Sorry for the simple question, but I am self taught and know that there are gaps in my education.
To print an array in objective C, I believe is:
NSLog(#"My array: %#", myArray);
How can I print an array of arrays?
Thanks
You want this:
for(NSArray *subArray in myArray) {
NSLog(#"Array in myArray: %#",subArray);
}
This will work for an array that has arrays nested one level deep.
You don't need to do anything different to log an array of arrays; the code exactly as you've written it will already show the contents of the sub-arrays.
That is, the following program:
#import <Foundation/Foundation.h>
int main (int argc, const char * argv[]) {
NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];
NSMutableArray *array = [NSMutableArray array];
for (int i=0; i<5; ++i) {
NSMutableArray *sub = [NSMutableArray array];
for (int j=0; j<=i; ++j) {
[sub addObject:[NSString stringWithFormat:#"%d", j]];
}
[array addObject:sub];
}
NSLog(#"Array: %#", array);
[pool drain];
return 0;
}
Produces the following output:
Array: (
(
0
),
(
0,
1
),
(
0,
1,
2
),
(
0,
1,
2,
3
),
(
0,
1,
2,
3,
4
)
)
Clearly, it's already logging the sub-arrays just fine. If you want to control the formatting differently, you'd have to manually iterate them, but by default, the -description of an NSArray is little more than the -description of every object in that array, which includes all sub-arrays.
So I was embarrassed by the recursiveDescription thing, so I wrote my own as a category on NSArray. Note that this code will print out a description for an array of arrays to any depth. The description itself could probably use a bit more formatting than commas and newlines. Here you go:
#interface NSArray (RecursiveDescription)
- (NSString *)recursiveDescription;
#end
#implementation NSArray (RecursiveDescription)
- (NSString *)recursiveDescription {
NSMutableString *description = [[NSMutableString alloc] initWithString:#"Array (\n"];
NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init];
for (NSObject *child in self) {
if ([child respondsToSelector:#selector(recursiveDescription)]) {
[description appendFormat:#"%#,\n", [child recursiveDescription]];
}
else {
[description appendFormat:#"%#,\n", [child description]];
}
}
[pool drain];
[description appendString:#"\n)"];
return [description autorelease];
}
#end
Try logging the return value from NSArray's -description method.
NSLog(#"My array: %#", [myArray description]);
Moreover, for print all of elements
int i = 0;
int j = 0;
for(NSArray *subArray in myArray) {
NSLog(#"[%d] %#",i, subArray);
j =0;
for(NSObject *element in subArray) {
NSLog(#"[%d:%d] %#", i,j,element);
++j;
}
++i;
}
As much as I like how easy it is to log out an object in Objective-C, I didn't like seeing a 2D array as a very long list. I created a category on NSArray that prints out 2D arrays. It's not perfect and can be improved, but it has worked for me.
Header:
#interface NSArray (Logging)
- (void)log2DArray;
#end
Implementation:
#import "NSArray+Logging.h"
#implementation NSArray (Logging)
- (void)log2DArray {
NSMutableString *formattedString = [[NSMutableString alloc] init];
NSInteger longestSubarrayLength = 0;
for (NSArray *subarray in self) {
if (subarray.count > longestSubarrayLength) {
longestSubarrayLength = subarray.count;
}
}
for (int i = 0; i < longestSubarrayLength; i++) {
[formattedString appendFormat:#"\n"];
for (int j = 0; j < self.count; j++) {
NSArray *tempArray = [self objectAtIndex:j];
if (tempArray.count <= longestSubarrayLength) {
[formattedString appendFormat:#"%#\t", [tempArray objectAtIndex:i]];
} else {
[formattedString appendFormat:#"\t"];
}
}
}
NSLog(#"%#", formattedString);
}
#end
Usage:
[myArray log2DArray];
Or use recursiveDescription :)
NSLog(#"my arrays: %#", [myArray recursiveDescription]);
Related
I have an NSmutable array and I am adding some strings present in the C array to it. By using this method
if (!self.arrayOfVariableNames) {
self.arrayOfVariableNames = [[NSMutableArray alloc] init];
for (int i = 0; i< cols; i++) {
[self.arrayOfVariableNames addObject:[NSString stringWithCString:cArrayOfVariableNames[i] encoding:NSUTF8StringEncoding ]];
}
}
else{
[self.arrayOfVariableNames removeAllObjects];
for (int i = 0; i< cols; i++) {
[self.arrayOfVariableNames addObject:[NSString stringWithCString:cArrayOfVariableNames[i] encoding:NSUTF8StringEncoding ]];
}
}
Does this method ensure that the objects in the NSmutableArray won't be deallocated when the C array is taken out of memory?
if this array arrayOfVariableNames is becoming Null, then the problem is with the initialisation of the array. Please try to use Lazy loading by doing this:
- (NSArray*)arrayOfVariableNames {
if (!_arrayOfVariableNames) {
_arrayOfVariableNames = [[NSMutableArray alloc] init]; //initialise the array if needed
}
return _arrayOfVariableNames; //else return the already initialized array
}
and please comment out this line in your code: self.arrayOfVariableNames = [[NSMutableArray alloc] init];
****EDIT****
Please find the update code in https://docs.google.com/file/d/0BybTW7Dwp2_vdHhQN1p1UzExdTA/edit?pli=1. Have a look at it.
Yes. NSArray retains anything in it.
But you should stop chaining your NSString creation and instead creat a string a line before adding it to the array. Then check for nil.
Only add it to the array if it is not nil.
Do code defensively.
arrayOfVariableNames will not change when the C array get deallocated.
Make sure that your arrayOfVariableNames variable is strong.
#property (nonatomic, strong) NSMutableArray *arrayOfVariableNames;
if (!self.arrayOfVariableNames)
{
self.arrayOfVariableNames = [[NSMutableArray alloc] init];
}
else
{
[self.arrayOfVariableNames removeAllObjects];
}
for (int i = 0; i< cols; i++)
{
NSString *tempString = [NSString stringWithCString:cArrayOfVariableNames[i] encoding:NSUTF8StringEncoding];
if([tempString length] > 0)
{
[self.arrayOfVariableNames addObject:tempString];
}
else
{
NSLog(#"string is empty");
}
}
#import <Foundation/Foundation.h>
int main(int argc, const char * argv[])
{
#autoreleasepool {
NSMutableString *outputStringSet = [[NSMutableString alloc] init];
NSMutableString *outputStringArray = [[NSMutableString alloc] init];
NSMutableSet *mySet = [[NSMutableSet alloc] init];
NSMutableArray *myArray = [[NSMutableArray alloc] initWithCapacity: 10];
int userInput;
NSLog(#"Enter 10 numbers");
for( int i = 0; i < 10; i++) {
scanf("%i", &userInput);
NSNumber *input = [[NSNumber alloc] initWithInt: userInput];
[myArray addObject:input];
if([mySet member: input]) {
[mySet addObject: input];
}
}
for (int k = 0; k < [myArray count]; k++) {
[outputStringArray appendFormat:#"%#, ", [myArray objectAtIndex:k]];
}
NSLog(#"%#", [outputStringArray substringToIndex:[outputStringArray length] - 2]);
for (int j = 0; j < [myArray count]; j++) {
if([mySet containsObject: [myArray objectAtIndex:j]]) {
[outputStringSet appendFormat:#"%#, ", [myArray objectAtIndex:j]];
}
NSLog(#"%#", outputStringSet);
}
}
return 0;
}
Code above prints the array but not the appropriate object in the set
Why?
Please explain clearly. I am a bit of a noob, and couldnt find the answer anywhere else.
thanks
if([mySet member: input]) {
[mySet addObject: input];
}
You're adding the object to the set if it’s already in it. You want the reverse: add the object if it's not in it.
Thus:
if ( ! [mySet member:input] )
[mySet addObject:input];
By the way, you should use containsObject: instead of member: in your test:
containsObject:
Returns a Boolean value that indicates whether a given
object is present in the set.
- (BOOL)containsObject:(id)anObject
Edit: you don't even need to test if the object is already in the set before adding it. After all, that's the main purpose of a NSSet: to ensure uniqueness of its objects. So if you add an object twice, the second call will silently be ignored, as the object is alreay in it.
Your set is empty because of
if([mySet member: input]) {
[mySet addObject: input];
}
member:
Determines whether the set contains an object equal to a given object,
and returns that object if it is present.
- (NSArray *) makeKeyValueArray: (NSArray *) arr
{
NSMutableArray *result = [[NSMutableArray alloc] init];
for(int i = 0; i < [arr count]; i++)
{
[result addObject:[[KeyValue alloc] initWithData:[arr objectAtIndex:i] :[arr objectAtIndex:i]]];
}
return result;
}
Instruments is showing 188 leaks in the above code, why is that? can anyone please explain it to me?
- (NSArray *) makeKeyValueArray: (NSArray *) arr
{
NSMutableArray *result = [[NSMutableArray alloc] init];
for(int i = 0; i < [arr count]; i++)
{
id obj = [[KeyValue alloc] initWithData:[arr objectAtIndex:i] :[arr objectAtIndex:i]]; // obj reference count is now 1, you are the owner
[result addObject:obj]; //reference count is now 2, the array is also an owner as well as you.
[obj release];// reference count is now 1, you are not the owner anymore
}
return [result autorelease];
}
Take a look at Basic Memory Management Rules
you must relinquish ownership of an object you own
I'm trying to re-arrange words into alphabetical order. For example, tomato would become amoott, or stack would become ackst.
I've found some methods to do this in C with char arrays, but I'm having issues getting that to work within the confines of the NSString object.
Is there an easier way to do it within the NSString object itself?
You could store each of the string's characters into an NSArray of NSNumber objects and then sort that. Seems a bit expensive, so I would perhaps just use qsort() instead.
Here it's provided as an Objective-C category (untested):
NSString+SortExtension.h:
#import <Foundation/Foundation.h>
#interface NSString (SortExtension)
- (NSString *)sorted;
#end
NSString+SortExtension.m:
#import "NSString+SortExtension.h"
#implementation NSString (SortExtension)
- (NSString *)sorted
{
// init
NSUInteger length = [self length];
unichar *chars = (unichar *)malloc(sizeof(unichar) * length);
// extract
[self getCharacters:chars range:NSMakeRange(0, length)];
// sort (for western alphabets only)
qsort_b(chars, length, sizeof(unichar), ^(const void *l, const void *r) {
unichar left = *(unichar *)l;
unichar right = *(unichar *)r;
return (int)(left - right);
});
// recreate
NSString *sorted = [NSString stringWithCharacters:chars length:length];
// clean-up
free(chars);
return sorted;
}
#end
I think separate the string to an array of string(each string in the array contains only one char from the original string). Then sort the array will be OK. This is not efficient but is enough when the string is not very long. I've tested the code.
NSString *str = #"stack";
NSMutableArray *charArray = [NSMutableArray arrayWithCapacity:str.length];
for (int i=0; i<str.length; ++i) {
NSString *charStr = [str substringWithRange:NSMakeRange(i, 1)];
[charArray addObject:charStr];
}
NSString *sortedStr = [[charArray sortedArrayUsingSelector:#selector(localizedCaseInsensitiveCompare:)] componentsJoinedByString:#""];
// --------- Function To Make an Array from String
NSArray *makeArrayFromString(NSString *my_string) {
NSMutableArray *array = [[NSMutableArray alloc] init];
for (int i = 0; i < my_string.length; i ++) {
[array addObject:[NSString stringWithFormat:#"%c", [my_string characterAtIndex:i]]];
}
return array;
}
// --------- Function To Sort Array
NSArray *sortArrayAlphabetically(NSArray *my_array) {
my_array= [my_array sortedArrayUsingSelector:#selector(localizedCaseInsensitiveCompare:)];
return my_array;
}
// --------- Function Combine Array To Single String
NSString *combineArrayIntoString(NSArray *my_array) {
NSString * combinedString = [[my_array valueForKey:#"description"] componentsJoinedByString:#""];
return combinedString;
}
// Now you can call the functions as in below where string_to_arrange is your string
NSArray *blowUpArray;
blowUpArray = makeArrayFromString(string_to_arrange);
blowUpArray = sortArrayAlphabetically(blowUpArray);
NSString *arrayToString= combineArrayIntoString(blowUpArray);
NSLog(#"arranged string = %#",arrayToString);
Just another example using NSMutableString and sortUsingComparator:
NSMutableString *mutableString = [[NSMutableString alloc] initWithString:#"tomat"];
[mutableString appendString:#"o"];
NSLog(#"Orignal string: %#", mutableString);
NSMutableArray *charArray = [NSMutableArray array];
for (int i = 0; i < mutableString.length; ++i) {
[charArray addObject:[NSNumber numberWithChar:[mutableString characterAtIndex:i]]];
}
[charArray sortUsingComparator:^NSComparisonResult(id _Nonnull obj1, id _Nonnull obj2) {
if ([obj1 charValue] < [obj2 charValue]) return NSOrderedAscending;
return NSOrderedDescending;
}];
[mutableString setString:#""];
for (int i = 0; i < charArray.count; ++i) {
[mutableString appendFormat:#"%c", [charArray[i] charValue]];
}
NSLog(#"Sorted string: %#", mutableString);
Output:
Orignal string: tomato
Sorted string: amoott
I have been told that I can use NSPredicate to duplicate the results of this method
- (void) clearArrayOut
{
bool goAgain = false;
for (int j=0; j<[array count]; j++)
{
if ([[array objectAtIndex:j] someMethod] == NO)
{
[array removeObjectAtIndex:j];
goAgain = true;
break;
}
}
if (goAgain) [self clearArrayOut];
}
How can I make an NSPredicate that will filter an array based on the results of some method of a custom class's call?
To make a copy with the filter applied:
NSArray *filteredArray = [someArray filteredArrayUsingPredicate:
[NSPredicate predicateWithBlock:^(id object, NSDictionary *bindings) {
return [object someMethod]; // if someMethod returns YES, the object is kept
}]];
To filter an NSMutableArray in place:
[someMutableArray filterUsingPredicate:
[NSPredicate predicateWithBlock:^(id object, NSDictionary *bindings) {
return [object someMethod]; // if someMethod returns YES, the object is kept
}]];
But I would probably just use a for loop if I were filtering a small array. However, I'd write my for loop a little differently to avoid having to either decrement the index variable or call myself recursively:
- (void)clearArrayOut:(NSMutableArray *)array {
for (int i = array.count - 1; i >= 0; --i) {
if (![[array objectAtIndex:i] someMethod]) {
[array removeObjectAtIndex:i];
}
}
}
You simply write it into your predicate, for example, lets assume you have an object with a method called isOdd and you want to filter your array to include only objects that return true for isOdd, you can do this:
#import <Foundation/Foundation.h>
#interface barfoo : NSObject
{
int number;
}
- (BOOL)isOdd;
- (id)initWithNumber:(int)number;
#end
#implementation barfoo
- (NSString *)description
{
return [NSString stringWithFormat:#"%i", number];
}
- (BOOL)isOdd
{
return (number % 2);
}
- (id)initWithNumber:(int)tnumber
{
if((self = [super init]))
{
number = tnumber;
}
return self;
}
#end
int main(int argc, char *argv[]) {
#autoreleasepool {
NSMutableArray *array = [NSMutableArray array];
for(int i=0; i<10; i++)
{
barfoo *foo = [[barfoo alloc] initWithNumber:i];
[array addObject:[foo autorelease]];
}
NSLog(#"%#", array); // prints 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
NSPredicate *predicate = [NSPredicate predicateWithFormat:#"isOdd == true"]; // This is oure predicate. isOdd must be true for objects to pass
NSArray *result = [array filteredArrayUsingPredicate:predicate];
NSLog(#"%#", result);
}
}
Of course this also works the other way around, your predicate could also read isOdd == false or you can add even more requirements for an object to pass. Eg isOdd == true AND foo == bar. You can read more about the NSPredicate syntax in the NSPredicate documentation.
Your implementation is terribly inefficient to start with: rather than continuing the deletions recursively, you could change your loop to not advance if an object has been deleted, like this:
- (void) clearArrayOut {
int j = 0;
while (j < [array count]) {
if ([[array objectAtIndex:j] someMethod] == NO) {
[array removeObjectAtIndex:j];
} else {
j++;
}
}
}
You could do the same thing using filterUsingPredicate:, like this:
- (void) clearArrayOut {
NSPredicate *p = [NSPredicate predicateWithBlock:^BOOL(id obj, NSDictionary *bindings) {
return [obj someMethod] == NO
}];
[array filterUsingPredicate:p];
}