When is LIMIT applied? Will it select all results before limiting? - sql

I'm concerned about the performance of a query such as SELECT * FROM user LIMIT 5 on a very large user table. Will it select all records then limit to 5?
More specifically will the following query select all assetids before limiting...
SELECT * FROM assets WHERE asset_id IN(1,2,3,4,5,6,7,8,9,10) LIMIT 5
I realize it doesn't make sense to include all ids in the IN() clause if I'm limiting but I'd like to know how mysql behaves in this situation.
Thanks.

This depends on your query. See this page for more explanations of how LIMIT is applied:
http://dev.mysql.com/doc/refman/5.0/en/limit-optimization.html
For that specific query, the following would apply:
"As soon as MySQL has sent the required number of rows to the client, it aborts the query unless you are using SQL_CALC_FOUND_ROWS."
Hope that helps.

Your query will have to scan all rows by asset_id column, so you better have an index on it. In my experience, you would always want to set an order by clause also, since the result set will be internally (i.e. order unknown), and you would not know why the returned 5 results were the ones you actually wanted.

Related

Postgres Skipping Duplicate Field in Select

I want to select a limited number of items but only keeping ones with a distinct value for a specific field. I have tried using SELECT DISTINCT ON(field) as well as GROUP BY but they are both extremely slow because the table is very large. I assume this is because using DISTINCT will actually sort the table into distinct values before selecting at all.
SELECT DISTINCT ON(parent) id FROM posts WHERE sub = ? LIMIT 25
For my purposes this is unnecessary because I am using a LIMIT and can guarantee the limit will be met without scanning much of the table at all. Similar to selecting a value with a condition, which (without an index) will scan each row and check if it meets the condition before continuing, how can I use not having duplicate fields as a condition?
Another way to think about it is how do I do this:
SELECT DISTINCT ON (parent) post.id FROM
(SELECT id FROM posts WHERE sub = ? ORDER BY id LIMIT 25) AS post
While guaranteeing that there are 25 results. Here the result is very fast but it will usually have less results than required because multiple rows can have the same parent.
The way you're thinking may seem to make sense, but if you think a little deeper, you'll find that it cannot work that way. You want 25 unique result. To give you that, first it needs to go through the records and find the unique ones then return the first 25.
What you actually want is for it to go through the records one by one and check, do I already have similar value? If yes, discard it and continue, if no, add it to the results. Now check, do I already have 25 results? If no, continue, if yes, stop and return the results.
This is not a trivial task to do in a query. Your best bet is to do it in a stored procedure with a cursor. That will be much easier as you are in full control of the flow, just follow the steps as per the description above.
For my purposes this is unnecessary because I am using a LIMIT and can guarantee the limit will be met without scanning much of the table at all.
If you really know that your first 25 results will be found in the first xx records (say first 100), and that's all you care to achieve, then you can use a somewhat dumb query:
SELECT DISTINCT ON (parent) post.id
FROM (SELECT id FROM posts WHERE sub = ? ORDER BY id LIMIT 100) AS post
LIMIT 25
Change the 100 to whatever suits your needs.
When you use distinct on, you should use order by:
SELECT DISTINCT ON (parent) id
FROM posts
WHERE sub = ?
ORDER BY parent
LIMIT 25;
To optimize this query, you want an index on posts(sub, parent, id).

SQL Select, different than the last 10 records

I have a table called "dutyroster". I want to make a random selection from this table's "names" column, but, I want the selection be different than the last 10 records so that the same guy is not given a second duty in 10 days. Is that possible ?
Create a temporary table with only one column called oldnames which will have no records initially. For each select, execute a query like
select names from dutyroster where dutyroster.names not in (select oldnamesfrom temporarytable) limit 10
and when execution is done add the resultset to the temporary table
The other answer already here is addressing the portion of the question on how to avoid duplicating selections.
To accomplish the random part of the selection, leverage newid() directly within your select statement. I've made this sqlfiddle as an example.
SELECT TOP 10
newid() AS [RandomSortColumn],
*
FROM
dutyroster
ORDER BY
[RandomSortColumn] ASC
Keep executing the query, and you'll keep getting different results. Use the technique in the other answer for avoiding doubling a guy up.
The basic idea is to use a subquery to get all but users from the last ten days, then sort the rest randomly:
select dr.*
from dutyroster dr
where dr.name not in (select dr2.name
from dutyroster dr2
where dr2.datetimecol >= date_sub(curdate(), interval 10 day)
)
order by rand()
limit 1;
Different databases may have different syntax for limit, rand(), and for the date/time functions. The above gives the structure of the query, but the functions may differ.
If you have a large amount of data and performance is a concern, there are other (more complicated) ways to take a random sample.
you could use TOP function for SQL Server
and for MYSQL you could use LIMIT function
Maybe this would help...
SELECT TOP number|percent column_name(s)
FROM table_name;
Source: http://www.w3schools.com/sql/sql_top.asp

Using limit in sqlite SQL statement in combination with order by clause

Will the following two SQL statements always produce the same result set?
1. SELECT * FROM MyTable where Status='0' order by StartTime asc limit 10
2. SELECT * FROM (SELECT * FROM MyTable where Status='0' order by StartTime asc) limit 10
Yes, but ordering subqueries is probably a bad habit to get into. You could feasibly add a further ORDER BY outside the subquery in your second example, e.g.
SELECT *
FROM (SELECT *
FROM Test
ORDER BY ID ASC
) AS A
ORDER BY ID DESC
LIMIT 10;
SQLite still performs the ORDER BY on the inner query, before sorting them again in the outer query. A needless waste of resources.
I've done an SQL Fiddle to demonstrate so you can view the execution plans for each.
No. First because the StartTime column may not have UNIQUE constraint. So, even the first query may not always produce the same result - with itself!
Second, even if there are never two rows with same StartTime, the answer is still negative.
The first statement will always order on StartTime and produce the first 10 rows. The second query may produce the same result set but only with a primitive optimizer that doesn't understand that the ORDER BY in the subquery is redundant. And only if the execution plan includes this ordering phase.
The SQLite query optimizer may (at the moment) not be very bright and do just that (no idea really, we'll have to check the source code of SQLite*). So, it may appear that the two queries are producing identical results all the time. Still, it's not a good idea to count on it. You never know what changes will be made in a future version of SQLite.
I think it's not good practice to use LIMIT without ORDER BY, in any DBMS. It may work now, but you never know how long these queries will be used by the application. And you may not be around when SQLite is upgraded or the DBMS is changed.
(*) #Gareth's link provides the execution plan which suggests that current SQLite code is dumb enough to execute the redundant ordering.

Does SQL Server TOP stop processing once it finds enough rows?

When you use the SQL Server TOP clause in a query, does the SQL Server engine stop searching for rows once it has enough to satisfy the TOP X needed to be returned?
Consider the following queries (assume some_text_field is unique and not set for full-text indexing):
SELECT
pk_id
FROM
some_table
WHERE
some_text_field = 'some_value';
and
SELECT TOP 1
pk_id
FROM
some_table
WHERE
some_text_field = 'some_value';
The first query would need to search the entire table and return all of the results it found. The way we have it setup though, that query would ever really return one value. So, would using TOP 1 prevent SQL server from scanning the rest of the table once it has found a match?
Yes, the query stops once it has found enough rows, and doesn't query the rest of the table(s).
Note however that you would probably want to have an index that the database can use for the query. In that case there isn't really any performance difference between getting the first match and getting all one matches.
Yes.
In this case you would get 1 undefined row (as TOP without ORDER BY doesn't guarantee any particular result) then it would stop processing (The TOP iterator in the plan won't request any more rows from child iterators).
If there is a blocking operator (such as SORT) in the plan before the TOP operator or parallel operators before the TOP it may end up doing a lot of work for rows not returned in the final result anyway though.

SQL Server UNION - What is the default ORDER BY Behaviour

If I have a few UNION Statements as a contrived example:
SELECT * FROM xxx WHERE z = 1
UNION
SELECT * FROM xxx WHERE z = 2
UNION
SELECT * FROM xxx WHERE z = 3
What is the default order by behaviour?
The test data I'm seeing essentially does not return the data in the order that is specified above. I.e. the data is ordered, but I wanted to know what are the rules of precedence on this.
Another thing is that in this case xxx is a View. The view joins 3 different tables together to return the results I want.
There is no default order.
Without an Order By clause the order returned is undefined. That means SQL Server can bring them back in any order it likes.
EDIT:
Based on what I have seen, without an Order By, the order that the results come back in depends on the query plan. So if there is an index that it is using, the result may come back in that order but again there is no guarantee.
In regards to adding an ORDER BY clause:
This is probably elementary to most here but I thought I add this.
Sometimes you don't want the results mixed, so you want the first query's results then the second and so on. To do that I just add a dummy first column and order by that. Because of possible issues with forgetting to alias a column in unions, I usually use ordinals in the order by clause, not column names.
For example:
SELECT 1, * FROM xxx WHERE z = 'abc'
UNION ALL
SELECT 2, * FROM xxx WHERE z = 'def'
UNION ALL
SELECT 3, * FROM xxx WHERE z = 'ghi'
ORDER BY 1
The dummy ordinal column is also useful for times when I'm going to run two queries and I know only one is going to return any results. Then I can just check the ordinal of the returned results. This saves me from having to do multiple database calls and most empty resultset checking.
Just found the actual answer.
Because UNION removes duplicates it does a DISTINCT SORT. This is done before all the UNION statements are concatenated (check out the execution plan).
To stop a sort, do a UNION ALL and this will also not remove duplicates.
If you care what order the records are returned, you MUST use an order by.
If you leave it out, it may appear organized (based on the indexes chosen by the query plan), but the results you see today may NOT be the results you expect, and it could even change when the same query is run tomorrow.
Edit: Some good, specific examples: (all examples are MS SQL server)
Dave Pinal's blog describes how two very similar queries can show a different apparent order, because different indexes are used:
SELECT ContactID FROM Person.Contact
SELECT * FROM Person.Contact
Conor Cunningham shows how the apparent order can change when the table gets larger (if the query optimizer decides to use a parallel execution plan).
Hugo Kornelis proves that the apparent order is not always based on primary key. Here is his follow-up post with explanation.
A UNION can be deceptive with respect to result set ordering because a database will sometimes use a sort method to provide the DISTINCT that is implicit in UNION , which makes it look like the rows are deliberately ordered -- this doesn't apply to UNION ALL for which there is no implicit distinct, of course.
However there are algorithms for the implicit distinct, such as Oracle's hash method in 10g+, for which no ordering will be applied.
As DJ says, always use an ORDER BY
It's very common to come across poorly written code that assumes table data is returned in insert order, and 95% of the time the coder gets away with it and is never aware that this is a problem as on many common databases (MSSQL, Oracle, MySQL). It is of course a complete fallacy and should always be corrected when it's come across, and always, without exception, use an Order By clause yourself.