In mysql I need to obtain all the last 5 days records.
So if I have
Name date
aaaa 20/11/2010
dddd* 24/11/2010*
bbbb 22/11/2010
cccc 23/11/2010
eeee* 25/11/2010*
ffff* 26/11/2010*
I need only the last 5 days records.
I tried something like:
SELECT name,date
from Lineas
WHERE date >= DATE_SUB(CURDATE(), INTERVAL 5 DAY)
ORDER BY date DESC
but it isn´t working....
If the problem is "records from the future" then you simply need to restrain your results a bit more than you've already done:
SELECT name,date
from Lineas
WHERE date >= DATE_SUB(CURDATE(), INTERVAL 5 DAY) AND date <= CURDATE()
ORDER BY date DESC
Have you tried between
SELECT name,
date
from Lineas
WHERE date BETWEEN DATE_SUB(CURDATE(), INTERVAL 5 DAY) AND CURDATE()
ORDER BY date DESC
Related
I have the below code to which I want to return the last 7 days excluding today (for example from 5th May - 11th May as opposed to 5th May - 12th May)
What else would I be able to include to acheive this?
SELECT *
FROM TABLE_1
WHERE DATE_TIME >= SYSDATE -7
You want to have a range that starts from 7 days before midnight today and ends before midnight today:
SELECT *
FROM table_name
WHERE date_time >= TRUNC(sysdate) - 7
AND date_time < TRUNC(sysdate);
This should work:
SELECT *
FROM TABLE_1
WHERE DATE_TIME >= SYSDATE -7
AND TRUNC(DATE_TIME) != TRUNC(SYSDATE)
The TRUNC is needed to strip the time portion of the date column and sysdate.
Note that DATE_TIME >= SYSDATE -7 will include the time portion of SYSDATE and substract 7 days. If you run the query at 10AM, do you want to include rows that have date_time = sysdate - 7 at 9AM too ? If so it is better to add a TRUNC there too DATE_TIME >= TRUNC(SYSDATE) -7.
I want to get data from last month day by day, I can get the last 30 days but I just want the month as it may be less or more than 30 days,
this is the query for getting the last 30 days
SELECT Trunc(timestamp),
Count(*)
FROM table1
WHERE Trunc(timestamp) > Trunc(sysdate - 30)
GROUP BY Trunc(timestamp)
ORDER BY 1;
Also, I am using it in a shell script if I can make a variable in the script and put it the query
To get data from the start of the current month until today:
SELECT TRUNC(timestamp) AS day,
COUNT(*)
FROM table1
WHERE timestamp >= TRUNC(SYSDATE, 'MM')
AND timestamp < TRUNC(SYSDATE) + INTERVAL '1' DAY
GROUP BY TRUNC(timestamp)
ORDER BY day
To get data from the same day last month until today:
SELECT TRUNC(timestamp) AS day,
COUNT(*)
FROM table1
WHERE timestamp >= ADD_MONTHS(TRUNC(SYSDATE), -1)
AND timestamp < TRUNC(SYSDATE) + INTERVAL '1' DAY
GROUP BY TRUNC(timestamp)
ORDER BY day
db<>fiddle here
I'm trying to create a query to only return data where date is minus 3 days from the current date. I've tried:
date <= DATE_ADD(CURRENT_DATE(), -3, 'DAY')
But this returns Error: Expected INTERVAL expression
See WHERE clause in below example
#standardSQL
WITH yourTable AS (
SELECT i, date
FROM UNNEST(GENERATE_DATE_ARRAY('2017-04-15', '2017-04-28')) AS date WITH OFFSET AS i
)
SELECT *
FROM yourTable
WHERE date <= DATE_SUB(CURRENT_DATE(), INTERVAL 3 DAY)
-- ORDER BY date
Btw, in case if you are still with Legacy SQL - see below example
#legacySQL
SELECT *
FROM -- yourTable
(SELECT 1 AS id, DATE('2017-04-20') AS date),
(SELECT 2 AS id, DATE('2017-04-21') AS date),
(SELECT 3 AS id, DATE('2017-04-22') AS date),
(SELECT 4 AS id, DATE('2017-04-23') AS date),
(SELECT 5 AS id, DATE('2017-04-24') AS date),
(SELECT 6 AS id, DATE('2017-04-25') AS date)
WHERE TIMESTAMP(date) <= DATE_ADD(TIMESTAMP(CURRENT_DATE()), -3, 'DAY')
-- ORDER BY date
This works with a string formatted date.
DATE(TIMESTAMP(date)) <= DATE_SUB(CURRENT_DATE(), INTERVAL 3 DAY)
Just tested this and seems to work.
I added this :
and DATE(TIMESTAMP(datevalue)) >= DATE_SUB(CURRENT_DATE(), INTERVAL 21 DAY)
and managed to get all records greater than last 21 days worth. Only thing I changed from #ericbrownaustin 's code was changed the 'date' in the first piece of code in the second set of parenthesis.
I have about 50k rows in a Postgres database that are users and when they signed up.
I am trying to understand how many users sign up for each day of the week since the start of the year, e.g.:
1238 on Monday
3487 on Tuesday
1237 on Wednesday
Example date entry: '2014-10-31 17:17:30.138579'
A plain aggregate query after extracting the weekday. You could use to_char() to get the (English by default) weekday:
SELECT to_char(created_at, 'Day'), count(*) AS ct
FROM tbl
WHERE created_at >= date_trunc('year', now())
GROUP BY 1;
If performance is important, EXTRACT() is slightly faster:
SELECT EXTRACT(ISODOW FROM created_at), count(*) AS ct
FROM tbl
WHERE created_at >= date_trunc('year', now())
GROUP BY 1;
1 .. Monday, ... , 7 .. Sunday.
You can use the EXTRACT(DOW from timestamp) to determined the day of the week. 0 is Sunday. 6 is Saturday.
Example:
SELECT EXTRACT(DOW FROM TIMESTAMP '2015-06-22 20:38:40');
Result is 1 (Monday)
I wanna get rows in recent date, this week or month, etc. suppose the table has a field named: product_date.
To get the rows in the last month, you could use something like:
SELECT * FROM table WHERE product_date >= DATE_SUB(NOW(), INTERVAL 1 MONTH);
Or for the last week:
SELECT * FROM table WHERE product_date >= DATE_SUB(NOW(), INTERVAL 1 WEEK);
For within the last seven days:
WHERE product_date BETWEEN DATE_ADD(NOW(), INTERVAL -7 DAY) AND NOW()
For the last month:
WHERE product_date BETWEEN DATE_ADD(NOW(), INTERVAL -1 MONTH) AND NOW()
While mopoke's solution gets results from last 30 or 7 days, this gives you results for current month only:
SELECT * FROM table WHERE DATE_FORMAT(product_date, '%c-%Y') = DATE_FORMAT(CURDATE(), '%c-%Y');
Or for current week:
SELECT * FROM table WHERE DATE_FORMAT(product_date, '%u-%Y') = DATE_FORMAT(CURDATE(), '%u-%Y');