Get all the Subchild values using XQUERY-SQL - xquery-sql

Question

I'm attempting to create an xquery expression that will return all the subchild node values. Now I get only the first subchild under each child.
I have the following XML:
<order>
<child1>
<subchild id="S1">
<name type="primary">
<first>NAOMI</first>
<middle />
<last>ADAMS</last>
<suffix />
</name>
</subchild>
<subchild id="S2">
<name type="primary">
<first>TOVER</first>
<middle />
<last>DALI</last>
<suffix />
</name>
</subchild>
</child1>
<child2>
<subchild id="V1">
<year>2002</year>
<make>PONTI</make>
<model>AZTEK</model>
<vin>3G7DA03E32S597676</vin>
</subchild>
<subchild id="V2">
<year>2003</year>
<make>HONDA</make>
<model>CIVIC</model>
<vin>2H94DA03E80S1538</vin>
</subchild>
</child2>
<child3>
<subchild id="A1">
<house>7741</house>
<street1>SAINT BERNARD ST</street1>
<apartment />
<city>PLAYA DEL REY</city>
<state>CA</state>
<postalcode>90293</postalcode>
</subchild>
<subchild id="A2">
<house>2371</house>
<street1>HANNUM DR</street1>
<apartment />
<city>MARINA DEL REY</city>
<state>CA</state>
<postalcode>90293</postalcode>
</subchild>
</child3>
</order>
My result should look like :
FirstName LastName HouseNumber StreetName City SState Zip Year Model Make VIN
NAOMI ADAMS 7741 SAINT BERNARD ST PLAYA DEL REY CA 90293 2002 PONTI AZTEK G7DA03E32S597676
TOVER DALI 2371 HANNUM DR MARINA DEL REY CA 90024 2003 HONDA CIVIC 2H94DA03E80S1538
My query :
SELECT
FirstName, LastName, HouseNumber, StreetName, City, SState, Zip, Year, Model, Make, VIN
FROM
xmlTable
OUTER APPLY
(
SELECT
tbl.col.value('(child1/subchild/name/first)[1]','varchar(20)') AS FirstName,
tbl.col.value('(child1/subchild/name/last)[1]','varchar(20)') AS LastName,
tbl.col.value('(child1/subchild/name/middle)[1]','varchar(20)') AS MiddleName,
tbl.col.value('(child3/subchild/house)[1]','varchar(20)') AS HouseNumber,
tbl.col.value('(child3/subchild/street1)[1]','varchar(20)') AS StreetName,
tbl.col.value('(child3/subchild/city)[1]','varchar(20)') AS City,
tbl.col.value('(child3/subchild/state)[1]','varchar(20)') AS SState,
tbl.col.value('(child3/subchild/postalcode)[1]','varchar(20)') AS Zip,
tbl.col.value('(child2/subchild/model_year)[1]','varchar(20)') AS Year,
tbl.col.value('(child2/subchild/model)[1]','varchar(20)') AS Model,
tbl.col.value('(child2/subchild/make)[1]','varchar(20)') AS Make,
tbl.col.value('(child2/subchild/vin)[1]','varchar(20)') AS VIN
FROM
xmldocument.nodes('//order') AS tbl(col)
) Y
Thanks

Answer 1

DECLARE #x XML
SELECT #x = 'Your XML here'
SELECT
tbl.col.value('(child1/subchild/name/first)[position() = sql:column("s.number")][1]','varchar(20)') AS FirstName,
tbl.col.value('(child1/subchild/name/last)[position() = sql:column("s.number")][1]', 'varchar(20)') AS LastName,
tbl.col.value('(child1/subchild/name/middle)[position() = sql:column("s.number")][1]', 'varchar(20)') AS MiddleName,
tbl.col.value('(child3/subchild/house)[position() = sql:column("s.number")][1]', 'varchar(20)') AS HouseNumber,
tbl.col.value('(child3/subchild/street1)[position() = sql:column("s.number")][1]', 'varchar(20)') AS StreetName,
tbl.col.value('(child3/subchild/city)[position() = sql:column("s.number")][1]', 'varchar(20)') AS City,
tbl.col.value('(child3/subchild/state)[position() = sql:column("s.number")][1]', 'varchar(20)') AS SState,
tbl.col.value('(child3/subchild/postalcode)[position() = sql:column("s.number")][1]', varchar(20)') AS Zip,
tbl.col.value('(child2/subchild/model_year)[position() = sql:column("s.number")][1]', 'varchar(20)') AS Year,
tbl.col.value('(child2/subchild/model)[position() = sql:column("s.number")][1]', 'varchar(20)') AS Model,
tbl.col.value('(child2/subchild/make)[position() = sql:column("s.number")][1]', 'varchar(20)') AS Make,
tbl.col.value('(child2/subchild/vin)[position() = sql:column("s.number")][1]', 'varchar(20)') AS VIN
FROM #x.nodes('/order') AS tbl(col)
CROSS JOIN master..spt_values s
WHERE type = 'P' AND number BETWEEN 1
AND col.query('count(child1/subchild)').value('.', 'INT')