db2 special character 0x1A - sql

How can I seach for a special character like "→" (0x1A)?
An example for my query is:
select * from Data where Name like '%→%'
I want to use instead of "→" something like 0x1A.
I can't use any Java or C# Code. I just have SQuirrel to connect and send commands to the database.

You can use chr() to search the charater:
select * from data where name like '%' + chr(26) + '%'

Old topic, but a current issue nevertheless. My DB2 environment runs on AS400/iSeries and use EBCDIC instead of ASCII. I worked out the character from the EBCDIC table at lookuptables.com.
ASCII 0x1a translates to SUB, and SUB translates to EBCDIC 0x3f.
Using that in SQL looks like this:
select productDescription
from productsTable
where productDescription like '%' || x'3F' || '%'`

Solution 1: Use chr(26).
Solution 2: Write the query in Java or another programming language which lets you build the SQL from pieces and where you can enter hex codes.

This query has worked for me in the past on iSeries DB2.
select * from db/table where posstr(field, x'3F') > 0
Trouble is you have to be certain of the hex value you are searching for in the string. I had a similar situation where the I was sure the hex code for the character was x'3F, but when I sub-string the non-viewable character it was actually x'22. You might want to single out the character that is giving you the issue and see what it's value is.
select hex(substr(field, 21,1)) from db/table where posstr(field, 'StringBeforeCharacter') > 0

Related

SQL: Select a column where a longer string is like a column

I want to change some data in the database where the text of a column is in a string.
For example we have the String: 'QWZ-$ §_REMARKIUFZQ'
Now I want to select a column where the column name has the text 'Mark'.
Something like this stupid try:
SELECT info FROM database WHERE '%'+name+'%' LIKE 'QWZ-$ §_REMARKIUFZQ'
Best Regards,
Christian
From sqlite doc:
The operand to the right of the LIKE operator contains the pattern and the left hand operand contains the string to match against the pattern.
Switch the LIKE operands i.e. WHERE 'QWZ-$ §_REMARKIUFZQ' LIKE '%'||name||'%' (notice + changed to sqlite concatenate operator || for native sqlite syntax).
Assuming sqlite3 version >= 3.16, you may find the table valued function pragma_table_info is the place to look.

Regular Expression Pattern for Search in SQL

I want to search a table which has file name(s) with a {Numerical Pattern String}.PDF.
Example: 1.PDF, 12.PDF, 123.PDF 1234.PDF etc.....
select * from web_pub_subfile where file_name like '[0-9]%[^a-z].pdf'
But above SQL Query is resulting even these kind of files
1801350 Ortho.pdf
699413.processing2.pdf
15-NOE-301.pdf
Could any one help me what I am missing here.
One way to do it is getting the substring before the file extension and checking if it is numeric. This solution only works well if there is only one . character in the file name.
select * from web_pub_subfile
where isnumeric(left(file_name,charindex('.',file_name)-1)) = 1
Note:
ISNUMERIC returns 1 for some characters that are not numbers, such as plus (+), minus (-), and valid currency symbols such as the dollar sign ($).
To handle file names with mutliple . characters and if there is always a .filetype extension, use
select * from web_pub_subfile
where isnumeric(left(file_name,len(file_name)-charindex('.',reverse(file_name)))) = 1
and charindex('.',file_name) > 0
Sample demo
As suggested by #Blorgbeard in the comments, to avoid the use of isnumeric, use
select * from web_pub_subfile
where left(file_name,len(file_name)-charindex('.',reverse(file_name))) NOT LIKE '%[^0-9]%'
and len(left(file_name,len(file_name)-charindex('.',reverse(file_name)))) > 0
You can't really do what you are trying to do using plain out of the box sql. The reason you are seeing those results is that the % character matches any character, any number of times. It's not like * in a regex which matches the pervious character 0 or more times.
Your best option would probably be to create some CLR functions that implement regex functionality on the SQL Server side. You can take a look at this link to find a good place to start.
Depending on your version if 2012+, you could use Try_Convert()
select * from web_pub_subfile where Try_Convert(int,replace(file_name,'.pdf',''))>0
Declare #web_pub_subfile table (file_name varchar(100))
Insert Into #web_pub_subfile values
('1801350 Ortho.pdf'),
('699413.processing2.pdf'),
('15-NOE-301.pdf'),
('1.pdf'),
('1234.pdf')
select * from #web_pub_subfile where Try_Convert(int,replace(file_name,'.pdf',''))>0
Returns
file_name
1.pdf
1234.pdf

Search special characters from SQL table

Text = “World“ world ” <world <Word> ‘ word’ ‘ word“ word’ =1254.25 = 2545.58. 20%
Hey guys,
I need to search a word from a string which was saved in my db. The searching word contains special characters such as ""'!##$%^<>. Below is the sql select query used for the search.
select * from TABLE where TABLE.text like ('%'+ '“ World' +'%')
as a result some of the special character are not searched. Characters such as double quotation, single quotation are not searched from this. need assistance with solving this problem asap. thank you :)
These Special characters are Unicode characters, When ever dealing with these characters in sql server you have to tell sql server explicitly that there can be some unicode characters in the strings you are about to manipulate by prefixing your strings with N'String'
In your case you would write a query something like ....
select * from TABLE
where TABLE.text like N'%'+ N'“ World' + N'%'
you can use the ESCAPE clause and escape your parameter value. http://technet.microsoft.com/en-us/library/ms179859.aspx
so for example to search for a string containing the character %
select * from TABLE where TABLE.text like ('%'+ N'\%' +'%') ESCAPE '\'

SQL server - how to find Hexadecimal character in a table

How to search hexadecimal characters from a SQL Server table? Actually I tried like below but it is searching all zeroes in the field.
select Email,*
from address
where CHARINDEX(convert(varchar, Ascii(0x00)), Email) > 0
Thanks
I had a similar problem where a hexadecimal character was crashing a query. This is what I did to find it.
select Email
from address
where Email like '%' + CHAR(0x00) +'%'
Now to stop the bad data getting in in the first place...

Search for “whole word match” with SQL Server LIKE pattern

Does anyone have a LIKE pattern that matches whole words only?
It needs to account for spaces, punctuation, and start/end of string as word boundaries.
I am not using SQL Full Text Search as that is not available. I don't think it would be necessary for a simple keyword search when LIKE should be able to do the trick. However if anyone has tested performance of Full Text Search against LIKE patterns, I would be interested to hear.
Edit:
I got it to this stage, but it does not match start/end of string as a word boundary.
where DealTitle like '%[^a-zA-Z]pit[^a-zA-Z]%'
I want this to match "pit" but not "spit" in a sentence or as a single word.
E.g. DealTitle might contain "a pit of despair" or "pit your wits" or "a pit" or "a pit." or "pit!" or just "pit".
Full text indexes is the answer.
The poor cousin alternative is
'.' + column + '.' LIKE '%[^a-z]pit[^a-z]%'
FYI unless you are using _CS collation, there is no need for a-zA-Z
you can just use below condition for whitespace delimiters:
(' '+YOUR_FIELD_NAME+' ') like '% doc %'
it works faster and better than other solutions. so in your case it works fine with "a pit of despair" or "pit your wits" or "a pit" or "a pit." or just "pit", but not works for "pit!".
I think the recommended patterns exclude words with do not have any character at the beginning or at the end. I would use the following additional criteria.
where DealTitle like '%[^a-z]pit[^a-z]%' OR
DealTitle like 'pit[^a-z]%' OR
DealTitle like '%[^a-z]pit'
I hope it helps you guys!
Surround your string with spaces and create a test column like this:
SELECT t.DealTitle
FROM yourtable t
CROSS APPLY (SELECT testDeal = ' ' + ISNULL(t.DealTitle,'') + ' ') fx1
WHERE fx1.testDeal LIKE '%[^a-z]pit[^a-z]%'
If you can use regexp operator in your SQL query..
For finding any combination of spaces, punctuation and start/end of string as word boundaries:
where DealTitle regexp '(^|[[:punct:]]|[[:space:]])pit([[:space:]]|[[:punct:]]|$)'
Another simple alternative:
WHERE DealTitle like '%[^a-z]pit[^a-z]%' OR
DealTitle like '[^a-z]pit[^a-z]%' OR
DealTitle like '%[^a-z]pit[^a-z]'
This is a good topic and I want to complement this to someone how needs to find some word in some string passing this as element of a query.
SELECT
ST.WORD, ND.TEXT_STRING
FROM
[ST_TABLE] ST
LEFT JOIN
[ND_TABLE] ND ON ND.TEXT_STRING LIKE '%[^a-z]' + ST.WORD + '[^a-z]%'
WHERE
ST.WORD = 'STACK_OVERFLOW' -- OPTIONAL
With this you can list all the incidences of the ST.WORD in the ND.TEXT_STRING and you can use the WHERE clausule to filter this using some word.
You could search for the entire string in SQL:
select * from YourTable where col1 like '%TheWord%'
Then you could filter the returned rows client site, adding the extra condition that it must be a whole word. For example, if it matches the regex:
\bTheWord\b
Another option is to use a CLR function, available in SQL Server 2005 and higher. That would allow you to search for the regex server-side. This MSDN artcile has the details of how to set up a dbo.RegexMatch function.
Try using charindex to find the match:
Select *
from table
where charindex( 'Whole word to be searched', columnname) > 0