question on Group by clause in Sql server - sql

Question

Table: Customer
Name Type Amount
James P 125.00
James P 125.00
James P 125.00
James R 225.00
James R 225.00
Rajiv R 155.00
Rajiv R 155.00
Rajiv R 155.00
Rajiv P 150.00
Rajiv P 150.00
Saran R 175.00
In this table structure I want a output which will give each person’s count of P, count of R, sum of Amount where type = P, Sum of amount where type = R
Any clues for me as stuck up with group by did not help me much in this scenario.

Answer 1

If you want the result as separate records, you simply group on the name and type:
select Name, Type, count(*) as Cnt, sum(Amount) as AmountSum
from Customer
Group by Name, Type
order by Name, Type
Result:
Name Type Cnt AmountSum
James P 3 375.00
James R 2 450.00
Rajiv P 2 300.00
Rajiv R 3 465.00
Saran R 1 175.00
If you want the count and sum for a person in the same record, you have to do some comparisons:
select
Name,
count(case Type when 'P' then 1 else null end) as CntP,
sum(case Type when 'P' then Amount else 0 end) as AmountSumP,
count(case Type when 'R' then 1 else null end) as CntR,
sum(case Type when 'R' then Amount else 0 end) as AmountSumR,
from Customer
Group by Name
order by Name
Result:
Name CntP AmountSumP CntR AmountSumR
James 3 375.00 2 450.00
Rajiv 2 300.00 3 465.00
Saran 0 0.00 1 175.00

Answer 2

One query, no CTE, no derived tables:
SELECT
Name,
SUM(CASE WHEN Type = 'P' THEN 1 ELSE 0 END) AS PCount,
SUM(CASE WHEN Type = 'R' THEN 1 ELSE 0 END) AS RCount,
SUM(CASE WHEN Type = 'P' THEN Amount ELSE 0 END) AS PAmount,
SUM(CASE WHEN Type = 'R' THEN Amount ELSE 0 END) AS RAmount
FROM yourTable
GROUP BY Name
using the
CREATE TABLE customer (name varchar(50), type char(1), amount decimal(6,2));
INSERT INTO customer VALUES ('James', 'P', 125.00);
INSERT INTO customer VALUES ('James', 'P', 125.00);
INSERT INTO customer VALUES ('James', 'P', 125.00);
INSERT INTO customer VALUES ('James', 'R', 225.00);
INSERT INTO customer VALUES ('James', 'R', 225.00);
INSERT INTO customer VALUES ('Rajiv', 'R', 155.00);
INSERT INTO customer VALUES ('Rajiv', 'R', 155.00);
INSERT INTO customer VALUES ('Rajiv', 'R', 155.00);
INSERT INTO customer VALUES ('Rajiv', 'P', 150.00);
INSERT INTO customer VALUES ('Rajiv', 'P', 150.00);
INSERT INTO customer VALUES ('Saran', 'R', 175.00);
SELECT
Name,
SUM(CASE WHEN Type = 'P' THEN 1 ELSE 0 END) AS PCount,
SUM(CASE WHEN Type = 'R' THEN 1 ELSE 0 END) AS RCount,
SUM(CASE WHEN Type = 'P' THEN Amount ELSE 0 END) AS PAmount,
SUM(CASE WHEN Type = 'R' THEN Amount ELSE 0 END) AS RAmount
FROM customer
GROUP BY Name
James 3 2 375.00 450.00
Rajiv 2 3 300.00 465.00
Saran 0 1 0.00 175.00

Answer 3

Edited Answer: After gbn pointed out a mistake in my original answer
SELECT name,
SUM( CASE WHEN [type] = 'P' THEN 1 ELSE 0 END) CountOfP ,
SUM( CASE WHEN [type] = 'R' THEN 1 ELSE 0 END) CountOfR,
SUM( CASE WHEN [type] = 'P' THEN Amount End) SumOfP ,
SUM( CASE WHEN [type] = 'R' THEN Amount END) SumOfR
FROM customer
GROUP BY name
Original Answer
SELECT name,
COUNT( CASE WHEN [type] = 'P' THEN 1 ELSE 0 END) CountOfP ,
COUNT( CASE WHEN [type] = 'R' THEN 1 ELSE 0 END) CountOfR,
SUM( CASE WHEN [type] = 'P' THEN Amount End) SumOfP ,
SUM( CASE WHEN [type] = 'R' THEN Amount END) SumOfR
FROM customer
GROUP BY name