I have a date picker. After choosing a time from this I would like to get the dates and time of next 30 min and 1 hour.
How would I go about writing a method to take a date and time and return as two NSDates for the next 30 min and 1 hour from that date-time.
Example: I picked time 1:30 pm from date picker then I want to fetch next 30 min time and 1 hour time with there time set.
Can any one help on this ??
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [NSDateComponents new];
components.minute = 30;
components.hour = 1;
NSDate *date = [calendar dateByAddingComponents:components toDate:< your date > options:0];
You can just use dateByAddingTimeInterval method of NSDate.
Example :
NSDate *NextDateOneHour = [oldDate dateByAddingTimeInterval:3600]; //3600 second equivalent to 60 mins
NSDate *NextDateHalfAnHour = [oldDate dateByAddingTimeInterval:1800]; //1800 second equivalent to 30 mins
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *comps = [[NSDateComponents alloc] init];
[comps setHour:1];
NSDate *afterHour = [gregorian dateByAddingComponents:comps toDate:[NSDate date] options:0];
[comps setMinute:30];
NSDate *afterHalfHour = [gregorian dateByAddingComponents:comps toDate:[NSDate date] options:0];
I have an NSDate object *myDate.I can get the week day from this date and I want to set the weekday to an integer c and get the new date object in that week only.
I searched for it and I found the answer,here is the code..
NSDateComponents *comps = [[NSDateComponents alloc] init];
[comps setDay:1];
NSDate *newDate = [[NSCalendar currentCalendar] dateByAddingComponents:comps toDate:[NSDate date] options:0];
NSLog(#"new date==%#",newDate);
This will return date of the next day.
NSDate *date = [NSDate date];
NSDateFormatter *formatter = [[[NSDateFormatter alloc] init] autorelease];
[formatter setDateFormat:#"MMM dd, yyy"];
date = [formatter dateFromString:string];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSInteger units = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit | NSWeekdayCalendarUnit;
NSDateComponents *components = [calendar components:units fromDate:date];
NSInteger day = [components day];
NSInteger weekday = [components weekday]; // if necessary
NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSUInteger unitFlags = NSMonthCalendarUnit | NSDayCalendarUnit;
NSDateComponents *components = [gregorian components:unitFlags
fromDate:dateBegin
toDate:dateEnd options:0];
totalDays = [components day];
That not gives me the total days between the 2 dates but simple the difference between the 2 days of the 2 dates. it dateBegin is 8 sep 2012 and dateEnd is 10 nov 2012 the result is 2! Why ?
Change your bellow line
NSUInteger unitFlags = NSMonthCalendarUnit | NSDayCalendarUnit;
to
NSUInteger unitFlags = NSDayCalendarUnit;
NSDateComponents *components;
NSInteger days;
components = [[NSCalendar currentCalendar] components: NSDayCalendarUnit
fromDate: startDate toDate: endDate options: 0];
days = [components day];
I've found that solution too.
What is the most efficient way to obtain an NSDate object that represents midnight of the current day?
New API in iOS 8
iOS 8 includes a new method on NSCalendar called startOfDayForDate, which is really easy to use:
let startOfToday = NSCalendar.currentCalendar().startOfDayForDate(NSDate())
Apple's description:
This API returns the first moment date of a given date.
Pass in [NSDate date], for example, if you want the start of "today".
If there were two midnights, it returns the first. If there was none, it returns the first moment that did exist.
Update, regarding time zones:
Since startOfDayForDate is a method on NSCalendar, it uses the NSCalendar's time zone. So if I wanted to see what time it was in New York, when today began in Los Angeles, I could do this:
let losAngelesCalendar = NSCalendar.currentCalendar().copy() as! NSCalendar
losAngelesCalendar.timeZone = NSTimeZone(name: "America/Los_Angeles")!
let dateTodayBeganInLosAngeles = losAngelesCalendar.startOfDayForDate(NSDate())
dateTodayBeganInLosAngeles.timeIntervalSince1970
let dateFormatter = NSDateFormatter()
dateFormatter.dateStyle = .MediumStyle
dateFormatter.timeStyle = .ShortStyle
dateFormatter.timeZone = NSTimeZone(name: "America/New_York")!
let timeInNewYorkWhenTodayBeganInLosAngeles = dateFormatter.stringFromDate(dateTodayBeganInLosAngeles)
print(timeInNewYorkWhenTodayBeganInLosAngeles) // prints "Jul 29, 2015, 3:00 AM"
Try this:
NSDate *const date = NSDate.date;
NSCalendar *const calendar = NSCalendar.currentCalendar;
NSCalendarUnit const preservedComponents = (NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay);
NSDateComponents *const components = [calendar components:preservedComponents fromDate:date];
NSDate *const normalizedDate = [calendar dateFromComponents:components];
NSCalendar *cal = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
[cal setTimeZone:[NSTimeZone systemTimeZone]];
NSDateComponents * comp = [cal components:( NSYearCalendarUnit| NSMonthCalendarUnit | NSDayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit) fromDate:[NSDate date]];
[comp setMinute:0];
[comp setHour:0];
[comp setSecond:0];
NSDate *startOfToday = [cal dateFromComponents:comp];
If you mean midnight as 23:59 then set component's hour as 23 and minutes as 59.
Swift:
let cal = NSCalendar.currentCalendar()
//tip:NSCalendarUnit can be omitted, but with the presence of it, you can take advantage of Xcode's auto-completion
var comps = cal.components(NSCalendarUnit.YearCalendarUnit | .MonthCalendarUnit | .DayCalendarUnit | .HourCalendarUnit | .MinuteCalendarUnit | .SecondCalendarUnit, fromDate: NSDate())
comps.hour = 0
comps.minute = 0
comps.second = 0
let midnightOfToday = cal.dateFromComponents(comps)!
Swift 2.2:
let cal = NSCalendar.currentCalendar()
let comps = cal.components([.Year, .Month, .Day, .Hour, .Minute, .Second], fromDate: NSDate())
comps.hour = 0
comps.minute = 0
comps.second = 0
let midnightOfToday = cal.dateFromComponents(comps)!
Objective-C:
NSCalendar *cal = [NSCalendar currentCalendar];
NSDateComponents *comps = [cal components:(NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay | NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:[NSDate date]];
[comps setHour:0];
[comps setMinute:0];
[comps setSecond:0];
NSDate *midnightOfToday = [cal dateFromComponents:comps];
You could use the following method to get the midnight value for an NSDate.
- (NSDate *)dateAtBeginningOfDayForDate:(NSDate *)inputDate
{
// Use the user's current calendar and time zone
NSCalendar *calendar = [NSCalendar currentCalendar];
NSTimeZone *timeZone = [NSTimeZone systemTimeZone];
[calendar setTimeZone:timeZone];
// Selectively convert the date components (year, month, day) of the input date
NSDateComponents *dateComps = [calendar components:NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:inputDate];
// Set the time components manually
[dateComps setHour:0];
[dateComps setMinute:0];
[dateComps setSecond:0];
// Convert back
NSDate *beginningOfDay = [calendar dateFromComponents:dateComps];
return beginningOfDay;
}
Thkis is taken from here website.
From iOS8, you can use startDayForDate.
So, in order to get the start of today (Objective -C):
NSDate * midnight;
midnight = [[NSCalendar currentCalendar] startOfDayForDate: [NSDate date]];
try this:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *now = [NSDate date];
NSDateComponents *components = [gregorian components:NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit fromDate:now];
NSDateFormatter* df = [[NSDateFormatter alloc]init];
[df setDateFormat:#"MM/dd/yyyy HH:mm:ss.SSS"];
NSLog(#"%#",[df stringFromDate:[gregorian dateFromComponents:components]]);
NSDate *now = [NSDate date];
NSDate *beginningOfToday = nil;
[[NSCalendar currentCalendar] rangeOfUnit:NSDayCalendarUnit startDate:&beginningOfToday interval:NULL forDate:now];
You could use NSCalendar's dateBySettingHour:minute:second:ofDate:options:
So it would be as easy as doing:
NSCalendar *calendar = [NSCalendar currentCalendar];
calendar.timeZone = [NSTimeZone timeZoneWithName:#"UTC"];
NSDate *midnight = [calendar dateBySettingHour:0 minute:0 second:0 ofDate:[NSDate date] options:0];
let calendar = NSCalendar.currentCalendar()
let unitFlags: NSCalendarUnit = [.Year, .Month, .Day, .Minute, .Second]
let components = calendar.components(unitFlags , fromDate: NSDate())
components.hour = 0
components.minute = 0
components.second = 0
//Gives Midnight time of today
let midnightOfToday = calendar.dateFromComponents(components)!
I'm trying to figure out what day (i.e. Monday, Friday...) of any given date (i.e. Jun 27th, 2009)
Thank you.
I've been doing:
NSDateFormatter* theDateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[theDateFormatter setFormatterBehavior:NSDateFormatterBehavior10_4];
[theDateFormatter setDateFormat:#"EEEE"];
NSString *weekDay = [theDateFormatter stringFromDate:[NSDate date]];
This has the added bonus of letting you choose how you'd like the weekday to be returned (by changing the date format string in the setDateFormat: call
Lots more information at:
http://developer.apple.com/documentation/Cocoa/Conceptual/DataFormatting/Articles/dfDateFormatting10_4.html#//apple_ref/doc/uid/TP40002369
You may have a look to the NSDate and NSCalendar classes.
For example, here and here
They provide the following code:
NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *weekdayComponents =
[gregorian components:(NSDayCalendarUnit | NSWeekdayCalendarUnit) fromDate:today];
NSInteger day = [weekdayComponents day];
NSInteger weekday = [weekdayComponents weekday];
Use NSCalendar and NSDateComponents. As shown in the NSDateComponents documentation:
NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *date = [gregorian dateFromComponents:comps];
NSDateComponents *weekdayComponents = [gregorian components:NSWeekdayCalendarUnit fromDate:date];
int weekday = [weekdayComponents weekday];
Here's what I wound up with, which works exactly as intended. It takes a date, alters the date to be the first of the month, and gets the day of that date:
NSDateComponents *components = [[NSCalendar currentCalendar] components:NSCalendarUnitDay | NSCalendarUnitMonth | NSCalendarUnitYear fromDate:date];
NSDateComponents *monthDateComponents = [[NSCalendar currentCalendar] components: NSCalendarUnitDay | NSCalendarUnitMonth | NSCalendarUnitYear |
NSCalendarUnitHour | NSCalendarUnitMinute | NSCalendarUnitSecond fromDate: date];
// build date as start of month
monthDateComponents.year = components.year;
monthDateComponents.month = components.month;
monthDateComponents.day = 1;
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
// [gregorian setFirstWeekday:1];
NSDate *builtDate =[gregorian dateFromComponents: monthDateComponents];
// NSDateComponents *weekdayComponents =[gregorian components: NSCalendarUnitWeekday fromDate: builtDate];
NSDateFormatter *df = [NSDateFormatter new];
[df setDateFormat:#"E"];
NSString *firstDay = [df stringFromDate:builtDate];
if([firstDay isEqual:#"Sun"]) // do for the other 6 days as appropriate
return 7;