Passing config to ExtJS prototypes - config

Question

I'm trying to figure out how ExtJS4 passes around config objects.
I want to do the equivalent of...
store = function(config){
if ( typeof config.call !== 'unndefined' ){
config.url = "server.php?c=" + config.call || config.url;
};
Sketch.Data.AutoSaveStore.superclass.constructor.call(this,config);
};
Ext.extend(store, Ext.data.Store{})
I am probably missing something obvious here, but having dug around in the sandbox file, the closest I have come is....
Ext.define('My.awesome.Class', {
// what i would like to pass.
config:{},
constructor: function(config) {
this.initConfig(config);
return this;
}
});
which doesn't seem to work if you do something like...
var awesome = Ext.create('My.awesome.Class',{
name="Super awesome"
});
alert(awesome.getName()); // 'awesome.getName is not a function'
However
Ext.define('My.awesome.Class', {
// The default config
config: {
name: 'Awesome',
isAwesome: true
},
constructor: function(config) {
this.initConfig(config);
return this;
}
});
var awesome = Ext.create('My.awesome.Class',{
name="Super awesome"
});
alert(awesome.getName()); // 'Super Awesome'
This is biting me in the rear end when trying to do complex store extensions.
Anyone have any idea how I pass a bunch of random params to the prototype?

Answer 1

You should not be using new operator to create new instance on your class. In ExtJS4, you should use Ext.create() method.
Try doing:
var awesome = Ext.create('My.awesome.Class');
alert(awesome.getName());
And if you want to pass some param when creating an instance, you can do the following
var awesome = Ext.create('My.awesome.Class',{name:'New Awesome'});