I try to understand with this example.
What I happened so far trying, is a result full of dupplicates:
select t2.id
from my_table as t
inner join my_table as t2 on t2.value2 = t.value2
where t2.value < ( select value from my_table where name = 'a_name');
I think this will solve your problem.
select t1.id
from my_table as t1
join my_table as t2
on t1.value2 = t2.value2
and t2.name = 'a_name'
and t1.value < t2.value
You should use self join instead of inner join see this
http://msdn.microsoft.com/en-us/library/ms177490%28v=sql.105%29.aspx
You can always get distinct results by calling "SELECT distinct t2.id ..."
However, that will not enhance your understanding of inner joins. If you are willing, keep reading on. Let's start by getting all records with name = 'a_name'.
SELECT a.*
FROM my_table as a
WHERE a.name = 'a.name';
A simpler way to perform your inner joins is to understand that the result for the above query is yet another table, formally known as a relation. You can think of it as joining on the same table, but an easier way to think of it is as "joining on the result of this query". Lets put this to the test.
SELECT other.id
FROM my_table as a,
INNER JOIN my_table as other ON other.value2 = a.value2
WHERE a.name = 'a_name'
AND other.value < a.value;
If the first query (all rows with name = 'a_name') has many results, you stand a good chance of the second query having duplicates, because the inner join between aliases 'a' and 'other' is a subset of their cross product.
Edits: Grammar, Clarity
please try this
select t.id
from my_table as t
inner join
(select value from my_table where name = 'a_name')t1 on t.value<t1.value
inner join
(select value2 from my_table where name = 'a_name')t2 on t.value2=t2.value2

SQL - Query to return result

There is a table with Columns as below:
Id : long autoincrement;
timestamp:long;
price:long
Timestamp is given as a unix_time in ms.
Question: what is the average time difference between the records ?
First thought is a sub-query grabbing the record immediately previous:
SELECT timestamp -
(select top 1 timestamp from Table T1 where T1.Id < Table.Id order by Id desc)
FROM Table
Then you can take the average of that:
SELECT AVG(delta)
from (SELECT timestamp -
(select top 1 timestamp from Table T1 where T1.Id < Table.Id order by Id desc) as delta
FROM Table) T
There will probably need to be some handling of the null that results for the first row, but I haven't tested to be sure.
In SQL Server, you could write something like that to get that information:
SELECT
t1.ID, t2.ID,
DATEDIFF(MILLISECOND, t2.PriceTime, test2.PriceTime)
FROM table t1
INNER JOIN table t2 ON t2.ID = t1.ID-1
WHERE t1.ID > (SELECT MIN(ID) FROM table)
and if you're only interested in the AVG across all entries, you could use:
SELECT
AVG(DATEDIFF(MILLISECOND, t2.PriceTime, test2.PriceTime))
FROM table t1
INNER JOIN table t2 ON t2.ID = t1.ID-1
WHERE t1.ID > (SELECT MIN(ID) FROM table)
Basically, you need to join the table with itself, and use "t1.ID = t2.ID-1" to associate item no. 2 in one table with item no. 1 in the other table and then calculate the time difference between the two. In order to avoid accessing item no. 0 which doesn't exist, use the "T1.ID > (SELECT MIN(ID) FROM table)" clause to start from the second item.
Marc
At a guess:
SELECT AVG(timestamp)
I think you need to provide more information in your question for us to help.
If you mean difference between each-other row:
select AVG(x) from (
select a.timestamp - b.timestamp as x
from table a, table b -- this multiplies a*b ) sub
SELECT AVG(T2.Timestamp - T1.TimeStamp)
FROM Table T1
JOIN Table T2 ON T2.ID = T1.ID + 1
try this
Select Avg(E.Timestamp - B.Timestamp)
From Table B Join Table E
On E.Timestamp =
(Select Max(Timestamp)
From Table
Where Timestamp < R.Timestamp)

How do I compare 2 rows from the same table (SQL Server)?

I need to create a background job that processes a table looking for rows matching on a particular id with different statuses. It will store the row data in a string to compare the data against a row with a matching id.
I know the syntax to get the row data, but I have never tried comparing 2 rows from the same table before. How is it done? Would I need to use variables to store the data from each? Or some other way?
(Using SQL Server 2008)
You can join a table to itself as many times as you require, it is called a self join.
An alias is assigned to each instance of the table (as in the example below) to differentiate one from another.
SELECT a.SelfJoinTableID
FROM dbo.SelfJoinTable a
INNER JOIN dbo.SelfJoinTable b
ON a.SelfJoinTableID = b.SelfJoinTableID
INNER JOIN dbo.SelfJoinTable c
ON a.SelfJoinTableID = c.SelfJoinTableID
WHERE a.Status = 'Status to filter a'
AND b.Status = 'Status to filter b'
AND c.Status = 'Status to filter c'
OK, after 2 years it's finally time to correct the syntax:
SELECT t1.value, t2.value
FROM MyTable t1
JOIN MyTable t2
ON t1.id = t2.id
WHERE t1.id = #id
AND t1.status = #status1
AND t2.status = #status2
Some people find the following alternative syntax easier to see what is going on:
select t1.value,t2.value
from MyTable t1
inner join MyTable t2 on
t1.id = t2.id
where t1.id = #id
SELECT COUNT(*) FROM (SELECT * FROM tbl WHERE id=1 UNION SELECT * FROM tbl WHERE id=2) a
If you got two rows, they different, if one - the same.
SELECT * FROM A AS b INNER JOIN A AS c ON b.a = c.a
WHERE b.a = 'some column value'
I had a situation where I needed to compare each row of a table with the next row to it, (next here is relative to my problem specification) in the example next row is specified using the order by clause inside the row_number() function.
so I wrote this:
DECLARE #T TABLE (col1 nvarchar(50));
insert into #T VALUES ('A'),('B'),('C'),('D'),('E')
select I1.col1 Instance_One_Col, I2.col1 Instance_Two_Col from (
select col1,row_number() over (order by col1) as row_num
FROM #T
) AS I1
left join (
select col1,row_number() over (order by col1) as row_num
FROM #T
) AS I2 on I1.row_num = I2.row_num - 1
after that I can compare each row to the next one as I need