Morning folks,
I have a temporary table with 135,000 rows and 24 columns, of those rows I need to insert about 8,000 of them into an 8 column table. If run my insert the first time round (i.e. when my 8 column table is empty) it runs in about 6 seconds. When I run the same query again (this time round it shouldn't insert anything as the rows have already been inserted) it takes 30 minutes!!
I've been unable to re-create this with a small simplified sample, but here's some sql for you to run anyway. It's running the last insert when the programme table has entries which causes the problems. Can anyone shed some light as to why this might be?
CREATE TEMPORARY TABLE TVTEMPTABLE (
PROGTITLE TEXT, YR YEAR, DIRECTOR TEXT, GENRE TEXT
);
CREATE TABLE GENRE (
GENREID INT NOT NULL AUTO_INCREMENT, GENRE TEXT, PRIMARY KEY(GENREID)
) ENGINE=INNODB;
CREATE TABLE PROGRAMME (
PROGRAMMEID INT NOT NULL AUTO_INCREMENT, GENREID INT NOT NULL, PROGTITLE TEXT, YR YEAR,
DIRECTOR TEXT, PRIMARY KEY(PROGRAMMEID), INDEX (GENREID), FOREIGN KEY (GENREID) REFERENCES GENRE(GENREID)
) ENGINE=INNODB;
INSERT INTO GENRE(GENRE) VALUES
('Consumer'),('Entertainment'),('Comedy'),('Film'),('Drama'),('Sport'),
('Sitcom'),('Travel'),('Documentary'),('Factual');
INSERT INTO TVTEMPTABLE(PROGTITLE, YR, DIRECTOR, GENRE) VALUES
('Breakfast','2011','n/a','Consumer'),('Breakfast','2011','n/a','Consumer'),
('Wanted Down Under','2011','n/a','Entertainment'),('Wanted Down Under','2011','n/a','Entertainment'),
('Lorraine','2011','n/a','Comedy'),('Lorraine','2011','n/a','Comedy'),
('Supernanny USA','2011','n/a','Film'),('Supernanny USA','2011','n/a','Film'),
('Three Coins in the Fountain','2011','n/a','Drama'),('Three Coins in the Fountain','2011','n/a','Drama'),
('The Wright Stuff','2011','n/a','Sport'),('The Wright Stuff','2011','n/a','Sport'),
('This Morning','2011','n/a','Sitcom'),('This Morning','2011','n/a','Sitcom'),
('Homes Under the Hammer','2011','n/a','Travel'),('Homes Under the Hammer','2011','n/a','Travel'),
('LazyTown','2011','n/a','Documentary'),('LazyTown','2011','n/a','Documentary'),
('Jeremy Kyle','2011','n/a','Factual'),('Jeremy Kyle','2011','n/a','Factual');
INSERT INTO PROGRAMME (
PROGTITLE, GENREID, YR,
DIRECTOR)
SELECT
T.PROGTITLE, MAX(G.GENREID),
MAX(T.YR), MAX(T.DIRECTOR)
FROM
TVTEMPTABLE T
INNER JOIN GENRE G ON G.GENRE=T.GENRE
LEFT JOIN PROGRAMME P ON P.PROGTITLE=T.PROGTITLE
WHERE P.PROGTITLE IS NULL
GROUP BY T.PROGTITLE;
Edit: Is this what you mean by index?
CREATE TEMPORARY TABLE TVTEMPTABLE (
PROGTITLE VARCHAR(50), YR YEAR, DIRECTOR TEXT, GENRE VARCHAR(50), INDEX(PROGTITLE,GENRE)
);
CREATE TABLE PROGRAMME (
PROGRAMMEID INT NOT NULL AUTO_INCREMENT, GENREID INT NOT NULL, PROGTITLE VARCHAR(50), YR YEAR,
DIRECTOR TEXT, PRIMARY KEY(PROGRAMMEID), INDEX (GENREID,PROGTITLE), FOREIGN KEY (GENREID) REFERENCES GENRE(GENREID)
) ENGINE=INNODB;
Edit 2: This is the result from the desc extended. After indexing (I may have done this wrong?). The insert still takes a long time
Ok yes the answer was to properly index my tables, what I didn't realise however was
INDEX(A,B,C);
Is different from
INDEX(A),INDEX(B),INDEX(C);
Related
I keep getting the error:
Cannot add or update a child row: a foreign key constraint fails
(myWork.Bookingss, CONSTRAINT Bookingss_ibfk_1 FOREIGN KEY
(CustomersID) REFERENCES Customers (CustomersID))
I have spent a while researching as this is apart of a school assignment and can not seem to resolve the problem.
Here is my SQL code:
USE myWork ;
DROP TABLE IF EXISTS Bookingss ;
DROP TABLE IF EXISTS Customers ;
CREATE TABLE myWork.Customers
(
CustomersID INT NOT NULL AUTO_INCREMENT,
Surname CHAR(30) NOT NULL ,
FirstName CHAR(30) NOT NULL ,
Title CHAR(10),
DOB DATE,
HouseNumber INT,
StreetName CHAR(30),
Town CHAR(30),
PostCode CHAR(9),
Telephone INT,
PRIMARY KEY (CustomersID)
) ;
CREATE TABLE myWork.Bookingss
(
BookingsID INT NOT NULL AUTO_INCREMENT,
CustomersID INT NOT NULL,
AdultsBooked INT NOT NULL,
ChildrenBooked INT NOT NULL,
Check_In DATE,
Check_Out DATE,
PRIMARY KEY (BookingsID),
FOREIGN KEY (CustomersID)
REFERENCES myWork.Customers (CustomersID)
) ;
SHOW TABLES ;
INSERT INTO myWork.Bookingss ( CustomersID, AdultsBooked , ChildrenBooked , Check_In , Check_Out )
VALUES ("1", "2", "3", "2022-04-10", "2022-04-13" ) ;
INSERT INTO myWork.Customers ( Surname , FirstName , Title , DOB )
VALUES ( "smith" , "ryan" , "Mr" , "1998-02-16" ) ;
SELECT * FROM Customers , Bookingss;
You got the order wrong and some challenges to overcome. You are trying to insert a booking first, and this with an id for a customer that does not yet exist in the customer table at that moment.
You have to insert the customer first, then use the customer's id to insert the booking for the customer (using his id).
And there is the first challenge. The customer id is an auto increment field. You would not know the id when you insert a customer in the table.
You would have to fetch the customer and use the id of that customer to insert a booking for the customer. How do you fetch the customer? Selecting the customer with a specific name surname and first name is not a correct choice, any other field (or composition of fields) that I see in the table definition is not a good choice neither.
You'd need to think further about a good solution. There are several options I could tell you about. But the appropriate solution depends on your assignment/context.
By the way, the last select clause may not deliver the result you expect. You are producing a cartesian product (every row of the first table with every row of the second table). What you probably want is a JOIN where you link the first table with the second table accordingly (e.g. using the primary key and the foreign key).
I have created two tables and now I want to find the movie that yielded the highest revenue for each platform(Hulu, Disney and Netflix). The problem here is I do not know how to output the names of the platform as it is a column title. Can anyone help me?
CREATE TABLE "StreamedMovies" (
"Title" TEXT,
"Netflix" INTEGER, -- 1 if the movie is streamed in this platform, 0 otherwise
"Hulu" INTEGER, -- 1 if the movie is streamed in this platform, 0 otherwise
"Disney" INTEGER, -- 1 if the movie is streamed in this platform, 0 otherwise
"ScreenTime" REAL,
PRIMARY KEY("Title")
)
CREATE TABLE "MovieData" (
"Title" TEXT,
"Genre" TEXT,
"Director" TEXT,
"Casting" TEXT,
"Rating" REAL,
"Revenue" REAL,
PRIMARY KEY("Title")
)
You'll have to write a case statement.
select
Title,
case
when Netflix == 1 then 'Netflix'
when Hulu = 1 then 'Hulu'
when Disney = 1 then 'Disney'
end as Platform
from StreamedMovies
This indicates a flaw in your design. A number of flaws. For example, there's nothing stopping a row from having multiple platforms. Or no platforms. Or having a platform set to 42.
Instead, add a platforms table and a join table to indicate which movies are streaming on which platforms.
While we're at it we'll fix some other issues.
Titles can change. Use a simple integer primary key.
Don't quote column and table names, it makes them case sensitive.
Declare your foreign keys.
Use not null to require important data.
-- The platforms available for streaming.
create table platforms (
id integer primary key,
name text not null
);
insert into platforms (id, name)
values ('Netflix'), ('Hulu'), ('Disney+');
-- The movies.
create table movies (
id integer primary key,
title text not null
);
insert into movies (title) values ('Bad Taste');
-- A join table for which platforms movies are streaming on.
create table streamed_movies (
movie_id integer not null references movies,
platform_id integer not null references platforms
);
insert into streamed_movies (movie_id, platform_id) values (1, 1), (1, 3);
select
movies.title, platforms.name
from streamed_movies sm
join movies on sm.movie_id = movies.id
join platforms on sm.platform_id = platforms.id
title name
--------- -------
Bad Taste Netflix
Bad Taste Disney+
I use 4 table in database.
Example:
Create table applicant(
Id int not null primary key,
IdName integer
idSkill integer,
idContact integer
Constraint initial foreign key (idName) References Initiale(id)
CONSTRAINT contacT foreign key (idContact) References contact(id)
CONSTRAINT Skills foreign key (idSkill) references skill(id))
Create table Initiale(
Id int not null primary key,
firstname text,
middlename text)
Create table contact(
Id int not null primary key,
phone text,
email text)
Create tabke Skills(
Id int not null primary key,,
Nane text)
I want insert data promptly in 4 table,but i not understand, what get id and insert in applicant.
Create tabke Skills ..... will fail. You should use Create table Skills.
Nor should you have Id int not null primary key,, (two commas), this would fail.
You should very likely be using Id INTEGER PRIMARY KEY not Id int not null primary key.
That is because generally an Id column should be a unique identifier of the row. With SQLite INTEGER PRIMARY KEY has a special meaining whilst INT PRIMARY KEY does not.
That is, if INTEGER PRIMARY KEY is used then the column will be an alias of the rowid column which has to be a unique signed 64 bit integer and importantly if no value is provided when inserting a row then SQLite will assign a unique integer. i.e. the all important Id.
This Id will initially be 1, then likely 2, then likely 3 and so on, although there is no guarantee that the Id will be monotonically increasing.
There are additional errors, mainly comma's omitted. The following should work :-
CREATE TABLE IF NOT EXISTS applicant(
Id INTEGER PRIMARY KEY,
IdName integer,
idSkill integer,
idContact integer,
Constraint initial foreign key (idName) References Initiale(id),
CONSTRAINT contacT foreign key (idContact) References contact(id),
CONSTRAINT Skills foreign key (idSkill) references Skills(id));
Create table IF NOT EXISTS Initiale(
Id INTEGER PRIMARY KEY,
firstname text,
middlename text);
Create table IF NOT EXISTS contact(
Id INTEGER PRIMARY KEY,
phone text,
email text);
Create table IF NOT EXISTS Skills(
Id INTEGER PRIMARY KEY,
Nane text);
You could then insert data along the lines of :-
INSERT INTO Initiale (firstname,middlename) -- Note absence of Id so SQLite will generate
VALUES
('Fred','James'), -- very likely id 1
('Alan','Roy'), -- very likely id 2
('Simon','Gerorge')-- very likely id 3
;
INSERT INTO contact -- alternative way of getting Id generated (specify null for Id)
VALUES
(null,'0123456789','email01#email.com'), -- very likely id 1
(null,'0987654321','email02#email.com'), -- very likely id 2
(null,'3333333333','email03.#email.com') -- very likely id 3
;
INSERT INTO Skills (Nane)
VALUES
('Skill01'),('Skill02'),('Skill03') -- very likely id's 1,2 and 3
;
INSERT INTO applicant (IdName,idSkill,idContact)
VALUES
-- First applicant
(2, -- Alan Roy
3, -- Skill 3
1), -- Contact 0123456789 )
-- Second Applicant
(3, -- Simon George
3, -- Skill 3
2), -- Contact 0987654321 )
-- Third Applicant
(2, -- Alan Roy again????
1, -- Skill 1
3), -- contact 3333333333)
(1,1,1) -- Fred James/ Skill 1/ Contact 0123456789
--- etc
;
Noting that Rows on the Initiale, Contact and Skills table MUST exists before insertions can be made into the Applicant table.
You could then run a query such as :-
SELECT * FROM applicant
JOIN Initiale ON Initiale.Id = idName
JOIN contact ON contact.Id = idContact
JOIN Skills ON Skills.Id = idSkill
This would result in (using the data as inserted above) :-
I'm new to databases, so I'll start by showing what I would do if I was using a simple table in a csv file. Presently, I'm building a Shiny (R) app to keep track of people taking part in studies. The idea is to make sure no one is doing more than one study at the same time, and that enough time has passed between studies.
A single table would look like something like this:
study_title contact_person tasks first_name last_name
MX9345-3 John Doe OGTT Michael Smith
MX9345-3 John Doe PVT Michael Smith
MX9345-3 John Doe OGTT Julia Barnes
MX9345-3 John Doe PVT Julia Barnes
...
So each study has a single contact person, but multiple tasks. It is possible other studies will use the same tasks.
Each task should have a description
Each person can be connected to multiple studies (the final database has timestamps to make sure this does not happen at the same time), and consequently repeat the same tasks.
the SQLite code could look something like this
CREATE TABLE studies (study_title TEXT, contact_person TEXT);
CREATE TABLE tasks (task_name TEXT, description TEXT);
CREATE TABLE participants (first_name TEXT, last_name TEXT);
Now I'm stuck. If I add a primary key and foreign keys (say in studies an ID for each study, and foreign keys for each task and person), the primary keys will repeat, which is not possible. A Study is defined by the tasks it contains (akin to an album and music tracks).
How should I approach this situation in SQLite? And importantly, how are the INSERTs done in these situations? I've seen lots of SELECT examples, but few INSERTs that match all IDs in each table, for example when adding a new person to a running study.
What you do is use tables to map/reference/relate/associate.
The first step would be to utilise alias's of the rowid so instead of :-
CREATE TABLE studies (study_title TEXT, contact_person TEXT);
CREATE TABLE tasks (task_name TEXT, description TEXT);
CREATE TABLE participants (first_name TEXT, last_name TEXT);
you would use :-
CREATE TABLE studies (id INTEGER PRIMARY KEY,study_title TEXT, contact_person TEXT);
CREATE TABLE tasks (id INTEGER PRIMARY KEY, task_name TEXT, description TEXT);
CREATE TABLE participants (id INTEGER PRIMARY KEY, first_name TEXT, last_name TEXT);
With SQLite INTEGER PRIMARY KEY (or INTEGER PRIMARY KEY AUTOINCREMENT) makes the column (id in the above although they can have any valid column name) and alias of the rowid (max of 1 per table), which uniquely identifies the rows.
Why not to use AUTOINCREMENT plus more seeSQLite Autoincrement
Insert some data for demonstration :-
INSERT INTO studies (study_title, contact_person)
VALUES ('Maths','Mr Smith'),('English','Mrs Taylor'),('Geography','Mary White'),('Phsyics','Mr Smith');
INSERT INTO tasks (task_name,description)
VALUES ('Task1','Do task 1'),('Task2','Do task 2'),('Task3','Do task 3'),('Task4','Do task 4'),('Mark','Mark the sudies');
INSERT INTO participants (first_name,last_name)
VALUES ('Tom','Jones'),('Susan','Smythe'),('Sarah','Toms'),('Alan','Francis'),('Julian','MacDonald'),('Fred','Bloggs'),('Rory','Belcher');
First mapping/reference... Table :-
CREATE TABLE IF NOT EXISTS study_task_relationship (study_reference INTEGER, task_reference INTEGER, PRIMARY KEY (study_reference,task_reference));
Map/relate Study's with Tasks (many-many possible)
Do some mapping (INSERT some data) :-
INSERT INTO study_task_relationship
VALUES
(1,2), -- Maths Has Task2
(1,5), -- Maths has Mark Questions
(2,1), -- English has Task1
(2,4), -- English has Task4
(2,5), -- English has Mark questions
(3,3), -- Geography has Task3
(3,1), -- Geoegrapyh has Task1
(3,2), -- Geography has Task2
(3,5), -- Geography has Mark Questions
(4,4) -- Physics has Task4
;
- See comments on each line
List the Studies along with the tasks
SELECT study_title, task_name -- (just want the Study title and task name)
FROM study_task_relationship -- use the mapping table as the main table
JOIN studies ON study_reference = studies.id -- get the related studies
JOIN tasks ON task_reference = tasks.id -- get the related tasks
ORDER BY study_title -- Order by Study title
results in :-
List each study with all it's tasks
SELECT study_title, group_concat(task_name,'...') AS tasklist
FROM study_task_relationship
JOIN studies ON study_reference = studies.id
JOIN tasks ON task_reference = tasks.id
GROUP BY studies.id
ORDER by study_title;
results in :-
Add study-participants associative table and populate it :-
CREATE TABLE IF NOT EXISTS study_participants_relationship (study_reference INTEGER, participant_reference INTEGER, PRIMARY KEY (study_reference,participant_reference));
INSERT INTO study_participants_relationship
VALUES
(1,1), -- Maths has Tom Jones
(1,5), -- Maths has Julian MacDonald
(1,6), -- Maths has Fred Bloggs
(2,4), -- English has Alan Francis
(2,7), -- English has Rory Belcher
(3,3), -- Geography has Sarah Toms
(3,2) -- Susan Smythe
;
You can now, as an example, get a list of participants the tasks along with the study title :-
SELECT study_title, task_name, participants.first_name ||' '||participants.last_name AS fullname
FROM study_task_relationship
JOIN tasks ON study_task_relationship.task_reference = tasks.id
JOIN studies On study_task_relationship.study_reference = studies.id
JOIN study_participants_relationship ON study_task_relationship.study_reference = study_participants_relationship.study_reference
JOIN participants ON study_participants_relationship.participant_reference = participants.id
ORDER BY fullname, study_title
which would result in :-
FOREIGN KEYS
As you can see there is no actual need for defining FOREIGN KEYS. They are really just an aid to stop you inadvertently doing something like :-
INSERT INTO study_participants_relationship VALUES(30,25);
No such study nor no such participant
To utilise FOREIGN KEYS you have to ensure that they are enabled, the simplest is just to issue the command to turn them on (as if it were a normal SQL statment).
PRAGMA foreign_keys=1
A FOREIGN KEY is a constraint, it stops you INSERTING, UPDATING or DELETING a row that would violate the constraint/rule.
Basically the rule is that the column to which the FOREIGN key is defined (the child) must have a value that is in the referenced table/column the parent.
So assumning that FOREIGN KEYS are turned on then coding :-
CREATE TABLE IF NOT EXISTS study_participants_relationship
(
study_reference INTEGER REFERENCES studies(id), -- column foreign key constraint
participant_reference INTEGER,
FOREIGN KEY (participant_reference) REFERENCES participants(id) -- table foreign key constraint
PRIMARY KEY (study_reference,participant_reference
)
);
Would result in INSERT INTO study_participants_relationship VALUES(30,25); failing e.g.
FOREIGN KEY constraint failed: INSERT INTO study_participants_relationship VALUES(30,25);
It fails as there is no row in studies with an id who's value is 30 (the first column foreign key constraint). If the value 30 did exist then the second constraint would kick in as there is no row in participants with an id of 25.
There is no difference between a column Foreign key constraint and a table Foreign key constraint other than where and how they are coded.
However, the above wouldn't stop you deleting all rows from the study_participants_relationship table as it would stop you deleting a row from the studies or participants table if they were referenced by the study_participants_relationship table.
"deal with an id that needs to be matched to multiple ids in SQLite?"
For many-to-many couplings, make extra coupling tables, like the study_task and participent_task tables below. This is many-to-many since a task can be on many studies and a study can have many tasks.
"make sure no one is doing more than one study at the same time"
That could be handled by letting each participant only have a column for current study (no place for more than one then).
PRAGMA foreign_keys = ON;
CREATE TABLE study (id INTEGER PRIMARY KEY, study_title TEXT, contact_person TEXT);
CREATE TABLE task (id INTEGER PRIMARY KEY, task_name TEXT, description TEXT);
CREATE TABLE participant (
id INTEGER PRIMARY KEY,
first_name TEXT,
last_name TEXT,
id_current_study INTEGER references study(id),
started_current_study DATE
);
CREATE TABLE study_task (
id_study INTEGER NOT NULL references study(id),
id_task INTEGER NOT NULL references task(id),
primary key (id_study,id_task)
);
CREATE TABLE participant_task (
id_participant INTEGER NOT NULL references participant(id),
id_task INTEGER NOT NULL references task(id),
status TEXT check (status in ('STARTED', 'DELIVERED', 'PASSED', 'FAILED')),
primary key (id_participant,id_task)
);
insert into study values (1, 'MX9345-3', 'John Doe');
insert into study values (2, 'MX9300-2', 'Jane Doe');
insert into participant values (1001, 'Michael', 'Smith', 1,'2018-04-21');
insert into participant values (1002, 'Julia', 'Barnes', 1, '2018-04-10');
insert into task values (51, 'OGTT', 'Make a ...');
insert into task values (52, 'PVT', 'Inspect the ...');
insert into study_task values (1,51);
insert into study_task values (1,52);
insert into study_task values (2,51);
--insert into study_task values (2,66); --would fail since 66 doesnt exists (controlled and enforced by foreign key)
The PRAGMA on the first line is needed to make SQLite (above version 3.6 from 2009 I think) enforce foreign keys, without it it just accepts the foreign key syntax, but no controlling is done.
I have only done databases without relations, but now I need to do something more serious and correct.
Here is my database design:
Kunde = Customer
Vare = Product
Ordre = Order (Read: I want to make an order)
VareGruppe = ehm..type? (Read: Car, chair, closet etc.)
VareOrdre = Product_Orders
Here is my SQL (SQLite) schema:
CREATE TABLE Post (
Postnr INTEGER NOT NULL PRIMARY KEY,
Bynavn VARCHAR(50) NOT NULL
);
CREATE TABLE Kunde (
CPR INTEGER NOT NULL PRIMARY KEY,
Navn VARCHAR(50) NOT NULL,
Tlf INTEGER NOT NULL,
Adresse VARCHAR(50) NOT NULL,
Postnr INTEGER NOT NULL
CONSTRAINT fk_postnr_post REFERENCES Post(Postnr)
);
CREATE TABLE Varegruppe (
VGnr INTEGER PRIMARY KEY,
Typenavn VARCHAR(50) NOT NULL
);
CREATE TABLE Vare (
Vnr INTEGER PRIMARY KEY,
Navn VARCHAR(50) NOT NULL,
Pris DEC NOT NULL,
Beholdning INTEGER NOT NULL,
VGnr INTEGER NOT NULL
CONSTRAINT fk_varegruppevgnr_vgnr REFERENCES Varegruppe(VGnr)
);
CREATE TABLE Ordre (
Onr INTEGER PRIMARY KEY,
CPR INTEGER NOT NULL
CONSTRAINT fk_kundecpr_cpr REFERENCES Kunde(CPR),
Dato DATETIME NOT NULL,
SamletPris DEC NOT NULL
);
CREATE TABLE VareOrdre (
VareOrdreID INTEGER PRIMARY KEY,
Onr INTEGER NOT NULL
CONSTRAINT fk_ordrenr_onr REFERENCES Ordre(Onr),
Vnr INTEGER NOT NULL
CONSTRAINT fk_varevnr_vnr REFERENCES Vare(Vnr),
Antal INTEGER NOT NULL
);
It should work correctly.
But I am confused about Product_Orders.
How do I create an order? For example, 2 products using SQL INSERT INTO?
I can get nothing to work.
So far:
Only when I manually insert products and data into Product_Orders and then add that data to Orders = which makes it complete. Or the other way around (create an order in with 1 SQL, then manually inserting products into Product_orders - 1 SQL for each entry)
You should first create an order and then insert products in the table Product_Orders. This is necessary because you need an actual order with an id to associate it with the table Product_Orders.
You always should create a record in the foreign-key table before being able to create one in your current table. That way you should create a "Post", customer, type, product, order and product_order.
Try this ...
first you have to insert a customer
insert into kunde values(1, 'navn', 1, 'adresse', 1)
then you insert a type
insert into VareGruppe values(1, 'Type1')
then you insert a product
insert into vare values(1, 'product1', '10.0', 1, 1)
then you add an order
insert into ordre values(1, 1, '20090101', '10.0')
then you insert a register to the product_orders table
insert into VareOrdre values (1, 1, 1, 1)
I think this is it. :-)
As the primary keys are autoincrement, don't add them to the insert and specify the columns like this
insert into vare(Nav, Pris, Beholdning, VGnr) values('product1', '10.0', 1, 1)
Use Select ##identity to see the onr value
I think you already have the hang of what needs to happen. But what I think you are getting at is how to ensure data integrity.
This is where Transactions become important.
http://www.sqlteam.com/article/introduction-to-transactions
Is it the SalesPrice (I'm guessing that's what SamletPris means) that's causing the issue? I can see that being a problem here. One common design solution is to have 2 tables: Order and OrderLine. The Order is a header table - it will have the foreign key relationship to the Customer table, and any other 'top level' data. The OrderLine table has FK relationships to the Order table and to the Product table, along with quantity, unit price, etc. that are unique to an order's line item. Now, to get the sales price for an order, you sum the (unit price * quantity) of the OrderLine table for that order. Storing the SalesPrice for a whole order is likely to cause big issues down the line.
A note just in case this is MySQL: If you're using MyISAM, the MySQL server ignores the foreign keys completely. You have to set the engine to InnoDB if you want any kind of integrity actually enforced on the database end instead of just in your logic. This isn't your question but it is something to be aware of.
fbinder got the question right :)