My query is:
SELECT DISTINCT IncidentStatus.IncidentStatusName, Incident.IncidentID AS Bob
FROM Incident
INNER JOIN IncidentMember
ON Incident.IncidentID = IncidentMember.IncidentId
INNER JOIN IncidentStatus
ON Incident.IncidentStatusID = IncidentStatus.IncidentStatusID
WHERE (IncidentMember.MemberId = 6)
And the result is:
IncidentStatusName Bob
---------------------------
Closed 9267
In Progress 9251
In Progress 9289
New 7893
Resolved 7750
Required Result is:
IncidentStatusName Bob
---------------------------
Closed 1
In Progress 2
New 1
Resolved 1
Help Requested.
SELECT IncidentStatus.IncidentStatusName, COUNT(Incident.IncidentID) AS Bob
FROM Incident
INNER JOIN IncidentMember ON Incident.IncidentID = IncidentMember.IncidentId
INNER JOIN IncidentStatus ON Incident.IncidentStatusID = IncidentStatus.IncidentStatusID
WHERE (IncidentMember.MemberId = 6)
GROUP BY IncidentStatus.IncidentStatusName
Or maybe you need COUNT(DISTINCT Incident.IncidentID) (depends on your table structure)
take your PK field, Incident.IncidentID, out of the select distinct clause
Related
MaingroupTable
MubGroupCodeid MainName maincode
1 Health 098
2 Social 078
SubGroup Table
SubGroupCodeid SubName subcode
1 Nursing 211
2 Civics 224
SubandMainGroup table
subandmainid **MubGroupCodeid** **subgroupcodeid**
1 1 1
2 2 2
Student Table
studid studname **subandmainid** (foriegn key of **subandmain group** table)
1 Alex 1
2 siraj 2
then I want to join and concatinate studname-maingroupcode-subgroupcode to get output like below
Alex-098-211
siraj-078-224
This will get you started and explain the joins. You'll probably also want to do some casting for the maincode and subcode, but since it's not 100% clear they aren't already varchar values I left that out.
SELECT s.studname + '-' + m.maincode + '-' + s.subcode
FROM Student s
INNER JOIN SubandMainGroup smg on smg.subandmainid = s.subandmainid
INNER JOIN MainGroup m on m.mubgroupcodeid = smg.mubgroupcodeid
INNER JOIN SubGroup s on s.subgroupcodeid = smg.subgroupcodeid
use join and concat all the required column by using ||
select s.studname ||'-'||subG.subcode ||'-' M.maincode
from
Student s join SubandMainGroup subM on s.subandmainid=subM.subandmainid
join SubGroup subG on subG.SubGroupCodeid=subM.subgroupcodeid
join MaingroupTable M on M.MubGroupCodeid=subM.MubGroupCodeid
Use the below query to solve the problem.
select stu.studname + '-'+mgrp.maincode +'-'+sgrp.subcode from Student_ stu
join Maingroup mgrp on stu.studid=mgrp.MubGroupCodeid
join SubGroup sgrp on sgrp.SubGroupCodeid=stu.studid
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SELECT
TR.UserKeyCode, TR.ProductID, TR.Line_No
FROM
TBLT_RESULTDTL_DONE TR
LEFT OUTER JOIN
TBLM_PRODUCT TP ON TR.ProductID = TP.ProductID
WHERE
TR.UserKeyCode = 'E01_00001' AND TR.QustionID = 1
Result:
E01_00001 11 1
E01_00001 36 2
E01_00001 16 3
Product table all results and Result record 3 only i need others will be null
SELECT
TR.UserKeyCode, TR.ProductID, TR.Line_No
FROM
TBLM_PRODUCT TP
LEFT OUTER JOIN
TBLT_RESULTDTL_DONE TR ON TR.ProductID = TP.ProductID and TR.UserKeyCode = 'E01_00001' AND TR.QustionID = 1
I have 3 tables: firearms_firearmbook, inventory_inventory and inventory_inventorytransaction.
And i have 2 Cases:
If inventory_inventory Table has no inventory_inventorytransaction with item action of 16, show inventory_inventory record
If inventory_inventory Table has inventory_inventorytransaction with item action of 16, show inventory_inventory and inventory_inventorytransaction.item_action_id
The query bellow works for the first cause, but its not working for the second cause.
It should show smth like this:
-----------------------------------
| id | serial | action_id |
-----------------------------------
1 MAGUM
2 EAGLE
2 EAGLE 16
Query:
SELECT FB.id, INV.serial_number, INV.id, INVT.item_action_id FROM firearms_firearmbook AS FB
LEFT JOIN inventory_inventory AS INV ON INV.id = FB.item_id
LEFT JOIN inventory_inventorytransaction AS INVT ON INVT.item_id = INV.id AND INVT.item_action_id = 16
WHERE FB.store_id = 1
It seems that if there is an action 16 record for a given item, you need two records in the output: one with a blank in the third column, and one with 16 in the third column.
In that case you could do this:
with base as (
select fb.id,
inv.serial_number,
inv.id,
from firearms_firearmbook as fb
inner join inventory_inventory as inv
on inv.id = fb.item_id
where fb.store_id = 1
)
select base.*,
invt.item_action_id
from base
inner join inventory_inventorytransaction as invt
on invt.item_id = base.id
and invt.item_action_id = 16
union all
select base.*,
null
from base
order by 1, 2, 3, 4 desc
Hi I think this is what your after.
I've made a CASE statement for the two situation you describe. I wasn't sure what you column you wanted for 2) when you say "inventory_inventory" so I put the id column and you can change it for another column.
I've also removed INVT.item_action_id = 16 part of the inventory_inventorytransaction join as I don't think it's necessary as it is handled in the CASE statement.
SELECT
FB.id,
INV.serial_number,
INV.id,
INVT.item_action_id,
CASE
WHEN INVT.item_action_id = 16 THEN CAST(INV.id as VARCHAR) + ' ' + CAST(INVT.item_action_id as VARCHAR) -- This is Case 2
ELSE INV.record -- This is Case 1
END as answer
FROM firearms_firearmbook AS FB
LEFT JOIN inventory_inventory AS INV ON INV.id = FB.item_id
LEFT JOIN inventory_inventorytransaction AS INVT ON INVT.item_id = INV.id -- Removed JOIN on INVT.item_action_id = 16 and moved it to CASE
WHERE FB.store_id = 1;
I have the following query;
What I get is tickets information. I use self-join to obtain the requester and the assignee in the same row:
SELECT z.id AS TICKET, z.name AS Subject, reqs.name AS Requester, techs.name AS Assignee,
e.name AS Entity,DATE_FORMAT(tt.date,'%y%-%m%-%d') AS DATE,
DATE_FORMAT(tt.date,'%T') AS HOUR,
CASE WHEN z.priority = 6 THEN 'Mayor' WHEN z.priority = 5 THEN 'Muy urgente' WHEN z.priority = 4 THEN 'Urgente'WHEN z.priority = 3 THEN 'Mediana' WHEN z.priority = 2 THEN 'Baja' WHEN z.priority =1 THEN 'Muy baja' END AS Priority,
c.name AS Category, i.name AS Department
FROM glpi_tickets_users tureq
JOIN glpi_tickets_users tutech ON tureq.tickets_id = tutech.tickets_id
JOIN glpi_users AS reqs ON tureq.users_id = reqs.id
JOIN glpi_users AS techs ON tutech.users_id = techs.id
JOIN glpi_tickets z ON z.id = tureq.tickets_id
LEFT OUTER JOIN glpi_tickettasks tt ON z.id = tt.tickets_id
LEFT JOIN glpi_itilcategories i ON z.itilcategories_id = i.id
LEFT JOIN glpi_usercategories c ON c.id = reqs.usercategories_id
INNER JOIN glpi_entities e ON z.entities_id = e.id
WHERE (tureq.id < tutech.id AND tureq.type < tutech.type) OR
(tureq.id < tutech.id AND tureq.users_id = tutech.users_id) OR
(tureq.id = tutech.id AND tureq.users_id = tutech.users_id)
The problem is that I get something like that:
1 Report jdoe jdoe Development 16-06-07 11:56:17 Mediana Software Mkt
1 Report jdoe fwilson Development 16-06-07 11:56:17 Mediana Software MKt
1 Report fwilson fwilson Development 16-06-07 11:56:17 Mediana Software Mkt
2 Task11 gwilliams gwilliams Ops 16-06-08 12:00:00 ALTA Hardware Def
3 Task12 gwilliams gwilliams Ops 16-06-08 12:01:00 ALTA Hardware Def
I don't want first and third row because is a CROSS JOIN result. Second row is OK, because jdoe is a requester and fwilson an assignee.
The problem is that sometimes requester and assignee are the same, eg: he creates a ticket for a task that himself will do. For example, 4th and 5th rows are OK.
So, how should I do to make a difference for those distinct cases, i.e.: I need to include:
tureq.id = tech.id AND req.users_id = tech.users.id
BUT NOT IF ALREADY EXISTS
tureq.id = tech.id AND req.users_id <> tech.users_id
Update
The main problem is that a user can assign to himself a ticket:
SELECT * from glpi_tickets_users WHERE type = 2 GROUP BY tickets_id HAVING COUNT(users_id)<2 limit 3;
+----+------------+----------+------+------------------+-------------------+
| id | tickets_id | users_id | type | use_notification | alternative_email |
+----+------------+----------+------+------------------+-------------------+
| 1 | 2 | 12 | 2 | 1 | NULL |
| 3 | 6 | 13 | 2 | 1 | NULL |
| 7 | 8 | 14 | 2 | 1 | NULL |
+----+------------+----------+------+------------------+-------------------+
Update 2:
It was a human mistake. The problem was really not about self-assigned tickets. Rather it was either that some tickets had not Requester or had Requester but still had not any resolver assigned.
I've found
As there are always the two types per ticket you are interested in, you can simply select the according records, so as to get requester and assignee per ticket.
select
t.id as ticket,
t.name as subject,
requester.name as requester,
assignee.name as assignee,
e.name as entity,
date_format(tt.date,'%y%-%m%-%d') as date,
date_format(tt.date,'%T') as hour,
case t.priority
when 6 then 'Mayor'
when 5 then 'Muy urgente'
when 4 then 'Urgente'
when 3 then 'Mediana'
when 2 then 'Baja'
when 1 then 'Muy baja'
end as priority,
uc.name as category,
ic.name as department
from glpi_tickets t
join glpi_entities e on e.id = t.entities_id
join
(
select tu.tickets_id, u.name, u.usercategories_id
from glpi_tickets_users tu
join glpi_users u on u.id = users_id
where tu.type = 1
) requester on requester.tickets_id = t.id
join
(
select tu.tickets_id, u.name
from glpi_tickets_users tu
join glpi_users u on u.id = users_id
where tu.type = 2
) assignee on assignee.tickets_id = t.id
left join glpi_itilcategories ic on ic.id = t.itilcategories_id
left join glpi_usercategories uc on uc.id = requester.usercategories_id;
left outer join glpi_tickettasks tt on tt.tickets_id = t.id
The only thing I wonder is: There can be several ticket tasks per ticket. So what do you want to do then? Have one line per ticket task in your results? This is what the query does. Only, it looks queer that your result rows don't contain any information on the tasks except for the dates, so you may have many, many lines with the same data, only with different dates. So maybe, you'd rather want the first or last date per ticket. To get the last date per ticket, you'd replace the last line in the query with:
left outer join
(
select tickets_id, max(date) as date
from glpi_tickettasks
group by tickets_id
) tt on tt.tickets_id = t.id
And you probably want to add an ORDER BY clause.
you need to add more qualifiers to your joins for example
JOIN glpi_tickets_users tutech ON tureq.tickets_id = tutech.tickets_id and tutech.type = 2
I am actually creating a crystal reports v12 (2008) report but can't find the method, using Crystal, to extract the following. I thought if someone might answer in SQL language, I could piece it together.
2 Tables: hbmast, ddmast
SELECT hbmast.custno, hbmast.id, ddmast.name, ddmast.status
WHERE hbmast.custno = ddmast.custno
GROUP BY hbmast.id
pseudo code::show all hbmast values that have ddmast.status = '2'
Sample output:
J0001, 111222, PAUL JONES, 1
111222, PAUL JONES, 2
111222, PAUL JONES, 1
K0001, 555333, PETER KING, 3
555333, PETER KING, 1
I would like to have Paul show on the report with all child records but Peter should not be returned on the report since he has no child records with '2' for ddmast.status field.
Thanks for the help
I think you're looking for this:
select hb.custno, hb.id, dd.name, dd.status from hbmast hb
join ddmast dd on hb.custno = dd.custno
where hb.custno in (
select custno from ddmast
where status = '2'
)
Let me know if this returns your expected result.
The way to achieve this in Crystal would be to have your hb and dd tables then a second alias of the dd table.
So you would filter your dd alias table where status = 2 then join to your hb table and back to your dd table (not the alias). The SQL would end up looking like:
select hb.custno, hb.id, dd.name, dd.status from hbmast hb
inner join ddmast dd on hb.custno = dd.custno
inner join ddmast dd2 on hb.custno = dd2.custno
where dd2.status = '2'
Andomar makes a valid point about duplicate records appearing if there is more than 1 record per group with a status of 2. If that is the case you can either group by primary key and show row information at group footer level OR use a sql expression with a subquery in your selection formula instead of the double join method.
SQL Expression: (select count(*) from ddmast where custno = "hbmast.custno" and status = '2')
Then record selection expert: {%sqlexpression} > 0
And a different way to get the same...
SELECT hb.custno, hb.id, dd.name, dd.status
FROM hbmast hb
INNER join ddmast dd
on hb.custno = dd.custno
INNER JOIN DDMAST2 DD2
on DD2.custNo = HB.custNo
AND DD2.Status='2'