I have a varchar field with the following data:
Interface
Gig1/0/1
Gig1/0/3
Gig1/0/5
Gig1/0/10
Gig1/1/11
I am trying to do a search (BETWEEN).
Select * from test1 where Interface Between "Gig1/0/1" and "Gig1/0/5"
Returns all the records except for Gig1/1/11
What about using the substring_index function?
select substring_index(fieldname,'/',-1) as v from tablename where v between 1 and 5
Related
I need a select which would return row if column A of that row contains any word from a list of words which get from user input
SELECT *
FROM MyTable
WHERE ColumnA CONTAINS ANY 'list of word'
Since the list of words has an unknown number of words, I store the whole list in the same string. each word can be separated with "_", "-" or white space.
You can try something like this if you are using oracle :
SELECT * FROM MyTable WHERE ColumnA in (select upper(regexp_substr('word1-
word2-word3','[^-]+',1,level)) from dual
connect by upper(regexp_substr('word1-word2-word3','[^-]+',1,level)) is
not null)
If you are using "_" then replace the hyphen with underscore is regexp_substr parameter.
I've came up with this solution:
SELECT *
from TableA tb
RIGHT JOIN STRING_SPLIT ( 'list of words' , 'seperator' ) v on tb.ColumnA = v.value
WHERE tb.ColumnA IS NOT NULL
I am working on a Microsoft SQL Server database and I have the following problem to implement these 2 simple select query.
So I have a table named MyTable that has a column OtherFieldFK of type BigInt with a value of 70016592107.
So for example I want search all the record in this table that have the OtherFieldFK starting with the value 70.
I tried to use like in this way:
select *
from MyTable
where OtherFieldFK like = '70%'
but it doesn't work. I think that like clause works only on string, is it right?
In this table I also have a DATETIME column named DataInizioGestione.
I tried to do the same thing:
select *
from DataInizioGestione
where OtherFieldFK like = '2016%'
but in this case it doesn't work either.
How can I correctly implement these 2 queries?
the first should be right, as you wrote:
select * from MyTable where OtherFieldFK like = '70%'
for the second should be converted to the date format in the nvarchar (es 121 with this format aaaa-mm-gg hh:mi:ss.mmm(24h)); in this way you can make the comparison with the like:
select * from MyTable where convert(nvarchar,DataInizioGestione,121) like = '2016%'
or you can directly compare the year:
select * from MyTable where year(DataInizioGestione) = 2016
Using Remove part of string in table as an example, I want to change part of my string in my database column with a different string.
Ex:
Database says E:\websites\nas\globe.png , E:\websites\nas\apple.png and etc
I want it to say \\nas\globe.png, \\nas\apple.png,
Only part I want to replace is the E:\websites\ not the rest of the string
How do I do this?
So far I have:
SELECT file_name,
REPLACE(file_name,'E:\websites\','\\nas\')
FROM t_class;
I just referenced http://nntp-archive.sybase.com/nntp-archive/action/article/%3C348_1744DC78C1045E920059DE7F85256A8B.0037D71C85256A8B#webforums%3E
and used:
SELECT REPLACE('E:\websites\web\Class\Main_Image\','E:\websites\web\Class\Main_Image\','\\nas\class_s\Main_Image\') "Changes"
FROM DUAL;
but once again it wouldn't change O.o
In Oracle, you may need to double up on the back slashes:
SELECT file_name,
REPLACE(file_name,'E:\\websites\\', '\\\\nas\\')
FROM t_class;
For the fun of it, using regexp_replace:
SQL> with tbl(filename) as (
2 select 'E:\websites\nas\globe.png' from dual
3 union
4 select 'E:\websites\nas\apple.png' from dual
5 )
6 select filename, regexp_replace(filename, 'E:\\websites', '\\') edited
7 from tbl;
FILENAME EDITED
------------------------- --------------------
E:\websites\nas\apple.png \\nas\apple.png
E:\websites\nas\globe.png \\nas\globe.png
SQL>
I found a reference at how to replace string values of column values by SQL Stored Procedure
by doing the following:
UPDATE t_class SET file_name =
REPLACE
(file_name, 'E:\websites\web\Class\Main_Image\No_Image_Available.png', '\\nas\class_s\Main_Image\No_Image_Available.png');
so only difference is the update and = sign
I have a query that gives list of IDs:
ID
2
3
4
5
6
25
ID is integer.
I want to get that result like that in ARRAY of integers type:
ID
2,3,4,5,6,25
I wrote this query:
select string_agg(ID::text,',')
from A
where .....
I have to convert it to text otherwise it won't work. string_agg expect to get (text,text)
this works fine the thing is that this result should later be used in many places that expect ARRAY of integers.
I tried :
select ('{' || string_agg(ID::text,',') || '}')::integer[]
from A
WHERE ...
which gives: {2,3,4,5,6,25} in type int4 integer[]
but this isn't the correct type... I need the same type as ARRAY.
for example SELECT ARRAY[4,5] gives array integer[]
in simple words I want the result of my query to work with (for example):
select *
from b
where b.ID = ANY (FIRST QUERY RESULT) // aka: = ANY (ARRAY[2,3,4,5,6,25])
this is failing as ANY expect array and it doesn't work with regular integer[], i get an error:
ERROR: operator does not exist: integer = integer[]
note: the result of the query is part of a function and will be saved in a variable for later work. Please don't take it to places where you bypass the problem and offer a solution which won't give the ARRAY of Integers.
EDIT: why does
select *
from b
where b.ID = ANY (array [4,5])
is working. but
select *
from b
where b.ID = ANY(select array_agg(ID) from A where ..... )
doesn't work
select *
from b
where b.ID = ANY(select array_agg(4))
doesn't work either
the error is still:
ERROR: operator does not exist: integer = integer[]
Expression select array_agg(4) returns set of rows (actually set of rows with 1 row). Hence the query
select *
from b
where b.id = any (select array_agg(4)) -- ERROR
tries to compare an integer (b.id) to a value of a row (which has 1 column of type integer[]). It raises an error.
To fix it you should use a subquery which returns integers (not arrays of integers):
select *
from b
where b.id = any (select unnest(array_agg(4)))
Alternatively, you can place the column name of the result of select array_agg(4) as an argument of any, e.g.:
select *
from b
cross join (select array_agg(4)) agg(arr)
where b.id = any (arr)
or
with agg as (
select array_agg(4) as arr)
select *
from b
cross join agg
where b.id = any (arr)
More formally, the first two queries use ANY of the form:
expression operator ANY (subquery)
and the other two use
expression operator ANY (array expression)
like it is described in the documentation: 9.22.4. ANY/SOME
and 9.23.3. ANY/SOME (array).
How about this query? Does this give you the expected result?
SELECT *
FROM b b_out
WHERE EXISTS (SELECT 1
FROM b b_in
WHERE b_out.id = b_in.id
AND b_in.id IN (SELECT <<first query that returns 2,3,4,...>>))
What I've tried to do is to break down the logic of ANY into two separate logical checks in order to achieve the same result.
Hence, ANY would be equivalent with a combination of EXISTS at least one of the values IN your list of values returned by the first SELECT.
I have a table column that has data like
NA_PTR_51000_LAT_CO-BOGOTA_S_A
NA_PTR_51000_LAT_COL_M_A
NA_PTR_51000_LAT_COL_S_A
NA_PTR_51000_LAT_COL_S_B
NA_PTR_51000_LAT_MX-MC_L_A
NA_PTR_51000_LAT_MX-MTY_M_A
I want to parse each column value so that I get the values in column_B. Thank you.
COLUMN_A COLUMN_B
NA_PTR_51000_LAT_CO-BOGOTA_S_A CO-BOGOTA
NA_PTR_51000_LAT_COL_M_A COL
NA_PTR_51000_LAT_COL_S_A COL
NA_PTR_51000_LAT_COL_S_B COL
NA_PTR_51000_LAT_MX-MC_L_A MX-MC
NA_PTR_51000_LAT_MX-MTY_M_A MX-MTY
I'm not sure of the Postgresql and I can't get SQL fiddle to accept the schema build...
substring and length may vary...
Select Column_A, substr(columN_A,18,length(columN_A)-17-4) from tableName
Ok how about this then:
http://sqlfiddle.com/#!15/ad0dd/56/0
Select column_A, b
from (
Select Column_A, b, row_number() OVER (ORDER BY column_A) AS k
FROM (
SELECT Column_A
, regexp_split_to_table(Column_A, '_') b
FROM test
) I
) X
Where k%7=5
Inside out:
Inner most select simply splits the data into multiple rows on _
middle select adds a row number so that we can use the use the mod operator to find all occurances of a 5th remainder.
This ASSUMES that the section of data you're after is always the 5th segment AND that there are always 7 segments...
Use regexp_matches() with a search pattern like 'NA_PTR_51000_LAT_(.+)_'
This should return everything after NA_PTR_51000_LAT_ before the next underscore, which would match the pattern you are looking for.