How to split a single column values to multiple column values? - sql

Question

I have a problem splitting single column values to multiple column values.
For Example:
Name
------------
abcd efgh
ijk lmn opq
asd j. asdjja
asb (asdfas) asd
asd
and I need the output something like this:
first_name last_name
----------------------------------
abcd efgh
ijk opq
asd asdjja
asb asd
asd null
The middle name can be omitted (no need for a middle name) The columns are already created and need to insert the data from that single Name column.

Answer 1

Your approach won't deal with lot of names correctly but...
SELECT CASE
WHEN name LIKE '% %' THEN LEFT(name, Charindex(' ', name) - 1)
ELSE name
END,
CASE
WHEN name LIKE '% %' THEN RIGHT(name, Charindex(' ', Reverse(name)) - 1)
END
FROM YourTable

Answer 2

An alternative to Martin's
select LEFT(name, CHARINDEX(' ', name + ' ') -1),
STUFF(name, 1, Len(Name) +1- CHARINDEX(' ',Reverse(name)), '')
from somenames
Sample table
create table somenames (Name varchar(100))
insert somenames select 'abcd efgh'
insert somenames select 'ijk lmn opq'
insert somenames select 'asd j. asdjja'
insert somenames select 'asb (asdfas) asd'
insert somenames select 'asd'
insert somenames select ''
insert somenames select null

Answer 3

;WITH Split_Names (Name, xmlname)
AS
(
SELECT
Name,
CONVERT(XML,'<Names><name>'
+ REPLACE(Name,' ', '</name><name>') + '</name></Names>') AS xmlname
FROM somenames
)
SELECT
xmlname.value('/Names[1]/name[1]','varchar(100)') AS first_name,
xmlname.value('/Names[1]/name[2]','varchar(100)') AS last_name
FROM Split_Names
and also check the link below for reference
http://jahaines.blogspot.in/2009/06/converting-delimited-string-of-values.html

Answer 4

What you need is a split user-defined function. With that, the solution looks like
With SplitValues As
(
Select T.Name, Z.Position, Z.Value
, Row_Number() Over ( Partition By T.Name Order By Z.Position ) As Num
From Table As T
Cross Apply dbo.udf_Split( T.Name, ' ' ) As Z
)
Select Name
, FirstName.Value
, Case When ThirdName Is Null Then SecondName Else ThirdName End As LastName
From SplitValues As FirstName
Left Join SplitValues As SecondName
On S2.Name = S1.Name
And S2.Num = 2
Left Join SplitValues As ThirdName
On S2.Name = S1.Name
And S2.Num = 3
Where FirstName.Num = 1
Here's a sample split function:
Create Function [dbo].[udf_Split]
(
#DelimitedList nvarchar(max)
, #Delimiter nvarchar(2) = ','
)
RETURNS TABLE
AS
RETURN
(
With CorrectedList As
(
Select Case When Left(#DelimitedList, Len(#Delimiter)) <> #Delimiter Then #Delimiter Else '' End
+ #DelimitedList
+ Case When Right(#DelimitedList, Len(#Delimiter)) <> #Delimiter Then #Delimiter Else '' End
As List
, Len(#Delimiter) As DelimiterLen
)
, Numbers As
(
Select TOP( Coalesce(DataLength(#DelimitedList)/2,0) ) Row_Number() Over ( Order By c1.object_id ) As Value
From sys.columns As c1
Cross Join sys.columns As c2
)
Select CharIndex(#Delimiter, CL.list, N.Value) + CL.DelimiterLen As Position
, Substring (
CL.List
, CharIndex(#Delimiter, CL.list, N.Value) + CL.DelimiterLen
, CharIndex(#Delimiter, CL.list, N.Value + 1)
- ( CharIndex(#Delimiter, CL.list, N.Value) + CL.DelimiterLen )
) As Value
From CorrectedList As CL
Cross Join Numbers As N
Where N.Value <= DataLength(CL.List) / 2
And Substring(CL.List, N.Value, CL.DelimiterLen) = #Delimiter
)

Answer 5

SELECT
SUBSTRING_INDEX(SUBSTRING_INDEX(rent, ' ', 1), ' ', -1) AS currency,
SUBSTRING_INDEX(SUBSTRING_INDEX(rent, ' ', 3), ' ', -1) AS rent
FROM tolets

Answer 6

I used it recently:
select
substring(name,1,charindex(' ',name)-1) as Col1,
substring(name,charindex(' ',name)+1,len(name)) as Col2
from TableName

Answer 7

Here is how I did this on a SQLite database:
SELECT SUBSTR(name, 1,INSTR(name, " ")-1) as Firstname,
SUBSTR(name, INSTR(name," ")+1, LENGTH(name)) as Lastname
FROM YourTable;
Hope it helps.