How to find the size of a table in SQL? - sql

Question

How to find the size of a table in SQL?

Answer 1

SQL Server:-
sp_spaceused 'TableName'
Or in management studio:
Right Click on table -> Properties -> Storage
MySQL:-
SELECT table_schema, table_name, data_length, index_length FROM information_schema.tables
Sybase:-
sp_spaceused 'TableName'
Oracle:-
how-do-i-calculate-tables-size-in-oracle

Answer 2

Updating (after more than 10 years!) with an improved version using suggestions from the comments:
This gives you a list of all your tables in order of reserved size, ordered from largest to smallest.
This uses the same method as the previous one, but makes the results table a variable so it doesn't have to be cleaned up when done. Also it converts all the values to actual integers so they can be easily viewed and sorted.
DECLARE #tmpTableSizes TABLE
(
tableName VARCHAR(100),
numberofRows VARCHAR(100),
reservedSize VARCHAR(50),
dataSize VARCHAR(50),
indexSize VARCHAR(50),
unusedSize VARCHAR(50)
)
INSERT #tmpTableSizes
EXEC sp_MSforeachtable #command1="EXEC sp_spaceused '?'"
SELECT
tableName,
CAST(numberofRows AS INT) 'numberOfRows',
CAST(LEFT(reservedSize, LEN(reservedSize) - 3) AS INT) 'reservedSize KB',
CAST(LEFT(dataSize, LEN(dataSize) - 3) AS INT) 'dataSize KB',
CAST(LEFT(indexSize, LEN(indexSize) - 3) AS INT) 'indexSize KB',
CAST(LEFT(unusedSize, LEN(unusedSize) - 3) AS INT) 'unusedSize KB'
FROM
#tmpTableSizes
ORDER BY
[reservedSize KB] DESC
Previous Version before 2023-02-21:
Combining the answers from ratty's and Haim's posts (including comments) I've come up with this, which for SQL Server seems to be the most elegant so far:
-- DROP TABLE #tmpTableSizes
CREATE TABLE #tmpTableSizes
(
tableName varchar(100),
numberofRows varchar(100),
reservedSize varchar(50),
dataSize varchar(50),
indexSize varchar(50),
unusedSize varchar(50)
)
insert #tmpTableSizes
EXEC sp_MSforeachtable #command1="EXEC sp_spaceused '?'"
select * from #tmpTableSizes
order by cast(LEFT(reservedSize, LEN(reservedSize) - 4) as int) desc
This gives you a list of all your tables in order of reserved size, ordered from largest to smallest.

Answer 3

SQL Server provides a built-in stored procedure that you can run to easily show the size of a table, including the size of the indexes… which might surprise you.
Syntax:
sp_spaceused 'Tablename'
see in :
http://www.howtogeek.com/howto/database/determine-size-of-a-table-in-sql-server/

Answer 4

A query (modification of https://stackoverflow.com/a/7892349/1737819) to find a custom name table size in GB. You might try this, replace 'YourTableName' with the name of your table.
SELECT
t.NAME AS TableName,
p.rows AS RowCounts,
CONVERT(DECIMAL,SUM(a.total_pages)) * 8 / 1024 / 1024 AS TotalSpaceGB,
SUM(a.used_pages) * 8 / 1024 / 1024 AS UsedSpaceGB ,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 / 1024 / 1024 AS UnusedSpaceGB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME = 'YourTable'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
UsedSpaceGB DESC, t.Name

Answer 5

Do you by size mean the number of records in the table, by any chance? In that case:
SELECT COUNT(*) FROM your_table_name

Answer 6

I know that in SQL 2012 (may work in other versions) you can do the following:
Right click on the database name in the Object Explorer.
Select Reports > Standard Reports > Disk Usage by Top Tables.
That will give you a list of the top 1000 tables and then you can order it by data size etc.

Answer 7

And in PostgreSQL:
SELECT pg_size_pretty(pg_relation_size('tablename'));

Answer 8

SQL Server, nicely formatted table for all tables in KB/MB:
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
t.Name

Answer 9

You may refer the answer by Marc_s in another thread, Very useful.
Get size of all tables in database

Answer 10

Here's a simple query, if you are just trying to find the largest tables.
-- Find largest table partitions
SELECT top 20 obj.name, LTRIM (STR ( sz.in_row_data_page_count * 8, 15, 0) + ' KB') as Size, * FROM sys.dm_db_partition_stats sz
inner join sys.objects obj on obj.object_id = sz.object_id
order by sz.in_row_data_page_count desc

Answer 11

In SQL Server run below query you will get table with size of table.
SELECT
CASE WHEN (GROUPING(sob.name)=1) THEN 'All_Tables'
ELSE ISNULL(sob.name, 'unknown') END AS TableName,
SUM(sys.length) AS ByteLength
FROM sysobjects sob, syscolumns sys
WHERE sob.xtype='u' AND sys.id = sob.id
GROUP BY sob.name
WITH CUBE
ORDER BY SUM(sys.length) DESC