I am working with SQL and I have two columns with datetime field.
What I want to do is just compare the date portion of the these datetime fields and see if there are different.
For example,
col1 | col2
'2010-01-02 23:58:00.000' | '2010-01-03 06:21:00.000'
'2010-01-04 16:03:00.000' | '2010-01-04 21:34:00.000'
Row1's dates are different but row2 are same
I am thinking something like datediff(day,col2,col1) < 1 //Then this is different else they are same.
Not sure how to parse the date then compare two fields.
abs(datediff(day, col1, col2)) > 0
This should work in many databases:
DATE(col1) = DATE(col2)
By "using SQL" I assume you meant SQL Server.
For all records where col1 and col2 are different days, you can use !=
SELECT *
FROM TBL
WHERE DateDiff(d, col1, col2) != 0
Check out the DatePart function. It enables extracting day, month, year, etc. from a date, which appears is what you are asking about.
http://msdn.microsoft.com/en-us/library/ms174420.aspx
If you are using SQL Server (version 2008 and above), you can compare just the date portions of the datetime fields by casting them to the DATE format:
CAST(MyDate AS DATE) >= CAST(TheOtherDate AS DATE)
Related
I am trying to execute a regular expression in SQL Server to match a MM/YY formatted VARCHAR string.
I have tried
WHERE ExpiryDate LIKE '[0-9][0-9]/[0-9][0-9]'
which allows incorrect dates like 30/18.
I also tried
WHERE ExpiryDate LIKE '0[1-9]|1[012]/[0-3][0-9]'
But SQL Server does not accept pipe separated as an OR operator.
I need the month to match 01 - 12
I can do
WHERE ExpiryDate LIKE '0[1-9]/[0-9][0-9]'
OR ExpiryDate LIKE '10/[0-9][0-9]'
OR ExpiryDate LIKE '11/[0-9][0-9]'
OR ExpiryDate LIKE '12/[0-9][0-9]'
but I would prefer it to be within the regular expression.
Thanks in advance for any help.
If 2012+, you could use try_convert() to convert the expiration string into a date. Try_Convert() will return a NULL value if the conversion fails.
Example
Declare #YourTable table (ID int, ExpiryDate varchar(25))
Insert Into #YourTable values
(1,'09/17')
,(2,'30/17')
Select *
From #YourTable
Where try_convert(date,replace(ExpiryDate,'/','/01/')) >= '2017-09-01'
-- Where try_convert(date,replace(ExpiryDate,'/','/01/')) is null
Returns
ID ExpiryDate
1 09/17
If you need to convalidate dates, you could try something like this:
SET DATEFORMAT dmy
;WITH A AS (SELECT '18/12' AS EXPDATE UNION ALL SELECT '10/17' UNION ALL SELECT 'x2/16' )
SELECT *, ISDATE('01/'+EXPDATE) AS CHK FROM A
Output:
EXPDATE CHK
18/12 0
10/17 1
x2/16 0
date LIKE '0[1-9]/[0-9][0-9]' OR
date LIKE '1[0-2]/[0-9][0-9]'
Is much shorter. But without | it is hard to make variants... Notice, that LIKE takes not regexes, but wildcards.
Don't forget, that '[1-9]/[0-9][0-9]' can also happen. And other variants, with inner spaces and so on. If you are not absolutely sure in month format used, and don't depend on high speed, use #JohnCampeletti variant.
I'm using SQL Server 2012 and I need to write a query that will extract data greater than a particular date. The date field is called 'CreatedOn" and dates are recorded in this format "2014-08-18 17:02:57.903".
Currently, the date part of my query stands as follows:
WHERE CreatedOn > '2014-08-18'
Problem is extracted data includes those of '2014-08-18'. It's like the > (greater than) is acting like >= (greater than or equal)!
How should I write my query if I need all data, say greater than '2014-08-18'?
Try the following condition. The problem is that 2014-08-18 is really 2014-08-18 00:00:00 (includes the hour), so any date time in that day will be greater.
WHERE CreatedOn >= '2014-08-19'
'2014-08-18' actually means '2014-08-18 00:00:00'
So if you do not want 18th you should put either '2014-08-19' or specify the hours you want your date to be bigger of.
As the others have said it is actually translating to CreatedOn > 2014-08-18 00:00:00
Instead try converting your datetime field to a short ate and compare those.
The 126 in Convert maps to the yyyy-mm-ddThh:mi:ss.mmm format.
WHERE CONVERT(char(10), CreatedOn,126) > '2014-08-18'
It sounds like when you're saying you want records "greater than '2014-08-18' you actually mean "records that occurred past 2014-08-18 23:59:59.999999" - you have to take into account time when working with dates, unless the time is otherwise removed (which in your sample data it was not.
You could do something like the following:
declare #gtDate datetime
set #gtDate = dateadd(d, 1, convert(datetime,convert(varchar(10), '2014-08-18', 101)))
....
WHERE CreatedOn >= #gtDate
Here we're taking your '2014-08-18', convert it to a varchar containing only the date (to help in case '2014-08-18' is ever '2014-08-18 12:00:00 as an example)
Then we convert the varchar back to a date, and add a day to it. In the end the statement says
Give me records that occured on 2014-08-19 or greater
EDIT:
Here's a fiddle demonstrating
http://sqlfiddle.com/#!6/90465/1
Note that we have 4 rows of data potential
insert into sampleData (Created)
select '2014-08-17'
union all select '2014-08-18'
union all select '2014-08-18 12:00:00'
union all select '2014-08-19'
union all select '2014-08-19 15:00:00'
only the bottom 2 rows (2014-08-19 and 2014-08-19 15:00:00) would be returned
I have a table with one column dateX formatted as datetime and containing standard dates.
How can I select all records from this table where this dateX equals a certain date, e.g. May 9, 2014 ?
I tried the following, but this returns nothing even if I have several records with this date.
SELECT *
FROM dbo.LogRequests
WHERE (CONVERT(VARCHAR(10), dateX, 101) = '09/05/14')
Edit: In the database the above example looks as follows, using SQL 2012: 2014-05-09 00:00:00.000
The easiest way is to convert to a date:
SELECT *
FROM dbo.LogRequests
WHERE cast(dateX as date) = '2014-05-09';
Often, such expressions preclude the use of an index. However, according to various sources on the web, the above is sargable (meaning it will use an index), such as this and this.
I would be inclined to use the following, just out of habit:
SELECT *
FROM dbo.LogRequests
WHERE dateX >= '2014-05-09' and dateX < '2014-05-10';
For Perfect DateTime Match in SQL Server
SELECT ID FROM [Table Name] WHERE (DateLog between '2017-02-16 **00:00:00.000**' and '2017-12-16 **23:59:00.999**') ORDER BY DateLog DESC
SELECT *
FROM LogRequests
WHERE cast(dateX as date) between '2014-05-09' and '2014-05-10';
This will select all the data between the 2 dates
I using a query where I am selecting some attributes from the table based on a where condition. My where condition is-
date>GetDate();
I have tried this-
SELECT TOP 2 img,name,substring(description,1,80) as
description,Convert(nvarchar,date,106) as date
FROM tbl_test
where date>=Convert(nvarchar,GetDate(),106)
order by date Asc;
This query is running fine but showing different result as compared to a different query of similar kind in which I am not converting the date format.
SELECT TOP 2 img,name,substring(description,1,80) as description,date
FROM tbl_test
where date>=GetDate()
order by date Asc;
Please guide me where I am doing wrong?
Your first query will convert getdate() into nvarchar data type and it will compare date with string while 2nd query will compare 2 dates. So 2nd option is better. Still if you want to convert date into string then check then use 102 format like
WHERE CONVERT(varchar(20),date,102) >= CONVERT(varchar(20), getdate(),102)
For select column you can use format which you want like
SELECT CONVERT(varchar(20),date,106)
Final Query is :
SELECT TOP 2
img,
name,
SUBSTRING(description,1,80) as description,
CONVERT(varchar(20),date,106) as [DisplayDate]
FROM tbl_test
WHERE CONVERT(varchar(20),date,102) >= CONVERT(varchar(20), getdate(),102)
ORDER BY date ASC;
Without convert to varchar, you can cast getdate() to date to remove time part :
SELECT TOP 2
img,
name,
SUBSTRING(description,1,80) as description,
CONVERT(varchar(20),date,106) as [DisplayDate]
FROM tbl_test
WHERE date >= CAST(getdate() as date)
ORDER BY date ASC;
SQL Fiddle Demo
DECLARE #Date Datetime;
SET #Date = GETDATE();
SELECT CONVERT(VARCHAR(12), #Date, 113) AS Date
RESULT
╔══════════════╗
║ Date ║
╠══════════════╣
║ 01 Jan 2014 ║
╚══════════════╝
Edit
as Upendra Chaudhari has explained that when you do comparing column Date with a string =Convert(varchar(20),GetDate(),102),
what is actually happening behind the scenes is Convert(varchar(20),GetDate(),102) returns a string 2014.01.01 but to compare this string with a Datetime column SQL Server does an implicit conversion to compare both values. Sql Server have to have both values in the same datatype to compare them.
Now datatype Datetime has Precedence over nvarchar/varchar datatype so sql server converts the string into datetime datatype which returns something like
SELECT CAST('2014.01.01' AS DATETIME)
Result : 2014-01-01 00:00:00.000
Now in this process of converting your values to string and then back to datetime you have actually lost all the time values in your comparing values. and this is the reason why you are getting unexpected results back.
so make sure whenever you are comparing to have exactly the same datatype on both sides and take control of any data conversions in your code rather then sql server doing datatype conversions for you.
I hope this will explain you why you are getting different results .
You may try:
where date>=CONVERT(VARCHAR(11), GETDATE(), 113)
I have a set of dates that are in the format DD-MMM-YYYY. I need to be able to compare dates by using only the DD-MMM part of the date, since the year isn't important.
How would I achieve this?
I have tried reading up on the DATEPART function (edit: which evidently wouldn't work) but I can only theoretically get that to return either the DD or the MMM parts, not both of them at once.
Edit: added oracle tag. Sorry.
Example of date field: 01-MAR-1994
If your column is of type DATE then it doesn't have a format.
If I understand you right, then you want to view the mon-dd part only, so you need to convert it with TO_CHAR function,
i.e.:
select to_char(your_date_column, 'mon-dd') from your_table
Convert your dates using the following format, it will only month and the date part. You have to replace getdate() with you date fields.:
select convert(varchar(5),getdate(),110)
Assuming that you are using SQL Server or Oracle since you attempted using DATEPART, you can just get the day and month using the DAY() and MONTH() functions. Assuming, again, that the dates you are comparing are in two different tables, it would look similar to this:
SELECT MONTH(t1.date), DAY(t2.date)
FROM table AS t1
INNER JOIN table2 AS t2
ON t1.key = t2.key
WHERE MONTH(t1.date) = MONTH(t2.date)
AND DAY(t1.date) = DAY(t2.date)
EDIT: If you are just comparing rows in the same table, you only need a very simple query.
SQLFiddle
select id, TO_CHAR(most_recent, 'mon-dd')
from (
select id, MAX(date1) AS most_recent
from table1
group by id
)
You can also combine month and day into one integer:
EXTRACT(MONTH FROM datecol) * 100 + EXTRACT(DAY FROM datecol) AS MonthDay
Then it's easier to sort and compare.
select FORMAT(yourcoulmn_name, 'dd/MM') from table
This should do the trick
`select CONVERT(varchar(7),datetime_column,100) from your_table`
date_default_timezone_set("Asia/Kolkata");
$m = date("m");//Month
$d = date("d");//Day
$sql = "SELECT * FROM contactdata WHERE MONTH(date) = '$m' AND DAY(date) = '$d' ";
only checks day and month and returns today, day and month from database
SELECT LEFT(REPLACE(CONVERT(varchar(10),GETDATE()-1,3),'/',''),4)
WOuld this work for you?
FROMAT(DATETIME, 'dd-MMM') = FROMAT(DATETIME, 'dd-MMM') use any format you want