Related
I am trying to replace SQL results with all the middle values with asterix, *. All results are words. I am using SSMS.
The words that are 4-5 letters, it should only show 1 letter in the beginning, one to the end.
6 letters and more, it it should only show 2 letter in the beginning, 2 letters in the end.
1-3 letters, no replacement.
For example:
(I am now using - instead of * so it does not make the text bold).
"Banana" 6 letters should become ba--na
"False" 5 letters should become F---e
"a" stays the same
"Selin is a vegetable and banana is a fruit" becomes "S---n is a ve-----le and ba--na is a f---t."
What I have done so far, is to make this for emails, after the #. But now I want it to happen with every word of the result.
What I've done:
DECLARE #String VARCHAR(100) = 'sample#gmail.com'
SELECT STUFF(STUFF(#STring,
CHARINDEX('#',#String)+2,
(CHARINDEX('.',#String, CHARINDEX('#',#String))-CHARINDEX('#',#String)-3),
REPLICATE('*',CHARINDEX('.',#String, CHARINDEX('#',#String))-CHARINDEX('#',#String)))
,2
,CHARINDEX('#',#String)-3
,REPLICATE('*',CHARINDEX('#',#String)-3))```
With result s----e#g------l.com
instead of -
And I tried the mask method
Select
--select first character from Email and use replicate
SUBSTRING(Sxolia,1,1) + REPLICATE('*',5)+
--function to put asterisks
SUBSTRING(Sxolia,CHARINDEX('#',Sxolia),len(Sxolia)-CHARINDEX('#',Sxolia)+1)
--at this statement i select this part #gmail,com and to first part to become like this A*****#gmail.com
as Emailmask
From [mytable]
With result
B***** Bana is a fruit
And
declare #str nvarchar(max)
select #str = '123456'
select '****' + substring(#str, 5, len(#str) - 3)
Result: ****56
Not what I am looking for.
How should I look into this?
If I had to deal with this in SQL Server I'd operate on each word as a row, however using string_split is not (currently) an option since it does not guarantee ordering.
The following uses json to split the string as an array and provides a key value for ordering, which allows the words to be aggregated in the correct order:
select t.Sentence,
String_Agg( masked, ' ') within group(order by seq) Masked
from t
cross apply (
select seq, [value] word,
case
when l<=3 then [value]
when l<=5 then Stuff([value],2,l-2,Replicate('*',l-2))
else
Stuff([value],3,l-4,Replicate('*',l-4))
end Masked
from (
select j.[value], 1 + Convert(tinyint,j.[key]) Seq
from OpenJson(Concat('["',replace(t.Sentence,' ', '","'),'"]')) j
)w
cross apply (values(Len([value])))x(l)
)w
group by t.Sentence;
See working demo
Result:
I'm not sure how e-mail fits into all this because you're asking for word masks, so I'm going to assume you actually want this. Use divide and conquer to implement this, so first implement an expression that would do this for simplest cases (e.g. single words). Then if you need it for e-mails, just split the e-mails however you see fit and then apply the same expression.
The expression itself is rather simple:
SELECT *
FROM (VALUES
('banana'),
('selin'),
('vegetable')
) words(word)
CROSS
APPLY (SELECT CASE
WHEN ln BETWEEN 4 AND 5
THEN LEFT(word, 1) + REPLICATE('*', ln-2) + RIGHT(word, 1)
WHEN ln >= 6
THEN LEFT(word, 2) + REPLICATE('*', ln-4) + RIGHT(word, 2)
ELSE word
END as result
FROM (VALUES (LEN(words.word))) x(ln)
) calc
This already provides the expected result. You could define a function out of this, if you have the permissions, and use it like so:
SELECT *
FROM (VALUES
('banana'),
('selin'),
('vegetable')
) words(word)
CROSS
APPLY fnMaskWord(word)
Here's a working demo on dbfiddle, it includes the statement to create the function.
Expanding on a few answers:
select case when len(#String) <= 3 then #String
when len(#String) > 3 AND len(#String) <= 5 then
substring(#String, 1, 2) +
REPLICATE('*', Len(#String) - 2) +
substring(#String, Len(#String) - 1, 2)
when len(#String) >= 6 then
substring(#String, 1, 2) +
REPLICATE('*', Len(#String) - 2) +
substring(#String, Len(#String) - 1, 2)
else 'unrecognized length!'
If the length of the string is less than or equal to 3, return the string.
If the length of the string is more than 3 and less than or equal to 5 then create a substring starting at position 1, then replicate * by the length of the string -2 and finally add another substring -1 from the end of the string.
Similar for if the result is over 6 characters.
Else unrecognized length!
Hope this helps understand what's going on!
Maybe this can help
declare #t table (word varchar(50))
insert into #t values ('banana'), ('selin'), ('vegetable')
select case when len(t.word) < 3 then t.word
else left(t.word, 1) + -- take first char from left
replicate('*', Len(t.word) - 2) + -- fill middle with *
right(t.word, 1) -- take last char from right
end
from #t t
this returns
COLUMN1
b****a
s***l
v*******e
If you want to keep 2 chars left and right when the len > 5 then maybe this
select case when len(t.word) < 3 then t.word
when len(t.word) < 6 then
left(t.word, 1) +
replicate('*', len(t.word) - 2) +
right(t.word, 1)
else left(t.word, 2) +
replicate('*', len(t.word) - 4) +
right(t.word, 2)
end
from #t t
The result
COLUMN1
ba**na
s***l
ve*****le
EDIT: What if there is a whole sentence ?
Well then we first split the sentence in words,
and then concat the individual words back together while putting the ** in them
declare #t table (word varchar(50))
insert into #t values ('banana'), ('selin'), ('vegetable'), ('Banana is a fruit')
select t.word,
-- put the words back togheter into the sentence, and ** them while we are at it
( select string_agg(case when len(value) < 3 then value
when len(value) < 6 then
left(value, 1) +
replicate('*', len(value) - 2) +
right(value, 1)
else left(value, 2) +
replicate('*', len(value) - 4) +
right(value, 2)
end,
' ')
)
from #t t
cross apply string_split(t.word, ' ') s -- split the sentence into words
group by t.word
the result is
word COLUMN1
---- -------
banana ba**na
Banana is a fruit Ba**na is a f***t
selin s***n
vegetable ve*****le
I have a column with different length strings which has dashes (-) that separates alphanumeric strings.
The string could look like "A1-2-3".
I need to order by first "A1" then "2" then "3"
I want to achieve the following order for the column:
A1
A1-1-1
A1-1-2
A1-1-3
A1-2-1
A1-2-2
A1-2-3
A1-7
A2-1-1
A2-1-2
A2-1-3
A2-2-1
A2-2-2
A2-2-3
A2-10-1
A2-10-2
A2-10-3
A10-1-1
A10-1-2
A10-1-3
A10-2-1
A10-2-2
A10-2-3
I can separate the string with the following code:
declare #string varchar(max) = 'A1-2-3'
declare #first varchar(max) = SUBSTRING(#string,1,charindex('-',#string)-1)
declare #second varchar(max) = substring(#string, charindex('-',#string) + 1, charindex('-',reverse(#string))-1)
declare #third varchar(max) = right(#string,charindex('-',reverse(#string))-1)
select #first, #second, #third
With the above logic I thought that I could use the following:
Note this only regards strings with 2 dashes
select barcode from tabelWithBarcodes
order by
case when len(barcode) - len(replace(barcode,'-','')) = 2 then
len(SUBSTRING(barcode,1,charindex('-',barcode)-1))
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
SUBSTRING(barcode,1,(charindex('-',barcode)-1))
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
len(substring(barcode, charindex('-',barcode) + 1, charindex('-',reverse(barcode))-1))
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
substring(barcode, charindex('-',barcode) + 1, charindex('-',reverse(barcode))-1)
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
len(right(barcode,charindex('-',reverse(barcode))-1))
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
right(barcode,charindex('-',reverse(barcode))-1)
end
But the sorting is not working for the second and third section of the string.
(I haven't added the code for checking if the string has only 1 or no dash in it for simplicity)
Not sure if I'm on the right path here.
Is anybody able to solve this?
This is not pretty, however...
USE Sandbox;
GO
WITH VTE AS(
SELECT V.SomeString
--Randomised order
FROM (VALUES ('A1-1-1'),
('A10-1-3'),
('A10-2-2'),
('A1-1-3'),
('A10-2-1'),
('A2-2-2'),
('A1-2-1'),
('A1-2-2'),
('A2-1-1'),
('A10-1-2'),
('B2-1-2'),
('A1'),
('A2-2-1'),
('A2-10-3'),
('A10-2-3'),
('A2-1-2'),
('B1-4'),
('A2-10-2'),
('A2-2-3'),
('A10-1-1'),
('A1-A1-3'),
('A1-7'),
('A2-10-1'),
('A2-1-3'),
('A1-1-2'),
('A1-2-3')) V(SomeString)),
Splits AS(
SELECT V.SomeString,
DS.Item,
DS.ItemNumber,
CONVERT(int,STUFF((SELECT '' + NG.token
FROM dbo.NGrams8k(DS.item,1) NG
WHERE TRY_CONVERT(int, NG.Token) IS NOT NULL
ORDER BY NG.position
FOR XML PATH('')),1,0,'')) AS NumericPortion
FROM VTE V
CROSS APPLY dbo.DelimitedSplit8K(V.SomeString,'-') DS),
Pivoted AS(
SELECT S.SomeString,
MIN(CASE V.P1 WHEN S.Itemnumber THEN REPLACE(S.Item, S.NumericPortion,'') END) AS P1Alpha,
MIN(CASE V.P1 WHEN S.Itemnumber THEN S.NumericPortion END) AS P1Numeric,
MIN(CASE V.P2 WHEN S.Itemnumber THEN REPLACE(S.Item, S.NumericPortion,'') END) AS P2Alpha,
MIN(CASE V.P2 WHEN S.Itemnumber THEN S.NumericPortion END) AS P2Numeric,
MIN(CASE V.P3 WHEN S.Itemnumber THEN REPLACE(S.Item, S.NumericPortion,'') END) AS P3Alpha,
MIN(CASE V.P3 WHEN S.Itemnumber THEN S.NumericPortion END) AS P3Numeric
FROM Splits S
CROSS APPLY (VALUES(1,2,3)) AS V(P1,P2,P3)
GROUP BY S.SomeString)
SELECT P.SomeString
FROM Pivoted P
ORDER BY P.P1Alpha,
P.P1Numeric,
P.P2Alpha,
P.P2Numeric,
P.P3Alpha,
P.P3Numeric;
This outputs:
A1
A1-1-1
A1-1-2
A1-1-3
A1-2-1
A1-2-2
A1-2-3
A1-7
A1-A1-3
A2-1-1
A2-1-2
A2-1-3
A2-2-1
A2-2-2
A2-2-3
A2-10-1
A2-10-2
A2-10-3
A10-1-1
A10-1-2
A10-1-3
A10-2-1
A10-2-2
A10-2-3
B1-4
B2-1-2
This makes use of 2 user defined functions. Firstly or DelimitedSplit8k_Lead (I used DelimitedSplit8k as I don't have the other on my sandbox at the moment). Then you also have NGrams8k.
I really should explain how this works, but yuck... (edit coming).
OK... (/sigh) What it does. Firstly, we split the data into its relevant parts using delimitedsplit8k(_lead). Then, within the SELECT we use FOR XML PATH to get (only) the nuemrical part of that string (For example, for 'A10' we get '10') and we convert it to a numerical value (an int).
Then we pivot that data out into respective parts. The alphanumerical part, and the numerical part. So, for the value 'A10-A1-12' we end up with the row:
'A', 10, 'A', 1, 12
Then, now that we've pivoted the data, we sort it by each column individually. And voila.
This will fall over if you have a value like 'A1A' or '1B1', and honestly, I'm not changing it to catter for that. This was messy, and really isn't what the RDBMS should be doing.
Up to 3 dashes can be covered by fiddling with replace & parsename & patindex:
declare #TabelWithBarcodes table (id int primary key identity(1,1), barcode varchar(20) not null, unique (barcode));
insert into #TabelWithBarcodes (barcode) values
('2-2-3'),('A2-2-2'),('A2-2-1'),('A2-10-3'),('A2-10-2'),('A2-10-1'),('A2-1-3'),('A2-1-2'),('A2-1-1'),
('A10-2-3'),('A10-2-2'),('A10-2-10'),('A10-1-3'),('AA10-A111-2'),('A10-1-1'),
('A1-7'),('A1-2-3'),('A1-2-12'),('A1-2-1'),('A1-1-3'),('B1-1-2'),('A1-1-1'),('A1'),('A10-10-1'),('A12-10-1'), ('AB1-2-E1') ;
with cte as
(
select barcode,
replace(BarCode, '-', '.')
+ replicate('.0', 3 - (len(BarCode)-len(replace(BarCode, '-', '')))) as x
from #TabelWithBarcodes
)
select *
, substring(parsename(x,4), 1, patindex('%[0-9]%',parsename(x,4))-1)
,cast(substring(parsename(x,4), patindex('%[0-9]%',parsename(x,4)), 10) as int)
,substring(parsename(x,3), 1, patindex('%[0-9]%',parsename(x,3))-1)
,cast(substring(parsename(x,3), patindex('%[0-9]%',parsename(x,3)), 10) as int)
,substring(parsename(x,2), 1, patindex('%[0-9]%',parsename(x,2))-1)
,cast(substring(parsename(x,2), patindex('%[0-9]%',parsename(x,2)), 10) as int)
,substring(parsename(x,1), 1, patindex('%[0-9]%',parsename(x,1))-1)
,cast(substring(parsename(x,1), patindex('%[0-9]%',parsename(x,1)), 10) as int)
from cte
order by
substring(parsename(x,4), 1, patindex('%[0-9]%',parsename(x,4))-1)
,cast(substring(parsename(x,4), patindex('%[0-9]%',parsename(x,4)), 10) as int)
,substring(parsename(x,3), 1, patindex('%[0-9]%',parsename(x,3))-1)
,cast(substring(parsename(x,3), patindex('%[0-9]%',parsename(x,3)), 10) as int)
,substring(parsename(x,2), 1, patindex('%[0-9]%',parsename(x,2))-1)
,cast(substring(parsename(x,2), patindex('%[0-9]%',parsename(x,2)), 10) as int)
,substring(parsename(x,1), 1, patindex('%[0-9]%',parsename(x,1))-1)
,cast(substring(parsename(x,1), patindex('%[0-9]%',parsename(x,1)), 10) as int)
extend each barcode to 4 groups by adding trailing .0 if missing
split each barcode in 4 groups
split each group in leading characters and trailing digits
sort by the leading character first
then by casting the digits as numeric
See db<>fiddle
An alterative approach would be to use your technique to split the string into its 3 component parts, then left pad those strings with leading zeros (or characters of your choice). That avoids any issues where the string may contain alphanumerics rather than just numerics. However, it does mean that strings containing different length alphabetic characters may not be sorted as you may expect... Here's the code to play with (using the definitions from #dnoeth's excellent answer):
;with cte as
(
select barcode
, case
when barcode like '%-%' then
substring(barcode,1,charindex('-',barcode)-1)
else
barcode
end part1
, case
when barcode like '%-%' then
substring(barcode, charindex('-',barcode) + 1, case
when barcode like '%-%-%' then
(charindex('-',barcode,charindex('-',barcode) + 1)) - 1
else
len(barcode)
end
- charindex('-',barcode))
else
''
end part2
, case
when barcode like '%-%-%' then
right(barcode,charindex('-',reverse(barcode))-1) --note: assumes you don't have %-%-%-%
else
''
end part3
from #TabelWithBarcodes
)
select barcode
, part1, part2, part3
, right('0000000000' + coalesce(part1,''), 10) lpad1
, right('0000000000' + coalesce(part2,''), 10) lpad2
, right('0000000000' + coalesce(part3,''), 10) lpad3
from cte
order by lpad1, lpad2, lpad3
DBFiddle Example
The DBMS in this case is SQL Server 2012.
I need a SQL query that will grab just the numbers from a device name. I've got devices that follow a naming scheme that SHOULD look like this:
XXXnnnnn
or
XXXnnnnn-XX
Where X is a letter and n is a number which should be left padded with 0's where appropriate. However, not all of the names are properly padded in this way.
So, imagine you have a column that looks something like this:
Name
----
XXX01234
XXX222
XXX0390-A2
XXX00965-A1
I need an SQL query that will return results from this example column as follows.
Number
------
01234
00222
00390
00965
Anyone have any thoughts? I've tried things like casting the name first as a float and then as an int, but to be honest, I'm just not skilled enough with SQL yet to find the solution.
Any help is greatly appreciated!
SQL Server does not have great string parsing functions. For your particular example, I think a case statement might be the simplest approach:
select (case when number like '___[0-9][0-9][0-9][0-9][0-9]%'
then substring(number, 4, 5)
when number like '___[0-9][0-9][0-9][0-9]%'
then '0' + substring(number, 4, 4)
when number like '___[0-9][0-9][0-9]%'
then '00' + substring(number, 4)
when number like '___[0-9][0-9]%'
then '000' + substring(number, 4, 2)
when number like '___[0-9][0-9]%'
then '0000' + substring(number, 4, 1)
else '00000'
end) as EmbeddedNumber
This might work :
SELECT RIGHT('00000'
+ SUBSTRING(Col, 1, ISNULL(NULLIF((PATINDEX('%-%', Col)), 0) - 1, LEN(Col))), 5)
FROM (SELECT REPLACE(YourColumn, 'XXX', '') Col
FROM YourTable)t
SQLFIDDLE
This will work even when XXX can be of different len:
DECLARE #t TABLE ( n NVARCHAR(50) )
INSERT INTO #t
VALUES ( 'XXXXXXX01234' ),
( 'XX222' ),
( 'X0390-A2' ),
( 'XXXXXXX00965-A1' )
SELECT REPLICATE('0', 5 - LEN(n)) + n AS n
FROM ( SELECT SUBSTRING(n, PATINDEX('%[0-9]%', n),
CHARINDEX('-', n + '-') - PATINDEX('%[0-9]%', n)) AS n
FROM #t
) t
Output:
n
01234
00222
00390
00965
If the first 3 chars are always needed to be removed, then you can do something like that (will work if the characters will start only after '-' sign):
DECLARE #a AS TABLE ( a VARCHAR(100) );
INSERT INTO #a
VALUES
( 'XXX01234' ),
( 'XXX222' ),
( 'XXX0390-A2' ),
( 'XXX00965-A1' );
SELECT RIGHT('00000' + SUBSTRING(a, 4, CHARINDEX('-',a+'-')-4),5)
FROM #a
-- OUTPUT
01234
00222
00390
00965
Another option (will extract numbers after first 3 characters):
SELECT
RIGHT('00000' + LEFT(REPLACE(a, LEFT(a, 3), ''),
COALESCE(NULLIF(PATINDEX('%[^0-9]%',
REPLACE(a, LEFT(a, 3), '')),
0) - 1,
LEN(REPLACE(a, LEFT(a, 3), '')))), 5)
FROM
#a;
-- OUTPUT
01234
00222
00390
00965
I have to check the string with the following scenarios in WHERE condition.
The data ProductId stored in the database can be like
7314-3337 sometimes with - symbol and not prefixed with 19
73143337 sometimes without symbol and not prefixed with 19
1973143337 correct format
197314-3337 sometimes with - symbol
I need to filter the record ProductId and the input is correct format , i.e 1973143337
WHERE P.ProductId=#ProductId
How can i filter it if the data stored in other 3 formats?
How to use the string replace(-) and prefix 19 if not exists in SQL server?
please check this 2 approach.
one is very simple and second is some trick. (I think you go with second option which cover everythings)
declare #t table (ProductId varchar(100))
insert into #t
values
('7314-3337')
,('73143337')
,('1973143337')
,('197314-3337')
,('73683337')
,('73143338')
declare #valuetosearch varchar(100) = '1973143337'
--this is very simple , but not work in each schenerio. the second approach is fine.
--select CHARINDEX ( '19','1973143337'), SUBSTRING('1973143337',3,len('1973143337'))
--select * from
--#t
--where
--replace(REPLACE(ProductId ,'-','') ,'19','') = replace(REPLACE(#valuetosearch ,'-','') ,'19','')
select * from
#t
where
REPLACE( case when CHARINDEX ( '19',ProductId) = 1
then SUBSTRING( ProductId ,3,LEN(ProductId))
else ProductId
end ,'-','')
=
REPLACE ( case when CHARINDEX ( '19',#valuetosearch) = 1
then SUBSTRING( #valuetosearch ,3,LEN(#valuetosearch))
else #valuetosearch
end ,'-','')
You should first sanitize your data, if it is not consistent then you won't be able to get the correct results.
For prefixing with 19:
UPDATE foo
SET ProductId = '19' + ProductId
WHERE Left(ProductID, 2) <> '19'
For removing the '-':
UPDATE foo
SET ProductId = REPLACE(ProductId, '-', '')
Then you should be able to get the results you want.
UPDATE:
You could construct a CTE with the results in a single format, and then, filter that CTE:
WITH cte (
FormattedPID
,ProductId
)
AS (
SELECT CASE
WHEN LEFT(ProductId, 2) = '19'
THEN REPLACE(ProductId, '-', '')
ELSE '19' + REPLACE(ProductId, '-', '')
END
,ProductId
FROM foo
)
SELECT FormattedPID
,ProductId
FROM cte
WHERE FormattedPID = #ProductID
You could make sure the column is in the correct format like this:
Remove the - by replacing it with an empty string (197314-3337 -> 1973143337, 7314-3337 -> 73143337).
Add 19 at the beginning (1973143337 -> 191973143337, 73143337 -> 1973143337).
Take 10 rightmost characters of the result and compare to the input (1973143337 -> 1973143337, 1973143337 -> 1973143337).
In Transact-SQL:
WHERE RIGHT('19' + REPLACE(P.ProductId, '-', ''), 10) = #ProductId
Of course, this means no index seek for you, because we are applying functions to the column.
An alternative to that would be to produce the three non-standard formats out of the input:
cut off the initial 19 (1973143337 -> 73143337);
insert the - (1973143337 -> 197314-3337);
insert the - and cut off the 19 (1973143337 -> 197314-3337 -> 7314-3337).
In Transact-SQL:
WHERE P.ProductId IN (
#ProductId,
SUBSTRING(#ProductId, 3, 999999999),
STUFF(#ProductId, 7, 0, '-'),
SUBSTRING(STUFF(#ProductId, 7, 0, '-'), 3, 999999999)
)
This way if there is an index on P.ProductId, it will be used efficiently.
Both approaches assume that the length of the correct format is fixed.
I need some help with a sql transformation. This part of query that I have been provided with:
'$' + replace(cast((CAST(p.Price1 AS decimal(10,2)) * cast(isnull(p.Multiplier,1) as decimal(10,2))) as varchar), '.0000', '')
Basically, it ends up being a varchar that looks like this: $26980
I need to insert a comma at the thousand and million mark (if applicable). So in this instance, $26,980
What's the easiest way to do that without having to rewrite the whole thing?
Do it on the client side. Having said that, this example should show you the way.
with p(price1, multiplier) as (select 1234.5, 10)
select '$' + replace(cast((CAST(p.Price1 AS decimal(10,2)) * cast(isnull(p.Multiplier,1) as decimal(10,2))) as varchar), '.0000', ''),
'$' + parsename(convert(varchar,cast(p.price1*isnull(p.Multiplier,1) as money),1),2)
from p
The key is in the last expression
'$' + parsename(convert(varchar,cast(p.price1*isnull(p.Multiplier,1) as money),1),2)
Note: if p.price1 is of a higher precision than decimal(10,2), then you may have to cast it in the expression as well to produce a faithful translation since the original CAST(p.Priced1 as decimal(10,2)) will be performing rounding.
If you really must do it in TSQL you can use CONVERT(), but this sort of thing really doesn't belong in the database:
declare #m money = 12345678
-- with decimal places
select '$' + convert(varchar, #m, 1)
-- without decimal places
select '$' + replace(convert(varchar, #m, 1), '.00', '')
You could turn this into a function, it only goes 50 characters back.
DECLARE #input VARCHAR(50)
SELECT #input = '123123123.00'
SELECT #input = CASE WHEN CHARINDEX('.', #input) > offset +1
THEN STUFF(#input, CHARINDEX('.', #input) - offset, 0, ',')
ELSE #input END
FROM (SELECT 3 offset UNION SELECT 7 UNION SELECT 12 UNION SELECT 18 UNION SELECT 25 UNION SELECT 33 UNION SELECT 42) b
PRINT #input
The offset grows by +1 for each position, because it's assuming you've already inserted the commas for the previous positions.