I have a table with 5 columns:
tag 1
tag 2
tag 3
tag 4
tag 5
If I want to show results ordered by the popularity(frequency) of those tags, what kind of query would i use?
Because the table isn't normalized, you'll have to flatten it first:
SELECT a.column, a.tag1 AS tag
FROM TABLE a
UNION ALL
SELECT b.column, b.tag2
FROM TABLE b
UNION ALL
SELECT c.column, c.tag3
FROM TABLE c
UNION ALL
SELECT d.column, d.tag4
FROM TABLE d
UNION ALL
SELECT e.column, e.tag5
FROM TABLE e
...before you can count them:
SELECT t.tag, COUNT(*) tag_popularity
FROM (SELECT a.column, a.tag1 AS tag
FROM TABLE a
UNION ALL
SELECT b.column, b.tag2
FROM TABLE b
UNION ALL
SELECT c.column, c.tag3
FROM TABLE c
UNION ALL
SELECT d.column, d.tag4
FROM TABLE d
UNION ALL
SELECT e.column, e.tag5
FROM TABLE e) x
GROUP BY x.tag
ORDER BY tag_popularity DESC
Related
I have a simple SQLite table which has just one ID column.
I have some variable IDs that may be duplicates of each other like: 1,2,3,4,3,1 (These IDs are just examples, there could be hundreds of them).
And I have a simple query as follows:
SELECT ID FROM TABLE WHERE ID in (1,2,3,4,3,1)
In the usual case the answer contains only 4 rows with ids 1,2,3,4. Is there any way to force SQLite to return rows in the order of the request (1,2,3,4,3,1) even if they are duplicates?
I have n IDs in my query and I want n rows in return even if they are duplicates.
Edit: The Table Definition is:
CREATE TABLE TEST(ID TEXT PRIMARY KEY)
You can use left join:
select t.*
from (select 1 as id, 1 as ord union all
select 2 as id, 2 as ord union all
select 3 as id, 3 as ord union all
select 4 as id, 4 as ord union all
select 3 as id, 5 as ord union all
select 1 as id, 6 as ord
) ids left join
t
on t.id = ids.id
order by ids.ord;
I have a table in data base in which there are corresponding values for the primary key.
I want to count the distinct values from two columns.
I already know one method of using union all and then applying groupby on that resultant table.
Select Id,Brand1
into #Temp
from data
union all
Select Id,Brand2
from data
Select ID,Count(Distinct Brand1)
from #Temp
group by ID
Same thing we can do in big query also using temp table only.
Sample Table
ID Brand1 Brand2
1 A B
1 B C
2 D A
2 A D
Resultant Table
ID Distinct_Count_Brand
1 3
2 2
As you can see in this column Distinct_count_Brand It is counting the unique count of Brand from two columns Brand1 and Brand2.
I already know one way (Basically unpivoting) but want to know if there is some other way around to count unique values from two columns.
I don't know BigQuery's quirks, but perhaps you can just inline the union query:
SELECT ID, COUNT(DISTINCT Brand)
FROM
(
SELECT ID, Brand1 AS Brand FROM data
UNION ALL
SELECT ID, Brand2 FROM data
) t
GROUP BY ID;
In SQL Server, I woud use:
Select b.id, count(distinct b.brand)
from data d cross apply
(values (id, brand1), (id, brand2)) b(id, brand)
group by b.id;
Here is a db<>fiddle.
In BigQuery, the equivalent would be expressed as:
select t.id, count(distinct brand)
from t cross join
unnest(array[brand1, brand2]) brand
group by t.id;
Here is a BQ query that demonstrates that this works:
with t as (
select 1 as id, 'A' as brand1, 'B' as brand2 union all
select 1, 'B', 'C' union all
select 2, 'D', 'A' union all
select 2, 'A', 'D'
)
select t.id, count(distinct brand)
from t cross join
unnest(array[brand1, brand2]) brand
group by t.id;
In oracle is it possible to join a static list to a table?
The list I have is something like this
ID
1
2
3
4
5
6
I don't want to create a table for this list
But then I want to join the list to an existing table that has the ID's in it... hoping to do a left join with the list
Is this possible?
You are lookig for a WITH clause that contains UNIONs of SELECT FROM DUAL.
Like :
WITH my_list AS (
select 'A' my_value from dual
UNION ALL select 'B' my_value from dual
UNION ALL select 'C' my_value from dual
)
SELECT
*
FROM
my_list
LEFT JOIN my_table ON my_table.my_field = my_list.my_value
;
You can generate the ID list in a CTE and then join it to whatever you want.
with id_list as (
select rownum as id
from dual
connect by level <= 6
)
select * from id_list;
ID
1
2
3
4
5
6
https://livesql.oracle.com/apex/livesql/s/hm2mczgx5udiig9vhryo86mfm
I am sorry , this one is not working... May be I should have clarified this earlier. The values A,B,C,D etc... Are the Distinct values for CODE in the Table. There are several hundreds of IDs in the table and each ID can have one to many Code values. In the above example assume that there are 5 distinct values of Code from table A. There are 3 IDs and each ID is associated in Table A as follows
ID Code
1 A
1 B
1 C
2 D
2 A
3 B
3 C
4 A
4 B
4 C
4 D
4 E
As you see above there are several IDs associated with different Code values. I need the result as follows
ID CODE
1 D
1 E
2 B
2 C
2 E
3 A
3 D
3 E
ID 4 should not return anything because it contain all possible Codes (in this case A,B,C,D,E)
First you should take distinct values for both column in different sub-query, second cross join them - that will give you all possible combination,
finally exclude combination which are already presnet
select *
from
(select distinct ID
from your_table) ytI, /* this sub-query will return all possible ID */
(select distinct code
from your_table) ytc /* this sub-query will return all possible code */
where (ytI.ID,ytc.Code) /* there will be cross-join as there are no join condition between first two tables*/
not in /* exclude those records which are already present */
(select id,code
from your_table yt_i)
try this
select T2.ID, T1.missing_value
from
(
select 'A' missing_value from dual UNION
select 'B' from dual UNION
select 'C' from dual UNION
select 'D' from dual UNION
select 'E' from dual
) T1,
(
select distinct id from MYTABLE
) T2
WHERE NOT EXISTS
(
SELECT * FROM MYTABLE M WHERE M.CODE = T1.missing_value and M.ID = T2.ID
)
ORDER BY T2.ID, T1.missing_value
I'm doing
SELECT Name WHERE Id IN (3,4,5,3,7,8,9)
where in this case the '3' Id is duplicated.
The query automatically excludes the duplicated items while for me would be important to get them all.
Is there a way to do that directly in SQL?
The query doesn't exclude duplicates, there just isn't any duplicates to exclude. There is only one record with id 3 in the table, and that is included because there is a 3 in the in () set, but it's not included twice because the 3 exists twice in the set.
To get duplicates you would have to create a table result that has duplicates, and join the table against that. For example:
select t.Name
from someTable t
inner join (
select id = 3 union all
select 4 union all
select 5 union all
select 3 union all
select 7 union all
select 8 union all
select 9
) x on x.id = t.id
Try this:
SELECT Name FROM Tbl
JOIN
(
SELECT 3 Id UNION ALL
SELECT 4 Id UNION ALL
SELECT 5 Id UNION ALL
SELECT 3 Id UNION ALL
SELECT 7 Id UNION ALL
SELECT 8 Id UNION ALL
SELECT 9 Id
) Tmp
ON tbl.Id = Tmp.Id