Related
I know there are several examples of recursion with CTE and so on, but how can this be accomplished just by using window functions in SQL Server 2012:
CREATE TABLE #temp
(
ID INT PRIMARY KEY IDENTITY(1,1) NOT NULL,
Percentage INT NOT NULL
)
DECLARE #Calculated MONEY = 1000
INSERT INTO #temp ( Percentage ) VALUES ( 100 )
INSERT INTO #temp ( Percentage ) VALUES ( 90)
INSERT INTO #temp ( Percentage ) VALUES ( 60)
INSERT INTO #temp ( Percentage ) VALUES ( 50)
INSERT INTO #temp ( Percentage ) VALUES ( 100)
And the result would be a running percentage like so (we are starting with $1000)
id percentage calculated
-- -------- ---------
1 100 1000
2 50 500
3 90 450
4 80 360
5 100 360
So the value for the next row is the percentage multiplied by the calculated value above that row. Can LAG be used on a computed alias?
Thanks,
You need a running product of the percentages instead of always comparing 2 consecutive rows, which is why LEAD and LAG won't work here.
You can use a windowed sum to keep a running product of the percentages against your variable to get your desired calculation:
SELECT
ID,
Expected,
EXP(SUM(LOG(CONVERT(FLOAT, Percentage) / 100)) OVER (ORDER BY ID)) * #Calculated AS Actual
FROM #Temp
Adding this to your sample code (with a column I added for your expected output):
CREATE TABLE #temp
(
ID INT PRIMARY KEY IDENTITY(1,1) NOT NULL,
Percentage INT NOT NULL,
Expected MONEY NOT NULL
)
DECLARE #Calculated MONEY = 1000
INSERT INTO #temp ( Percentage, Expected ) VALUES ( 100 , 1000)
INSERT INTO #temp ( Percentage, Expected ) VALUES ( 50, 500)
INSERT INTO #temp ( Percentage, Expected ) VALUES ( 90, 450)
INSERT INTO #temp ( Percentage, Expected ) VALUES ( 80, 360)
INSERT INTO #temp ( Percentage, Expected ) VALUES ( 100, 360)
SELECT
ID,
Expected,
EXP(SUM(LOG(CONVERT(FLOAT, Percentage) / 100)) OVER (ORDER BY ID)) * #Calculated AS Actual
FROM #Temp
This will yield your expected output:
ID Expected Actual
----------- --------------------- ----------------------
1 1000.00 1000
2 500.00 500
3 450.00 450
4 360.00 360
5 360.00 360
you can use recursive cte to get the desired result
with cte
as
(
select id, percentage, 1000 as calculated
from #temp
where id =1
union all
select t.id, t.percentage, t.percentage*cte.calculated/100 as calculated
from #temp t
join cte
on t.id = cte.id+1
)
select * from cte
I'm afraid, widow functions won't help here (at least they won't make it simple). The easiest way to achieve your goal is update statement with double assignment:
alter table #temp add VAL decimal
declare #val decimal = 1000
update t set
#val = VAL = #val * Percentage / 100
from (select top 100 percent * from #temp order by id) as t
select * from #temp
I have a scenario where I have to select multiple rows from table, I have multiple rows of one record but with different status,
at times I have two identical rows with identical data for status < for that case I canted to select Non zero for the first occurrence and set 0 for the remaining occurrences.
Below is the Image to show and I have marked strike-out and marked 0 for the remaining occurrence.
And body could suggest better SQL Query:
Here is the Query: I am getting zero value for status 1 for ID =1 but I need to show first as regular and then 0 if that status repeats again.
CREATE TABLE #Temp
(ID INT,
ItemName varchar(10),
Price Money,
[Status] INT,
[Date] Datetime)
INSERT INTO #Temp VALUES(1,'ABC',10,1,'2014-08-27')
INSERT INTO #Temp VALUES(1,'ABC',10,2,'2014-08-27')
INSERT INTO #Temp VALUES(1,'ABC',10,1,'2014-08-28')
INSERT INTO #Temp VALUES(2,'DEF',25,1,'2014-08-26')
INSERT INTO #Temp VALUES(2,'DEF',25,3,'2014-08-27')
INSERT INTO #Temp VALUES(2,'DEF',25,1,'2014-08-28')
INSERT INTO #Temp VALUES(3,'GHI',30,1,'2014-08-27')
SELECT CASE WHEN Temp.Status = 1 THEN
0
ELSE
Temp.Price END AS Price,
* FROM (SELECT * FROM #Temp) Temp
DROP TABLE #Temp
Here is the result:
You might modify your inner select using Row_Number() and set price to Zero for RowNumber > 1.
SELECT CASE WHEN Temp.RowNumber > 1 THEN
0
ELSE
Temp.Price END AS Price,
* FROM (
SELECT *,Row_Number() over (PARTITION by ID,Status ORDER BY ID,Date) AS 'RowNumber'
FROM #Temp
) Temp
Order by ID,Date
You can try this:
;WITH DataSource AS
(
SELECT RANK() OVER (PARTITION BY [ID], [ItemName], [Price], [Status] ORDER BY Date) AS [RankID]
,*
FROM #Temp
)
SELECT [ID]
,[ItemName]
,IIF([RankID] = 1, [Price], 0)
,[Status]
,[Date]
FROM DataSource
ORDER BY [ID]
,[Date]
Here is the output:
please try this below code . it is working for me.
CREATE TABLE #Temp
(ID INT,
ItemName varchar(10),
Price Money,
[Status] INT,
[Date] Datetime)
INSERT INTO #Temp VALUES(1,'ABC',10,1,'2014-08-27')
INSERT INTO #Temp VALUES(1,'ABC',10,2,'2014-08-27')
INSERT INTO #Temp VALUES(1,'ABC',10,1,'2014-08-28')
INSERT INTO #Temp VALUES(2,'DEF',25,1,'2014-08-26')
INSERT INTO #Temp VALUES(2,'DEF',25,3,'2014-08-27')
INSERT INTO #Temp VALUES(2,'DEF',25,1,'2014-08-28')
INSERT INTO #Temp VALUES(3,'GHI',30,1,'2014-08-27')
select *,case when a.rn=1 and status!=2 then price else 0 end as price from
(select *,ROW_NUMBER() over(partition by status,date order by date asc) rn from #Temp) a
order by ItemName asc
You can do this with UNION:
SELECT * FROM #Temp t
WHERE NOT EXISTS
(SELECT * FROM #Temp
WHERE t.id = id and t.status = status and t.date < date)
UNION ALL
SELECT ID, ItemName, 0 as Price, status, date
WHERE EXISTS
(SELECT * FROM #Temp
WHERE t.id = id and t.status = status and t.date < date)
Or subquery:
SELECT CASE
WHEN (SELECT COUNT(*)
FROM #Temp
WHERE t.id = id and t.status = status
and t.date > date) > 1 THEN 0 ELSE price END as NewPrice, t.*
FROM #Temp t
Or possibly RANK() function:
SELECT CASE
WHEN RANK() OVER (PARTITION BY id, status ORDER BY date) > 1
THEN 0 ELSE Price END,
t.*
FROM #Temp t
TableA:
Brand Product
------------------
A X
A XX
A XXX
B Y
B YY
C Z
I need data as shown in Table below:
A B C
-------------------
X Y Z
XX YY NULL
XXX NULL NULL
How to do that in Sql Server 2008 ?
I dont beleive a PIVOT is what you are looking for here.
From what I can see you are looking at using the entries in order to generate the rows?
Also, PIVOTs make use of aggregate functions, so I cant see this happening.
What you can try, is something like
DECLARE #Table TABLE(
Brand VARCHAR(10),
Product VARCHAR(10)
)
INSERT INTO #Table SELECT 'A','X '
INSERT INTO #Table SELECT 'A','XX'
INSERT INTO #Table SELECT 'A','XXX'
INSERT INTO #Table SELECT 'B','Y'
INSERT INTO #Table SELECT 'B','YY'
INSERT INTO #Table SELECT 'C','Z'
;WITH Vals AS (
SELECT *,
ROW_NUMBER() OVER(PARTITION BY Brand ORDER BY (SELECT NULL)) RID
FROM #Table
)
, RIDs AS (
SELECT DISTINCT
RID
FROM Vals
)
SELECT vA.Product [A],
vB.Product [B],
vC.Product [C]
FROM RIDs r LEFT JOIN
Vals vA ON r.RID = vA.RID
AND vA.Brand = 'A' LEFT JOIN
Vals vB ON r.RID = vB.RID
AND vB.Brand = 'B' LEFT JOIN
Vals vC ON r.RID = vC.RID
AND vC.Brand = 'C'
I know it is a late entry, but here is a different approach to solve it:
DECLARE #Table TABLE(Brand VARCHAR(10), Product VARCHAR(10))
INSERT INTO #Table SELECT 'A','X '
INSERT INTO #Table SELECT 'A','XX'
INSERT INTO #Table SELECT 'A','XXX'
INSERT INTO #Table SELECT 'B','Y'
INSERT INTO #Table SELECT 'B','YY'
INSERT INTO #Table SELECT 'C','Z'
SELECT [A],[B],[C] FROM (
SELECT row_number() over (partition by brand order by product) rn,
Product, brand FROM #table
) as p
PIVOT(
MAX(product) for Brand in ([A],[B],[C])
)as pvt
I have a dataset like:
type seqID text
A 1 Text1a
A 2 Text2a
A 3 Text3a
B 1 Text1b
B 2 Text2b
How do I get the row back by type with the highest seqID grouped by type? So in the above example I would want the row that has A, 3, Text3a and B, 2, Text2b returned.
SELECT *
FROM tmp t1
WHERE NOT EXISTS
(SELECT 1 FROM tmp t2 WHERE t1.type = t2.type AND t2.seqID > t1.seqID)
It shouldn't exists any other row with the same type and higher seqID.
You kind of need an ID, but since "Text" seems unique for this example
CREATE TABLE #TMP
(type VARCHAR(3), seqID INT, [text] varchar(256))
insert #TMP values ('A' , 1 , 'Text1a')
insert #TMP values ('A' , 2 , 'Text2a')
insert #TMP values ('A' , 3 , 'Text3a')
insert #TMP values ('B' , 1 , 'Text1b')
insert #TMP values ('B' , 2 , 'Text2b')
SELECT * FROM #TMP T
where [text] IN
(SELECT TOP 1 [text] FROM #TMP t2 WHERE t.type = t2.type ORDER BY t2.seqID DESC)
SELECT tbl.*
FROM
( SELECT type, MAX(seqID)
FROM tbl
GROUP BY type) maxes
WHERE
tbl.type= maxes.type AND
tbl.seqID= maxes.seqID
SELECT t.* FROM
(
SELECT type, MAX(seqID) as maxId
FROM Table
GROUP BY type
) m
INNER JOIN Table t ON m.maxId = t.seqId
Using CTE
;WITH maxIds(maxId)
AS
(
SELECT type, MAX(seqID) as maxId
FROM Table
GROUP BY type
)
SELECT t.* FROM
Table t
INNER JOIN maxIds m ON m.maxId = t.seqID
If you are on SQL Server 2005+, you could use a ranking function (more specifically, ROW_NUMBER()):
SELECT
type,
seqID,
text
FROM (
SELECT
*,
rnk = ROW_NUMBER() OVER (PARTITION BY type ORDER BY seqID DESC)
FROM atable
) s
WHERE rnk = 1
create table #tlb1(
[type] VARCHAR(3), seqID INT, [text] varchar(max)
)
declare #type varchar(3), #text varchar(max);
declare #seqID int;
declare seq_cursor cursor for
select [type], max(seqID) from tbl group by [type]
open seq_cursor
fetch next from seq_cursor into #type,#seqID
while(##fetch_status=0)
begin
set #text= (select [text] from tbl where [type]=#type and seqID=#seqid);
insert into #tlb1 values (#type, #seqID,#text);
fetch next from seq_cursor into #type,#seqID
end
select * from #tlb1
close seq_cursor
deallocate seq_cursor
truncate table #tlb1
Try:
SELECT type, max(seqID),text
FROM 'db'
GROUP BY type
As easy as that.
EDITED solution. Consider this a psuedo-code (since I am not familiar with SQL server syntax):
SELECT a.type, a.seqID, a.text FROM table a
JOIN
(SELECT type, max(seqID) seqID FROM table GROUP BY type) b
ON a.seqID = b.seqID AND a.type=b.type
I have a table like this:
ID Seq Amt
1 1 500
1 2 500
1 3 500
1 5 500
2 10 600
2 11 600
3 1 700
3 3 700
I want to group the continuous sequence numbers into a single row like this:
ID Start End TotalAmt
1 1 3 1500
1 5 5 500
2 10 11 1200
3 1 1 700
3 3 3 700
Please help to achieve this result.
WITH numbered AS (
SELECT
ID, Seq, Amt,
SeqGroup = ROW_NUMBER() OVER (PARTITION BY ID ORDER BY Seq) - Seq
FROM atable
)
SELECT
ID,
Start = MIN(Seq),
[End] = MAX(Seq),
TotalAmt = SUM(Amt)
FROM numbered
GROUP BY ID, SeqGroup
ORDER BY ID, Start
;
Well, there's perhaps a more elegant way to do this (something hints at me that there is), but here's an approach that will work if you're using a version of SQL Server that accepts common table expressions:
use Tempdb
go
create table [Test]
(
[id] int not null,
[Seq] int not null,
[Amt] int not null
)
insert into [Test] values
(1, 1, 500),
(1, 2, 500),
(1, 3, 500),
(1, 5, 500),
(2, 10, 600),
(2, 11, 600),
(3, 1, 700),
(3, 3, 700)
;with
lower_bound as (
select *
from Test
where not exists (
select *
from Test as t1
where t1.id = Test.id and t1.Seq = Test.Seq - 1
)
),
upper_bound as (
select *
from Test
where not exists (
select *
from Test as t1
where t1.id = Test.id and t1.Seq = Test.Seq + 1
)
),
bounds as (
select id, (select MAX(seq) from lower_bound where lower_bound.id = upper_bound.id and lower_bound.Seq <= upper_bound.Seq) as LBound, Seq as Ubound
from upper_bound
)
select Test.id, LBound As [Start], UBound As [End], SUM(Amt) As TotalAmt
from Test
join bounds
on Test.id = bounds.id
and Test.Seq between bounds.LBound and bounds.Ubound
group by Test.id, LBound, UBound
drop table [Test]
This seems to work nicely. #breakingRows will contain all rows that break the sequence of id and seq (i.e. if id changes or if seq is not 1 more than the previous seq). With that table you can select all rows of such a sequence within #temp. I must add however that performance will probably be not all that good because of all the subqueries but you'll need to test to be sure.
declare #temp table (id int, seq int, amt int)
insert into #temp select 1, 1, 500
insert into #temp select 1, 2, 500
insert into #temp select 1, 3, 500
insert into #temp select 1, 5, 500
insert into #temp select 2, 10, 600
insert into #temp select 2, 11, 600
insert into #temp select 3, 1, 700
insert into #temp select 3, 3, 700
declare #breakingRows table (ctr int identity(1,1), id int, seq int)
insert into #breakingRows(id, seq)
select id, seq
from #temp t1
where not exists
(select 1 from #temp t2 where t1.id = t2.id and t1.seq - 1 = t2.seq)
order by id, seq
select br.id, br.seq as start,
isnull ((select top 1 seq from #temp t2
where id < (select id from #breakingRows br2 where br.ctr = br2.ctr - 1) or
(id = (select id from #breakingRows br2 where br.ctr = br2.ctr - 1) and
seq < (select seq from #breakingRows br2 where br.ctr = br2.ctr - 1))
order by id desc, seq desc),
br.seq)
as [end],
(select SUM(amt) from #temp t1 where t1.id = br.id and
t1.seq <
isnull((select seq from #breakingRows br2 where br.ctr = br2.ctr - 1 and br.id = br2.id),
(select max(seq) + 1 from #temp)) and
t1.seq >= br.seq)
from #breakingRows br
order by id, seq
Since Andriy has already posted the gold solution, here's my take using an UPDATE statement to get the result from a temp table, just for fun.
declare #tmp table (
id int, seq int, amt money, start int, this int, total money,
primary key clustered(id, seq))
;
insert #tmp
select *, start=seq, this=seq, total=convert(money,amt)
from btable
;
declare #id int, #seq int, #start int, #amt money
update #tmp
set
#amt = total = case when id = #id and seq = #seq+1 then #amt+total else amt end,
#start = start = case when id = #id and seq = #seq+1 then #start else seq end,
#seq = this = seq,
#id = id = id
from #tmp
option (maxdop 1)
;
select id, start, max(this) [end], max(total) total
from #tmp
group by id, start
order by id, start
Notes:
btable: your table name
id int, seq int, amt money: expected columns in your table
Try following query.
select id, min(seq), max(seq), sum(amt) from table group by id
OOps, sorry, it is wrong query as you need sequence
SELECT Id, MIN(Seq) as Start, MAX(Seq) as End, SUM(Amount) as Total
FROM (
SELECT t.*, Seq - ROW_NUMBER() OVER (PARTITION BY Id ORDER BY Seq) Rn
FROM [Table] t
) as T
GROUP BY Id, Rn
ORDER BY Id, MIN(Seq)