I was trying with a code that coverts Text to Image using Vb.net and my problem is I need to accept a message from user (Max 160 Characters) by a text box and i need to convert it to a Image. The generated image should be aligned in the middle and the image max resolution should be 800x600.
So the message should be neatly aligned in new lines if needed and perfectly aligned to the middle.
The code I am trying is as follows:
======================================================
Try
Dim Text As String = TextBox3.Text
Dim FontColor As Color = Color.Blue
Dim BackColor As Color = Color.White
Dim FontName As String = "Times New Roman"
Dim FontSize As Integer = 36
Dim Height As Integer = 60
Dim Width As Integer = 200
Dim daten As String
daten = Now.ToString("ddMMyyyyhhmmss")
Dim FileName As String = daten
Dim objBitmap As New Bitmap(Width, Height)
Dim objGraphics As Graphics = Graphics.FromImage(objBitmap)
Dim objColor As Color
objColor = Nothing
Dim objFont As New Font(FontName, FontSize)
'Following PointF object defines where the text will be displayed in the
'specified area of the image
Dim objPoint As New PointF(5.0F, 5.0F)
Dim objBrushForeColor As New SolidBrush(FontColor)
Dim objBrushBackColor As New SolidBrush(BackColor)
objGraphics.FillRectangle(objBrushBackColor, 0, 0, Width, Height)
objGraphics.DrawString(Text, objFont, objBrushForeColor, objPoint)
objBitmap.Save("D:\DNB\" + daten + ".JPG", ImageFormat.Jpeg)
PictureBox1.Image = Image.FromFile("D:\DNB\" + daten + ".JPG")
Catch ex As Exception
End Try
Have you tried the MeasureString function of the Graphics object and it's various overrides? With that you can measure how much space a text in a given size and font needs on the screen. With that knowledge you can calculate the upper left point to use to make the text appear centered.
I have a form that is going to allow a user to create custom "stamps" to place on a PDF. The form displays with a image of the first page of the pdf and I want the user to basically click on the screen where they want their stamp and be able to preview what its going to look like. Don't worry about any of the PDF stuff, I have that handled.
To make things snazzy, I have two copies of the image, the normal one and one with reduced brightness. I display the low brightness image and as the user moves the mouse over, a chunk of the original image is revealed or highlighted. I then display in that area the text the user is going to put on the PDF.
I allow the user to use the mousewheel to scroll and change the angle of the text they are placing (from -45 degrees to +45 degrees).
Here is my problem: I can't calculate the proper rectangles/coordinates. Sometimes everything looks great, other times (as font sizes change) they don't quite fit.
How do I calculate the x and y coordinates for:
placement of the rotated text
AND a bounding rectangle padding the text at its width and height with 10px
The code below works, until I start to crank up the font size, then everything gets out of skew.
First two images show text + bounding rectangle at smaller fonts. It looks good:
The next image shows that as the text size gets larger, my pixels are moving all around and gets chopped off. In even larger text, the widths/heights end being way off as well.
Sorry the example images don't show much detail. I have actual data that I can't share.
Private Sub PanelMouseMove(ByVal sender As Object, ByVal e As MouseEventArgs) '// handles the mouse move (handler added elsehwere)
With CType(sender, PictureBox)
.Image.Dispose() '// get rid of old image
Dim b As Bitmap = _curGray.Clone '// the low brightness image as the base image
'// stamp font and text values are initiated from another form
Using g As Graphics = Graphics.FromImage(b),
f As New Font(DefaultFont.FontFamily, CSng(_stmpTools.StampTextSize), If(_stmpTools.StampBold, FontStyle.Bold, FontStyle.Regular))
Const borderWidth As Integer = 10
Const borderPadding As Integer = 5
'// measure the string
Dim szx As SizeF = g.MeasureString(_stmpTools.StampText, f, Integer.MaxValue, StringFormat.GenericDefault)
Dim strLength As Single = szx.Width
Dim strHeight As Single = szx.Height
Dim x As Single = e.X - borderWidth - borderPadding,
y As Single = e.Y
Dim w As Double, h As Double
If Math.Abs(_angle) > Double.Epsilon Then
h = CDbl(strLength) * Math.Sin(CDbl(Math.Abs(_angle)) * Math.PI / 180.0F)
w = Math.Sqrt(CDbl(strLength) * CDbl(strLength) - h * h)
Else
'// its zero. so use calculated values
h = strHeight
w = strLength
End If
'// add space for the 10px border plus 5px of padding
Dim r As New Rectangle(0, 0, w, h)
r.Inflate(borderWidth + borderPadding, borderWidth + borderPadding)
h = r.Height
w = r.Width
'// keep box from moving off the left
If x < .Location.X Then
x = .Location.X
End If
'// keep box from moving off the right
If x > .Location.X + .Width - w Then
x = .Location.X + .Width - w
End If
'// I don't know, but these values work for most smaller fonts, but
'// it has got to be a fluke
If _angle > 0 Then
y = y - h + borderWidth + borderWidth
Else
y = y - borderWidth
End If
'// can't go off the top
If y < .Location.Y Then
y = .Location.Y
End If
'// can't go off the bottom
If y > .Location.Y + .Height - h Then
y = .Location.Y + .Height - h
End If
Dim rect As New Rectangle(x, y, w, h)
g.DrawImage(_curImg, rect, rect, GraphicsUnit.Pixel)
Using br As New SolidBrush(_stmpTools.StampTextColor)
RotateString(_stmpTools.StampText, _angle, e.X, e.Y, f, g, br)
End Using
'//draw bounding rectangle
Using p As New Pen(Color.Black, borderWidth)
g.DrawRectangle(p, rect)
End Using
End Using
'// set the picture box to show the new image
.Image = b
End With
End Sub
Private Sub RotateString(ByVal Text As String, ByVal angle As Integer, _
ByVal x As Integer, ByVal y As Integer, myfont As Font, mydrawing As Graphics, myColor As Brush)
Dim myMatrix As New Matrix
myMatrix.RotateAt(angle * -1, New Point(x, y)) 'Rotate drawing
mydrawing.Transform = myMatrix
mydrawing.DrawString(Text, myFont, myColor, x, y) 'Draw the text string
myMatrix.RotateAt(angle, New Point(x, y)) 'Rotate back
mydrawing.Transform = myMatrix
End Sub
I'm not the greatest when it comes to drawing. So any help would be great
Using the solution below from #LarsTech. I replaced the g.FillRectangle with:
g.DrawImage(_curImg, r, r, GraphicsUnit.Pixel)
_curImg is a copy of the original image with the brightness tuned up. When I change the code from below I end up with:
Note the double lines. They rotate with the stamp, even though they are acting as a background image and should be unrotated
Per suggestion, I changed the DrawStamp from #LarsTech to the following:
Private Sub DrawStamp(g As Graphics, text As String,
f As Font, center As Point, angle As Integer, backImg As Image)
Dim s As Size = g.MeasureString(text, f).ToSize
Dim r As New Rectangle(center.X - (s.Width / 2) - 16,
center.Y - (s.Height / 2) - 16,
s.Width + 32,
s.Height + 32)
g.DrawImage(backImg, r, r, GraphicsUnit.Pixel)
Using m As New Matrix
m.RotateAt(angle, center)
g.Transform = m
Using p As New Pen(Color.Black, 6)
g.DrawRectangle(p, r)
End Using
Using sf As New StringFormat
sf.LineAlignment = StringAlignment.Center
sf.Alignment = StringAlignment.Center
g.DrawString(text, f, Brushes.Black, r, sf)
End Using
g.ResetTransform()
End Using
End Sub
However, I am now left with
Notice it drew the background, then did the rotation and drew the stamp. It ALMOST works. In this example the straight lines show the intended behavior... however i'm looking to fill the entire stamp with the background. That extra white on the sides would have been what was rotated into the stamp's background. I'm confused because the 'grey' portions I would then suspect to be clipping out parts of the image, but they aren't (if i move it over other areas that I unfortunately can't post on here) notice is out of skew except for the fact that the sides of the rectangle paint as such.
Another Edit with hopefully some more info
Here is hopefully a better explaination of what I am trying to do. I use a third party PDF viewer and I need to allow the user to add an image to the PDF. The viewer doesn't allow me to raise click events on it, so in order to grab user mouse clicks, I do the following:
Take a screen grab of form
Hide the PDF Viewer
Add a PictureBox control to my form, replacing the area where the PDF viewer was
With my screen grab, I make a copy of the image with the brightness reduced
Display the gray scale copy of the image and draw directly on the image using mouse over events on the picturebox
I draw a stamp on the picturebox, but want the background of it to be the original (non adjusted brightness image). However, since the area might be transformed using a rotation, I can't grab the background image. If no angle is provided, the source rectangle matches. However if its rotated, I cannot grab the same rotated rectangle off the source image.
Button Click Event:
Dim bds As Rectangle = AxDPVActiveX1.Bounds
Dim pt As Point = AxDPVActiveX1.PointToScreen(bds.Location)
Using bit As Bitmap = New Bitmap(bds.Width, bds.Height)
Using g As Graphics = Graphics.FromImage(bit)
g.CopyFromScreen(New Point(pt.X - AxDPVActiveX1.Location.X, pt.Y - AxDPVActiveX1.Location.Y), Point.Empty, bds.Size)
End Using
_angle = 0
_curImg = bit.Clone
_curGray = Utils.CopyImageAndAdjustBrightness(bit, -100)
End Using
Dim p As New PictureBox
Utils.SetControlDoubleBuffered(p)
p.Dock = DockStyle.Fill
p.BackColor = Color.Transparent
AxDPVActiveX1.Visible = False
p.Image = _curImg.Clone
AddHandler p.MouseClick, AddressOf PanelDownMouse
AddHandler p.MouseMove, AddressOf PanelMouseMove
AddHandler p.MouseWheel, Sub(s As Object, ee As MouseEventArgs)
_angle = Math.Max(Math.Min(_angle + (ee.Delta / 30), 45), -45)
PanelMouseMove(s, ee)
End Sub
AddHandler p.MouseEnter, Sub(s As Object, ee As EventArgs)
CType(s, Control).Focus()
End Sub
AxDPVActiveX1.Parent.Controls.Add(p)
After that code I end up with two images. _curgray is an image with adjusted brightness, and _curImg is my original screen grab.
_curGray:
_curImg:
A mouseMove move event is applied to my new picture box. This is where all the code from earlier in the question comes into play.
Using the code above, my mouseMove event keeps creating a new imageto display in my picture box. If there is no rotation involved, I get pretty much what I'm looking for. Notice in the below image how the background of the stamp is brighter than everything. The portion over the blue square is slightly lighter. I am using this a way to draw the viewers eye to this area... its important for what I'm doing.
However, when applying a rotation to it, I cannot seem to copy from the original image. Look at the following image, the backgroundisn't rotating with it. I need to grab a rotated rectangle from the ORIGINAL image.
http://msdn.microsoft.com/en-us/library/ms142040(v=vs.110).aspx Graphics.DrawImage() accepts
Public Sub DrawImage ( _
image As Image, _
destRect As Rectangle, _
srcRect As Rectangle, _
srcUnit As GraphicsUnit _
)
where I can specify copy this source rectangle from my source image (in this case _curImg) and place onto my new drawing. It does not allow me to apply a transformation to the source rectangle. Basically I want to copy from my source image an area equivalent to the rotated rectangle (based on the transformation from #larstech )
I don't know how to express this concept any clearer. If it still doesn't make sense I will just accept LarsTech answer as the best answer and scrap my idea.
It's just trigonometry:
You know c because you know how wide the original text is, and you know h because you know the height of your text. You also need to know alpha, it's the angle that you rotated your text.
Now you need to work the power of math: First take the small rectangles at the end. In the bottom left you can see, that the angle right of the x is actually 180°-90°-alpha, or 90°-alpha. So alpha is also found on the opposite site. So you can find x:
x = h * sin(alpha)
The same goes for y, but it's either sin(90°-alpha), or cos(alpha)
y = h * cos(alpha)
Next you need to find a and b to complete the rectangle. The large triangle gives you
a = w * cos(alpha)
and
b = w * sin(alpha)
Then just add the parts together:
NewWidth = a + x
NewHeight = b + y
That way you get the size of the bounding box. As for the coordinates, it depends on which point is actually defined when you print the rotated text.
I would try drawing the rectangle and the text together:
Private Sub DrawStamp(g As Graphics, text As String,
f As Font, center As Point, angle As Integer)
Using m As New Matrix
g.SmoothingMode = SmoothingMode.AntiAlias
g.TextRenderingHint = TextRenderingHint.AntiAlias
m.RotateAt(angle, center)
g.Transform = m
Dim s As Size = g.MeasureString(text, f).ToSize
Dim r As New Rectangle(center.X - (s.Width / 2) - 16,
center.Y - (s.Height / 2) - 16,
s.Width + 32,
s.Height + 32)
g.FillRectangle(Brushes.White, r)
Using p As New Pen(Color.Black, 6)
g.DrawRectangle(p, r)
End Using
Using sf As New StringFormat
sf.LineAlignment = StringAlignment.Center
sf.Alignment = StringAlignment.Center
g.DrawString(text, f, Brushes.Black, r, sf)
End Using
g.ResetTransform()
End Using
End Sub
The paint example:
Protected Overrides Sub OnPaint(e As PaintEventArgs)
MyBase.OnPaint(e)
e.Graphics.Clear(Color.LightGray)
Using f As New Font("Calibri", 16, FontStyle.Bold)
DrawStamp(e.Graphics,
"Reviewed By Doctor Papa",
f,
New Point(Me.ClientSize.Width / 2, Me.ClientSize.Height / 2),
-25)
End Using
End Sub
Result:
Here I updated the code to "clip" the rotated rectangle so that I can copy that same area from the original image before applying the text and border:
Private Sub DrawStamp(g As Graphics, text As String,
f As Font, center As Point, angle As Integer)
Dim s As Size = g.MeasureString(text, f).ToSize
Dim r As New Rectangle(center.X - (s.Width / 2) - 16,
center.Y - (s.Height / 2) - 16,
s.Width + 32,
s.Height + 32)
Using bmp As New Bitmap(_curImg.Width, _curImg.Height)
Using gx As Graphics = Graphics.FromImage(bmp)
Using m As New Matrix
m.RotateAt(angle, center)
gx.Transform = m
gx.SetClip(r)
gx.ResetTransform()
End Using
gx.DrawImage(_curImg, Point.Empty)
End Using
g.DrawImage(bmp, Point.Empty)
End Using
Using m As New Matrix
g.SmoothingMode = SmoothingMode.AntiAlias
g.TextRenderingHint = TextRenderingHint.AntiAlias
m.RotateAt(angle, center)
g.Transform = m
Using p As New Pen(Color.Black, 6)
g.DrawRectangle(p, r)
End Using
Using sf As New StringFormat
sf.LineAlignment = StringAlignment.Center
sf.Alignment = StringAlignment.Center
g.DrawString(text, f, Brushes.Black, r, sf)
End Using
g.ResetTransform()
End Using
End Sub
New Result:
I am adding watermark text to PDFs in a class library I have created. The code I posted below works fine, however the watermark is sometimes difficult to read because it overlays with content on the PDF. How would I go about adding a white background color around the watermark text? I basically would like the watermark text to be surrounded inside a white rectangle the size of the text. Thanks
Public Function AddWatermarkText(ByVal tempDirectory As String) As String
' Just return the full path of the PDF if we don't need to add a watermark.
If Me.Document.RevRank <> 0 OrElse Me.Document.ReleaseDate Is Nothing Then Return Me.FullPath
Dim reader As iTextSharp.text.pdf.PdfReader = Nothing
Dim stamper As iTextSharp.text.pdf.PdfStamper = Nothing
Dim gstate As New iTextSharp.text.pdf.PdfGState()
Dim overContent As iTextSharp.text.pdf.PdfContentByte = Nothing
Dim rect As iTextSharp.text.Rectangle = Nothing
Dim watermarkFont As iTextSharp.text.pdf.BaseFont = Nothing
Dim folderGuid As Guid = Guid.NewGuid()
Dim outputFile As String = tempDirectory & System.IO.Path.DirectorySeparatorChar & folderGuid.ToString() & System.IO.Path.DirectorySeparatorChar _
& Me.Document.Prefix & Me.Document.BaseNumber & Me.Document.Revision & ".pdf"
' Create the temp directory to place the new PDF in.
If Not My.Computer.FileSystem.DirectoryExists(tempDirectory) Then My.Computer.FileSystem.CreateDirectory(tempDirectory)
My.Computer.FileSystem.CreateDirectory(tempDirectory & System.IO.Path.DirectorySeparatorChar & folderGuid.ToString())
reader = New iTextSharp.text.pdf.PdfReader(Me.FullPath)
rect = reader.GetPageSizeWithRotation(1)
stamper = New iTextSharp.text.pdf.PdfStamper(reader, New System.IO.FileStream(outputFile, IO.FileMode.Create))
watermarkFont = iTextSharp.text.pdf.BaseFont.CreateFont(iTextSharp.text.pdf.BaseFont.HELVETICA_BOLD, _
iTextSharp.text.pdf.BaseFont.CP1252, _
iTextSharp.text.pdf.BaseFont.NOT_EMBEDDED)
gstate.FillOpacity = 0.9F
gstate.StrokeOpacity = 1.0F
' Add the watermark to each page in the document.
For i As Integer = 1 To reader.NumberOfPages()
overContent = stamper.GetOverContent(i)
With overContent
.SaveState()
.SetGState(gstate)
.SetColorFill(iTextSharp.text.BaseColor.BLUE)
.Fill()
.BeginText()
.SetFontAndSize(watermarkFont, 8)
.SetTextMatrix(30, 30)
If Me.Document.RevRank = 0 AndAlso Me.Document.ReleaseDate IsNot Nothing Then
.ShowTextAligned(iTextSharp.text.Element.ALIGN_LEFT, UCase(String.Format("CONTROLLED DOCUMENT – THIS COPY IS THE LATEST REVISION AS OF {0}" _
, Date.Now.ToString("ddMMMyyyy"))), 10, rect.Height - 15, 0)
End If
.Fill()
.EndText()
.RestoreState()
End With
Next
stamper.Close()
reader.Close()
Return outputFile
End Function
I usually like to have code that you can just plop in but unfortunately you're code is a little too domain-specific to provide a direct answer (lots of Me.* that we have to guess at) but I can still get you there with a little code refactoring.
To do what you want to do you have to measure the string that you are drawing and then draw a rectangle to those dimensions. The PDF spec doesn't have a concept of "background color" for text and any implementation that makes it look like it does is really just drawing rectangles for you. (Yes, you can highlight text but that's an Annotation which is different.)
So first I'm going to pull things out into variables so that we can reuse and adjust them easier:
''//Text to measure and draw
Dim myText As String = UCase(String.Format("CONTROLLED DOCUMENT – THIS COPY IS THE LATEST REVISION AS OF {0}", Date.Now.ToString("ddMMMyyyy")))
''//Font size to measure and draw with
Dim TextFontSize As Integer = 8
''//Original X,Y positions that we were drawing the text at
Dim TextX As Single = 10
Dim TextY As Single = rect.Height - 15
Next we need to calculate the width and height. The former is easy but the latter requires us to first get the Ascent and Descent of the text and then calculate the difference.
''//Calculate the width
Dim TextWidth As Single = watermarkFont.GetWidthPoint(myText, TextFontSize)
''//Calculate the ascent and decent
Dim TextAscent As Single = watermarkFont.GetAscentPoint(myText, TextFontSize)
Dim TextDescent As Single = watermarkFont.GetDescentPoint(myText, TextFontSize)
''//The height is the difference between the two
Dim TextHeight As Single = TextAscent - TextDescent
(NOTE: I'm not sure if GetWidthPoint(), GetAscentPoint() and GetDescentPoint() work as desired with multi-line text.)
Then you probably want to have some padding between the box and text:
''//Amount of padding around the text when drawing the box
Dim TextPadding As Single = 2
Lastly, somewhere before you setup and draw the text you want to first draw the rectangle:
''//Set a background color
.SetColorFill(BaseColor.YELLOW)
''//Create a rectangle
.Rectangle(TextX - TextPadding, TextY - TextPadding, TextWidth + (TextPadding * 2), TextHeight + (TextPadding * 2))
''//Fill it
.Fill()
I am hoping that someone can help me with a problem I've got at the moment using Compact Framework.Net 2 SP 2.
At the moment I have a UI with a series of text boxes and each textbox displays the contents of a database field. These are shown one beneath another with a scroll bar on the right hand side of the form. Each textbox has a set width which might
I would like to adjust the height each text box based on the number of lines it is holding, the font size and the font in order to avoid using scroll bars on each textbox.
At the moment I am been able to do this in a test application.
Screenshot:
see screenshot for output http://morrislgn.brinkster.net/SO/screenshot.jpg
My code:
'Text used in this example:
'TextBox1qwertyuiop lkjhgfdsazxcvbnm1234567890 TextBo
'x1qwer tyuioplkjhgfdsazxcvb nm1234567890
'qwe
'End of exmaple text.
Me.Textbox2.Text = Me.Textbox1.Text
Dim pobjGraphic As Graphics = Me.Textbox2.Parent.CreateGraphics()
Dim pobjSize As SizeF
'Padding values:
Dim piTop As Int32 = 4 'top of text and top of textbox
Dim piBottom As Int32 = 3 'bottom of text and top of textbox
Dim piLines As Int32 = 0
'Based on the font size chosen by the user, create a font to perform the calculation with.
Dim piFontSize As Single = 10
If Me.CheckBox1.Checked.Equals(True) Then
piFontSize = 6
ElseIf Me.CheckBox2.Checked.Equals(True) Then
piFontSize = 8
ElseIf Me.CheckBox3.Checked.Equals(True) Then
piFontSize = 12
Else
piFontSize = 10
End If
Dim pobjFont As New Font("Tahoma", piFontSize, FontStyle.Regular)
'Calculate the height of one line.
pobjSize = pobjGraphic.MeasureString("HELLO WORLD", pobjFont)
'Value of pobjSize returned: {Width = 71.0 Height = 13.0}
'Calculate the number of lines
Dim b As Bitmap
b = New Bitmap(1, 1, Imaging.PixelFormat.Format32bppRgb)
'Calculate the number of lines required to display the text properly based on the lenght of the text the width of the control.
'Length of text to show divide by the width of the textbox
piLines = Graphics.FromImage(b).MeasureString(Me.Textbox2.Text, pobjFont).Width / Me.Textbox2.Width
'Value of piLines returned: 2
If piLines = 0 Then
piLines = 1
End If
'Calculate the size of the text to be displayed using the margins, height of one line and number of lines.
Me.Textbox2.Height = (pobjSize.Height * piLines) + piTop + piBottom
' value produced: 33 = (13 * 2) + 4 + 3
'set font of text box
Me.Textbox2.Font = pobjFont
Finally, I know this can be achieved using a call to the COREDLL.dll using p/invoke but doing this makes the application crash.
Hi Folks,
Below is the pinvoke code as requested:
<Runtime.InteropServices.DllImport("coredll.dll")> _
Private Function SendMessage( _
ByVal hwnd As IntPtr, ByVal msg As Integer, _
ByVal wParam As Integer, ByVal lParam As Integer) As Integer
End Function
<Runtime.InteropServices.DllImport("coredll.dll")> _
Private Function GetCapture() As IntPtr
End Function
<Runtime.InteropServices.DllImport("coredll.dll")> _
Private Function ReleaseCapture() As Boolean
End Function
Public Function GetNumberOfLines(ByVal ptxtCountBox As TextBox) As Integer
Try
Dim hnd As IntPtr = New IntPtr
ptxtCountBox.Capture = True
' Capture the textbox handle.
hnd = GetCapture()
ptxtCountBox.Capture = False
' Get the count of the lines in the box.
Dim plCount As Integer = SendMessage(ptxtCountBox.Handle, EM_GETLINECOUNT, 0, 0)
' Count the number of return lines as we minus this from the total lines to take.
plCount = plCount - (CharCount(ptxtCountBox.Text, vbCrLf, False))
plCount += RemoveNonASCIIReturns(ptxtCountBox)
ReleaseCapture()
hnd = Nothing
' Return the line count.
Return plCount
Catch ex As Exception
GenerateError(msCLASS_NAME, "GetNumberOfLines", ex.Message.ToString)
End Try
End Function
Thanks,
Morris
I asked a similar question and got an answer that completely satisfied my needs on the subject! Please check out stevo3000's answer from my question:
AutoSize for Label / TextBox in .NET Compact Framework
He referred to these two blog posts that just completely fixed my problem with one swipe!
http://www.mobilepractices.com/2007/12/multi-line-graphicsmeasurestring.html
http://www.mobilepractices.com/2008/01/making-multiline-measurestring-work.html
Think I got to the bottom of this:
Public Function GetNumberOfLines(ByVal pstext As String, ByVal pobjfont As Font, ByVal pobjDimensions As Size) As Decimal
Dim pslines As String() = Nothing
'Used to measure the string to be placed into the textbox
Dim pobjBitMap As Bitmap = Nothing
Dim pobjSize As SizeF = Nothing
Try
Dim psline As String = String.Empty
Dim pilinecount As Decimal = 0.0
'Spilt the text based on the number of lines breaks.
pslines = pstext.Split(vbCrLf)
For Each psline In pslines
'Create a graphics image which is used to work out the width of the text.
pobjBitMap = New Bitmap(1, 1, Imaging.PixelFormat.Format32bppRgb)
pobjSize = Graphics.FromImage(pobjBitMap).MeasureString(psline, pobjfont)
'If the width of the text is less than 1.0 then add one to the count. This would incidcate a line break.
If pobjSize.Width < 1.0 Then
pilinecount = pilinecount + 1
Else
'Based on the dimensions of the text, work out the number of lines. 0.5 is added to round the value to next whole number.
pilinecount = pilinecount + (Round((pobjSize.Width / pobjDimensions.Width) + 0.5))
End If
Next
'If the line count it less than 1 return one line.
If pilinecount < 1.0 Then
Return 1.0
Else
Return pilinecount
End If
Catch ex As Exception
Return 1.0
Finally
If pslines IsNot Nothing Then
Array.Clear(pslines, 0, pslines.Length - 1)
pslines = Nothing
End If
If pobjBitMap IsNot Nothing Then
pobjBitMap.Dispose()
End If
End Try
End Function
Granted, its a bit of a hack but it appears to work ok at the moment! Any observations or comments on how to improve this are more than welcome.
Also, about the p/invoke stuff, discovered the root of the problem, or rather the solution. Upgraded the .Net fx on my device and that appears to have resolved the issue.
Thanks
Morris
Well, I would suggest a sound and smart solution to you.
Here's is the Algorithm:
Use a Label control for reference.
Assign:
• The size of Textbox to the Label.
• The font of Textbox to the Label.
• Autosize-property of Label to be True.
• BorderStyle Property of the Label as of Textbox'.
• MinimumSize Property of Label as original size of the Textbox.
• MaximumSize Property of Label as Width-same as original and Height to be a large multiple the original height.
Assign the Textbox' Text to Label's text.
Now: if the PrefferdHeight-property of Label > Height of the Textbox == True
It's time to increase the height of the Textbox and check the above condition until it’s False.
The Label can be disposed off now.
I have also posted a similar solution in MSDN Forum which can also be checked out:
[http://social.msdn.microsoft.com/Forums/en-US/winforms/thread/03fc8e75-fc13-417a-ad8c-d2b26a3a4dda][1]
Regards.
:)