Try this:
unsigned long long int N; = 23229877463LL;
NSString* s = [NSString stringWithFormat:#"dec:%qi, hex:%qX",N,N];
NSLog(#"output: %#",s);
output: dec:23229877460, hex:689BCCD400000005
What's up with the 00000005??? In mySQL, hex(23229877460) = 5689BCCD4. Also, every other language seems to do this correctly. A 16 digit long hex is like 4 gazillion (16^16), right?
How can I get objective-c to format hex numbers that other languages can understand?
After fixing the spurious ; to yield:
unsigned long long int N = 23229877463LL;
NSString* s = [NSString stringWithFormat:#"dec:%qi, hex:%qX",N,N];
NSLog(#"output: %#",s);
The code works exactly as expected:
2011-01-09 10:46:16.236 dfjkdfkjfdjkfd[25716:a0f] output: dec:23229877463, hex:5689BCCD7
There is something else wrong. You'll need to post more code. The line used to compile the file would probably be helpful, too.
And for giggles:
unsigned long long int N = 23229877460LL;
NSString* s = [NSString stringWithFormat:#"dec:%qi, hex:%qX",N,N];
2011-01-09 10:49:10.425 dfjkdfkjfdjkfd[25755:a0f] output: dec:23229877460, hex:5689BCCD4
Related
My goal is to compare two hex strings and determine which number is higher. I assume I need to convert those hex strings to integers to be able to compare them mathematically, but the conversion to unsigned isn't working. Here's what I've tried:
NSString *firstHex = #"35c1f029684fe";
NSString *secondHex = #"35c1f029684ff";
unsigned first = 0;
unsigned second = 0;
NSScanner *firstScanner = [NSScanner scannerWithString:firstHex];
NSScanner *secondScanner = [NSScanner scannerWithString:secondHex];
[firstScanner scanHexInt:&first];
[secondScanner scanHexInt:&second];
NSLog(#"First: %d",first);
NSLog(#"Second: %d",second);
But the log output gives me:
First: -1
Second: -1
I can't figure out what I'm doing wrong. Am I using NSScanner correctly here? Thanks in advance.
Your hex numbers are 13 digits long - 52 binary bits. This is longer than 32 bits, use long long variables and scanHexLongLong: instead.
For the sake of completeness, here's the working code using the advice from the above answer:
NSString *firstHex = #"35c1f029684fe";
NSString *secondHex = #"35c1f029684ff";
unsigned long long first = 0;
unsigned long long second = 0;
NSScanner *firstScanner = [NSScanner scannerWithString:firstHex];
NSScanner *secondScanner = [NSScanner scannerWithString:secondHex];
[firstScanner scanHexLongLong:&first];
[secondScanner scanHexLongLong:&second];
NSLog(#"First: %llu",first);
NSLog(#"Second: %llu",second);
if(first > second){
NSLog(#"First is greater");
}else{
NSLog(#"Second is greater");
}
it must be faster to just find out which one is larger as a string:
the longer string is bigger (ignoring leading 0's)
if they are the same then you can convert each char and compare, Repeat for each char...
Please forgive the simplicity of the question. I'm completely new to Objective C.
I'd like to know how to concatenate integer and string values and print them to the console.
This is what I'd like for my output:
10 + 20 = 30
In Java I'd write this code to produce the needed results:
System.Out.Println(intVarWith10 + " + " + intVarWith20 + " = " + result);
Objective-C is quite different. How can we concatenate the 3 integers along with the strings in between?
You can use following code
int iFirst,iSecond;
iFirst=10;
iSecond=20;
NSLog(#"%#",[NSString stringWithFormat:#"%d + %d =%d",iFirst,iSecond,(iFirst+iSecond)]);
Take a look at NSString - it has a method stringWithFormat that does what you require. For example:
NSString* yString = [NSString stringWithFormat:#"%d + %d = %d",
intVarWith10, intVarWith20 , result];
You can use C style syntax, with NSLog (If you just need to print)
NSLog(#"%d+%d=%d",intvarWith10,intvarWith20,result);
If you want a string variable holding the value
NSString *str = [NSString stringWithFormat:#"%d+%d=%d",intvarWith10,intvarWith20,result];
You have to create an NSString with format and specify the data type.
Something like this :
NSInteger firstOperand=10;
NSInteger secondOperand=20;
NSInteger result=firstOperand+secondOperand;
NSString *operationString=[NSString stringWithFormat:#"%d + %d = %d",firstOperand,secondOperand,result];
NSLog(#"%#",operationString);
NSString with format follows the C printf syntax
Check below code :
int i = 8;
NSString * tempStr = [NSString stringWithFormat#"Hello %d",i];
NSLog(#"%#",tempStr);
I strongly recommend you this link Objective-C Reference.
The Objective-C int data type can store a positive or negative whole number. The actual size or range of integer that can be handled by the int data type is machine and compiler implementation dependent.
So you can store like this.
int a,b;
a= 10;
b= 10;
then performing operation you need to first understand NSString.
C style character strings are composed of single byte characters and therefore limited in the range of characters that can be stored.
int C = a + b;
NSString *strAnswer = [NSString stringWithFormat:#"Answer %d + %d = %d", a , b, c];
NSLog(#"%#",strAnswer)
Hope this will help you.
This question already has an answer here:
Closed 11 years ago.
Possible Duplicate:
Storing and retrieving unsigned long long value to/from NSString
Having problems trying to convert an NSString to an unsigned long long. Heres the code:
NSString* mp3id = [[NSString alloc] initWithUTF8String:"16902439379132728577"];
NSNumberFormatter * f = [[NSNumberFormatter alloc] init];
NSNumber* persistentId = [f numberFromString:mp3id];
unsigned long long test = [persistentId unsignedLongLongValue];
NSLog(#"unsigned long long is %llu",test);
[f release];
Output:
2011-07-09 15:28:06.834 NBUnityMP3Plugin[443:307] unsigned long long is 16902439379132729344
2011-07-09 15:28:06.847 NBUnityMP3Plugin[443:307] persistant id is 1.690243937913273e+19
To make it clearner:
16902439379132728577 - input
16902439379132729344 - output
Ideally I would like to get that unsigned long long into an NSNumber variable. I figured that would be easy if I only had an unsigned long long.
NSNumberFormatter is representing the unsigned long long as a float, and I thought setting [f setAllowsFloats:NO]; after initializing the NSNumberFormatter would fix the problem. It doesn't seem to do that, though (returning nil when trying to set the number). It is possible that 16902439379132728577 is too long for NSNumberFormatter to handle as an integer, and it may only handle signed integers in the long long range.
I need to get a long value from an NSString.
For example, I have this:
NSString *test = #"5437128";
and I need :
long myLong = 5437128;
How I can get this long value from the NSString?
Thank you, it will help me!
long longVariable = [test longLongValue];
See NSString documentation..
Use the NSScanner like in the following code:
unsigned x;
[[NSScanner scannerWithString: s2] scanHexInt: &x];
when typing the scanHexInt stop at scan and see yourself which one you need - there are many possibilities to get values from strings....
You might want to use scanlonglong... having declared your variable as long
use this code :
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
long number = [[numberFormatter numberFromString:string] longValue];
[numberFormatter release];
i use the following in case you don't want to lose the fractions value of your number
double x =[stringValue doubleValue];
instead of
double x = [stringValue longLongValue];
if we assume that we have the following string value
and we want to convert it to double we have 2 ways
NSString * stringValue = #"31.211529225111";
way #1
double x = [stringValue longLongValue];
result will be : x = 31
way #2
double x =[stringValue doubleValue];
result will be : x = 31.211529225111001
Are there any Cocoa classes that will help me convert a hex value in a NSString like 0x12FA to a long or NSNumber? It doesn't look like any of the classes like NSNumberFormatter support hex numbers.
Thanks,
Hua-Ying
Here's a short example of how you would do it using NSScanner:
NSString* pString = #"0xDEADBABE";
NSScanner* pScanner = [NSScanner scannerWithString: pString];
unsigned int iValue;
[pScanner scanHexInt: &iValue];
See NSScanner's scanHex...: methods. That'll get you the primitive that you can wrap in an NSNumber.
here is the other way conversion, a long long int to hex string.
first the hex to long long.
NSString* pString = #"ffffb382ddfe";
NSScanner* pScanner = [NSScanner scannerWithString: pString];
unsigned long long iValue2;
[pScanner scanHexLongLong: &iValue2];
NSLog(#"iValue2 = %lld", iValue2);
and the other way, longlong to hex string...
NSNumber *number;
NSString *hexString;
number = [NSNumber numberWithLongLong:iValue2];
hexString = [NSString stringWithFormat:#"%qx", [number longLongValue]];
NSLog(#"hexString = %#", hexString);