Does Selenium's waitForpageToLoad function always wait the full time? - selenium

Does waitForPageToLoad wait for the full time specified or return sooner if the page gets loaded?
For example:
$this->waitForPageToLoad("6000");
Does this load after 6 seconds always, or sooner if the page loads in 1 second?

It returns sooner. The argument is a timeout, a period after which to abort waiting for the page to load.

It should return before that time if the page is loaded.

The argument you are passing, is the maximum time duration as per your expectation. If the page is loaded before it, it returns back to execute next command. if not then it will show the error msg

Related

Why does Selenium get the child elements slowly

For example, HTML:
<input type="hidden" name="ie" value="utf-8">
this element don't have child element, when I use code:
List<WebElement> childElements = ele.findElements(By.xpath("./*"));
the program uses a very long time (about 30s) return a result. And the result size is right which is zero.
So how can I resolve this problem? Thanks.
As per the documentation findElements() method is affected by the implicit wait duration in force at the time of execution. When implicitly waiting, findElements() method will return as soon as there are more than 0 items in the found collection, or will return an empty list if the timeout is reached.
Possibly you have set implicitlyWait() somewhere before this block of code and configured as 30 seconds. Hence the TimeOut occurs at 30 seconds.

How to reduce tag waiting time in selenium

I'm trying to click a specific link in the web page with specific text.
However, if the link is not present, it takes 1 minute before it prints out element is not found. How do I reduce this time for faster execution?
try{
if (!driver.findElements(By.xpath("//a[text()='specifictext']/#href")).isEmpty())
{
By loadMoreComment=By.linkText("specifictext");
driver.findElement(loadMoreComment).click();
}
}
catch (NoSuchElementException e)
{
logger.warn("Specific text not found");
}
That would only happen because of implicit waits. Look at below definition
Implicit Waits
An implicit wait is to tell WebDriver to poll the DOM for a certain amount of time when trying to find an element or elements if they are not immediately available. The default setting is 0. Once set, the implicit wait is set for the life of the WebDriver object instance.
So you should lower that implicit wait if you want an early failure
driver.manage().timeouts().implicitlyWait(2, TimeUnit.SECONDS);
The above call before your code, will ensure the failure happens within 2 seconds
Use Implicit wait to reduce tag waiting time.
Implicit waits are used to provide a waiting time (say 30 seconds)
between each consecutive test steps across the entire test script or
program. Next step only executed when the 30 Seconds (or whatever time
is given is elapsed) after execution of previous step.
driver.manage().timeouts().implicitlyWait(20, TimeUnit.SECONDS);

Will the Implicit wait will move on if findElement action is complete?

Implicit Wait : If wait is set, it will wait for specified amount of time for each findElement/findElements call. It will throw an exception if action is not complete.
Assume we set implicit wait to 10 secs. My question is will selenium move on to next step if findElement action is complete before 10 secs?
Yes. Setting implicit wait causes the driver object to wait for the set time if the element it is looking for is not found immediately. The driver object keeps polling the DOM every 500 milliseconds until it finds the element or the time-out expires.
This is the explanation from official Selenium documentation page:
An implicit wait is to tell WebDriver to poll the DOM for a certain
amount of time when trying to find an element or elements if they are
not immediately available. The default setting is 0. Once set, the
implicit wait is set for the life of the WebDriver object instance.
So, to answer your question in short, yes it continues with executing next steps as soon as it finds the element(s) it is looking for. You may also understand that to be the case from a simple experiment like #sircapsalot has shown in his answer.
Answer:
Yes. It will continue with the next step if it finds the element before the implicit timeout is hit.
Proof of concept:
#Test
public void test29800926() {
driver.get("http://ddavison.io/tests/getting-started-with-selenium.htm");
driver.manage().timeouts().implicitlyWait(30000, TimeUnit.MILLISECONDS);
System.out.println(driver.findElement(By.id("click")).getText());
}
Instead of waiting the total of 30 seconds that I set the implicit wait to (30000ms / 1000 = 30sec), it found it immediately and continued to print the text of the element.

Why Wait.until() doesn't work in Selenium WebDriver?

I have been using Selenium WebDriver. I want to wait until the element is present on the webpage, for which i am using:
WebDriverWait wait = new WebDriverWait(driver, Long.parseLong(timeout));
wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath(locator)));
but my test get stucks in the second line if the element I am looking for, is not present and even beyond the timeout. Pls Help. Thanks.
Maybe:
- the element is present, so no exception is thrown
- then gets stuck because you are not doing anything else afterwards
Try printing smt after the until call. My guess is it will get printed.
Otherwise maybe it's the timeout:
It must be in seconds, not milli seconds.
http://selenium.googlecode.com/git/docs/api/java/org/openqa/selenium/support/ui/WebDriverWait.html#WebDriverWait(org.openqa.selenium.WebDriver, long)
I got it worked. I changed the timeout from 60000 to 60 since it takes the second argument as seconds and not millisecs.

jmeter stop current iteration

I am facing the following problem:
I have multiple HTTP Requests in my testplan.
I want every request to be repeated 4 times if they fail.
I realized that with a BeanShell Assertion, and its already working fine.
My problem is, that I don't want requests to be executed if a previous Request failed 5 times,
BUT I also dont want the thread to end.
I just want the current thread iteration to end,
so that the next iteration of the thread can start again with the 1st request (if the thread is meant to be repeated).
How do I realize that within the BeanShell Assertion?
Here is just a short extract of my code where i want the solution to have
badResponseCounter is being increased for every failed try of the request, this seems to work so far. Afterwards, the variable gets resetted.
if (badResponseCounter = 5) {
badResponseCounter = 0;
// Stop current iteration
}
I already checked the API, methods like setStopTest() or setStopThread() are given, but nothing for quitting the current iteration. I also need the preference "continue" in the thread group, as otherwise the entire test will stop after 1 single request failed.
Any ideas of how to do this?
In my opinion the easiest way is using following combination:
If Controller to check ${JMeterThread.last_sample_ok} and badResponseCounter variables
Test Action Sampler as a child of If Controller configured to "Go to next loop iteration"
Try this.
ctx.setRestartNextLoop(true);
if the thread number is 2, i tried to skip. I get the below result as i expected (it does not call b-2). It does not kill the thread either.