So in this URL: http://twitpic.com/2paihn
The Twitpic ID is: 2paihn
And the actual image URL is:
http://s3.amazonaws.com/twitpic/photos/large/163413275.jpg?AWSAccessKeyId=0ZRYP5X5F6FSMBCCSE82&Expires=1284740401&Signature=6lgT6ruyyUDDjLOB7d42XABoCLU%3D
I've tried getting the integer id through the api (i.e. 163413275) and replacing it in the s3.amazon.com url, but this seems to only work some of the time. Most of the time I get an 'access denied' message when I request the amazon-hosted image.
Do you know of another hack to do this?
This is the direct link to the image:
http://twitpic.com/show/full/2paihn
You can use it in an img tag or link it. It will forward to the amazon S3 url with a new expiration date and signature so whoever you're showing it to won't get the access denied message.
Source: http://dev.twitpic.com/docs/thumbnails/
Use http://twitpic.com/show/thumb/<imageid> to get a thumbnail version.
Related
I'm able to get a list of gists and their files https://api.git.mygithub.net/users/myuser/gists?per_page=100&page=1 which I found using the docs here: https://docs.github.com/en/free-pro-team#latest/rest/reference/gists#get-a-gist
The files on the gist object have a raw_url. If I fetch the raw_url with the same token, it fails wanting me to authenticate. If I add the header: Accept: application/vnd.github.v3.raw it returns a 406 Not Acceptable. I've references to that header around.
I'm not sure what the scope should be on the token. It seems like it would be the same one I accessed the API. In the UI if you click the raw file it gets a token appended to the url. That token doesn't look like one of the Private tokens mentioned here: https://docs.github.com/en/free-pro-team#latest/github/authenticating-to-github/creating-a-personal-access-token
So what is the format of the HTTP request to download the raw gist?
The raw url needs to have the hostname of gist. changed to raw. and the url path needs to start with /gist/.
Example code in Go fixing it:
url := gistFile.RawUrl
url = strings.Replace(url, "gist.", "raw.", 1)
url = strings.Replace(url, ".net/", ".net/gist/", 1)
We have implemented an error handler for Yii 1. Also we have implemented the mail functionality with this as any error occurred an email will be send to us but the problem is we are not getting the current URL on which error is generating. Like one page controller/action can contain many images favicons etc. So if any image is missing then we are getting the image URL which showing 404 from:
$url = Yii::app()->createAbsoluteUrl(Yii::app()->request->url);
But we are not getting current URL not even in $error = Yii::app()->errorHandler->error.
So we are not getting the page in which image is absent. Please let me know if is there any way to get current page URL as I have tried many ways but all they are returning the missing images URL instead of main page URL for which images are missing.
createAbsoluteUrl() expects route as first argument - it may return random results if you provide URL instead of route (like in your code snippet).
If you want absolute URL of current request, you may use combination of getUrl() and getHostInfo():
$url = Yii::app()->request->getHostInfo() . Yii::app()->request->getUrl();
In case of error you can get current page url using Yii::app()->request->requestUri in Yii 1.
When I create a share link in the UI with the "Anyone with this link can view this item" option, I get a URL that looks like https://onedrive.live.com/redir?resid=XXX!YYYY&authkey=!ZZZZZ&ithint=<contentType>. What I can't figure out is how to use this URL from code to download the content of the file. Hitting the link gives HTML for a page to show the file.
How can I construct a call to download the file? Also, is there a way to construct a call to get some (XML/JSON) metadata about the file, and maybe even a preview or something? I want to be able to do this all without prompting a user for credentials, and all the API docs are about how to make authenticated calls. I want to make anonymous calls to get publicly-shared files.
Have a read over https://dev.onedrive.com - it documents how you can make a query to our service to get the metadata for an item, along with URLs that can be used to directly download the content.
Update with more details
Sorry, the documentation you need for your specific scenario is still in process (along with the associated SDK changes) so I'll give you an overview of how to do it.
There's a sibling to the /drives path called /shares which accepts a sharing URL (such as the one you have above) in an encoded format and allows you to get metadata for the item it represents. This does not require authentication provided the sharing URL has a valid authkey.
The encoding scheme for the id is u!<UrlSafeBase64EncodedUrl>, where <UrlSafeBase64EncodedUrl> follows the guidelines outlined here (trim the = characters from the end).
Here's a snippet that should give you an idea of the whole process:
string originalUrl = "https://onedrive.live.com/redir?resid=XXX!YYYY&authkey=!foo";
byte[] urlAsUtf8Bytes = Encoding.UTF8.GetBytes(originalUrl);
string utf8BytesAsBase64String = Convert.ToBase64String(urlAsUtf8Bytes);
string encodedUrl = "u!" + utf8BytesAsBase64String.TrimEnd('=').Replace('/', '_').Replace('+', '-');
string metadataUrl = "https://api.onedrive.com/v1.0/shares/" + encodedUrl + "/root";
From there you can append /content if you want to get the contents of the file, or you can start navigating through if the URL represents a folder (e.g. /children/childfile.txt)
I am using the telegram bot API but I cant see anyway to download a filé that was sent to my bot. I get a hash of the file but dont know what to do with it. Is there any way? Thanks.
This is now available!
https://core.telegram.org/bots/api#getfile
Hooray! It was added on Sep 18th (2015):
https://core.telegram.org/bots/api
Usage:
In the JSON of the message you will receive a file_id as before. An example of a message object with a voice file:
{
message_id: 2675,
from: {
id: 10000001,
first_name: 'john',
username: 'john'
},
chat: {
id: 10000001,
first_name: 'john',
username: 'john'
},
date: 1442848171,
voice: {
duration: 2,
mime_type: 'audio/ogg',
file_id: 'AwADBAADYwADO1wlBuF1ogMa7HnMAg', // <------- file_id
file_size: 17746
}
}
Via the API's getFile you can now get the required path information for the file:
https://api.telegram.org/bot<bot_token>/getFile?file_id=the_file_id
This will return an object with file_id, file_size and file_path. You can then use the file_path to download the file:
https://api.telegram.org/file/bot<token>/<file_path>
Note that this link will only be available for an hour. After an hour you can request another link. This means that if you want to host the file somehow and you rather avoid checking and re-checking for fresh links every time you serve it you might be better off downloading the file to your own hosting service.
The maximum size of a file obtained through this method is 20MB.
Error: Obtained when a file large than 20mb is used.(Shown below)
{"ok":false,"error_code":400,"description":"Bad Request: file is too big[size:1556925644]"}
From telegram's docs:
On success, a File object is returned. The file can then be downloaded via the link https://api.telegram.org/file/bot/<file_path>, where <file_path> is taken from the response. It is guaranteed that the link will be valid for at least 1 hour. When the link expires, a new one can be requested by calling getFile again.For the moment, bots can download files of up to 20MB in size.
Yay! It's just added at September 18, 2015
You can use getFile(file_id). This function returns a File object containing file_path. You can download the file through this address:
https://api.telegram.org/file/bot<token>/<file_path>
As mentioned in Telegram Bot API Documentation, the File object will be valid for about one hour. You should call getFile again to get a new File object if the old one expires.
If you are using pyTelegramBotAPI you can download your photo using this code:
raw = message.photo[2].file_id
path = raw+".jpg"
file_info = bot.get_file(raw)
downloaded_file = bot.download_file(file_info.file_path)
with open(path,'wb') as new_file:
new_file.write(downloaded_file)
The method to work with files is not available yet.
Source: telegram on twitter
https://twitter.com/telegram/status/614468951926509568
If you have the file_id then you need to use the sendDocument or sendPhoto methods, if you want to send to yourself, you need to tell your bot your user id or your chat id (the same in one-to-one chat).
Also, pay attention, that Telegram api (by webhook) provides thumbs prop, for images and gifs it will provide thumbnail of file. To get source file, you need to check root object file_id.
I have installed AWS S3 toolkit on sdfc. I have the following code where AWS_S3_ExampleController is part of the installed toolkit. When i execute this code the debug log shows the generic "internal Server error" 500.
The returned soap message has
soapenv:Value>ns1:Client.InvalidArgument soapenv:Value soapenv:Code soapenv:Reasonsoapenv:Text xml:lang="en"Invalid id /soapenv:Text/soapenv:Reason soapenv:Detail ArgumentValue>SAmeer Thakur ArgumentValue>ArgumentName>CanonicalUser/ID/soapenv:Detail>soapenv:Fault> soapenv:Body>soapenv:Envelope>
I do not know how to resolve the Invalid id being seen
AWS_S3_ExampleController c = new AWS_S3_ExampleController();
c.constructor();
c.fileName=fileName;
c.OwnerId='Sameer Thakur';
c.bucketToUploadObject= bucketName;
c.fileSize=100000;
c.fileBlob= Blob.valueOf(record);
c.accessTypeSelected='public-read-write';
System.debug('Before insert');
c.syncFilesystemDoc();
System.debug('After insert');
Any pointer would be appreciated
Thank you
Sameer
The problem was i needed to define ownerid with canonical value.
This value is generated using access key and secret key.
The url to generate canonical user id value is # http://www.bucketexplorer.com/awsutility.aspx
regards
Sameer