I have a table that I need to normalize with many fields In SQL-Server 2000.
It contains 2 fields which I'm using to come up with distinct combination as defined by the specs.
ID and Rate: there are multiple rows of same IDs and Rates
I first created a temp table by grouping the IDs and Rates combination.
SELECT ID, Count(*) AS IDCounts, SUM(RATE) As Total
INTO #Temp
GROUP BY ID
Now I use Distinct to find only the unique combinations. So i'll have multiple ID groups sharing same Total and IDCounts
SELECT DISTINCT Total, IDCounts
INTO #uniques
FROM #Temp
Now my question is how to join a single ID back to that distinct grouping of IDCounts and Total and put that into a new table? It doesn't matter which one of the IDs in the groups as long as I use one from the same grouping.
Keeping your temp tables (although this could all be done in a single query):
SELECT ID, Count(*) AS IDCounts, SUM(RATE) As Total
INTO #Temp
GROUP BY ID
SELECT Total, IDCounts, MIN(ID) AS SomeID
INTO #uniques
FROM #Temp
GROUP BY Total, IDCounts
Add "Min(ID) AS FirstID" to the select into #uniques.
Try something like this:
SELECT MAX(ID) AS Id, Count(*) AS IDCounts, SUM(RATE) As Total
FROM SOMETABLE
GROUP BY IDCounts, Total
Related
I have a table with various SKU in totes.
The table is totecontents with below columns:
ToteID
SKU
Each Tote can contain a maximum of 6 SKUs. (programmatically constrained)
select toteid, count(*) as qtypertote
from totecontents
group by toteid;
gives me a list of totes with the number of skus in each.
I now want to get to a table with following result
SkuCount Occurences where each row would have the ordinal value (1 through 6 ) and then the number of occurences of that value.
My efforts included the following approach
select count(*)
from
( select toteid, count(*) as qtypertote
from totecontents
group by toteid)
group by qtypertote;
Stung by the comments I performed more research. This works:
SELECT CountOfskus, COUNT(1) groupedCount
FROM
( SELECT COUNT(*) as countofskus, toteid
FROM totecontents
Group By toteid
) MyTable
GROUP BY countofskus;
I want to do a count grouping by the first column but omitting the others columns in the group by. Let me explain:
I have a table with those columns
So, what I want to get is a new column with the work orders total by Instrument, something like this:
How can I do that? Because if I do a count like this:
SELECT INSTRUMENT, WORKORDER, DATE, COUNT(*)
FROM TABLE1
GROUP BY INSTRUMENT, WORKORDER, DATE;
I get this:
Just use a window function:
select t.*,
count(*) over (partition by instrument) as instrument_count
from table1 t;
Although answer given by Gordon is perfect but there is also another option by using group by and subquery. You can add date column to this query as well
SELECT * FROM
(
SELECT A.INSTRUMENT, B.TOTAL_COUNT_BY_INSTRUMENT
FROM work_order A,
(SELECT COUNT(1) AS TOTAL_COUNT_BY_INSTRUMENT,
INSTRUMENT
FROM WORK_ORDER
GROUP BY INSTRUMENT
) B
WHERE A.INSTRUMENT = B.instrument);
Given the following table where the Name value might be repeated in multiple rows:
How can we determine how many times a Name value exists in the table and can we filter on names that have a specific number of occurrances.
For instance, how can I filter this table to show only names that appear twice?
You can use group by and having to exhibit names that appear twice in the table:
select name, count(*) cnt
from mytable
group by name
having count(*) = 2
Then if you want the overall count of names that appear twice, you can add another level of aggregation:
select count(*) cnt
from (
select name
from mytable
group by name
having count(*) = 2
) t
It sounds like you're looking for a histogram of the frequency of name counts. Something like this
with counts_cte(name, cnt) as (
select name, count(*)
from mytable
group by name)
select cnt, count(*) num_names
from counts_cte
group by cnt
order by 2 desc;
You need to use a GROUP BY clause to find counts of name repeated as
select name, count(*) AS Repeated
from Your_Table_Name
group by name;
If You want to show only those Which are repeated more than one times. Then use the below query which will show those occurrences which are there more than one times.
select name, count(*) AS Repeated
from Your_Table_Name
group by name having count(*) > 1;
Is it possible to write one query, where I would group by 2 columns in a table to get the count of total members plus get a sum of one column in that same table, but grouped by one column?
For example, the data looks like this
I want to get a count on distinct combinations of columns "OHID" and "MemID" and get the SUM of the "Amount" column grouped by OHID. The result is supposed to look like this
I was able to get the count correct using this query below
SELECT count(*) as TotCount
from (Select DISTINCT OHID, MemID
from #temp) AS TotMembers
However, when I try to use this query below to get all the results together, I am getting a count of 15 and a totally different total sum.
SELECT t.OHID,
count(TotMembers.MemID) as TotCount,
sum(t.Amount) as TotalAmount
from (Select DISTINCT OHID, MemID
from #temp) AS TotMembers
join #temp t on t.OHID = TotMembers .OHID
GROUP by t.OHID
If I understand correctly, you want to consider NULL as a valid value. The rest is just aggregation:
select t.ohid,
(count(distinct t.memid) +
(case when count(*) <> count(t.memid) then 1 else 0 end)
) as num_memid,
sum(t.amount) as total_amount
from #temp t
group by t.ohid,
The case logic might be a bit off-putting. It is just adding 1 if any values are NULL.
You might find this easier to follow with two levels of aggregation:
select t.ohid, count(*), sum(amount)
from (select t.ohid, t.memid, sum(t.amount) as amount
from #temp t
group by t.ohid, t.memid
) t
group by t.ohid
I am using the below query to get distinct records from 4 specific columns in an sql DB.
SELECT DISTINCT customer,
product,
category,
sector
FROM data_table
I need to add the count of products in this query. Any ideas?
are you find something below
select count(*) from
(SELECT DISTINCT customer, product, category, sector
FROM data_table
) a
or do you need window function count() if your dbms support
SELECT DISTINCT customer, product, category, sector,
count(*) over() as cnt
FROM data_table