IF ELSE problem COMMAND BATCH - scripting

Question

I have problem about IF ELSE in Command Batch script...
In Notepad:
Code:
:CHECKACCOUNT
if /I "%user%"=="insertusername" ( GOTO :ACCOUNT ) ELSE ( GOTO :CHECKPASSACCT )
:CHECKPASSACCT
if /I "%pass%"=="insertpassword" ( GOTO :ACCOUNT ) ELSE ( GOTO :COUNTER )
In COMMAND:
Code:
( was unexpected at this time.
FULL Script Code:
#echo off
::SETTINGS:::::::::::::::::::::::
set filetxt =userpass.txt
set log=logfile.log
set timer=900
::set default = true
::set user = 0
::set pass = 0
:::::::::::::::::::::::::::::::::
:STARTER
ECHO.>>%log%
ECHO ========START========>>%log%
SetLocal EnableDelayedExpansion
Set n=
Set _InputFile=%filetxt%
For /F "tokens=*" %%I IN (%_InputFile%) DO (
Set /a n+=1
Set acct!n!=%%I
)
set router_ip=%acct1%
set user=%acct2%
set pass=%acct3%
GOTO :CHECKFILE1
:CHECKFILE1
CLS
IF EXIST curl.exe ( GOTO :CHECKFILE2 ) else (
ECHO ERROR: curl.exe was not found.>>%log%
ECHO ERROR: curl.exe was not found.
ECHO.
ECHO.
GOTO :PAUSEEXIT
)
:CHECKFILE2
CLS
IF EXIST sleep.exe ( GOTO :CHECKACCOUNT ) else (
ECHO ERROR: sleep.exe was not found.>>%log%
ECHO ERROR: sleep.exe was not found.
ECHO.
ECHO.
GOTO :PAUSEEXIT
)
:CHECKACCOUNT
if /I "%user%"=="insertusername" GOTO ACCOUNT
GOTO CHECKPASSACCT
:CHECKPASSACCT
if /I "%pass%"=="insertpassword" GOTO ACCOUNT
GOTO COUNTER
:ACCOUNT
CLS
::if %default% = true ( GOTO :COUNTER ) ELSE (
ECHO To edit/change USERNAME and PASSWORD... Please type: OPTION
ECHO.
SET /P user="Please enter the username of your Router:"
IF /I %user%==OPTION ( Goto :EDITBAT )
CLS
ECHO To edit/change USERNAME and PASSWORD... Please type: OPTION
ECHO.
SET /P pass="Please enter the password of your Router:"
IF /I %pass%==OPTION ( Goto :EDITBAT )
CLS
set /a i = 1
GOTO :CHECKACCOUNT
::)
:EDITBAT
start /WAIT notepad %filetxt%
set router_ip=%acct1%
set user=%acct2%
set pass=%acct3%
GOTO :CHECKACCOUNT
:COUNTER
IF %i%==0 ( GOTO :RESETROUTER ) ELSE (
ECHO WAIT %i% seconds...
sleep 1
set /a i = i - 1
CLS
GOTO :COUNTER
)
:RESETROUTER
CLS
ECHO READY to RESET....
ECHO Preparing....
sleep 2
sleep 2
CLS
ECHO Processing....
sleep 5
sleep 2
CLS
ECHO Success....
sleep 5
set /a i = %timer%
CLS
GOTO :COUNTER
:PAUSEEXIT
PAUSE
:EXIT
ECHO.>>%log%
ECHO ========END OF LOG FILE========>>%log%

Answer 1

Your error as seen comes from wrong formatting. Don't put it all on 1 line. Instead use this:
if /I "%user%"=="insertusername" (
GOTO :ACCOUNT
) ELSE (
GOTO :CHECKPASSACCT
)
The deeper, underlying reason is: goto :somewhere command needs to be terminated by a newline.

Answer 2

You can simplify this down to:
:CHECKACCOUNT
if /I "%user%"=="insertusername" GOTO ACCOUNT
GOTO CHECKPASSACCT
:CHECKPASSACCT
if /I "%pass%"=="insertpassword" GOTO ACCOUNT
GOTO COUNTER
The ELSE statements aren't needed. Since the IF block will jump somewhere else, placing the second GOTO on the next line or in an ELSE block should be equivalent.
Also, you need the leading colon when defining a GOTO target but not when referring to the target name inside the GOTO statement itself.

Answer 3

The problem has nothing to do with the shown code!
The problem is at
:COUNTER
IF %i%==0 ( GOTO :RESETROUTER ) ELSE (
As the variable i isn't defined, the line will be expanded to
IF ==0 ( GOTO :RESETROUTER ) ELSE (
That is an invalid expression.
To find such simple syntax fails, you should enable debugging with ECHO ON.

Answer 4

You don't need to use the parentheses. You're basically telling the system
"if %user% is insertusername (" and it's asking "what is the '(' supposed to do?"