How I can calculate bit length of an integer in Oracle's PL/SQL?
I would like to get something like cast INT to BIT STRING and then LENGTH( LTRIM(BIT STRING, '0') )'
you can use the following formula to get the number of characters of the binary representation of an integer n (n>0):
ceil(log(2, n + 1))
SQL> SELECT n, ceil(log(2, n + 1)) num_of_char
2 FROM (SELECT ROWNUM n FROM dual CONNECT BY LEVEL <= 64);
N NUM_OF_CHAR
---------- -----------
1 1
2 2
3 2
4 3
5 3
6 3
7 3
8 4
[...]
15 4
16 5
[...]
31 5
32 6
[...]
63 6
64 7
Related
How can I code this 'if' conditions in GAMS?
Set j/1*10/
S/1*6/;
Parameter
b(s,j) export this from excel
U(s,j) export from excel
M(s)/1 100,2 250,3 140,4 120,5 132/ export from excel
;
table b(s,j)
1 2 3 4 5 6 7 8 9 10
1 3 40 23 12 9 52 9 14 89 33
2 0 0 42 0 11 32 11 15 3 7
3 10 20 12 9 5 30 14 5 14 5
4 0 0 0 9 0 3 8 0 13 5
5 0 10 11 32 11 0 3 1 12 1
6 12 20 2 9 15 3 14 5 14 5
;
u(s,j)=0;
u(s,j)$(b(s,j))=1;
Variable delta(j); "binary"
After solving a model I got the value of delta ( suppose delta(1)=1, delta(5)=1). Then Set A is
A(j)$(delta.l(j)=1)=Yes; (A={1,5})
I want to calculate parameter R(s) according to the following :
If there is no j in A(j) s.t. j in u(s,j) then R(s)=M(s)
Else if there is a j in A(j) s.t. j in u(s,j) then R(s)=min{b(s,j): j in A(j) , j in u(s,j) }
Then R(1)=3, R(2)=11,R(3)=5, R(4)=120, R(5)=11,R(6)=12.
Is it possible to code this ' if then ' statement only by $ utility?
Thanks
Following on from the comments, I think this should work for you.
(Create a parameter that mimics your variable delta just for demonstration:)
parameter delta(j);
delta('1') = 1;
delta('5') = 1;
With loop and if/else:
Create parameter R(s). Then, looping over s , pick the minimum of b(s,A) across set A where b(s,A) is defined if the sum of b(s,A) is not zero (i.e. if one of the set is non-zero. Else, set R(s) equal to M(s).
Note, the loop is one solution to the issue you were having with mixed dimensions. And the $(b(s,A)) needs to be on the first argument of smin(.), not on the second argument.
parameter R(s);
loop(s,
if (sum(A, b(s,A)) ne 0,
R(s) = smin(A$b(s,A), b(s,A));
else
R(s) = M(s);
);
);
With $ command only (#Lutz in comments):
R(s)$(sum(A, b(s,A)) <> 0) = smin(A$b(s,A), b(s,A));
R(s)$(sum(A, b(s,A)) = 0) = M(s);
Gives:
---- 56 PARAMETER R
1 3.000, 2 11.000, 3 5.000, 4 120.000, 5 11.000, 6 12.000
i have a big query datatable with 512 variables as arrays with quite the long names (x__x_arrVal_arrSlices_0__arrValues to arrSlices_511). In each array are 360 values. the bi-tool cannot compute an array in this form. this is the reason why i want to have each value as an output.
the query excerpt i use right now is:
SELECT
timestamp, x_stArrayTag_sArrayName, x_stArrayTag_sComission,
1 as row,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(1)] AS f001,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(10)] AS f010,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(20)] AS f020,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(30)] AS f030,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(40)] AS f040,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(50)] AS f050,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(60)] AS f060,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(70)] AS f070,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(80)] AS f080,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(90)] AS f090,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(100)] AS f100,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(110)] AS f110,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(120)] AS f120,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(130)] AS f130,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(140)] AS f140,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(150)] AS f150,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(160)] AS f160,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(170)] AS f170,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(180)] AS f180,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(190)] AS f190,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(200)] AS f200,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(210)] AS f210,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(220)] AS f220,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(230)] AS f230,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(240)] AS f240,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(250)] AS f250,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(260)] AS f260,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(270)] AS f270,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(280)] AS f280,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(290)] as f290,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(300)] AS f300,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(310)] AS f310,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(320)] AS f320,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(330)] AS f330,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(340)] AS f340,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(350)] AS f350,
x__x_arrVal_arrSlices_1__arrValues[OFFSET(359)] AS f359
FROM
`project.table`
WHERE
_PARTITIONTIME >= "2017-01-01 00:00:00"
AND _PARTITIONTIME < "2018-02-16 00:00:00"
UNION ALL
The output i get is unfortunately only a fracture of all values. getting all 512*360 values with this query is not possible because if i used this query for all slices i reach the limit of bigquery.
is there a possibility to rename the the long name and to select a range?
best regards
scotti
You can get 360 rows and 512 columns by using UNNEST. Here is a small example:
WITH data AS (
SELECT
[1, 2, 3, 4] as a,
[2, 3, 4, 5] as b,
[3, 4, 5, 6] as c
)
SELECT v1, b[OFFSET(off)] as v2, c[OFFSET(off)] as v3
FROM data, unnest(a) as v1 WITH OFFSET off
Output:
v1 v2 v3
1 2 3
2 3 4
3 4 5
4 5 6
Having in mind a little messy table you are dealing with - in making decision on restructuring the important aspect is practicality of query to implement that decision
In your specific case - I would recommend full flattening of the data like below (each row will be transformed into ~180000 rows each representing one of the elements of one of the array in original row - slice field will represent array number and pos will represent element position in that array) - query is generic enough to handle any number/names of slices and array sizes and at the same time result is flexible and also generic enough to be used in any imaginable algorithm
#standardSQL
SELECT
id,
slice,
pos,
value
FROM `project.dataset.messytable` t,
UNNEST(REGEXP_EXTRACT_ALL(TO_JSON_STRING(t), r'"x__x_arrVal_arrSlices_(\d+)":\[.*?\]')) slice WITH OFFSET x
JOIN UNNEST(REGEXP_EXTRACT_ALL(TO_JSON_STRING(t), r'"x__x_arrVal_arrSlices_\d+":\[(.*?)\]')) arr WITH OFFSET y
ON x = y,
UNNEST(SPLIT(arr)) value WITH OFFSET pos
you can test/play with it using below dummy example
#standardSQL
WITH `project.dataset.messytable` AS (
SELECT 1 id,
[ 1, 2, 3, 4, 5] x__x_arrVal_arrSlices_0,
[11, 12, 13, 14, 15] x__x_arrVal_arrSlices_1,
[21, 22, 23, 24, 25] x__x_arrVal_arrSlices_2 UNION ALL
SELECT 2 id,
[ 6, 7, 8, 9, 10] x__x_arrVal_arrSlices_0,
[16, 17, 18, 19, 20] x__x_arrVal_arrSlices_1,
[26, 27, 28, 29, 30] x__x_arrVal_arrSlices_2
)
SELECT
id,
slice,
pos,
value
FROM `project.dataset.messytable` t,
UNNEST(REGEXP_EXTRACT_ALL(TO_JSON_STRING(t), r'"x__x_arrVal_arrSlices_(\d+)":\[.*?\]')) slice WITH OFFSET x
JOIN UNNEST(REGEXP_EXTRACT_ALL(TO_JSON_STRING(t), r'"x__x_arrVal_arrSlices_\d+":\[(.*?)\]')) arr WITH OFFSET y
ON x = y,
UNNEST(SPLIT(arr)) value WITH OFFSET pos
the result is as below
Row id slice pos value
1 1 0 0 1
2 1 0 1 2
3 1 0 2 3
4 1 0 3 4
5 1 0 4 5
6 1 1 0 11
7 1 1 1 12
8 1 1 2 13
9 1 1 3 14
10 1 1 4 15
11 1 2 0 21
12 1 2 1 22
13 1 2 2 23
14 1 2 3 24
15 1 2 4 25
16 2 0 0 6
17 2 0 1 7
18 2 0 2 8
19 2 0 3 9
20 2 0 4 10
21 2 1 0 16
22 2 1 1 17
23 2 1 2 18
24 2 1 3 19
25 2 1 4 20
26 2 2 0 26
27 2 2 1 27
28 2 2 2 28
29 2 2 3 29
30 2 2 4 30
I have a query below, I want it to sort the data by id, but it doesn't sort at all.
Select distinct ec.category,ec.id
from print ec
order by ec.id asc
What could be the reason?
this is the output :
Looking at your data, the column data type is a varchar, aka 'text'.
If it is text, it sorts like text, according to the place the character occurs in the character set used.
So each column is ordered on the first character, then the second, etc. So 2 comes after 11.
Either make the column a numeric data type, like number, or use to_number in the sorting:
select distinct ec.category,ec.id
from print ec
order by to_number(ec.id)
The difference lies in the way varchar and number are sorted. in your case, since you have used varchar data type to store number, the sorting is done for the ASCII values.
NUMBERS when sorted as STRING
SQL> WITH DATA AS(
2 SELECT LEVEL rn FROM dual CONNECT BY LEVEL < = 11
3 )
4 SELECT rn, ascii(rn) FROM DATA
5 order by ascii(rn)
6 /
RN ASCII(RN)
---------- ----------
1 49
11 49
10 49
2 50
3 51
4 52
5 53
6 54
7 55
8 56
9 57
11 rows selected.
SQL>
As you can see, the sorting is based on the ASCII values.
NUMBER when sorted as a NUMBER itself
SQL> WITH DATA AS(
2 SELECT LEVEL rn FROM dual CONNECT BY LEVEL < = 11
3 )
4 SELECT rn, ascii(rn) FROM DATA
5 ORDER BY rn
6 /
RN ASCII(RN)
---------- ----------
1 49
2 50
3 51
4 52
5 53
6 54
7 55
8 56
9 57
10 49
11 49
11 rows selected.
SQL>
How to fix the issue?
Change the data type to NUMBER. As a workaround, you could use to_number.
Using to_number -
SQL> WITH DATA AS(
2 SELECT to_char(LEVEL) rn FROM dual CONNECT BY LEVEL < = 11
3 )
4 SELECT rn, ascii(rn) FROM DATA
5 ORDER BY to_number(rn)
6 /
RN ASCII(RN)
--- ----------
1 49
2 50
3 51
4 52
5 53
6 54
7 55
8 56
9 57
10 49
11 49
11 rows selected.
SQL>
Make sure the type of your "id" column is int. (integer = number)
Right now it is probably text, char or varchar(for text, strings).
You can't sort numbers alphabetically or strings/text chronologically like you are trying now.
when you sort a string datatype that has in values it produce result as
1
10
11
2
21 etc...
Hence
Change your Id datatype to int/bigint
You can only just cast/convert the datatype in a query
Select distinct ec.category,ec.id
from print ec
order by cast(ec.id as int) asc
From a given table I want to be able to sum values having the same number (should be easy, right?)
Problem: A given value can be assigned from 2 to n consecutive numbers.
For some reasons this information is stored in a single row describing the value, the starting number and the ending number as below.
TABLE A
id | starting_number | ending_number | value
----+-----------------+---------------+-------
1 2 5 8
2 0 3 5
3 4 6 6
4 7 8 10
For instance the first row means:
value '8' is assigned to numbers: 2, 3 and 4 (5 is excluded)
So, I would like the following intermediairy result table
TABLE B
id | number | value
----+--------+-------
1 2 8
1 3 8
1 4 8
2 0 5
2 1 5
2 2 5
3 4 6
3 5 6
4 7 10
So I can sum 'value' for elements having identical 'number'
SELECT number, sum(value)
FROM B
GROUP BY number
TABLE C
number | sum(value)
--------+------------
2 13
3 8
4 14
0 5
1 5
5 6
7 10
I don't know how to do this and didn't find any answer on the web (maybe not looking with appropriate key words...)
Any idea?
You can do what you want with generate_series(). So, TableB is basically:
select id, generate_series(starting_number, ending_number - 1, 1) as n, value
from tableA;
Your aggregation is then:
select n, sum(value)
from (select id, generate_series(starting_number, ending_number - 1, 1) as n, value
from tableA
) a
group by n;
Remove the Decimal values
select cast(val as integer),val from table
and I tried round that is also not working pls tell me the way to solve this.
select ROUND(2.9,0) from dual
24 23.8331134259259
31 30.8322222222222
31 30.8321990740741
31 31.1120023148148
31 31.1119791666667
28 28.0590046296296
31 31.1177314814815
4 4.05344907407407
4 4.03957175925926
14 13.7137731481481
5 4.79490740740741
5 4.79490740740741
5 4.79489583333333
5 4.79488425925926
Expected Output :
23 23.8331134259259
30 30.8322222222222
30 30.8321990740741
30 31.1120023148148
30 31.1119791666667
28 28.0590046296296
31 31.1177314814815
4 4.05344907407407
4 4.03957175925926
13 13.7137731481481
4 4.79490740740741
4 4.79490740740741
4 4.79489583333333
4 4.79488425925926
Hi try truncate function
TRUNC( number, [ decimal_places ] )
Are you looking for FLOOR?
FLOOR returns the largest integer equal to or less than n. The number n can always be written as the sum of an integer k and a positive fraction f such that 0 <= f < 1 and n = k + f. The value of FLOOR is the integer k. Thus, the value of FLOOR is n itself if and only if n is precisely an integer.
Just select FLOOR(2.9,0) from dual