variable argument function - variables

Question

while doing a program related to variable argument function i
got the header file stdarg.h and have done some simple problem using it
but now when i a changing the actual argument's type it is showing some weird behaviour
here is my code:
#include<stdio.h>
#include<stdarg.h>
void fun(int a,...)
{
va_list k;
va_start(k,a);
int i=0;
printf("%d ",a);
while((i=va_arg(k,int)!=0)
{
printf(" %d ",i);
}
va_end(k);
}
int main()
{
fun(1,2,3,4,5,6);
printf("\n");
fflush(); //and without flush it is also showing some extra garbage value
fun(2,4,5);
printf("\n");
fflush();
fun('c','f','g','l');
return 0;
}

Answer 1

If you use the integer value 0 to indicate end of the argument list, you should also pass a 0 to fun.
fun(1,2,3,4,5,6,0);
fun(2,4,5,0);

Answer 2

First, end your list with 0, because you check for !=0 to detect the end. And also:
while((i=va_arg(k,int))!=0)
instead of
while(i=va_arg(k,int)!=0)
!= has higher precedence than =
This will give you the expected output:
1 2 3 4 5 6
Here's the complete code:
#include<stdio.h>
#include<stdarg.h>
void fun(int a,...)
{
va_list k;
va_start(k,a);
int i=0;
printf("%d ",a);
while((i=va_arg(k,int))!=0)
{
printf(" %d ",i);
}
va_end(k);
}
int main()
{
fun(1,2,3,4,5,6,0);
printf("\n");
//fun(2,4,5,0);
printf("\n");
//fun('c','f','g','l','\0');
getch();
return 0;
}