Google Analytics API: how to extract pageviews for a specific page?
I tried using something like
ga:pagePath=~page.php%3fid%3d44 (page.php?id=44)
but it doesn't seem to work... I get "no results found" where I have 20 pageviews for sure
UPDATE
I think I found the solution
ga:pagePath==/website/page.php?id=44
for some reason I had to include the complete path and ==
To use a partial path to match for a page in filters you should use
ga:pagePath=#page.php?id=44
=# tells ga to match a substring.
What you were originally using was incorrect for this.
I think your problem is that you put the hex version of the ? and = characters into your query, which doesn't match how Analytics stores the page paths. If you change these to the normal characters it should work:
ga:pagePath=~page.php?id=44
Your other solution should work as well but is a bit more inflexible in case you wanted to tweak the query to return other pages.
Related
I am using the Mendeley API to retrieve documents in the profile of a user.
Specifically, I am using this API:
GET https://api.mendeley.com/search/documents?view=all&limit=25&title=ONTOLOGY
I would like to search for all the documents that match a partial term, i.e. instead of the full word "ONTOLOGY" I would like to get the same result if I do an HTTP call like
GET https://api.mendeley.com/search/documents?view=all&limit=25&title=ONTOLO
How can I achieve that?
Should I put any jolly character?
I tried
ONTOLO*
ONTOLO$
ONTOLO?
with no luck.
I haven't found any documentation related to this feature.
Thanks!!
I am trying to retrieve data from cloudSearch, searching for the word "Person" and adding the following filter:
(prefix field=claimedgalleryid '')
The problem is that I don't know how to create the URL using that exact filter.
Could someone give me a suggestion or some link to Amazon documentation related to this topic?
What I've tried and didn't work:
...search?q=Gallerist&size=10&start=0&fq=(prefix%20field=claimedgalleryid%20%27%27)
...search?q=Gallerist&size=10&start=0&filter=(prefix%20field=claimedgalleryid%20%27%27)
You were close with your first attempt--it looks like you forgot to URI encode the = sign as %3D. Try this instead:
&fq=(prefix+field%3Dclaimedgalleryid+'')
I highly recommend using the "test search" feature to work out the kinks in your query syntax. You can see the results right there, and then use the "View Raw: JSON" link to copy the full request URL and see how characters get escaped and such.
I have a Drupal 7 website that is running apachesolr search and is using faceting through the facetapi module.
When I use the facets to narrow my searches, everything works perfectly and I can see the filters being added to the search URL, so I can copy them as links (ready-made narrowed searches) elsewhere on the site.
Here is an example of how the apachesolr URL looks after I select several facets/filters:
search_url/search_keyword?f[0]=im_field_tag_term1%3A1&f[1]=im_field_tag_term2%3A100
Where the 'search_keyword' portion is the text I'm searching for and the '%3A' is just the url encoded ':' (colon).
Knowing this format, I can create any number of ready-made searches by creating the correct format for the URL. Perfect!
However, these filters are always ANDed, the same way they are when using the facet interface. Does anyone know if there is a syntax I can use, specifically in the search URL, to OR my filters/facets? Meaning, to make it such that the result is all entries that contains EITHER of the two filters?
New edit:
I do know how to OR terms for one facet through the URL im_field_tag_term1:(x or y) but I need to know how to apply OR condition between two facets .
Thanks in advance .
I'm using the google custom search api and want to create a search using the siteSearch:
https://www.googleapis.com/customsearch/v1?key=k&cx=cx&q=cocos2d&siteSearch=www.cocos2d-iphone.org&siteSearchFilter=i
and it works fine (returns all the result only from the given site).
Then I want to specify TWO sites to search so I tried to change the :
siteSearch=www.cocos2d-iphone.org
to
siteSearch=www.cocos2d-iphone.org www.XXXXXXXX.org
siteSearch=www.cocos2d-iphone.org|www.XXXXXXXX.org
siteSearch=www.cocos2d-iphone.org||www.XXXXXXXX.org
but none of these works.
hope someone can help here, thanks:)
Currently I don't believe you can specify more site through the query param siteSearch.
nevertheless you can configure your Custom Search Engine here: https://www.google.com/cse/manage/all
in the "Site to search" area.
This also works for excluding, as you can read here: https://support.google.com/customsearch/bin/answer.py?hl=en&answer=2631038&topic=2601037&ctx=topic
You cannot do this with the as_sitesearch parameter as that only accepts a single value. But you can achieve what you want with the as_q parameter, setting it to some value like: "site:google.com OR site:microsoft.com" - that will work in a similar way to this search.
The as_q parameter is documented here as:
The as_q parameter provides search terms to check for in a document.
This parameter is also commonly used to allow users to specify
additional terms to search for within a set of search results.
Examples q=president&as_q=John+Adams
Use "space" as seperator
Below is sample PHP code which works for me
$url="https://www.googleapis.com/customsearch/v1?key=k&cx=cx&q=cocos2d&siteSearch=".urlencode("www.cocos2d-iphone.org www.XXXXXXXX.org")."&siteSearchFilter=i"
Thanks,
Ojal Suthar
I am making some PHP code which takes a given search phrase and url and searches through the google search results until it finds the url (only first 100 results). My problem is, this is only working for the US. I have tried adding the "&cr=" option, but it still on returns US results.
The full URL I am using for the request is:
https://www.googleapis.com/customsearch/v1?key=API_KEY&cx=CX_VALUE&q=KEYWORD&cr=COUNTRY&alt=JSON
Does anyone have any experience with this? I want to be able to see UK results. Tried inserting &cr=countryUK , but still only does US results.
Thanks :)
Regards,
Stian
Use the gl=<country code> param to limit it to your country of choice (so gl=gb for the uk).
More info here:
http://googleajaxsearchapi.blogspot.com/2009/10/web-search-in-your-country.html