I would like to know if anyone can help me with my method. I have the following method, which will zero out the seconds value of a NSDate object:
- (NSDate *)dateWithZeroSeconds:(NSDate *)date {
NSTimeInterval time = round([date timeIntervalSinceReferenceDate] / 60.0) * 60.0;
return [NSDate dateWithTimeIntervalSinceReferenceDate:time];
}
The problem is when passed a date such as:
2011-03-16 18:21:43 +0000
it returns:
2011-03-16 18:22:00 +0000
I do not want this rounding to occur, as it is a user who is actually specifying the date, so it needs to be exact to the minute they request.
Any help is greatly appreciated.
Use floor instead of round:
- (NSDate *)dateWithZeroSeconds:(NSDate *)date
{
NSTimeInterval time = floor([date timeIntervalSinceReferenceDate] / 60.0) * 60.0;
return [NSDate dateWithTimeIntervalSinceReferenceDate:time];
}
Use NSCalendar and NSDateComponents to get the parts of the date. Set the seconds component to 0, then create a new date from that NSDateComponents.
To be complete, here is the code referenced to iOS SDK 8.1 using NSCalendar and NSDateComponents.
+ (NSDate *)truncateSecondsForDate:(NSDate *)fromDate;
{
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
NSCalendarUnit unitFlags = NSCalendarUnitEra | NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay | NSCalendarUnitHour | NSCalendarUnitMinute;
NSDateComponents *fromDateComponents = [gregorian components:unitFlags fromDate:fromDate ];
return [gregorian dateFromComponents:fromDateComponents];
}
Note that as of iOS 8 the calendar unit names have changed.
You can get the start of any time unit — such as an minute — with rangeOfUnit:startDate:interval:forDate:
NSDate *startOfMinuteDate;
[[NSCalendar currentCalendar] rangeOfUnit:NSCalendarUnitMinute
startDate:&startOfMinuteDate
interval:NULL
forDate:originalDate];
Swift 2.2 version of #Neil answer:
func truncateSecondsForDate(fromDate: NSDate) -> NSDate {
let calendar : NSCalendar = NSCalendar.currentCalendar()
let unitFlags : NSCalendarUnit = [.Era , .Year , .Month , .Day , .Hour , .Minute]
let fromDateComponents: NSDateComponents = calendar.components(unitFlags, fromDate: fromDate)
return calendar.dateFromComponents(fromDateComponents)!
}
Swift 4 version :
func truncateSecondsForDate(fromDate: Date) -> Date {
let calendar = Calendar.current
let fromDateComponents: DateComponents = calendar.dateComponents([.era , .year , .month , .day , .hour , .minute], from: fromDate as Date) as DateComponents
return calendar.date(from: fromDateComponents as DateComponents)! as Date
}
Related
Does anyone know if there is a way to set the first day of the week on a NSCalendar, or is there a calendar that already has Monday as the first day of the week, instead of Sunday.
I'm currently working on an app that is based around a week's worth of work, and it needs to start on Monday, not Sunday. I can most likely do some work to work around this, but there will be a lot of corner cases. I'd prefer the platform do it for me.
Thanks in advance
Here's some the code that I'm using. it's saturday now, so what I would hope is that weekday would be 6, instead of 7. that would mean that Sunday would be 7 instead of rolling over to 0
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
[gregorian setFirstWeekday:0];
unsigned unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit | NSWeekCalendarUnit | NSWeekdayCalendarUnit;
NSDateComponents *todaysDate = [gregorian components:unitFlags fromDate:[NSDate date]];
int dayOfWeek = todaysDate.weekday;
Edit: This does not check the edge case where the beginning of the week starts in the prior month. Some updated code to cover this: https://stackoverflow.com/a/14688780/308315
In case anyone is still paying attention to this, you need to use
ordinalityOfUnit:inUnit:forDate:
and set firstWeekday to 2. (1 == Sunday and 7 == Saturday)
Here's the code:
NSCalendar *gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
[gregorian setFirstWeekday:2]; // Sunday == 1, Saturday == 7
NSUInteger adjustedWeekdayOrdinal = [gregorian ordinalityOfUnit:NSWeekdayCalendarUnit inUnit:NSWeekCalendarUnit forDate:[NSDate date]];
NSLog(#"Adjusted weekday ordinal: %d", adjustedWeekdayOrdinal);
Remember, the ordinals for weekdays start at 1 for the first day of the week, not zero.
Documentation link.
This code constructs a date that is set to Monday of the current week:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *today = [NSDate date];
NSDate *beginningOfWeek = nil;
BOOL ok = [gregorian rangeOfUnit:NSWeekCalendarUnit startDate:&beginningOfWeek
interval:NULL forDate: today];
setFirstWeekday: on the NSCalendar object.
Sets the index of the first weekday for the receiver.
- (void)setFirstWeekday:(NSUInteger)weekday
Should do the trick.
In my opinion this settings should be dynamic according to the user locale.
Therefore one should use:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
[gregorian setLocale:[NSLocale currentLocale]];
This will cause the calendar to set the first week day according to the user locale automatically. Unless you are developing your app for a specific purpose/user locale (or prefer to allow the user to choose this day).
I've done it like this.
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *today = [NSDate date];
NSDateComponents *compForWeekday = [gregorian components:(NSWeekdayCalendarUnit) fromDate:today];
NSInteger weekDayAsNumber = [compForWeekday weekday]; // The week day as number but with sunday starting as 1
weekDayAsNumber = ((weekDayAsNumber + 5) % 7) + 1; // Transforming so that monday = 1 and sunday = 7
I had trouble with a lot of the answers here. . maybe it was just me. .
Here's an answer that works for me:
- (NSDate*)firstDayOfWeek
{
NSCalendar* cal = [[NSCalendar currentCalendar] copy];
[cal setFirstWeekday:2]; //Override locale to make week start on Monday
NSDate* startOfTheWeek;
NSTimeInterval interval;
[cal rangeOfUnit:NSWeekCalendarUnit startDate:&startOfTheWeek interval:&interval forDate:self];
return startOfTheWeek;
}
- (NSDate*)lastDayOfWeek
{
NSCalendar* cal = [[NSCalendar currentCalendar] copy];
[cal setFirstWeekday:2]; //Override locale to make week start on Monday
NSDate* startOfTheWeek;
NSTimeInterval interval;
[cal rangeOfUnit:NSWeekCalendarUnit startDate:&startOfTheWeek interval:&interval forDate:self];
return [startOfTheWeek dateByAddingTimeInterval:interval - 1];
}
Update:
As pointed out (elsewhere) by #vikingosegundo, in general its best to let the local determine which day is the start of the week, however in this case the OP was asking for the start of the week to occur on Monday, hence we copy the system calendar, and override the firstWeekDay.
The problem with Kris' answer is the edge case where the beginning of the week starts in the prior month. Here's some easier code and it also checks the edge case:
// Finds the date for the first day of the week
- (NSDate *)getFirstDayOfTheWeekFromDate:(NSDate *)givenDate
{
NSCalendar *calendar = [NSCalendar currentCalendar];
// Edge case where beginning of week starts in the prior month
NSDateComponents *edgeCase = [[NSDateComponents alloc] init];
[edgeCase setMonth:2];
[edgeCase setDay:1];
[edgeCase setYear:2013];
NSDate *edgeCaseDate = [calendar dateFromComponents:edgeCase];
NSDateComponents *components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:edgeCaseDate];
[components setWeekday:1]; // 1 == Sunday, 7 == Saturday
[components setWeek:[components week]];
NSLog(#"Edge case date is %# and beginning of that week is %#", edgeCaseDate , [calendar dateFromComponents:components]);
// Find Sunday for the given date
components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:givenDate];
[components setWeekday:1]; // 1 == Sunday, 7 == Saturday
[components setWeek:[components week]];
NSLog(#"Original date is %# and beginning of week is %#", givenDate , [calendar dateFromComponents:components]);
return [calendar dateFromComponents:components];
}
I see misunderstanding in the other messages. The first weekday, whichever it is, has number 1 not 0. By default Sunday=1 as in the "Introduction to Date and Time Programming Guide for Cocoa: Calendrical Calculations":
"The weekday value for Sunday in the Gregorian calendar is 1"
For the Monday as a first workday the only remedy I have is brute force condition to fix the calculation
NSCalendar *cal=[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *comps = [cal components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
// set to 7 if it's Sunday otherwise decrease weekday number
NSInteger weekday=[comps weekday]==1?7:[comps weekday]-1;
Below also covers the edge case,
- (NSDate *)getFirstDayOfTheWeekFromDate:(NSDate *)givenDate
{
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:givenDate];
[components setWeekday:2]; // 1 == Sunday, 7 == Saturday
if([[calendar dateFromComponents:components] compare: curDate] == NSOrderedDescending) // if start is later in time than end
{
[components setWeek:[components week]-1];
}
return [calendar dateFromComponents:components];
}
You can just change .firstWeekday of the calendar.
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
calendar.firstWeekday = 2;
Then use rangeOfUnit:startDate:interval:forDate: to get the first day
NSDate *startOfWeek;
[calendar rangeOfUnit:NSCalendarUnitWeekOfYear startDate:&startOfWeek interval:nil forDate:[NSdate date]];
Try this:
NSCalendar *yourCal = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]
[yourCal setFirstWeekday:0];
Iv found out the way to display any weekday name using nscalender..using the following code..
Just open your console from xcode menu bar to see the results.Copy Paste the following code in your viewDidLoad method to get the first day of the week
NSDate *today = [NSDate date];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"MM/dd/yyyy :EEEE"];
NSString *dateString = [dateFormat stringFromDate:today];
NSLog(#"date: %#", dateString);
[dateFormat release];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [gregorian components:NSWeekdayCalendarUnit | NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:today];
[components setDay:([components day]-([components weekday]-1))];
NSDate *beginningOfWeek = [gregorian dateFromComponents:components];
NSDateFormatter *dateFormat_first = [[NSDateFormatter alloc] init];
[dateFormat_first setDateFormat:#"MM/dd/yyyy :EEEE"];
NSString *dateString_first = [dateFormat_first stringFromDate:beginningOfWeek];
NSLog(#"First_date: %#", dateString_first);
The Output will be:
date: 02/11/2010 :Thursday
First_date: 02/07/2010 :Sunday
since i had run this program on 2/11/2010 u will get the desired output depending on the current date.
Similarly if u want to get the first working day of the week i.e Monday's date then just modify the code a bit:
CHANGE :[components setDay:([components day]-([components weekday]-1))];
TO
[components setDay:([components day]-([components weekday]-2))];
to get Mondays date for that week..
Similarly u can try to find the date of any of seven workdays by changing the integer -1,-2 and so on...
Hope u r question is answered..
Thanks,
Bonson Dias
The ISO 8601 calendar appears to have it's first weekday set to monday by default.
Using the Calendar nextWeekend (iOS 10 or later) and ordinality (thanks #kris-markel). I've gotten Monday as first of the week for the en_US calendar.
Here is an example of it with fallback to firstWeekday:
extension Calendar {
var firstWorkWeekday: Int {
guard #available(iOS 10.0, *) else{
return self.firstWeekday
}
guard let endOfWeekend = self.nextWeekend(startingAfter: Date())?.end else {
return self.firstWeekday
}
return self.ordinality(of: .weekday, in: .weekOfYear, for: endOfWeekend) ?? self.firstWeekday
}
}
The Swift solution (note, use .yearForWeekOfYear, not .year):
let now = Date()
let cal = Calendar.current
var weekComponents = cal.dateComponents([.yearForWeekOfYear, .weekOfYear,
.weekday], from: now)
//weekComponents.weekday = 1 // if your week starts on Sunday
weekComponents.weekday = 2 // if your week starts on Monday
cal.date(from: weekComponents) // returns date with first day of the week
… is there a calendar that already has Monday as the first day of the week, instead of Sunday.
Someday, there will be.
My simple way of doing this is to get Monday = 0, Sunday = 6:
NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
NSInteger dayNumStartingFromMonday = ([dateComponents weekday] - 2 + 7) % 7; //normal: Sunday is 1, Monday is 2
I want to set the NSDate time with my desired hours:minutes:seconds
currently im working with NSDate component but it is not giving the desired result
[comps setHour: -hours];
[comps setMinute:0];
[comps setSecond:0];
NSDate *minDate = [calendar_c dateFromComponents:comps];
This works great as an NSDate category.
/** Returns a new NSDate object with the time set to the indicated hour,
* minute, and second.
* #param hour The hour to use in the new date.
* #param minute The number of minutes to use in the new date.
* #param second The number of seconds to use in the new date.
*/
-(NSDate *) dateWithHour:(NSInteger)hour
minute:(NSInteger)minute
second:(NSInteger)second
{
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components: NSYearCalendarUnit|
NSMonthCalendarUnit|
NSDayCalendarUnit
fromDate:self];
[components setHour:hour];
[components setMinute:minute];
[components setSecond:second];
NSDate *newDate = [calendar dateFromComponents:components];
return newDate;
}
With the above category, if you have an existing date you want to change the time on, you do so like this:
NSDate *newDate = [someDate dateWithHour:10 minute:30 second:00];
If, however, you are trying to add or subtract hours from an existing date, a category method to do that is also straightforward:
/** Returns a new date with the given number of hours added or subtracted.
* #param hours The number of hours to add or subtract from the date.
*/
-(NSDate*)dateByAddingHours:(NSInteger)hours
{
NSDateComponents *components = [[NSDateComponents alloc] init];
[components setHour:hours];
return [[NSCalendar currentCalendar]
dateByAddingComponents:components toDate:self options:0];
}
Your approach should work fine. I needed a solution for this type problem (setting the individual date components) and the following code works as expected for me. My situation: I wanted to create a date object that used the current date but had the time set to a value that was passed in as a string.
NSString *string = #"7:00";
NSLocale *locale = [[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"];
NSDateFormatter *timeOnlyFormatter = [[NSDateFormatter alloc] init];
[timeOnlyFormatter setLocale:locale];
[timeOnlyFormatter setDateFormat:#"h:mm"];
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *today = [NSDate date];
NSDateComponents *todayComps = [calendar components:(NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit) fromDate:today];
NSDateComponents *comps = [calendar components:(NSHourCalendarUnit | NSMinuteCalendarUnit) fromDate:[timeOnlyFormatter dateFromString:string]];
comps.day = todayComps.day;
comps.month = todayComps.month;
comps.year = todayComps.year;
NSDate *date = [calendar dateFromComponents:comps];
[calendar release];
[timeOnlyFormatter release];
[locale release];
One thing to note is that you really have to pay attention to time zones when you are judging whether a time appears to be accurate. For example, in my app, when you stop at a breakpoint, you will see the time in GMT (so it looks different than the input time, which is in my local time), but when the time is actually displayed on screen in the app, it is being formatted to display in the local timezone. You may need to take this into consideration to determine whether the result is actually different from what you would expect.
If this does not help, can you elaborate on "not giving the desired result"? What result is it giving and how does that compare to what you expected?
is Swift2
extension NSDate {
func dateWithHour (hour: Int, minute:Int, second:Int) ->NSDate?{
let calendar = NSCalendar.currentCalendar(),
components = calendar.components([.Day,.Month,.Year], fromDate: self)
components.hour = hour;
components.minute = minute;
components.second = second;
return calendar.dateFromComponents(components)
}
}
You can set 0 to hour, min, and second.
NSDateFormatter *tFmt = [[NSDateFormatter alloc] init];
tFmt.dateFormat = #"yyyy-MM-dd";
NSString *strNowDate = [NSString stringWithFormat:#"%# 00:00:00",[tFmt stringFromDate:[NSDate date]]];
NSDate *nowDate = [NSDate dateWithString:strNowDate formatString:#"yyyy-MM-dd HH:mm:ss"];
Swift 5 solution (based on #dattk answer) for those who fear Deprecation warnings :)
func date(withHour hour: Int, withMinute minute: Int, withSeconds second: Int) -> Date? {
let now = Date()
let calendar = NSCalendar.current
var components = calendar.dateComponents([.day,.month,.year], from: now)
components.hour = hour
components.minute = minute
components.second = second
return calendar.date(from: components)
}
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
NSDateComponents *comps = [calendar components:(NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:[NSDate date]];
comps.hour = 0;
comps.minute = 15;
NSDate *date = [calendar dateFromComponents:comps];
iOS 8
how do I set an existing NSDate's time?
That is I have a date (say current date/time), but then want to set this to a specific time (e.g. 11.23am) say. What is the quickest way to do this in objective C?
I'm looking at NSCalendar and see methods such as dateByAddingComponents:toDate:options:, and dateFromComponents:, but these don't seem to quite hit the mark for what I need here. For example:
dateFromComponents: - I would have to work out all components for this to work which seems like overkill
dateByAddingComponents:toDate:options: - I don't want to ADD in my case but rather "set" the time.
NSDate *date = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier: NSGregorianCalendar];
NSDateComponents *components = [gregorian components: NSUIntegerMax fromDate: date];
[components setHour: 7];
[components setMinute: 59];
[components setSecond: 17];
NSDate *newDate = [gregorian dateFromComponents: components];
I use NSUIntegerMax instead of specific OR-combined bit masks because it's easier, but if you want to specify which data components to receive, be my guest.
iOS 7 Note: I'm putting this in a few of these questions because use of NSUIntegerMax no longer seems to work on iOS7, and using it caused me to chase my tail for about 3 hours. I just discovered that when I use NSUIntegerMax, NSDateComponentsignores set year. So for example this DOES NOT change the year:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *comps = [gregorian components:NSUIntegerMax fromDate:date];
[comps setYear:year];
return [gregorian dateFromComponents:comps];
Whereas this DOES:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSUInteger timeComps = (NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit | NSTimeZoneCalendarUnit);
NSDateComponents *comps = [gregorian components:timeComps fromDate:date];
[comps setYear:year];
return [gregorian dateFromComponents:comps];
It may be an iOS7 bug or it may be that using NSUIntegerMax working was a fluke which no longer works. I will file a bug report and get a definitive answer.
Regardless, if you want to avoid unexpected consequences specify ALL the components else you might be chasing your tail!
Swift 2.0 version of how you'd set a given date to 8am
extension NSDate {
func setTo8AM() -> NSDate {
let calendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)!
let components = calendar.components(([.Day, .Month, .Year]), fromDate: self)
components.hour = 8
return calendar.dateFromComponents(components)!
}
}
Apply this to set the Time from an another date to an existing Date
NSDate *today = [NSDate date]; // from which i need only "Year" "Month" "Date"
NSCalendar *calendar = [NSCalendar currentCalendar]
NSDateComponents *dateComponents = [calendar components:( NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit ) fromDate:today];
NSDate *timeDate = datePicker.date; // from which i need only "Hours" "Minutes" and "Seconds"
NSDateComponents *timeComponents = [calendar components:( NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit ) fromDate:timeDate];
[dateComponents setHour:[timeComponents hour]];
[dateComponents setMinute:[timeComponents minute]];
[dateComponents setSecond:[timeComponents second]];
NSDate *newDate = [calendar dateFromComponents:dateComponents]; // New Date with My "Year" "Month" "Date" "Hours" "Minutes" and "Seconds"
NSLog(#"New Date: %#",newDate);
Here's a more generic Swift (v2.1.1) extension that builds on Andrew Schreiber's helpful answer.
extension NSDate {
func dateWithTime(hour: Int, minute: Int, second: Int) -> NSDate? {
let calendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)!
let components = calendar.components(([.Day, .Month, .Year]), fromDate: self)
components.hour = hour
components.minute = minute
components.second = second
let newDate = calendar.dateFromComponents(components)
return newDate
}
}
A swift example. For my purposes, I wanted to get the date for around 12 noon tomorrow.
var tomorrow:NSDate = NSDate().dateByAddingTimeInterval(60*60*24); //60seconds*60minutes*12hours
var gregorian:NSCalendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)!;
var unit : NSCalendarUnit = (NSCalendarUnit.YearCalendarUnit|NSCalendarUnit.MonthCalendarUnit|NSCalendarUnit.DayCalendarUnit|NSCalendarUnit.HourCalendarUnit|NSCalendarUnit.MinuteCalendarUnit);
var comps:NSDateComponents = gregorian.components(unit, fromDate: tomorrow);
comps.setValue(12, forComponent: NSCalendarUnit.HourCalendarUnit);
comps.setValue(0, forComponent: NSCalendarUnit.MinuteCalendarUnit);
var noon_tomorrow : NSDate = gregorian.dateFromComponents(comps)!;
So I have a unixtime datetime stamp. For arguments sake, lets say it's now at 23:49:24 on 21/02/2011 (GMT). This would be:
1298332164
Now, is there anyway to remove the seconds component from this? I'm writing this in Obj-C so currently I have:
NSDate *todayNow = [NSDate date];
int unixtimeNow = [todayNow timeIntervalSince1970];
And would end up with:
1298332140
Thanks
In Cocoa, you can do it like this:
NSCalendar *calendar = [NSCalendar currentCalendar];
NSUInteger calendarUnits = NSEraCalendarUnit | NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit;
NSDateComponents *dateComps = [calendar components:calendarUnits fromDate:todayNow];
[dateComps setSecond:0];
NSDate *todayNowNoSeconds = [calendar dateFromComponents:dateComps];
What about 1298332164 / 60 * 60 ?
NSTimeInterval seconds = fmod([self timeIntervalSince1970], 60);
NSDate *secondsTrimmedDtae = [self dateByAddingTimeInterval:-seconds];
Note self refers to NSDate instance you have to replace self with your date obj.
I know that I can figure out today's date by [NSDate date]; but how would I find out today day of the week, like Saturday, Friday etc.
I know that %w can be used in NSDateFormatter, but I don't know to use it.
NSCalendar* cal = [NSCalendar currentCalendar];
NSDateComponents* comp = [cal components:NSCalendarUnitWeekday fromDate:[NSDate date]];
return [comp weekday]; // 1 = Sunday, 2 = Monday, etc.
See #HuguesBR's answer if you just need the weekday without other components (requires iOS 8+).
NSInteger weekday = [[NSCalendar currentCalendar] component:NSCalendarUnitWeekday
fromDate:[NSDate date]];
(If you don't get a correct answer, check if you have mistyped NSCalendarUnitWeekday with other week-related components like NSCalendarUnitWeekdayOrdinal, etc.)
Swift 3:
let weekday = Calendar.current.component(.weekday, from: Date())
// 1 = Sunday, 2 = Monday, etc.
If someone is interested in a Swift solution, then use:
import Foundation
let weekday = NSCalendar.current.component(.weekday, from: Date())
print(weekday) // => prints the weekday number 1-7 (Sunday through Saturday)
See the demo.
Update: fixed to work in Swift 3
This is updated version valid for iOS 8
NSCalendar* currentCalendar = [NSCalendar currentCalendar];
NSDateComponents* dateComponents = [currentCalendar components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
return [dateComponents weekday];
Shorter version
NSCalendarUnit dayOfTheWeek = [[NSCalendar currentCalendar] component:NSCalendarUnitWeekday fromDate:yourDate];
let today = Date()
let day = Calendar.current.dateComponents([.weekday], from: today).weekday
if ( day == 5)
{
yourText.text = "Thursday"
}