MySQL has a function called STR_TO_DATE, that converts a string to date.
Question:
Is there a similar function in SQL Server?
If you need to parse a particular format, use CONVERT(datetime, #mystring, #format). Use this as a reference: https://web.archive.org/web/20200729210252/http://www.sqlusa.com/bestpractices/datetimeconversion/
Some examples:
SELECT convert(datetime, '10/23/2016', 101) -- mm/dd/yyyy
SELECT convert(datetime, '2016.10.23', 102) -- yyyy.mm.dd ANSI date with century
SELECT convert(datetime, '23/10/2016', 103) -- dd/mm/yyyy
SELECT convert(datetime, '23.10.2016', 104) -- dd.mm.yyyy
SELECT convert(datetime, '23-10-2016', 105) -- dd-mm-yyyy
-- mon types are nondeterministic conversions, dependent on language setting
SELECT convert(datetime, '23 OCT 2016', 106) -- dd mon yyyy
SELECT convert(datetime, 'Oct 23, 2016', 107) -- mon dd, yyyy
-- 2016-10-23 00:00:00.000
SELECT convert(datetime, '20:10:44', 108) -- hh:mm:ss
-- 1900-01-01 20:10:44.000
What if the string is 7/7/2010?
Then use CONVERT with either 101 (mm/dd/yy) or 103 (dd/mm/yy) depending on what you want:
SELECT CONVERT(DATE, '7/7/2010', 103)
Result:
2010-07-07
CAST(<string> AS DATETIME)
Use CAST.
declare #MyString varchar(10)
declare #MyDate datetime
set #MyString = '2010-08-19'
set #MyDate = cast(#MyString as datetime)
select #MyDate
Here is a good example:
declare #myDate datetime
set #myDate = '06/09/2017'
select concat(convert(varchar(20), #myDate,101), ' -- ',
convert(varchar(20), #myDate,103), ' -- ',
convert(varchar(20), #myDate,6))
This is what you get, depending on 101 or 103 or 6:
09/06/2017 -- 06/09/2017 -- 06 Sep 17
A good summary of types of dates is here - https://www.w3schools.com/sql/func_convert.asp
On MSSQL:
select cast('2012/06/12 10:32AM' as datetime);
You will get it:
2012-06-12 10:32:00.000
Related
I'm passing a start date and end date parameter to my stored procedure. I'm doing a simple test here:
DECLARE #StartDate DATE = '10/06/2013' --dd/mm/yyyy
SELECT #StartDate -- this statement running successfully
DECLARE #EndDate DATE = '30/06/2013' --dd/mm/yyyy
SELECT #EndDate -- this statement giving error
This statement returns the following error
Msg 241, Level 16, State 1, Line 2
Conversion failed when converting date and/or time from character string.
Does anybody have idea what's going wrong with EndDate?
I'm pretty sure the error is on this line:
DECLARE #EndDate DATE = '30/06/2013' --dd/mm/yyyy
Not on the SELECT. It wouldn't make sense that it would be on the SELECT, because processing a variable should be fine.
I would recommend that you use YYYYMMDD formats. The following is my preference:
DECLARE #EndDate DATE = '2013-30-06' ;
However, it can fail for certain internationalization settings. The following is documented to always work:
DECLARE #EndDate DATE = '20133006' ;
'10/06/2013' means 06-Oct-2013 not 10-Jun-2013. There is nothing exists with month 30 as in your #EndDate '30/06/2013'.
DECLARE #StartDate DATE='10/06/2013'
DECLARE #DummyDate DATE = '2013-Oct-06'
IF #StartDate = #DummyDate
BEGIN
SELECT 1
END
By default sql server takes date value in 'yyyy-mm-dd' format,
So you need to follow that format or you need to convert date format accordingly.
T-SQL convert string to datetime - SQL Server convert string to date
SELECT convert(datetime, '10/23/2016', 101) -- mm/dd/yyyy
SELECT convert(datetime, '2016.10.23', 102) -- yyyy.mm.dd
SELECT convert(datetime, '23/10/2016', 103) -- dd/mm/yyyy
SELECT convert(datetime, '23.10.2016', 104) -- dd.mm.yyyy
SELECT convert(datetime, '23-10-2016', 105) -- dd-mm-yyyy
-- mon types are nondeterministic conversions, dependent on language setting
SELECT convert(datetime, '23 OCT 2016', 106) -- dd mon yyyy
SELECT convert(datetime, 'Oct 23, 2016', 107) -- mon dd, yyyy
-- SQL string to datetime conversion without century - some exceptions
SELECT convert(datetime, '10/23/16', 1) -- mm/dd/yy
SELECT convert(datetime, '16.10.23', 2) -- yy.mm.dd
SELECT convert(datetime, '23/10/16', 3) -- dd/mm/yy
SELECT convert(datetime, '23.10.16', 4) -- dd.mm.yy
SELECT convert(datetime, '23-10-16', 5) -- dd-mm-yy
SELECT convert(datetime, '23 OCT 16', 6) -- dd mon yy
SELECT convert(datetime, 'Oct 23, 16', 7) -- mon dd, yy
I have a problem in converting sql server 2008 datetime to varchar,
Select convert(varchar(20),convert(datetime, '2013-12-11 00:59:00.000'))
the result is Dec 11 2013 12:59AM but I need it to be actually Dec 11 2013 00:59AM as in the database dates are of 24-Hour format.
How can I correct the query?
There are two functions, cast and convert that you can use.
http://msdn.microsoft.com/en-us/library/ms187928.aspx
You forgot to put in the format style.
-- Using cast
Select cast('2013-12-11 00:59:00.000' as varchar(20)) as my_casted_date
-- Using convert
Select convert(varchar(24), '2013-12-11 00:59:00.000', 113) as my_converted_date
Use format with custom date time strings for utlitmate flexibility.
http://msdn.microsoft.com/en-us/library/8kb3ddd4(v=vs.110).aspx
-- Using format
DECLARE #my_date datetime2 = '2013-12-11 00:59:00.000';
SELECT format(#my_date, 'MMM dd yyyy HH:MM tt', 'en-us') as str_english_date
Solution that will work with SQL Server 2008.
-- Create a date time variable
DECLARE #my_date DATETIME2 = '2013-12-11 00:59:00.000';
-- Using convert
SELECT
CONVERT(varchar(24), #my_date, 113) +
CASE
WHEN DATEPART(HH, #my_date) < 12 THEN ' AM'
ELSE ' PM'
END
AS my_converted_date;
This will be perfect for you..
declare #dt datetime
set #dt='12-Jan-2014 23:59'
SELECT Right(CONVERT(VARCHAR, #dt, 100),7) AS DateTime_In_12h_Format
It's not nice but it does its job:
DECLARE #Var DATETIME;
SET #Var = '2013-12-11T00:59:00.000';
SELECT
#Var AS SourceValue,
CONVERT(VARCHAR(50), #Var, 100) AS FormatedValue1,
CASE
WHEN CONVERT(VARCHAR(50), #Var, 100) LIKE '%[ ]12:__AM' THEN REPLACE(CONVERT(VARCHAR(50), #Var, 100), ' 12:', ' 00:')
ELSE CONVERT(VARCHAR(50), #Var, 100)
END AS FormatedValue2
SourceValue FormatedValue1 FormatedValue2
----------------------- ------------------- -------------------
2013-12-11 00:59:00.000 Dec 11 2013 12:59AM Dec 11 2013 00:59AM
Please try this
Select convert(varchar(20),convert(datetime, '2013-12-11 00:59:00.000'),113) + ' ' +RIGHT(CONVERT(VARCHAR(26), Convert(datetime,'2013-12-11 00:59:00.000'), 109), 2)
Output
11 Dec 2013 00:59:00 AM
Fiddle Demo
I have a table which has a datetime column. I want to show date in date-month-year forma.I am using SQL Server 2008.
You need to convert datetime column
select convert(varchar,datecolumn,103) from yourtable
Some datetime convertions:
SELECT convert(datetime, '10/23/2016', 101) -- mm/dd/yyyy
SELECT convert(datetime, '2016.10.23', 102) -- yyyy.mm.dd
SELECT convert(datetime, '23/10/2016', 103) -- dd/mm/yyyy
SELECT convert(datetime, '23.10.2016', 104) -- dd.mm.yyyy
SELECT convert(datetime, '23-10-2016', 105) -- dd-mm-yyyy
SELECT CONVERT(VARCHAR(10), GETDATE(), 111) AS [YYYY/MM/DD]
/* YYYY/MM/DD
2015/07/11 */
SELECT CONVERT(VARCHAR(10), GETDATE(), 112) AS [YYYYMMDD]
/* YYYYMMDD
20150711 */
-- SQL convert date string to datetime - time set to 00:00:00.000 or 12:00AM
PRINT CONVERT(datetime,'07-10-2012',110) -- Jul 10 2012 12:00AM
PRINT CONVERT(datetime,'2012/07/10',111) -- Jul 10 2012 12:00AM
PRINT CONVERT(datetime,'20120710', 112) -- Jul 10 2012
You can learn all DateTime convertion from here
FORMAT can be used for this;
SELECT FORMAT(GETDATE(), 'dd-MM-yyyy') --20-09-2021
in your case;
SELECT FORMAT(datetime, 'dd-MM-yyyy') AS datetime --20-09-2021
Edit;
Sorry to inform that I've just seen you mentioned SQL Server 2008 this code works for SQL Server 2012 for those who use 2012 and ends up in here!
How can I display a DATETIME value (2010-12-02 15:20:17.000) as 02/12-2010 15:20?
For SQL Server:
select stuff(convert(varchar, getdate(), 105), 3, 1, '/') + ' ' + left(convert(varchar, getdate(), 8), 5)
DateTime is a DateTime is a DateTime - it just holds a date and time and doesn't have any string representation, really.
See the CAST and CONVERT topic in the SQL Server Books Online for details - it shows all supported date formats that SQL Server supports.
For your source format (2010-12-02 15:20:17.000) you could probably use style no. 121
DECLARE #source VARCHAR(50)
SET #source = '2010-12-02 15:20:17.000'
DECLARE #Date DATETIME
SELECT #Date = CONVERT(DATETIME, #source, 121)
SELECT #Date
but your target format is a bit odd..... I don't see any "out of the box" style that would match your needs. You'll need to use some string manipulation code to get that exact format.
Use MSSQL's build-in function to convert datetime to string with format,
SELECT CONVERT(VARCHAR(8), GETDATE(), 1) AS [MM/DD/YY] --2/5/12
SELECT CONVERT(VARCHAR(10), GETDATE(), 103) AS [DD/MM/YYYY] --5/2/2012
You need to create custom function to get various format to use like this;
SELECT dbo.ufn_FormatDateTime(GETDATE(),'YYYY-MM-DD HH:mm:SS tt')
--Output : 2012-02-05 01:58:38 AM
SELECT dbo.ufn_FormatDateTime(GETDATE(),'(dddd) mmmm dd, yyyy hh:mm:ss.fff tt')
--Output : (Sunday) February 05, 2012 01:58:38.723 AM
SELECT dbo.ufn_FormatDateTime(GETDATE(),'dd/MM/yyyy')
--Output : 05/02/2012
SELECT dbo.ufn_FormatDateTime(GETDATE(),'yyyy MMM, dd (ddd) hh:mm:ss tt')
-- Output : 2012 Feb, 05 (Sun) 01:58:38 AM
Get the code snippet from this link.
http://www.tainyan.com/codesnippets/entry-62/sql-server-date-time-format-function.html
http://msdn.microsoft.com/en-us/library/ms189491.aspx
Is this what you're looking for?
Assuming Oracle:
select TO_CHAR(SYSDATE, "dd/mm-yyyy HH24:mi")
from DUAL;
Assuming SQL Server:
select STR(DATEPART(DAY, GETDATE()), 2)
+ '/'
+ STR(DATEPART(MONTH, GETDATE()), 2)
+ '-'
+ STR(DATEPART(YEAR, GETDATE()), 4)
+ ' '
+ STR(DATEPART(HOUR, GETDATE()), 2)
+ ':'
+ STR(DATEPART(MINUTE, GETDATE()), 2);
Little example I use for Germany and Switzerland: dd.mm.yyyy hh:mm
SELECT CONVERT(varchar, GETDATE(), 104) + ' ' + LEFT(CONVERT(varchar, GETDATE(), 108), 5)
i have time as 1:00PM.I have to convert to format '1/1/1900 01:00:00 PM'.Can anybody help?
select convert(datetime , "1/1/1900 " + "1:00 PM" , 101)
See "CAST and CONVERT" in sql server books online
dd/mm/yy hh:mi:ss:mmmAM
you probably want 131
but return it as a varchar
so
SELECT CONVERT(VARCHAR(20),GETDATE(),131)
STEP 1: Let's get the date and save it into #Date variable.
DECLARE #Date DATETIME;
SELECT #Date = CONVERT(DATETIME, '1:00PM' , 100);
Now #Date = 1900-01-01 13:00:00.000
STEP 2: Let's convert it into custom format
SELECT CONVERT(VARCHAR, #Date, 101) + ' '
+ REPLACE(LTRIM(SUBSTRING(CONVERT(VARCHAR, #Date, 131), 12, 14)),
':000', ' ');
This returns '1/1/1990 1:00:00 PM'