SELECT DISTINCT MonthName(Month([Date])) AS [Month], tblSupportCalls.System, Count(tblSupportCalls.System) AS [Total for System], Year([Date]) AS [Year]
FROM tblSupportCalls
WHERE (((tblSupportCalls.Date) Between Now() And Now()-7) AND ((tblSupportCalls.System) In ('Career Campus','E-PEEP')) AND ((tblSupportCalls.StartTime) Is Not Null) AND ((Hour([StartTime]))>=7))
GROUP BY tblSupportCalls.System, tblSupportCalls.Date;
Whenever I input that it gives me multiple months like:
July
July
July
I want it just to say July just 1 time and I cant figure out why ever field is repeating itself for different days. I just want it to say:
MONTH | System | Total Systems | Year
what I am looking at is
> MONTH | System | Total Systems | Year
> July CC 2 2010
> July CC 7 2010
> July CC 9 2010
> July EE 1 2010
> July EE 2 2010
Needs to be:
MONTH | System | Total Systems | Year
July CC 18 2010
July EE 03 2010
You'd want to group by your Year and Month instead of tblSupportCalls.Date.
...
GROUP BY tblSupportCalls.System, Year([Date]), Month([Date]);
You're still grouping the results by date, though (not by month). I think what you want is something like this:
GROUP BY tblSupportCalls.System, Year ([tblSupportCalls.Date]), [Month([tblSupportCalls.Date]);
I'm thinking you still want to group by Year as well, so that July 2010 shows up in a different row from July 2011.
Related
I have a dataset where I would like to query and obtain output of a count of records for the first of every month.
Data
name date1
hello july 1 2018
hello july 1 2018
hello july 10 2018
sure august 1 2019
sure august 1 2019
why august 20 2019
ok september 1 2019
ok september 1 2019
ok september 1 2019
sure september 5 2019
Desired
ID MONTH Day YEAR
2 July 1 2018
2 August 1 2019
3 September 1 2019
We are only counting the records from the 1st of each month
Doing
USE [Data]
SELECT COUNT(*) AS ID , MONTH(date1) AS MONTH, YEAR(date1) AS YEAR
FROM dbo.data1
GROUP BY MONTH(date1), YEAR(date1)
ORDER BY YEAR ASC
This only outputs the year and month
Any suggestion is appreciated
Assuming you are using the implicit conversion for date
Example
SELECT COUNT(*) AS ID,
DATENAME(MONTH,date1) AS MONTH,
DATEPART(DAY,date1) as DAY,
YEAR(date1) AS YEAR
FROM dbo.data1
WHERE DAY(date1)=1
GROUP BY YEAR(date1),DATENAME(MONTH,date1),DATEPART(DAY,date1)
ORDER BY YEAR ASC
Results
ID MONTH DAY YEAR
2 July 1 2018
2 August 1 2019
3 September 1 2019
In MS Access 365 I have 2 tables and I want to count the occurrence of a year from the first table in part of a string of the second table, purely with SQL (so far I used VBA, but I want to simplify).
The first table (tDistinctYears) contains all the years, in which one of our members paid:
ID
PaymentYear
1
2015
2
2016
3
2017
3
2018
4
2019
5
2020
6
2021
7
2022
The second table (tPayments) has all payments from members with one column containing a membership number and the other one containing payment years. Sometimes a member pays for one year, sometime for several years. The table therefore looks like that:
MembershipNr
YearPayment
11
2016
11
2017
11
2018
26
2017
26
2018;2019
26
2020;2021;2022
38
2016
38
2017
38
2018;2019;2020;2021
I want a query which tells me how many members paid in which year:
PaymentYear
Count
2015
0
2016
2
2017
3
2018
3
2019
2
2020
2
2021
2
I used the following SQL query, which I found using various answers on stackoverflow:
SELECT tDistinctYears.PaymentYear, (COUNT(tPayments.YearPayment)) AS [Count]
FROM tDistinctYears
LEFT JOIN tPayments ON tDistinctYears.PaymentYear like "*" & tPayments.YearPayment & "*"
WHERE (tDistinctYears.PaymentYear > 0 AND tDistinctYears.PaymentYear <= YEAR(NOW()))
GROUP BY tDistinctYears.PaymentYear;
But what I get is this:
PaymentYear
Count
2015
0
2016
2
2017
3
2018
1
2019
0
2020
0
2021
0
It seems as if the above query does not use the “like” expression in the JOIN ON section.
Can someone help me, please?
I think you are close just alter column in where condition tPayments.YearPayment should be first and tDistinctYears.PaymentYear should be inside like operator.
SELECT tDistinctYears.PaymentYear, (COUNT(tPayments.YearPayment)) AS [Count]
FROM tDistinctYears
LEFT JOIN tPayments ON tPayments.YearPayment like "*" &
tDistinctYears.PaymentYear
& "*" WHERE (tDistinctYears.PaymentYear > 0 AND tDistinctYears.PaymentYear <=
YEAR(NOW()))
GROUP BY tDistinctYears.PaymentYear;
I need to determine the counts breakdown to per month (and year) of customers [alias'ed as Patient_ID] which made their first visit to a store. The date times of store visits are stored in the [MDT Review Date] column of the table.
Customers can come to the store multiple times throughout the year and increase the total count-> but what I require is ONLY the first time a customer visited.
E.g. Tom Bombadil visited the store once in January 2019, so count increased to 1, then again 4 times in March, so count should be 1 for the month of March and 0 for febraury and 1 for January, then again 4 times in October, then again 2 times in December.
I require that Tom Bombadil should be counted one and only once for a particular month, his first occurrence which was per month
The output should be like :
rn1 YEAR Month_Number Month Total_Count
1 2010 6 June 2
1 2010 7 July 1
1 2010 8 August 5
1 2010 10 October 5
1 2010 11 November 3
1 2011 1 January 4
1 2011 2 February 6
1 2011 4 April 7
1 2011 5 May 4
1 2011 6 June 10
1 2011 7 July 10
1 2011 8 August 14
1 2011 9 September 4
1 2011 10 October 8
1 2011 11 November 11
1 2011 12 December 11
1 2012 1 January 8
1 2012 2 February 21
Please refer to my query. What I have attempts to use the windowing function COUNT to count the store visits per month. Then the ROW_NUMBER function attempts to assign a unique number to each visit. What am I doing wrong?
select
*
from
(select distinct
row_number() over (partition by p.Patient_ID, p.PAT_Forename1, p.PAT_Surname
order by PAT_Forename1, p.Patient_ID, PAT_Surname) AS rn1,
datepart(year, [DATE_COLUMN]) as YEAR,
datepart(month, [DATE_COLUMN]) as Month_Number,
datename(month,[DATE_COLUMN]) as Month,
count(p.Patient_ID) over (partition by datepart(year,[DATE_COLUMN]),
datename(month, [DATE_COLUMN])) as Total_Count
from
Tablename m
inner join
TableName p on m.PK_ID = p.PK_ID
) as temp
where
rn1 = 1
I recently started up working with Access database in a project at my work (hospital) and got lots of useful tips from this site. However, I have now a problem that I can't figure out how to solve.
I have a table containing treatment dates (as well as other data) for lots of patients. My task is to count the number of treatments given within each week (and possibly month/quarter/year as well). The treatment dates are located in the column 'TreatDate' in the table 'Data'.
I have used DatePart to separate out year and week number as:
SELECT
DatePart('yyyy',[TreatStart]) AS Year, DatePart('ww',[TreatStart]) AS Week
FROM Data
ORDER BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart]);
Which gives me:
Year Week
2006 16
2006 16
2006 16
2006 17
2006 17
2006 18
2006 19
2006 19
2006 19
... ...
How do I count the number of occurances in each week in order to get something like:
Year Week N
2006 16 3
2006 17 2
2006 18 1
2006 19 3
... ... ...
Best regards,
Mattias
Just add the group by on the same values by which you want count and add the count aggregate function to get the total count of the appointments at that given group.
SELECT DatePart('yyyy',[TreatStart]) AS Year, DatePart('ww',[TreatStart]) AS Week , COUNT(*) As N
FROM Data
GROUP BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart])
ORDER BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart]);
Use GROUP BY and COUNT:
SELECT DatePart('yyyy',[TreatStart]) AS Year,
DatePart('ww',[TreatStart]) AS Week,
COUNT(*) as N
FROM Data
GROUP BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart])
ORDER BY DatePart('yyyy',[TreatStart]),DatePart('ww',[TreatStart]);
The output will be:
Year Week N
2006 16 3
2006 17 2
2006 18 1
2006 19 3
I have a query returning a table which looks like:
Location | November | December | January | February | March | ... | October |
CT 30 70 80 90 60 30
etc.
and I'd like it to look like:
Location | Month | Value |
CT November 30
CT December 70
CT January 80
...
CT October 30
It looks like an unpivot, but I didn't pivot to get it into that form since the base table has the months as columns (the values are just sums of values grouped by location). I've seen plenty of rows-to-columns questions but I haven't found a good columns-to-rows answer, so I'm hoping someone can help me.
Thanks!
You will want to use the UNPIVOT function. This transforms the values of your columns and turns it into rows:
select location, month, value
from <yourquery here>
unpivot
(
value
for month in (January, February, March, April, May, June, July, August,
September, October, November, December)
) unpiv
See SQL Fiddle with Demo