Does Dynamic Linq support BindingList<T>? - .net-4.0

Question

Question
I'm trying to use the Dynamic Linq Sample from Microsoft with BindingList<T> objects. But it looks like the Dynamic Linq will only work with IQueryable. What's the deal here, why doesn't BindingList<T> implement IQueryable. And is there a way around this?
Background Detail: I have many data sets that I need to dynamically filter at run time. Here is an example:
BindingList<MyObject> list = new BindingList<MyObject>();
MyObject selectedObj = list.FirstOrDefault(o => o.Name == "Master P")
// then later ...
MyObject selectedObj = list.FirstOrDefault(o => o.City == "Boston")
I am trying to make these queries dynamic, so the user can choose from all properties of MyObject to use in the query.

Answer 1

There is an Extension method on BindingList; AsQueryable(). So you can use
list.AsQueryable();
But if you want to search on all criteria could you create a search that uses an instance of MyObject as the search criteria and then generated a result set based on the Criteria in the object using standard link.
For example:
public List<MyObject> Search(MyObject SearchCriteria)
{
BindingList<MyObject> list = new BindingList<MyObject>();
list.Add(new MyObject("Test", "Boston"));
list.Add(new MyObject("Test2", "Atlanta"));
IEnumerable<MyObject> results = list.AsEnumerable();
if (!String.IsNullOrEmpty(SearchCriteria.Name))
results = results.Where(l => l.Name.Contains(SearchCriteria.Name));
if (!String.IsNullOrEmpty(SearchCriteria.City))
results = results.Where(l => l.City.Contains(SearchCriteria.City));
return results.ToList();
}
So in the following, Results1 will have 2 results and Results 2 will have only 1.
List<MyObject> results1 = Search(new MyObject("Test", ""));
List<MyObject> results2 = Search(new MyObject("Test", "Boston"));
I used a simple structure for MyObject as an example in this:
public class MyObject
{
public MyObject(string name, string city)
{
this.Name = name;
this.City = city;
}
public string Name { get; set; }
public string City { get; set; }
}