Need help in writing the query to get the last month data as well as month to date data.
If today's date is Mar 23 2011, I need to retrieve the data from last month and the data till todays date(means Mar 23 2011).
If date is Apr 3 2011, data should consists of March month data and the data till Apr 3rd 2011.
Thanks,
Shahsra
Today including time info : getdate()
Today without time info : DATEADD(DAY, DATEDIFF(day, 0, getdate()), 0)
Tomorrow without time info : DATEADD(DAY, DATEDIFF(day, 0, getdate()), 1)
Beginning of current month : DATEADD(month, datediff(month, 0, getdate()), 0)
Beginning of last month : DATEADD(month, datediff(month, 0, getdate())-1, 0)
so most likely
WHERE dateColumn >= DATEADD(month, datediff(month, 0, getdate())-1, 0)
AND dateColumn < DATEADD(DAY, DATEDIFF(day, 0, getdate()), 1)
Step back one month, subtract the number of days to the current date, and add one day.
WHERE
DateField <= GetDate() AND
DateField >= DateAdd(
mm,
-1,
DateAdd(dd, -1*DatePart(dd, GetDate())+1, GetDate())
)
To remove the time quickly, you can use this
Cast( Floor( Cast( GETDATE() AS FLOAT ) ) AS DATETIME )
So the second part would be (without time)
DateField >= Cast( Floor( Cast( (DateAdd(
mm,
-1,
DateAdd(dd, -1*DatePart(dd, GetDate())+1, GetDate())
)) AS FLOAT ) ) AS DATETIME )
Select Column1, Column2 From Table1
Where DateColumn <= GetDate() AND
DateColumn >= DATEADD(dd, - (DAY(DATEADD(mm, 1, GetDate())) - 1), DATEADD(mm, - 1, GetDate()))
Edit: +1 to Russel Steen. I was posting mine before I knew he had posted.
Very helpful page
declare #d datetime = '2011-04-03';
declare #startDate datetime;
select #startDate =
CAST('01 '+ RIGHT(CONVERT(CHAR(11),DATEADD(MONTH,-1,#d),113),8) AS datetime);
select #startDate;
Related
I checked Get the records of last month in SQL server and it did not work!
I try to get the records of last month based on my database table and column issue_date.
What's the SQL query to do this?
For clarification, today (27-April-18) I want to get all records from March-18.
I have the issue_date in the format that I convert to date but below code gives me all records from 01-March-2018 to and including today.
DATEPART(month, CONVERT (VARCHAR(11),DATEADD(day,wo_header.issue_date,`1971/12/31`),106)) = DATEPART(month, DATEADD(month, -1, getdate()))
To get firstDay and lastDay of previous month
DECLARE #FirstDayOfLastMonth DATETIME = CONVERT(DATE, DATEADD(d, -(DAY(DATEADD(m, -1, GETDATE() - 2))), DATEADD(m, -1, GETDATE() - 1))),
#LastDayOfLastMonth DATETIME = CONVERT(DATE, DATEADD(d, -(DAY(GETDATE())), GETDATE()))
SELECT #FirstDayOfLastMonth, #LastDayOfLastMonth
Your required Query
SELECT *
FROM TABLE
WHERE CAST(issue_date AS DATE) BETWEEN CONVERT(DATE, DATEADD(d, -(DAY(DATEADD(m, -1, GETDATE() - 2))), DATEADD(m, -1, GETDATE() - 1))) AND CONVERT(DATE, DATEADD(d, -(DAY(GETDATE())), GETDATE()))
Perhaps the easiest method is eomonth(). If there is no time component on issuedate:
where issuedate > eomonth(getdate(), -2) and
issuedate <= eomonth(getdate(), -1)
If there is a time component:
where issuedate >= dateadd(day, 1, cast(eomonth(getdate(), -2) as date)) and
issuedate < dateadd(day, 1, cast(eomonth(getdate(), -1) as date))
Without eomonth, I would do:
where issuedate < cast(dateadd(day, 1 - day(getdate()), getdate()) as date) and
issuedate >= dateadd(month, -1, cast(dateadd(day, 1 - day(getdate()), getdate()) as date))
The code I figured out is not pretty but it works. It first adds extra column with the month number to the SELECT portion of my code:
Month(CONVERT (VARCHAR(11),DATEADD(day,wo_header.closing_date,'1971/12/31'),106)) As Month
And than is used for WHERE statement:
Month(CONVERT (VARCHAR(11),DATEADD(day,wo_header.closing_date,'1971/12/31'),106)) = month(getdate())-1
So for anyone like me working in SQL report kind-of environment it should work.
I am trying to fetch data for the previous full month, but the data from the last day is not fetching.
Output: Previous Month is April and this condition only retrieving data up to 29th April. Data for 30th April is missing.
Can please someone help me to correct this.
OLH.DateStamp > CONVERT(VARCHAR,DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE())-1, 0),101)
And
OLH.DateStamp < CONVERT(VARCHAR,DATEADD(MONTH, DATEDIFF(MONTH, -1, GETDATE())-1, -1),101))
Thanks in advance
The simplest way to get data for the previous month is:
DATEDIFF(month, OLH.DateStamp, GETDATE()) = 1
However, that does not use indexes. So, a better method is:
OLH.DateStamp >= DATEADD(MONTH, -1, DATEADD(DAY, 1 - DAY(GETDATE()), CAST(GETDATE() as DATE))) AND
OLH.DateStamp < DATEADD(DAY, 1 - DAY(GETDATE()), CAST(GETDATE() as DATE))
The expression:
DATEADD(DAY, 1 - DAY(GETDATE), CAST(GETDATE() as DATE))
returns midnight on the first day of the current month.
You should try last day of Month Should be <= OLH.Datestamp
To get Desired Output you are Looking for:
--Use It In Where Clause
DECLARE #FirstDayOfLastMonth
DATETIME = CONVERT(DATE, DATEADD(d, -( DAY(DATEADD(m, -1, GETDATE() -
2)) ), DATEADD(m, -1, GETDATE() - 1)))
,#LastDayOfLastMonth DATETIME = CONVERT(DATE, DATEADD(d, -( DAY(GETDATE()) ), GETDATE()))
OLH.DateStamp >= CONVERT(VARCHAR, #FirstDayOfLastMonth , 101) AND
OLH.DateStamp <= CONVERT(VARCHAR, #LastDayOfLastMonth , 101)
I am using SQL Server 2014 and I need to add a line of code to my SQL query that will filter the data extracted only to those records where the StayDate (a column in database) is greater than or equal to the 1st day of the current month.
In other words, the line of code I need is the following:
WHERE StayDate >= '1st Day of Current Month'
Note: StayDate is in the datetime format (eg: 2015-12-18 00:00:00.000)
Use EOMONTH to get the first day of current month
WHERE StayDate >= Dateadd(dd, 1, Eomonth(Getdate(), -1))
SQL Server 2012 and above
WHERE StayDate >= DATEADD(DAY, 1, EOMONTH(GETDATE(), -1))
Before SQL Server 2012
WHERE StayDate >= DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0)
You can try following approach:
declare #t datetime = '2016-02-28'
select DATEADD(D, -DATEPART(d, #t) + 1, #t)
So in your case:
WHERE StayDate >= DATEADD(D, -DATEPART(d, GETDATE()) + 1, GETDATE())
StayDate >= DATEADD(MONTH, DATEDIFF(MONTH, '19000101', GETDATE()), '19000101')
One other option; since staydate being on or after (greater than or equal to) the first day of the current month is equivalent to searching for staydates during the current month:
where datepart(mm, staydate) = datepart(mm, getdate())
and datepart(yyyy, staydate) = datepart(yyyy, getdate())
How to get the first day of the week and last day of the week when we input any one day of a week?
For example if we enter a date then the first(Monday) and last (Friday) day should be displayed.
that is if we enter 24-jan-2014 then 20-jan-2014 and 24-jan-2014 should be displayed.
Regards
Here's how you can do it:
DECLARE #yourdate date = getdate()
Select dateadd(ww, datediff(ww, 0, #yourdate), 0)
Select dateadd(ww, datediff(ww, 0, #yourdate), 4)
You set #yourdate to the date you want. The first SELECT will give you the first day and the second SELECT will give you the last date
This solves it and also wraps around year ends:
SELECT DATEADD(wk, DATEDIFF(d, 0, '01 January 2017') / 7, 0)
Try this
SELECT DATEADD(wk, DATEDIFF(wk, 6, '5/13/2005'), 6)
SELECT DATEADD(wk, DATEDIFF(wk, 5, '5/13/2005'), 5)
(Or)
Declare #Date datetime
Det #Date = '2012-04-12'
Delect #Date - DATEPART(dw, #Date) + 1 FirstDateOfWeek,
#Date + (7 - DATEPART(dw, #Date)) LastDateOfWeek
With a calendar date already loaded, group can be done like this for all the years existing in the table =)
select
Y,
M,
(Select dateadd(ww, datediff(ww, 0, dt), 0) ) wk_str_dt ,
(Select dateadd(ww, datediff(ww, 0, dt), 4) )wk_end_dt ,
dt recd_crt_dt
from [tcalendar]
where isWeekday= 1
AND DW = 2 -- only mondays
order by Y, W
With SQL Server, I have a column with a launch date (dateTime). I want to report on everything that is being launched between all of last month (from viewing date) thru all of this month and next month.
So basically a full 3 month period.
What is the best way to write that?
Are you looking for something like this?
DECLARE
#StartDate DATETIME,
#EndDate DATETIME
SELECT
#StartDate = DATEADD(MM, DATEDIFF(MM, 0, GETDATE()) - 1, 0),
#EndDate = DATEADD(MM, DATEDIFF(MM, 0, GETDATE()) + 2, 0)
-- DATEADD(MM, DATEDIFF(MM, 0, GETDATE()), 0), -- beginning of this month
-- DATEADD(MM, DATEDIFF(MM, 0, GETDATE()) - 1, 0), -- beginning of last month
-- DATEADD(MM, DATEDIFF(MM, 0, GETDATE()) + 1, 0) -- beginning of next month
-- DATEADD(MM, DATEDIFF(MM, 0, GETDATE()) + 2, 0) -- beginning of two months from now
SELECT
*
FROM
[Table]
WHERE
[LaunchDate] >= #StartDate
AND [LaunchDate] < #EndDate
This will give you all the results starting from the beginning of the previous month and before the beginning of two months from now (a full 3 month range)
Maybe something like SELECT /*what_you_want*/ from launches WHERE lauchDate BETWEEN DATEADD(MONTH, DATEDIFF(MONTH, '19000101', GETDATE()) - 1, '19000101') AND DATEADD(MONTH, DATEDIFF(MONTH, '19000101', GETDATE()) + 2, '19000101')
SELECT Foo
FROM Bar
WHERE LaunchDate >= DATEADD(mm, -1, GETDATE())
AND LaunchDate <= DATEADD(mm, 1, GETDATE())